\(\int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx\) [412]

Optimal result
Mathematica [A] (warning: unable to verify)
Rubi [F]
Maple [F]
Fricas [B] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [F(-1)]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 34, antiderivative size = 904 \[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx =\text {Too large to display} \] Output:

f^2*polylog(2,-exp(2*d*x+2*c))/b/d^3-(f*x+e)^2*tanh(d*x+c)/b/d+2*I*a^3*f^2 
*polylog(2,I*exp(d*x+c))/b^2/(a^2+b^2)/d^3+2*a^3*f*(f*x+e)*polylog(2,-b*ex 
p(d*x+c)/(a+(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d^2-2*a^3*f*(f*x+e)*polylo 
g(2,-b*exp(d*x+c)/(a-(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d^2+a^4*f^2*polyl 
og(2,-exp(2*d*x+2*c))/b^3/(a^2+b^2)/d^3-a^4*(f*x+e)^2*tanh(d*x+c)/b^3/(a^2 
+b^2)/d-a^3*(f*x+e)^2*sech(d*x+c)/b^2/(a^2+b^2)/d-a^2*f^2*polylog(2,-exp(2 
*d*x+2*c))/b^3/d^3+a^2*(f*x+e)^2*tanh(d*x+c)/b^3/d+a*(f*x+e)^2*sech(d*x+c) 
/b^2/d-a^4*(f*x+e)^2/b^3/(a^2+b^2)/d+2*a^4*f*(f*x+e)*ln(1+exp(2*d*x+2*c))/ 
b^3/(a^2+b^2)/d^2+4*a^3*f*(f*x+e)*arctan(exp(d*x+c))/b^2/(a^2+b^2)/d^2-2*I 
*a^3*f^2*polylog(2,-I*exp(d*x+c))/b^2/(a^2+b^2)/d^3+a^2*(f*x+e)^2/b^3/d+2* 
f*(f*x+e)*ln(1+exp(2*d*x+2*c))/b/d^2-2*a^2*f*(f*x+e)*ln(1+exp(2*d*x+2*c))/ 
b^3/d^2-4*a*f*(f*x+e)*arctan(exp(d*x+c))/b^2/d^2-2*I*a*f^2*polylog(2,I*exp 
(d*x+c))/b^2/d^3+1/3*(f*x+e)^3/b/f-(f*x+e)^2/b/d+a^3*(f*x+e)^2*ln(1+b*exp( 
d*x+c)/(a+(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d-a^3*(f*x+e)^2*ln(1+b*exp(d 
*x+c)/(a-(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d-2*a^3*f^2*polylog(3,-b*exp( 
d*x+c)/(a+(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d^3+2*a^3*f^2*polylog(3,-b*e 
xp(d*x+c)/(a-(a^2+b^2)^(1/2)))/b/(a^2+b^2)^(3/2)/d^3+2*I*a*f^2*polylog(2,- 
I*exp(d*x+c))/b^2/d^3
 

Mathematica [A] (warning: unable to verify)

Time = 2.89 (sec) , antiderivative size = 665, normalized size of antiderivative = 0.74 \[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\frac {x \left (3 e^2+3 e f x+f^2 x^2\right )}{3 b}-\frac {f \left (4 b d^2 e e^{2 c} x-4 b d^2 e \left (1+e^{2 c}\right ) x+2 b d^2 e^{2 c} f x^2-2 b d^2 \left (1+e^{2 c}\right ) f x^2+4 a d e \left (1+e^{2 c}\right ) \arctan \left (e^{c+d x}\right )+2 b d e \left (1+e^{2 c}\right ) \left (2 d x-\log \left (1+e^{2 (c+d x)}\right )\right )+2 i a \left (1+e^{2 c}\right ) f \left (d x \left (\log \left (1-i e^{c+d x}\right )-\log \left (1+i e^{c+d x}\right )\right )-\operatorname {PolyLog}\left (2,-i e^{c+d x}\right )+\operatorname {PolyLog}\left (2,i e^{c+d x}\right )\right )+b \left (1+e^{2 c}\right ) f \left (2 d x \left (d x-\log \left (1+e^{2 (c+d x)}\right )\right )-\operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )\right )\right )}{\left (a^2+b^2\right ) d^3 \left (1+e^{2 c}\right )}+\frac {a^3 \left (2 d^2 e^2 \text {arctanh}\left (\frac {a+b e^{c+d x}}{\sqrt {a^2+b^2}}\right )-2 d^2 e f x \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )-d^2 f^2 x^2 \log \left (1+\frac {b e^{c+d x}}{a-\sqrt {a^2+b^2}}\right )+2 d^2 e f x \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )+d^2 f^2 x^2 \log \left (1+\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )-2 d f (e+f x) \operatorname {PolyLog}\left (2,\frac {b e^{c+d x}}{-a+\sqrt {a^2+b^2}}\right )+2 d f (e+f x) \operatorname {PolyLog}\left (2,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )+2 f^2 \operatorname {PolyLog}\left (3,\frac {b e^{c+d x}}{-a+\sqrt {a^2+b^2}}\right )-2 f^2 \operatorname {PolyLog}\left (3,-\frac {b e^{c+d x}}{a+\sqrt {a^2+b^2}}\right )\right )}{b \left (a^2+b^2\right )^{3/2} d^3}+\frac {(e+f x)^2 \text {sech}(c+d x) (a-b \text {sech}(c) \sinh (d x))}{\left (a^2+b^2\right ) d} \] Input:

Integrate[((e + f*x)^2*Sinh[c + d*x]*Tanh[c + d*x]^2)/(a + b*Sinh[c + d*x] 
),x]
 

Output:

(x*(3*e^2 + 3*e*f*x + f^2*x^2))/(3*b) - (f*(4*b*d^2*e*E^(2*c)*x - 4*b*d^2* 
e*(1 + E^(2*c))*x + 2*b*d^2*E^(2*c)*f*x^2 - 2*b*d^2*(1 + E^(2*c))*f*x^2 + 
4*a*d*e*(1 + E^(2*c))*ArcTan[E^(c + d*x)] + 2*b*d*e*(1 + E^(2*c))*(2*d*x - 
 Log[1 + E^(2*(c + d*x))]) + (2*I)*a*(1 + E^(2*c))*f*(d*x*(Log[1 - I*E^(c 
+ d*x)] - Log[1 + I*E^(c + d*x)]) - PolyLog[2, (-I)*E^(c + d*x)] + PolyLog 
[2, I*E^(c + d*x)]) + b*(1 + E^(2*c))*f*(2*d*x*(d*x - Log[1 + E^(2*(c + d* 
x))]) - PolyLog[2, -E^(2*(c + d*x))])))/((a^2 + b^2)*d^3*(1 + E^(2*c))) + 
(a^3*(2*d^2*e^2*ArcTanh[(a + b*E^(c + d*x))/Sqrt[a^2 + b^2]] - 2*d^2*e*f*x 
*Log[1 + (b*E^(c + d*x))/(a - Sqrt[a^2 + b^2])] - d^2*f^2*x^2*Log[1 + (b*E 
^(c + d*x))/(a - Sqrt[a^2 + b^2])] + 2*d^2*e*f*x*Log[1 + (b*E^(c + d*x))/( 
a + Sqrt[a^2 + b^2])] + d^2*f^2*x^2*Log[1 + (b*E^(c + d*x))/(a + Sqrt[a^2 
+ b^2])] - 2*d*f*(e + f*x)*PolyLog[2, (b*E^(c + d*x))/(-a + Sqrt[a^2 + b^2 
])] + 2*d*f*(e + f*x)*PolyLog[2, -((b*E^(c + d*x))/(a + Sqrt[a^2 + b^2]))] 
 + 2*f^2*PolyLog[3, (b*E^(c + d*x))/(-a + Sqrt[a^2 + b^2])] - 2*f^2*PolyLo 
g[3, -((b*E^(c + d*x))/(a + Sqrt[a^2 + b^2]))]))/(b*(a^2 + b^2)^(3/2)*d^3) 
 + ((e + f*x)^2*Sech[c + d*x]*(a - b*Sech[c]*Sinh[d*x]))/((a^2 + b^2)*d)
 

Rubi [F]

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx\)

\(\Big \downarrow \) 6115

\(\displaystyle \frac {\int (e+f x)^2 \tanh ^2(c+d x)dx}{b}-\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\int -(e+f x)^2 \tan (i c+i d x)^2dx}{b}\)

\(\Big \downarrow \) 25

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\int (e+f x)^2 \tan (i c+i d x)^2dx}{b}\)

\(\Big \downarrow \) 4203

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \int i (e+f x) \tanh (c+d x)dx}{d}-\int (e+f x)^2dx+\frac {(e+f x)^2 \tanh (c+d x)}{d}}{b}\)

\(\Big \downarrow \) 17

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \int i (e+f x) \tanh (c+d x)dx}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 26

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {-\frac {2 f \int (e+f x) \tanh (c+d x)dx}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {-\frac {2 f \int -i (e+f x) \tan (i c+i d x)dx}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 26

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \int (e+f x) \tan (i c+i d x)dx}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 4201

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \left (2 i \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}}dx-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2620

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}-\frac {f \int \log \left (1+e^{2 (c+d x)}\right )dx}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2715

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}-\frac {f \int e^{-2 (c+d x)} \log \left (1+e^{2 (c+d x)}\right )de^{2 (c+d x)}}{4 d^2}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2838

\(\displaystyle -\frac {a \int \frac {(e+f x)^2 \tanh ^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 6101

\(\displaystyle -\frac {a \left (\frac {\int (e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)dx}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 5974

\(\displaystyle -\frac {a \left (\frac {\frac {2 f \int (e+f x) \text {sech}(c+d x)dx}{d}-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \int (e+f x) \csc \left (i c+i d x+\frac {\pi }{2}\right )dx}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 4668

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (-\frac {i f \int \log \left (1-i e^{c+d x}\right )dx}{d}+\frac {i f \int \log \left (1+i e^{c+d x}\right )dx}{d}+\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}\right )}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2715

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (-\frac {i f \int e^{-c-d x} \log \left (1-i e^{c+d x}\right )de^{c+d x}}{d^2}+\frac {i f \int e^{-c-d x} \log \left (1+i e^{c+d x}\right )de^{c+d x}}{d^2}+\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}\right )}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2838

\(\displaystyle -\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}(c+d x) \tanh (c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 6117

\(\displaystyle -\frac {a \left (-\frac {a \left (\frac {\int (e+f x)^2 \text {sech}^2(c+d x)dx}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}\right )}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\int (e+f x)^2 \csc \left (i c+i d x+\frac {\pi }{2}\right )^2dx}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 4672

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {2 i f \int -i (e+f x) \tanh (c+d x)dx}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 26

\(\displaystyle -\frac {a \left (-\frac {a \left (\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {2 f \int (e+f x) \tanh (c+d x)dx}{d}}{b}-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}\right )}{b}+\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {2 f \int -i (e+f x) \tan (i c+i d x)dx}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 26

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \int (e+f x) \tan (i c+i d x)dx}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 4201

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \int \frac {e^{2 (c+d x)} (e+f x)}{1+e^{2 (c+d x)}}dx-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2620

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \left (\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}-\frac {f \int \log \left (1+e^{2 (c+d x)}\right )dx}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2715

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \left (\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}-\frac {f \int e^{-2 (c+d x)} \log \left (1+e^{2 (c+d x)}\right )de^{2 (c+d x)}}{4 d^2}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 2838

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \int \frac {(e+f x)^2 \text {sech}^2(c+d x)}{a+b \sinh (c+d x)}dx}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 6107

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (-\frac {a \left (\frac {b^2 \int \frac {(e+f x)^2}{a+b \sinh (c+d x)}dx}{a^2+b^2}+\frac {\int (e+f x)^2 \text {sech}^2(c+d x) (a-b \sinh (c+d x))dx}{a^2+b^2}\right )}{b}+\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

\(\Big \downarrow \) 3042

\(\displaystyle -\frac {a \left (\frac {-\frac {(e+f x)^2 \text {sech}(c+d x)}{d}+\frac {2 f \left (\frac {2 (e+f x) \arctan \left (e^{c+d x}\right )}{d}-\frac {i f \operatorname {PolyLog}\left (2,-i e^{c+d x}\right )}{d^2}+\frac {i f \operatorname {PolyLog}\left (2,i e^{c+d x}\right )}{d^2}\right )}{d}}{b}-\frac {a \left (\frac {\frac {(e+f x)^2 \tanh (c+d x)}{d}+\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}}{b}-\frac {a \left (\frac {\int (e+f x)^2 \text {sech}^2(c+d x) (a-b \sinh (c+d x))dx}{a^2+b^2}+\frac {b^2 \int \frac {(e+f x)^2}{a-i b \sin (i c+i d x)}dx}{a^2+b^2}\right )}{b}\right )}{b}\right )}{b}-\frac {\frac {2 i f \left (2 i \left (\frac {f \operatorname {PolyLog}\left (2,-e^{2 (c+d x)}\right )}{4 d^2}+\frac {(e+f x) \log \left (e^{2 (c+d x)}+1\right )}{2 d}\right )-\frac {i (e+f x)^2}{2 f}\right )}{d}+\frac {(e+f x)^2 \tanh (c+d x)}{d}-\frac {(e+f x)^3}{3 f}}{b}\)

Input:

Int[((e + f*x)^2*Sinh[c + d*x]*Tanh[c + d*x]^2)/(a + b*Sinh[c + d*x]),x]
 

Output:

$Aborted
 
Maple [F]

\[\int \frac {\left (f x +e \right )^{2} \sinh \left (d x +c \right ) \tanh \left (d x +c \right )^{2}}{a +b \sinh \left (d x +c \right )}d x\]

Input:

int((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x)
 

Output:

int((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x)
 

Fricas [B] (verification not implemented)

Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 4196 vs. \(2 (841) = 1682\).

Time = 0.18 (sec) , antiderivative size = 4196, normalized size of antiderivative = 4.64 \[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\text {Too large to display} \] Input:

integrate((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x, algorit 
hm="fricas")
 

Output:

Too large to include
 

Sympy [F]

\[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\int \frac {\left (e + f x\right )^{2} \sinh {\left (c + d x \right )} \tanh ^{2}{\left (c + d x \right )}}{a + b \sinh {\left (c + d x \right )}}\, dx \] Input:

integrate((f*x+e)**2*sinh(d*x+c)*tanh(d*x+c)**2/(a+b*sinh(d*x+c)),x)
 

Output:

Integral((e + f*x)**2*sinh(c + d*x)*tanh(c + d*x)**2/(a + b*sinh(c + d*x)) 
, x)
 

Maxima [F]

\[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\int { \frac {{\left (f x + e\right )}^{2} \sinh \left (d x + c\right ) \tanh \left (d x + c\right )^{2}}{b \sinh \left (d x + c\right ) + a} \,d x } \] Input:

integrate((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x, algorit 
hm="maxima")
                                                                                    
                                                                                    
 

Output:

-2*b*e*f*(2*(d*x + c)/((a^2 + b^2)*d^2) - log(e^(2*d*x + 2*c) + 1)/((a^2 + 
 b^2)*d^2)) - 4*a*f^2*integrate(x*e^(d*x + c)/(a^2*d*e^(2*d*x + 2*c) + b^2 
*d*e^(2*d*x + 2*c) + a^2*d + b^2*d), x) - 4*b*f^2*integrate(x/(a^2*d*e^(2* 
d*x + 2*c) + b^2*d*e^(2*d*x + 2*c) + a^2*d + b^2*d), x) - (a^3*log((b*e^(- 
d*x - c) - a - sqrt(a^2 + b^2))/(b*e^(-d*x - c) - a + sqrt(a^2 + b^2)))/(( 
a^2*b + b^3)*sqrt(a^2 + b^2)*d) - 2*(a*e^(-d*x - c) - b)/((a^2 + b^2 + (a^ 
2 + b^2)*e^(-2*d*x - 2*c))*d) - (d*x + c)/(b*d))*e^2 - 4*a*e*f*arctan(e^(d 
*x + c))/((a^2 + b^2)*d^2) + 1/3*(12*b^2*e*f*x + (a^2*d*f^2 + b^2*d*f^2)*x 
^3 + 3*(a^2*d*e*f + (d*e*f + 2*f^2)*b^2)*x^2 + ((a^2*d*f^2*e^(2*c) + b^2*d 
*f^2*e^(2*c))*x^3 + 3*(a^2*d*e*f*e^(2*c) + b^2*d*e*f*e^(2*c))*x^2)*e^(2*d* 
x) + 6*(a*b*f^2*x^2*e^c + 2*a*b*e*f*x*e^c)*e^(d*x))/(a^2*b*d + b^3*d + (a^ 
2*b*d*e^(2*c) + b^3*d*e^(2*c))*e^(2*d*x)) - integrate(-2*(a^3*f^2*x^2*e^c 
+ 2*a^3*e*f*x*e^c)*e^(d*x)/(a^2*b^2 + b^4 - (a^2*b^2*e^(2*c) + b^4*e^(2*c) 
)*e^(2*d*x) - 2*(a^3*b*e^c + a*b^3*e^c)*e^(d*x)), x)
 

Giac [F(-1)]

Timed out. \[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\text {Timed out} \] Input:

integrate((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x, algorit 
hm="giac")
 

Output:

Timed out
 

Mupad [F(-1)]

Timed out. \[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\int \frac {\mathrm {sinh}\left (c+d\,x\right )\,{\mathrm {tanh}\left (c+d\,x\right )}^2\,{\left (e+f\,x\right )}^2}{a+b\,\mathrm {sinh}\left (c+d\,x\right )} \,d x \] Input:

int((sinh(c + d*x)*tanh(c + d*x)^2*(e + f*x)^2)/(a + b*sinh(c + d*x)),x)
 

Output:

int((sinh(c + d*x)*tanh(c + d*x)^2*(e + f*x)^2)/(a + b*sinh(c + d*x)), x)
 

Reduce [F]

\[ \int \frac {(e+f x)^2 \sinh (c+d x) \tanh ^2(c+d x)}{a+b \sinh (c+d x)} \, dx=\text {too large to display} \] Input:

int((f*x+e)^2*sinh(d*x+c)*tanh(d*x+c)^2/(a+b*sinh(d*x+c)),x)
 

Output:

( - 12*e**(2*c + 2*d*x)*atan(e**(c + d*x))*a**5*b*d*e*f - 12*e**(2*c + 2*d 
*x)*atan(e**(c + d*x))*a**5*b*f**2 - 24*e**(2*c + 2*d*x)*atan(e**(c + d*x) 
)*a**3*b**3*d*e*f - 24*e**(2*c + 2*d*x)*atan(e**(c + d*x))*a**3*b**3*f**2 
- 12*e**(2*c + 2*d*x)*atan(e**(c + d*x))*a*b**5*d*e*f - 12*e**(2*c + 2*d*x 
)*atan(e**(c + d*x))*a*b**5*f**2 - 12*atan(e**(c + d*x))*a**5*b*d*e*f - 12 
*atan(e**(c + d*x))*a**5*b*f**2 - 24*atan(e**(c + d*x))*a**3*b**3*d*e*f - 
24*atan(e**(c + d*x))*a**3*b**3*f**2 - 12*atan(e**(c + d*x))*a*b**5*d*e*f 
- 12*atan(e**(c + d*x))*a*b**5*f**2 - 6*e**(2*c + 2*d*x)*sqrt(a**2 + b**2) 
*atan((e**(c + d*x)*b*i + a*i)/sqrt(a**2 + b**2))*a**3*b**2*d**2*e**2*i - 
6*sqrt(a**2 + b**2)*atan((e**(c + d*x)*b*i + a*i)/sqrt(a**2 + b**2))*a**3* 
b**2*d**2*e**2*i - 24*e**(5*c + 2*d*x)*int((e**(3*d*x)*x**2)/(e**(6*c + 6* 
d*x)*b + 2*e**(5*c + 5*d*x)*a + e**(4*c + 4*d*x)*b + 4*e**(3*c + 3*d*x)*a 
- e**(2*c + 2*d*x)*b + 2*e**(c + d*x)*a - b),x)*a**7*d**3*f**2 - 48*e**(5* 
c + 2*d*x)*int((e**(3*d*x)*x**2)/(e**(6*c + 6*d*x)*b + 2*e**(5*c + 5*d*x)* 
a + e**(4*c + 4*d*x)*b + 4*e**(3*c + 3*d*x)*a - e**(2*c + 2*d*x)*b + 2*e** 
(c + d*x)*a - b),x)*a**5*b**2*d**3*f**2 - 24*e**(5*c + 2*d*x)*int((e**(3*d 
*x)*x**2)/(e**(6*c + 6*d*x)*b + 2*e**(5*c + 5*d*x)*a + e**(4*c + 4*d*x)*b 
+ 4*e**(3*c + 3*d*x)*a - e**(2*c + 2*d*x)*b + 2*e**(c + d*x)*a - b),x)*a** 
3*b**4*d**3*f**2 - 48*e**(5*c + 2*d*x)*int((e**(3*d*x)*x)/(e**(6*c + 6*d*x 
)*b + 2*e**(5*c + 5*d*x)*a + e**(4*c + 4*d*x)*b + 4*e**(3*c + 3*d*x)*a ...