\(\int e^x \text {csch}(4 x) \, dx\) [320]

Optimal result

Integrand size = 8, antiderivative size = 88 \[ \int e^x \text {csch}(4 x) \, dx=-\frac {1}{2} \arctan \left (e^x\right )-\frac {\arctan \left (1-\sqrt {2} e^x\right )}{2 \sqrt {2}}+\frac {\arctan \left (1+\sqrt {2} e^x\right )}{2 \sqrt {2}}-\frac {\text {arctanh}\left (e^x\right )}{2}+\frac {\text {arctanh}\left (\frac {\sqrt {2} e^x}{1+e^{2 x}}\right )}{2 \sqrt {2}} \] Output:

-1/2*arctan(exp(x))+1/4*arctan(-1+2^(1/2)*exp(x))*2^(1/2)+1/4*arctan(1+2^( 
1/2)*exp(x))*2^(1/2)-1/2*arctanh(exp(x))+1/4*arctanh(2^(1/2)*exp(x)/(1+exp 
(2*x)))*2^(1/2)
 

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.

Time = 0.01 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.25 \[ \int e^x \text {csch}(4 x) \, dx=-\frac {2}{5} e^{5 x} \operatorname {Hypergeometric2F1}\left (\frac {5}{8},1,\frac {13}{8},e^{8 x}\right ) \] Input:

Integrate[E^x*Csch[4*x],x]
 

Output:

(-2*E^(5*x)*Hypergeometric2F1[5/8, 1, 13/8, E^(8*x)])/5
 

Rubi [A] (verified)

Time = 0.38 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.48, number of steps used = 15, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 1.750, Rules used = {2720, 27, 830, 755, 756, 216, 219, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int e^x \text {csch}(4 x) \, dx\)

\(\Big \downarrow \) 2720

\(\displaystyle \int -\frac {2 e^{4 x}}{1-e^{8 x}}de^x\)

\(\Big \downarrow \) 27

\(\displaystyle -2 \int \frac {e^{4 x}}{1-e^{8 x}}de^x\)

\(\Big \downarrow \) 830

\(\displaystyle -2 \left (\frac {1}{2} \int \frac {1}{1-e^{4 x}}de^x-\frac {1}{2} \int \frac {1}{1+e^{4 x}}de^x\right )\)

\(\Big \downarrow \) 755

\(\displaystyle -2 \left (\frac {1}{2} \int \frac {1}{1-e^{4 x}}de^x+\frac {1}{2} \left (-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x-\frac {1}{2} \int \frac {1+e^{2 x}}{1+e^{4 x}}de^x\right )\right )\)

\(\Big \downarrow \) 756

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{1-e^{2 x}}de^x+\frac {1}{2} \int \frac {1}{1+e^{2 x}}de^x\right )+\frac {1}{2} \left (-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x-\frac {1}{2} \int \frac {1+e^{2 x}}{1+e^{4 x}}de^x\right )\right )\)

\(\Big \downarrow \) 216

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \int \frac {1}{1-e^{2 x}}de^x+\frac {\arctan \left (e^x\right )}{2}\right )+\frac {1}{2} \left (-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x-\frac {1}{2} \int \frac {1+e^{2 x}}{1+e^{4 x}}de^x\right )\right )\)

\(\Big \downarrow \) 219

\(\displaystyle -2 \left (\frac {1}{2} \left (-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x-\frac {1}{2} \int \frac {1+e^{2 x}}{1+e^{4 x}}de^x\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 1476

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (-\frac {1}{2} \int \frac {1}{1-\sqrt {2} e^x+e^{2 x}}de^x-\frac {1}{2} \int \frac {1}{1+\sqrt {2} e^x+e^{2 x}}de^x\right )-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 1082

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (\frac {\int \frac {1}{-1-e^{2 x}}d\left (1+\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\int \frac {1}{-1-e^{2 x}}d\left (1-\sqrt {2} e^x\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 217

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (\frac {\arctan \left (1-\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\arctan \left (\sqrt {2} e^x+1\right )}{\sqrt {2}}\right )-\frac {1}{2} \int \frac {1-e^{2 x}}{1+e^{4 x}}de^x\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 1479

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (\frac {\int -\frac {\sqrt {2}-2 e^x}{1-\sqrt {2} e^x+e^{2 x}}de^x}{2 \sqrt {2}}+\frac {\int -\frac {\sqrt {2} \left (1+\sqrt {2} e^x\right )}{1+\sqrt {2} e^x+e^{2 x}}de^x}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (1-\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\arctan \left (\sqrt {2} e^x+1\right )}{\sqrt {2}}\right )\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 25

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-2 e^x}{1-\sqrt {2} e^x+e^{2 x}}de^x}{2 \sqrt {2}}-\frac {\int \frac {\sqrt {2} \left (1+\sqrt {2} e^x\right )}{1+\sqrt {2} e^x+e^{2 x}}de^x}{2 \sqrt {2}}\right )+\frac {1}{2} \left (\frac {\arctan \left (1-\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\arctan \left (\sqrt {2} e^x+1\right )}{\sqrt {2}}\right )\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 27

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {1}{2} \left (-\frac {\int \frac {\sqrt {2}-2 e^x}{1-\sqrt {2} e^x+e^{2 x}}de^x}{2 \sqrt {2}}-\frac {1}{2} \int \frac {1+\sqrt {2} e^x}{1+\sqrt {2} e^x+e^{2 x}}de^x\right )+\frac {1}{2} \left (\frac {\arctan \left (1-\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\arctan \left (\sqrt {2} e^x+1\right )}{\sqrt {2}}\right )\right )+\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )\right )\)

\(\Big \downarrow \) 1103

\(\displaystyle -2 \left (\frac {1}{2} \left (\frac {\arctan \left (e^x\right )}{2}+\frac {\text {arctanh}\left (e^x\right )}{2}\right )+\frac {1}{2} \left (\frac {1}{2} \left (\frac {\arctan \left (1-\sqrt {2} e^x\right )}{\sqrt {2}}-\frac {\arctan \left (\sqrt {2} e^x+1\right )}{\sqrt {2}}\right )+\frac {1}{2} \left (\frac {\log \left (-\sqrt {2} e^x+e^{2 x}+1\right )}{2 \sqrt {2}}-\frac {\log \left (\sqrt {2} e^x+e^{2 x}+1\right )}{2 \sqrt {2}}\right )\right )\right )\)

Input:

Int[E^x*Csch[4*x],x]
 

Output:

-2*((ArcTan[E^x]/2 + ArcTanh[E^x]/2)/2 + ((ArcTan[1 - Sqrt[2]*E^x]/Sqrt[2] 
 - ArcTan[1 + Sqrt[2]*E^x]/Sqrt[2])/2 + (Log[1 - Sqrt[2]*E^x + E^(2*x)]/(2 
*Sqrt[2]) - Log[1 + Sqrt[2]*E^x + E^(2*x)]/(2*Sqrt[2]))/2)/2)
 

Defintions of rubi rules used

rule 25

Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27

Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 216

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[b, 2]))*A 
rcTan[Rt[b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (GtQ[a 
, 0] || GtQ[b, 0])
 

rule 217

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 219

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* 
ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt 
Q[a, 0] || LtQ[b, 0])
 

rule 755

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2] 
], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*r)   Int[(r - s*x^2)/(a + b*x^4) 
, x], x] + Simp[1/(2*r)   Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{a, 
 b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] & 
& AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 756

Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 
]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a)   Int[1/(r - s*x^2), x], x] 
 + Simp[r/(2*a)   Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ[a 
/b, 0]
 

rule 830

Int[(x_)^(m_)/((a_) + (b_.)*(x_)^(n_)), x_Symbol] :> With[{r = Numerator[Rt 
[-a/b, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[s/(2*b)   Int[x^(m - n/2)/( 
r + s*x^(n/2)), x], x] - Simp[s/(2*b)   Int[x^(m - n/2)/(r - s*x^(n/2)), x] 
, x]] /; FreeQ[{a, b}, x] && IGtQ[n/4, 0] && IGtQ[m, 0] && LeQ[n/2, m] && L 
tQ[m, n] &&  !GtQ[a/b, 0]
 

rule 1082

Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479

Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 2720

Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] 
   Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct 
ionOfExponentialQ[u, x] &&  !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ 
[{a, m, n}, x] && IntegerQ[m*n]] &&  !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) 
*(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
 

Maple [C] (verified)

Result contains higher order function than in optimal. Order 9 vs. order 3.

Time = 0.20 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.64

method	result	size
risch	\(\frac {\ln \left ({\mathrm e}^{x}-1\right )}{4}+\frac {i \ln \left ({\mathrm e}^{x}-i\right )}{4}-\frac {i \ln \left ({\mathrm e}^{x}+i\right )}{4}-\frac {\ln \left ({\mathrm e}^{x}+1\right )}{4}+2 \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (4096 \textit {\_Z}^{4}+1\right )}{\sum }\textit {\_R} \ln \left ({\mathrm e}^{x}+8 \textit {\_R} \right )\right )\)	\(56\)

Input:

int(exp(x)*csch(4*x),x,method=_RETURNVERBOSE)
 

Output:

1/4*ln(exp(x)-1)+1/4*I*ln(exp(x)-I)-1/4*I*ln(exp(x)+I)-1/4*ln(exp(x)+1)+2* 
sum(_R*ln(exp(x)+8*_R),_R=RootOf(4096*_Z^4+1))
 

Fricas [A] (verification not implemented)

Time = 0.09 (sec) , antiderivative size = 116, normalized size of antiderivative = 1.32 \[ \int e^x \text {csch}(4 x) \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\sqrt {2} \cosh \left (x\right ) + \sqrt {2} \sinh \left (x\right ) + 1\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (\sqrt {2} \cosh \left (x\right ) + \sqrt {2} \sinh \left (x\right ) - 1\right ) + \frac {1}{8} \, \sqrt {2} \log \left (\frac {\sqrt {2} + 2 \, \cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) - \frac {1}{8} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - 2 \, \cosh \left (x\right )}{\cosh \left (x\right ) - \sinh \left (x\right )}\right ) - \frac {1}{2} \, \arctan \left (\cosh \left (x\right ) + \sinh \left (x\right )\right ) - \frac {1}{4} \, \log \left (\cosh \left (x\right ) + \sinh \left (x\right ) + 1\right ) + \frac {1}{4} \, \log \left (\cosh \left (x\right ) + \sinh \left (x\right ) - 1\right ) \] Input:

integrate(exp(x)*csch(4*x),x, algorithm="fricas")
 

Output:

1/4*sqrt(2)*arctan(sqrt(2)*cosh(x) + sqrt(2)*sinh(x) + 1) + 1/4*sqrt(2)*ar 
ctan(sqrt(2)*cosh(x) + sqrt(2)*sinh(x) - 1) + 1/8*sqrt(2)*log((sqrt(2) + 2 
*cosh(x))/(cosh(x) - sinh(x))) - 1/8*sqrt(2)*log(-(sqrt(2) - 2*cosh(x))/(c 
osh(x) - sinh(x))) - 1/2*arctan(cosh(x) + sinh(x)) - 1/4*log(cosh(x) + sin 
h(x) + 1) + 1/4*log(cosh(x) + sinh(x) - 1)
 

Sympy [F]

\[ \int e^x \text {csch}(4 x) \, dx=\int e^{x} \operatorname {csch}{\left (4 x \right )}\, dx \] Input:

integrate(exp(x)*csch(4*x),x)
 

Output:

Integral(exp(x)*csch(4*x), x)
 

Maxima [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.08 \[ \int e^x \text {csch}(4 x) \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, e^{x}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, e^{x}\right )}\right ) + \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {1}{2} \, \arctan \left (e^{x}\right ) - \frac {1}{4} \, \log \left (e^{x} + 1\right ) + \frac {1}{4} \, \log \left (e^{x} - 1\right ) \] Input:

integrate(exp(x)*csch(4*x),x, algorithm="maxima")
 

Output:

1/4*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*e^x)) + 1/4*sqrt(2)*arctan(-1/ 
2*sqrt(2)*(sqrt(2) - 2*e^x)) + 1/8*sqrt(2)*log(sqrt(2)*e^x + e^(2*x) + 1) 
- 1/8*sqrt(2)*log(-sqrt(2)*e^x + e^(2*x) + 1) - 1/2*arctan(e^x) - 1/4*log( 
e^x + 1) + 1/4*log(e^x - 1)
 

Giac [A] (verification not implemented)

Time = 0.12 (sec) , antiderivative size = 96, normalized size of antiderivative = 1.09 \[ \int e^x \text {csch}(4 x) \, dx=\frac {1}{4} \, \sqrt {2} \arctan \left (\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} + 2 \, e^{x}\right )}\right ) + \frac {1}{4} \, \sqrt {2} \arctan \left (-\frac {1}{2} \, \sqrt {2} {\left (\sqrt {2} - 2 \, e^{x}\right )}\right ) + \frac {1}{8} \, \sqrt {2} \log \left (\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {1}{8} \, \sqrt {2} \log \left (-\sqrt {2} e^{x} + e^{\left (2 \, x\right )} + 1\right ) - \frac {1}{2} \, \arctan \left (e^{x}\right ) - \frac {1}{4} \, \log \left (e^{x} + 1\right ) + \frac {1}{4} \, \log \left ({\left | e^{x} - 1 \right |}\right ) \] Input:

integrate(exp(x)*csch(4*x),x, algorithm="giac")
 

Output:

1/4*sqrt(2)*arctan(1/2*sqrt(2)*(sqrt(2) + 2*e^x)) + 1/4*sqrt(2)*arctan(-1/ 
2*sqrt(2)*(sqrt(2) - 2*e^x)) + 1/8*sqrt(2)*log(sqrt(2)*e^x + e^(2*x) + 1) 
- 1/8*sqrt(2)*log(-sqrt(2)*e^x + e^(2*x) + 1) - 1/2*arctan(e^x) - 1/4*log( 
e^x + 1) + 1/4*log(abs(e^x - 1))
 

Mupad [B] (verification not implemented)

Time = 0.37 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.20 \[ \int e^x \text {csch}(4 x) \, dx=\frac {\ln \left (128-128\,{\mathrm {e}}^x\right )}{4}-\frac {\ln \left (-128\,{\mathrm {e}}^x-128\right )}{4}-\frac {\mathrm {atan}\left ({\mathrm {e}}^x\right )}{2}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\left (128\,{\mathrm {e}}^x-64\,\sqrt {2}\right )}{128}\right )}{4}+\frac {\sqrt {2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,\left (128\,{\mathrm {e}}^x+64\,\sqrt {2}\right )}{128}\right )}{4}-\frac {\sqrt {2}\,\ln \left ({\left (128\,{\mathrm {e}}^x-64\,\sqrt {2}\right )}^2+8192\right )}{8}+\frac {\sqrt {2}\,\ln \left ({\left (128\,{\mathrm {e}}^x+64\,\sqrt {2}\right )}^2+8192\right )}{8} \] Input:

int(exp(x)/sinh(4*x),x)
 

Output:

log(128 - 128*exp(x))/4 - log(- 128*exp(x) - 128)/4 - atan(exp(x))/2 + (2^ 
(1/2)*atan((2^(1/2)*(128*exp(x) - 64*2^(1/2)))/128))/4 + (2^(1/2)*atan((2^ 
(1/2)*(128*exp(x) + 64*2^(1/2)))/128))/4 - (2^(1/2)*log((128*exp(x) - 64*2 
^(1/2))^2 + 8192))/8 + (2^(1/2)*log((128*exp(x) + 64*2^(1/2))^2 + 8192))/8
 

Reduce [B] (verification not implemented)

Time = 0.15 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.11 \[ \int e^x \text {csch}(4 x) \, dx=-\frac {\mathit {atan} \left (e^{x}\right )}{2}+\frac {\sqrt {2}\, \mathit {atan} \left (\frac {2 e^{x}-\sqrt {2}}{\sqrt {2}}\right )}{4}+\frac {\sqrt {2}\, \mathit {atan} \left (\frac {2 e^{x}+\sqrt {2}}{\sqrt {2}}\right )}{4}-\frac {\sqrt {2}\, \mathrm {log}\left (e^{2 x}-e^{x} \sqrt {2}+1\right )}{8}+\frac {\sqrt {2}\, \mathrm {log}\left (e^{2 x}+e^{x} \sqrt {2}+1\right )}{8}+\frac {\mathrm {log}\left (e^{x}-1\right )}{4}-\frac {\mathrm {log}\left (e^{x}+1\right )}{4} \] Input:

int(exp(x)*csch(4*x),x)
 

Output:

( - 4*atan(e**x) + 2*sqrt(2)*atan((2*e**x - sqrt(2))/sqrt(2)) + 2*sqrt(2)* 
atan((2*e**x + sqrt(2))/sqrt(2)) - sqrt(2)*log(e**(2*x) - e**x*sqrt(2) + 1 
) + sqrt(2)*log(e**(2*x) + e**x*sqrt(2) + 1) + 2*log(e**x - 1) - 2*log(e** 
x + 1))/8