Integrand size = 23, antiderivative size = 60 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=-\frac {b \text {arctanh}\left (\frac {\sqrt {a-b} \tanh (c+d x)}{\sqrt {a}}\right )}{\sqrt {a} (a-b)^{3/2} d}+\frac {\tanh (c+d x)}{(a-b) d} \] Output:
-b*arctanh((a-b)^(1/2)*tanh(d*x+c)/a^(1/2))/a^(1/2)/(a-b)^(3/2)/d+tanh(d*x +c)/(a-b)/d
Time = 0.29 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.00 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=-\frac {b \text {arctanh}\left (\frac {\sqrt {a-b} \tanh (c+d x)}{\sqrt {a}}\right )}{\sqrt {a} (a-b)^{3/2} d}+\frac {\tanh (c+d x)}{(a-b) d} \] Input:
Integrate[Sech[c + d*x]^2/(a + b*Sinh[c + d*x]^2),x]
Output:
-((b*ArcTanh[(Sqrt[a - b]*Tanh[c + d*x])/Sqrt[a]])/(Sqrt[a]*(a - b)^(3/2)* d)) + Tanh[c + d*x]/((a - b)*d)
Time = 0.27 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.97, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3042, 3670, 299, 221}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \frac {1}{\cos (i c+i d x)^2 \left (a-b \sin (i c+i d x)^2\right )}dx\) |
\(\Big \downarrow \) 3670 |
\(\displaystyle \frac {\int \frac {1-\tanh ^2(c+d x)}{a-(a-b) \tanh ^2(c+d x)}d\tanh (c+d x)}{d}\) |
\(\Big \downarrow \) 299 |
\(\displaystyle \frac {\frac {\tanh (c+d x)}{a-b}-\frac {b \int \frac {1}{a-(a-b) \tanh ^2(c+d x)}d\tanh (c+d x)}{a-b}}{d}\) |
\(\Big \downarrow \) 221 |
\(\displaystyle \frac {\frac {\tanh (c+d x)}{a-b}-\frac {b \text {arctanh}\left (\frac {\sqrt {a-b} \tanh (c+d x)}{\sqrt {a}}\right )}{\sqrt {a} (a-b)^{3/2}}}{d}\) |
Input:
Int[Sech[c + d*x]^2/(a + b*Sinh[c + d*x]^2),x]
Output:
(-((b*ArcTanh[(Sqrt[a - b]*Tanh[c + d*x])/Sqrt[a]])/(Sqrt[a]*(a - b)^(3/2) )) + Tanh[c + d*x]/(a - b))/d
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x /Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
Int[((a_) + (b_.)*(x_)^2)^(p_)*((c_) + (d_.)*(x_)^2), x_Symbol] :> Simp[d*x *((a + b*x^2)^(p + 1)/(b*(2*p + 3))), x] - Simp[(a*d - b*c*(2*p + 3))/(b*(2 *p + 3)) Int[(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && NeQ[2*p + 3, 0]
Int[cos[(e_.) + (f_.)*(x_)]^(m_)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)]^2)^( p_.), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x], x]}, Simp[ff/f Su bst[Int[(a + (a + b)*ff^2*x^2)^p/(1 + ff^2*x^2)^(m/2 + p + 1), x], x, Tan[e + f*x]/ff], x]] /; FreeQ[{a, b, e, f}, x] && IntegerQ[m/2] && IntegerQ[p]
Leaf count of result is larger than twice the leaf count of optimal. \(194\) vs. \(2(52)=104\).
Time = 61.50 (sec) , antiderivative size = 195, normalized size of antiderivative = 3.25
method | result | size |
risch | \(-\frac {2}{d \left (a -b \right ) \left ({\mathrm e}^{2 d x +2 c}+1\right )}+\frac {b \ln \left ({\mathrm e}^{2 d x +2 c}+\frac {2 a \sqrt {a^{2}-a b}-b \sqrt {a^{2}-a b}+2 a^{2}-2 a b}{b \sqrt {a^{2}-a b}}\right )}{2 \sqrt {a^{2}-a b}\, \left (a -b \right ) d}-\frac {b \ln \left ({\mathrm e}^{2 d x +2 c}+\frac {2 a \sqrt {a^{2}-a b}-b \sqrt {a^{2}-a b}-2 a^{2}+2 a b}{b \sqrt {a^{2}-a b}}\right )}{2 \sqrt {a^{2}-a b}\, \left (a -b \right ) d}\) | \(195\) |
derivativedivides | \(\frac {\frac {2 b a \left (-\frac {\left (\sqrt {-b \left (a -b \right )}-b \right ) \operatorname {arctanh}\left (\frac {\tanh \left (\frac {d x}{2}+\frac {c}{2}\right ) a}{\sqrt {\left (2 \sqrt {-b \left (a -b \right )}+a -2 b \right ) a}}\right )}{2 a \sqrt {-b \left (a -b \right )}\, \sqrt {\left (2 \sqrt {-b \left (a -b \right )}+a -2 b \right ) a}}+\frac {\left (\sqrt {-b \left (a -b \right )}+b \right ) \arctan \left (\frac {\tanh \left (\frac {d x}{2}+\frac {c}{2}\right ) a}{\sqrt {\left (2 \sqrt {-b \left (a -b \right )}-a +2 b \right ) a}}\right )}{2 a \sqrt {-b \left (a -b \right )}\, \sqrt {\left (2 \sqrt {-b \left (a -b \right )}-a +2 b \right ) a}}\right )}{a -b}+\frac {2 \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{\left (a -b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+1\right )}}{d}\) | \(219\) |
default | \(\frac {\frac {2 b a \left (-\frac {\left (\sqrt {-b \left (a -b \right )}-b \right ) \operatorname {arctanh}\left (\frac {\tanh \left (\frac {d x}{2}+\frac {c}{2}\right ) a}{\sqrt {\left (2 \sqrt {-b \left (a -b \right )}+a -2 b \right ) a}}\right )}{2 a \sqrt {-b \left (a -b \right )}\, \sqrt {\left (2 \sqrt {-b \left (a -b \right )}+a -2 b \right ) a}}+\frac {\left (\sqrt {-b \left (a -b \right )}+b \right ) \arctan \left (\frac {\tanh \left (\frac {d x}{2}+\frac {c}{2}\right ) a}{\sqrt {\left (2 \sqrt {-b \left (a -b \right )}-a +2 b \right ) a}}\right )}{2 a \sqrt {-b \left (a -b \right )}\, \sqrt {\left (2 \sqrt {-b \left (a -b \right )}-a +2 b \right ) a}}\right )}{a -b}+\frac {2 \tanh \left (\frac {d x}{2}+\frac {c}{2}\right )}{\left (a -b \right ) \left (\tanh \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}+1\right )}}{d}\) | \(219\) |
Input:
int(sech(d*x+c)^2/(a+b*sinh(d*x+c)^2),x,method=_RETURNVERBOSE)
Output:
-2/d/(a-b)/(exp(2*d*x+2*c)+1)+1/2/(a^2-a*b)^(1/2)*b/(a-b)/d*ln(exp(2*d*x+2 *c)+(2*a*(a^2-a*b)^(1/2)-b*(a^2-a*b)^(1/2)+2*a^2-2*a*b)/b/(a^2-a*b)^(1/2)) -1/2/(a^2-a*b)^(1/2)*b/(a-b)/d*ln(exp(2*d*x+2*c)+(2*a*(a^2-a*b)^(1/2)-b*(a ^2-a*b)^(1/2)-2*a^2+2*a*b)/b/(a^2-a*b)^(1/2))
Leaf count of result is larger than twice the leaf count of optimal. 226 vs. \(2 (52) = 104\).
Time = 0.12 (sec) , antiderivative size = 709, normalized size of antiderivative = 11.82 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx =\text {Too large to display} \] Input:
integrate(sech(d*x+c)^2/(a+b*sinh(d*x+c)^2),x, algorithm="fricas")
Output:
[-1/2*((b*cosh(d*x + c)^2 + 2*b*cosh(d*x + c)*sinh(d*x + c) + b*sinh(d*x + c)^2 + b)*sqrt(a^2 - a*b)*log((b^2*cosh(d*x + c)^4 + 4*b^2*cosh(d*x + c)* sinh(d*x + c)^3 + b^2*sinh(d*x + c)^4 + 2*(2*a*b - b^2)*cosh(d*x + c)^2 + 2*(3*b^2*cosh(d*x + c)^2 + 2*a*b - b^2)*sinh(d*x + c)^2 + 8*a^2 - 8*a*b + b^2 + 4*(b^2*cosh(d*x + c)^3 + (2*a*b - b^2)*cosh(d*x + c))*sinh(d*x + c) - 4*(b*cosh(d*x + c)^2 + 2*b*cosh(d*x + c)*sinh(d*x + c) + b*sinh(d*x + c) ^2 + 2*a - b)*sqrt(a^2 - a*b))/(b*cosh(d*x + c)^4 + 4*b*cosh(d*x + c)*sinh (d*x + c)^3 + b*sinh(d*x + c)^4 + 2*(2*a - b)*cosh(d*x + c)^2 + 2*(3*b*cos h(d*x + c)^2 + 2*a - b)*sinh(d*x + c)^2 + 4*(b*cosh(d*x + c)^3 + (2*a - b) *cosh(d*x + c))*sinh(d*x + c) + b)) + 4*a^2 - 4*a*b)/((a^3 - 2*a^2*b + a*b ^2)*d*cosh(d*x + c)^2 + 2*(a^3 - 2*a^2*b + a*b^2)*d*cosh(d*x + c)*sinh(d*x + c) + (a^3 - 2*a^2*b + a*b^2)*d*sinh(d*x + c)^2 + (a^3 - 2*a^2*b + a*b^2 )*d), ((b*cosh(d*x + c)^2 + 2*b*cosh(d*x + c)*sinh(d*x + c) + b*sinh(d*x + c)^2 + b)*sqrt(-a^2 + a*b)*arctan(-1/2*(b*cosh(d*x + c)^2 + 2*b*cosh(d*x + c)*sinh(d*x + c) + b*sinh(d*x + c)^2 + 2*a - b)*sqrt(-a^2 + a*b)/(a^2 - a*b)) - 2*a^2 + 2*a*b)/((a^3 - 2*a^2*b + a*b^2)*d*cosh(d*x + c)^2 + 2*(a^3 - 2*a^2*b + a*b^2)*d*cosh(d*x + c)*sinh(d*x + c) + (a^3 - 2*a^2*b + a*b^2 )*d*sinh(d*x + c)^2 + (a^3 - 2*a^2*b + a*b^2)*d)]
\[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=\int \frac {\operatorname {sech}^{2}{\left (c + d x \right )}}{a + b \sinh ^{2}{\left (c + d x \right )}}\, dx \] Input:
integrate(sech(d*x+c)**2/(a+b*sinh(d*x+c)**2),x)
Output:
Integral(sech(c + d*x)**2/(a + b*sinh(c + d*x)**2), x)
Exception generated. \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=\text {Exception raised: ValueError} \] Input:
integrate(sech(d*x+c)^2/(a+b*sinh(d*x+c)^2),x, algorithm="maxima")
Output:
Exception raised: ValueError >> Computation failed since Maxima requested additional constraints; using the 'assume' command before evaluation *may* help (example of legal syntax is 'assume(b-a>0)', see `assume?` for more details)Is
Time = 0.23 (sec) , antiderivative size = 80, normalized size of antiderivative = 1.33 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=-\frac {\frac {b \arctan \left (\frac {b e^{\left (2 \, d x + 2 \, c\right )} + 2 \, a - b}{2 \, \sqrt {-a^{2} + a b}}\right )}{\sqrt {-a^{2} + a b} {\left (a - b\right )}} + \frac {2}{{\left (a - b\right )} {\left (e^{\left (2 \, d x + 2 \, c\right )} + 1\right )}}}{d} \] Input:
integrate(sech(d*x+c)^2/(a+b*sinh(d*x+c)^2),x, algorithm="giac")
Output:
-(b*arctan(1/2*(b*e^(2*d*x + 2*c) + 2*a - b)/sqrt(-a^2 + a*b))/(sqrt(-a^2 + a*b)*(a - b)) + 2/((a - b)*(e^(2*d*x + 2*c) + 1)))/d
Time = 2.35 (sec) , antiderivative size = 265, normalized size of antiderivative = 4.42 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=\frac {b\,\ln \left (\frac {4\,\left (2\,a\,b-b^2+8\,a^2\,{\mathrm {e}}^{2\,c+2\,d\,x}+b^2\,{\mathrm {e}}^{2\,c+2\,d\,x}-8\,a\,b\,{\mathrm {e}}^{2\,c+2\,d\,x}\right )}{a\,{\left (a-b\right )}^3}-\frac {8\,b+32\,a\,{\mathrm {e}}^{2\,c+2\,d\,x}-16\,b\,{\mathrm {e}}^{2\,c+2\,d\,x}}{\sqrt {a}\,{\left (a-b\right )}^{5/2}}\right )}{2\,\sqrt {a}\,d\,{\left (a-b\right )}^{3/2}}-\frac {b\,\ln \left (\frac {8\,b+32\,a\,{\mathrm {e}}^{2\,c+2\,d\,x}-16\,b\,{\mathrm {e}}^{2\,c+2\,d\,x}}{\sqrt {a}\,{\left (a-b\right )}^{5/2}}+\frac {4\,\left (2\,a\,b-b^2+8\,a^2\,{\mathrm {e}}^{2\,c+2\,d\,x}+b^2\,{\mathrm {e}}^{2\,c+2\,d\,x}-8\,a\,b\,{\mathrm {e}}^{2\,c+2\,d\,x}\right )}{a\,{\left (a-b\right )}^3}\right )}{2\,\sqrt {a}\,d\,{\left (a-b\right )}^{3/2}}-\frac {2}{\left ({\mathrm {e}}^{2\,c+2\,d\,x}+1\right )\,\left (a\,d-b\,d\right )} \] Input:
int(1/(cosh(c + d*x)^2*(a + b*sinh(c + d*x)^2)),x)
Output:
(b*log((4*(2*a*b - b^2 + 8*a^2*exp(2*c + 2*d*x) + b^2*exp(2*c + 2*d*x) - 8 *a*b*exp(2*c + 2*d*x)))/(a*(a - b)^3) - (8*b + 32*a*exp(2*c + 2*d*x) - 16* b*exp(2*c + 2*d*x))/(a^(1/2)*(a - b)^(5/2))))/(2*a^(1/2)*d*(a - b)^(3/2)) - (b*log((8*b + 32*a*exp(2*c + 2*d*x) - 16*b*exp(2*c + 2*d*x))/(a^(1/2)*(a - b)^(5/2)) + (4*(2*a*b - b^2 + 8*a^2*exp(2*c + 2*d*x) + b^2*exp(2*c + 2* d*x) - 8*a*b*exp(2*c + 2*d*x)))/(a*(a - b)^3)))/(2*a^(1/2)*d*(a - b)^(3/2) ) - 2/((exp(2*c + 2*d*x) + 1)*(a*d - b*d))
Time = 0.20 (sec) , antiderivative size = 363, normalized size of antiderivative = 6.05 \[ \int \frac {\text {sech}^2(c+d x)}{a+b \sinh ^2(c+d x)} \, dx=\frac {-e^{2 d x +2 c} \sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (-\sqrt {2 \sqrt {a}\, \sqrt {a -b}-2 a +b}+e^{d x +c} \sqrt {b}\right ) b -e^{2 d x +2 c} \sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (\sqrt {2 \sqrt {a}\, \sqrt {a -b}-2 a +b}+e^{d x +c} \sqrt {b}\right ) b +e^{2 d x +2 c} \sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (2 \sqrt {a}\, \sqrt {a -b}+e^{2 d x +2 c} b +2 a -b \right ) b -\sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (-\sqrt {2 \sqrt {a}\, \sqrt {a -b}-2 a +b}+e^{d x +c} \sqrt {b}\right ) b -\sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (\sqrt {2 \sqrt {a}\, \sqrt {a -b}-2 a +b}+e^{d x +c} \sqrt {b}\right ) b +\sqrt {a}\, \sqrt {a -b}\, \mathrm {log}\left (2 \sqrt {a}\, \sqrt {a -b}+e^{2 d x +2 c} b +2 a -b \right ) b +4 e^{2 d x +2 c} a^{2}-4 e^{2 d x +2 c} a b}{2 a d \left (e^{2 d x +2 c} a^{2}-2 e^{2 d x +2 c} a b +e^{2 d x +2 c} b^{2}+a^{2}-2 a b +b^{2}\right )} \] Input:
int(sech(d*x+c)^2/(a+b*sinh(d*x+c)^2),x)
Output:
( - e**(2*c + 2*d*x)*sqrt(a)*sqrt(a - b)*log( - sqrt(2*sqrt(a)*sqrt(a - b) - 2*a + b) + e**(c + d*x)*sqrt(b))*b - e**(2*c + 2*d*x)*sqrt(a)*sqrt(a - b)*log(sqrt(2*sqrt(a)*sqrt(a - b) - 2*a + b) + e**(c + d*x)*sqrt(b))*b + e **(2*c + 2*d*x)*sqrt(a)*sqrt(a - b)*log(2*sqrt(a)*sqrt(a - b) + e**(2*c + 2*d*x)*b + 2*a - b)*b - sqrt(a)*sqrt(a - b)*log( - sqrt(2*sqrt(a)*sqrt(a - b) - 2*a + b) + e**(c + d*x)*sqrt(b))*b - sqrt(a)*sqrt(a - b)*log(sqrt(2* sqrt(a)*sqrt(a - b) - 2*a + b) + e**(c + d*x)*sqrt(b))*b + sqrt(a)*sqrt(a - b)*log(2*sqrt(a)*sqrt(a - b) + e**(2*c + 2*d*x)*b + 2*a - b)*b + 4*e**(2 *c + 2*d*x)*a**2 - 4*e**(2*c + 2*d*x)*a*b)/(2*a*d*(e**(2*c + 2*d*x)*a**2 - 2*e**(2*c + 2*d*x)*a*b + e**(2*c + 2*d*x)*b**2 + a**2 - 2*a*b + b**2))