Integrand size = 14, antiderivative size = 110 \[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{a-\frac {b c}{d}} (c+d x)^m \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {b (c+d x)}{d}\right )}{2 b}-\frac {e^{-a+\frac {b c}{d}} (c+d x)^m \left (\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,\frac {b (c+d x)}{d}\right )}{2 b} \] Output:
1/2*exp(a-b*c/d)*(d*x+c)^m*GAMMA(1+m,-b*(d*x+c)/d)/b/((-b*(d*x+c)/d)^m)-1/ 2*exp(-a+b*c/d)*(d*x+c)^m*GAMMA(1+m,b*(d*x+c)/d)/b/((b*(d*x+c)/d)^m)
Time = 0.04 (sec) , antiderivative size = 102, normalized size of antiderivative = 0.93 \[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{-a-\frac {b c}{d}} (c+d x)^m \left (e^{2 a} \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (1+m,-\frac {b (c+d x)}{d}\right )-e^{\frac {2 b c}{d}} \left (b \left (\frac {c}{d}+x\right )\right )^{-m} \Gamma \left (1+m,\frac {b (c+d x)}{d}\right )\right )}{2 b} \] Input:
Integrate[(c + d*x)^m*Cosh[a + b*x],x]
Output:
(E^(-a - (b*c)/d)*(c + d*x)^m*((E^(2*a)*Gamma[1 + m, -((b*(c + d*x))/d)])/ (-((b*(c + d*x))/d))^m - (E^((2*b*c)/d)*Gamma[1 + m, (b*(c + d*x))/d])/(b* (c/d + x))^m))/(2*b)
Time = 0.31 (sec) , antiderivative size = 110, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3042, 3788, 26, 2612}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \cosh (a+b x) (c+d x)^m \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int \sin \left (i a+i b x+\frac {\pi }{2}\right ) (c+d x)^mdx\) |
\(\Big \downarrow \) 3788 |
\(\displaystyle \frac {1}{2} i \int -i e^{a+b x} (c+d x)^mdx-\frac {1}{2} i \int i e^{-a-b x} (c+d x)^mdx\) |
\(\Big \downarrow \) 26 |
\(\displaystyle \frac {1}{2} \int e^{-a-b x} (c+d x)^mdx+\frac {1}{2} \int e^{a+b x} (c+d x)^mdx\) |
\(\Big \downarrow \) 2612 |
\(\displaystyle \frac {e^{a-\frac {b c}{d}} (c+d x)^m \left (-\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (m+1,-\frac {b (c+d x)}{d}\right )}{2 b}-\frac {e^{\frac {b c}{d}-a} (c+d x)^m \left (\frac {b (c+d x)}{d}\right )^{-m} \Gamma \left (m+1,\frac {b (c+d x)}{d}\right )}{2 b}\) |
Input:
Int[(c + d*x)^m*Cosh[a + b*x],x]
Output:
(E^(a - (b*c)/d)*(c + d*x)^m*Gamma[1 + m, -((b*(c + d*x))/d)])/(2*b*(-((b* (c + d*x))/d))^m) - (E^(-a + (b*c)/d)*(c + d*x)^m*Gamma[1 + m, (b*(c + d*x ))/d])/(2*b*((b*(c + d*x))/d)^m)
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c + d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d) )^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m + 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] && !IntegerQ[m]
Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol ] :> Simp[I/2 Int[(c + d*x)^m/(E^(I*k*Pi)*E^(I*(e + f*x))), x], x] - Simp [I/2 Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d, e , f, m}, x] && IntegerQ[2*k]
\[\int \left (d x +c \right )^{m} \cosh \left (b x +a \right )d x\]
Input:
int((d*x+c)^m*cosh(b*x+a),x)
Output:
int((d*x+c)^m*cosh(b*x+a),x)
Time = 0.09 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.53 \[ \int (c+d x)^m \cosh (a+b x) \, dx=-\frac {\cosh \left (\frac {d m \log \left (\frac {b}{d}\right ) - b c + a d}{d}\right ) \Gamma \left (m + 1, \frac {b d x + b c}{d}\right ) - \cosh \left (\frac {d m \log \left (-\frac {b}{d}\right ) + b c - a d}{d}\right ) \Gamma \left (m + 1, -\frac {b d x + b c}{d}\right ) - \Gamma \left (m + 1, \frac {b d x + b c}{d}\right ) \sinh \left (\frac {d m \log \left (\frac {b}{d}\right ) - b c + a d}{d}\right ) + \Gamma \left (m + 1, -\frac {b d x + b c}{d}\right ) \sinh \left (\frac {d m \log \left (-\frac {b}{d}\right ) + b c - a d}{d}\right )}{2 \, b} \] Input:
integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="fricas")
Output:
-1/2*(cosh((d*m*log(b/d) - b*c + a*d)/d)*gamma(m + 1, (b*d*x + b*c)/d) - c osh((d*m*log(-b/d) + b*c - a*d)/d)*gamma(m + 1, -(b*d*x + b*c)/d) - gamma( m + 1, (b*d*x + b*c)/d)*sinh((d*m*log(b/d) - b*c + a*d)/d) + gamma(m + 1, -(b*d*x + b*c)/d)*sinh((d*m*log(-b/d) + b*c - a*d)/d))/b
Exception generated. \[ \int (c+d x)^m \cosh (a+b x) \, dx=\text {Exception raised: TypeError} \] Input:
integrate((d*x+c)**m*cosh(b*x+a),x)
Output:
Exception raised: TypeError >> cannot determine truth value of Relational
Time = 0.07 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.72 \[ \int (c+d x)^m \cosh (a+b x) \, dx=-\frac {{\left (d x + c\right )}^{m + 1} e^{\left (-a + \frac {b c}{d}\right )} E_{-m}\left (\frac {{\left (d x + c\right )} b}{d}\right )}{2 \, d} - \frac {{\left (d x + c\right )}^{m + 1} e^{\left (a - \frac {b c}{d}\right )} E_{-m}\left (-\frac {{\left (d x + c\right )} b}{d}\right )}{2 \, d} \] Input:
integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="maxima")
Output:
-1/2*(d*x + c)^(m + 1)*e^(-a + b*c/d)*exp_integral_e(-m, (d*x + c)*b/d)/d - 1/2*(d*x + c)^(m + 1)*e^(a - b*c/d)*exp_integral_e(-m, -(d*x + c)*b/d)/d
\[ \int (c+d x)^m \cosh (a+b x) \, dx=\int { {\left (d x + c\right )}^{m} \cosh \left (b x + a\right ) \,d x } \] Input:
integrate((d*x+c)^m*cosh(b*x+a),x, algorithm="giac")
Output:
integrate((d*x + c)^m*cosh(b*x + a), x)
Timed out. \[ \int (c+d x)^m \cosh (a+b x) \, dx=\int \mathrm {cosh}\left (a+b\,x\right )\,{\left (c+d\,x\right )}^m \,d x \] Input:
int(cosh(a + b*x)*(c + d*x)^m,x)
Output:
int(cosh(a + b*x)*(c + d*x)^m, x)
\[ \int (c+d x)^m \cosh (a+b x) \, dx=\frac {e^{2 b x +2 a} \left (d x +c \right )^{m}-\left (d x +c \right )^{m}-e^{b x +2 a} \left (\int \frac {e^{b x} \left (d x +c \right )^{m}}{d x +c}d x \right ) d m +e^{b x} \left (\int \frac {\left (d x +c \right )^{m}}{e^{b x} c +e^{b x} d x}d x \right ) d m}{2 e^{b x +a} b} \] Input:
int((d*x+c)^m*cosh(b*x+a),x)
Output:
(e**(2*a + 2*b*x)*(c + d*x)**m - (c + d*x)**m - e**(2*a + b*x)*int((e**(b* x)*(c + d*x)**m)/(c + d*x),x)*d*m + e**(b*x)*int((c + d*x)**m/(e**(b*x)*c + e**(b*x)*d*x),x)*d*m)/(2*e**(a + b*x)*b)