Integrand size = 18, antiderivative size = 126 \[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\text {Chi}\left (b \left (\sqrt {c}+\sqrt {c+d x}\right )\right ) \sinh \left (a-b \sqrt {c}\right )+\text {Chi}\left (b \sqrt {c}-b \sqrt {c+d x}\right ) \sinh \left (a+b \sqrt {c}\right )+\cosh \left (a-b \sqrt {c}\right ) \text {Shi}\left (b \left (\sqrt {c}+\sqrt {c+d x}\right )\right )-\cosh \left (a+b \sqrt {c}\right ) \text {Shi}\left (b \sqrt {c}-b \sqrt {c+d x}\right ) \] Output:
Chi(b*(c^(1/2)+(d*x+c)^(1/2)))*sinh(a-b*c^(1/2))+Chi(b*c^(1/2)-b*(d*x+c)^( 1/2))*sinh(a+b*c^(1/2))+cosh(a-b*c^(1/2))*Shi(b*(c^(1/2)+(d*x+c)^(1/2)))-c osh(a+b*c^(1/2))*Shi(b*c^(1/2)-b*(d*x+c)^(1/2))
Time = 2.68 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.03 \[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\frac {1}{2} e^{-a-b \sqrt {c}} \left (-\operatorname {ExpIntegralEi}\left (b \left (\sqrt {c}-\sqrt {c+d x}\right )\right )+e^{2 \left (a+b \sqrt {c}\right )} \operatorname {ExpIntegralEi}\left (b \left (-\sqrt {c}+\sqrt {c+d x}\right )\right )-e^{2 b \sqrt {c}} \operatorname {ExpIntegralEi}\left (-b \left (\sqrt {c}+\sqrt {c+d x}\right )\right )+e^{2 a} \operatorname {ExpIntegralEi}\left (b \left (\sqrt {c}+\sqrt {c+d x}\right )\right )\right ) \] Input:
Integrate[Sinh[a + b*Sqrt[c + d*x]]/x,x]
Output:
(E^(-a - b*Sqrt[c])*(-ExpIntegralEi[b*(Sqrt[c] - Sqrt[c + d*x])] + E^(2*(a + b*Sqrt[c]))*ExpIntegralEi[b*(-Sqrt[c] + Sqrt[c + d*x])] - E^(2*b*Sqrt[c ])*ExpIntegralEi[-(b*(Sqrt[c] + Sqrt[c + d*x]))] + E^(2*a)*ExpIntegralEi[b *(Sqrt[c] + Sqrt[c + d*x])]))/2
Time = 0.66 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.13, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {5887, 25, 7267, 5815, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx\) |
\(\Big \downarrow \) 5887 |
\(\displaystyle \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{d x}d(c+d x)\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\int -\frac {\sinh \left (a+b \sqrt {c+d x}\right )}{d x}d(c+d x)\) |
\(\Big \downarrow \) 7267 |
\(\displaystyle -2 \int -\frac {\sqrt {c+d x} \sinh \left (a+b \sqrt {c+d x}\right )}{d x}d\sqrt {c+d x}\) |
\(\Big \downarrow \) 5815 |
\(\displaystyle -2 \int \left (\frac {\sinh \left (a+b \sqrt {c+d x}\right )}{2 \left (-c+\sqrt {c}-d x\right )}-\frac {\sinh \left (a+b \sqrt {c+d x}\right )}{2 \left (\sqrt {c}+\sqrt {c+d x}\right )}\right )d\sqrt {c+d x}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle -2 \left (-\frac {1}{2} \sinh \left (a-b \sqrt {c}\right ) \text {Chi}\left (\sqrt {c} b+\sqrt {c+d x} b\right )-\frac {1}{2} \sinh \left (a+b \sqrt {c}\right ) \text {Chi}\left (b \sqrt {c}-b \sqrt {c+d x}\right )+\frac {1}{2} \cosh \left (a+b \sqrt {c}\right ) \text {Shi}\left (b \sqrt {c}-b \sqrt {c+d x}\right )-\frac {1}{2} \cosh \left (a-b \sqrt {c}\right ) \text {Shi}\left (\sqrt {c} b+\sqrt {c+d x} b\right )\right )\) |
Input:
Int[Sinh[a + b*Sqrt[c + d*x]]/x,x]
Output:
-2*(-1/2*(CoshIntegral[b*Sqrt[c] + b*Sqrt[c + d*x]]*Sinh[a - b*Sqrt[c]]) - (CoshIntegral[b*Sqrt[c] - b*Sqrt[c + d*x]]*Sinh[a + b*Sqrt[c]])/2 + (Cosh [a + b*Sqrt[c]]*SinhIntegral[b*Sqrt[c] - b*Sqrt[c + d*x]])/2 - (Cosh[a - b *Sqrt[c]]*SinhIntegral[b*Sqrt[c] + b*Sqrt[c + d*x]])/2)
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*Sinh[(c_.) + (d_.)*(x_)], x_Sy mbol] :> Int[ExpandIntegrand[Sinh[c + d*x], x^m*(a + b*x^n)^p, x], x] /; Fr eeQ[{a, b, c, d}, x] && ILtQ[p, 0] && IntegerQ[m] && IGtQ[n, 0] && (EqQ[n, 2] || EqQ[p, -1])
Int[(x_)^(m_.)*((a_.) + (b_.)*Sinh[(c_.) + (d_.)*(u_)^(n_)])^(p_.), x_Symbo l] :> Simp[1/Coefficient[u, x, 1]^(m + 1) Subst[Int[(x - Coefficient[u, x , 0])^m*(a + b*Sinh[c + d*x^n])^p, x], x, u], x] /; FreeQ[{a, b, c, d, n, p }, x] && LinearQ[u, x] && NeQ[u, x] && IntegerQ[m]
Int[u_, x_Symbol] :> With[{lst = SubstForFractionalPowerOfLinear[u, x]}, Si mp[lst[[2]]*lst[[4]] Subst[Int[lst[[1]], x], x, lst[[3]]^(1/lst[[2]])], x ] /; !FalseQ[lst] && SubstForFractionalPowerQ[u, lst[[3]], x]]
\[\int \frac {\sinh \left (a +b \sqrt {d x +c}\right )}{x}d x\]
Input:
int(sinh(a+b*(d*x+c)^(1/2))/x,x)
Output:
int(sinh(a+b*(d*x+c)^(1/2))/x,x)
Leaf count of result is larger than twice the leaf count of optimal. 217 vs. \(2 (102) = 204\).
Time = 0.09 (sec) , antiderivative size = 217, normalized size of antiderivative = 1.72 \[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\frac {1}{2} \, {\left ({\rm Ei}\left (\sqrt {d x + c} b - \sqrt {b^{2} c}\right ) - {\rm Ei}\left (-\sqrt {d x + c} b + \sqrt {b^{2} c}\right )\right )} \cosh \left (a + \sqrt {b^{2} c}\right ) + \frac {1}{2} \, {\left ({\rm Ei}\left (\sqrt {d x + c} b + \sqrt {b^{2} c}\right ) - {\rm Ei}\left (-\sqrt {d x + c} b - \sqrt {b^{2} c}\right )\right )} \cosh \left (-a + \sqrt {b^{2} c}\right ) + \frac {1}{2} \, {\left ({\rm Ei}\left (\sqrt {d x + c} b - \sqrt {b^{2} c}\right ) + {\rm Ei}\left (-\sqrt {d x + c} b + \sqrt {b^{2} c}\right )\right )} \sinh \left (a + \sqrt {b^{2} c}\right ) - \frac {1}{2} \, {\left ({\rm Ei}\left (\sqrt {d x + c} b + \sqrt {b^{2} c}\right ) + {\rm Ei}\left (-\sqrt {d x + c} b - \sqrt {b^{2} c}\right )\right )} \sinh \left (-a + \sqrt {b^{2} c}\right ) \] Input:
integrate(sinh(a+b*(d*x+c)^(1/2))/x,x, algorithm="fricas")
Output:
1/2*(Ei(sqrt(d*x + c)*b - sqrt(b^2*c)) - Ei(-sqrt(d*x + c)*b + sqrt(b^2*c) ))*cosh(a + sqrt(b^2*c)) + 1/2*(Ei(sqrt(d*x + c)*b + sqrt(b^2*c)) - Ei(-sq rt(d*x + c)*b - sqrt(b^2*c)))*cosh(-a + sqrt(b^2*c)) + 1/2*(Ei(sqrt(d*x + c)*b - sqrt(b^2*c)) + Ei(-sqrt(d*x + c)*b + sqrt(b^2*c)))*sinh(a + sqrt(b^ 2*c)) - 1/2*(Ei(sqrt(d*x + c)*b + sqrt(b^2*c)) + Ei(-sqrt(d*x + c)*b - sqr t(b^2*c)))*sinh(-a + sqrt(b^2*c))
\[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\int \frac {\sinh {\left (a + b \sqrt {c + d x} \right )}}{x}\, dx \] Input:
integrate(sinh(a+b*(d*x+c)**(1/2))/x,x)
Output:
Integral(sinh(a + b*sqrt(c + d*x))/x, x)
\[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\int { \frac {\sinh \left (\sqrt {d x + c} b + a\right )}{x} \,d x } \] Input:
integrate(sinh(a+b*(d*x+c)^(1/2))/x,x, algorithm="maxima")
Output:
integrate(sinh(sqrt(d*x + c)*b + a)/x, x)
\[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\int { \frac {\sinh \left (\sqrt {d x + c} b + a\right )}{x} \,d x } \] Input:
integrate(sinh(a+b*(d*x+c)^(1/2))/x,x, algorithm="giac")
Output:
integrate(sinh(sqrt(d*x + c)*b + a)/x, x)
Timed out. \[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\int \frac {\mathrm {sinh}\left (a+b\,\sqrt {c+d\,x}\right )}{x} \,d x \] Input:
int(sinh(a + b*(c + d*x)^(1/2))/x,x)
Output:
int(sinh(a + b*(c + d*x)^(1/2))/x, x)
\[ \int \frac {\sinh \left (a+b \sqrt {c+d x}\right )}{x} \, dx=\int \frac {\sinh \left (\sqrt {d x +c}\, b +a \right )}{x}d x \] Input:
int(sinh(a+b*(d*x+c)^(1/2))/x,x)
Output:
int(sinh(sqrt(c + d*x)*b + a)/x,x)