Integrand size = 21, antiderivative size = 51 \[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\frac {2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a+b \text {sech}(c+d x)}}{\sqrt {a}}\right )}{d}-\frac {2 \sqrt {a+b \text {sech}(c+d x)}}{d} \] Output:
2*a^(1/2)*arctanh((a+b*sech(d*x+c))^(1/2)/a^(1/2))/d-2*(a+b*sech(d*x+c))^( 1/2)/d
Time = 0.15 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.98 \[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=-\frac {-2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a+b \text {sech}(c+d x)}}{\sqrt {a}}\right )+2 \sqrt {a+b \text {sech}(c+d x)}}{d} \] Input:
Integrate[Sqrt[a + b*Sech[c + d*x]]*Tanh[c + d*x],x]
Output:
-((-2*Sqrt[a]*ArcTanh[Sqrt[a + b*Sech[c + d*x]]/Sqrt[a]] + 2*Sqrt[a + b*Se ch[c + d*x]])/d)
Time = 0.27 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.98, number of steps used = 7, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3042, 26, 4373, 60, 73, 220}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \tanh (c+d x) \sqrt {a+b \text {sech}(c+d x)} \, dx\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \int i \cot \left (i c+i d x+\frac {\pi }{2}\right ) \sqrt {a+b \csc \left (i c+i d x+\frac {\pi }{2}\right )}dx\) |
\(\Big \downarrow \) 26 |
\(\displaystyle i \int \cot \left (\frac {1}{2} (2 i c+\pi )+i d x\right ) \sqrt {a+b \csc \left (\frac {1}{2} (2 i c+\pi )+i d x\right )}dx\) |
\(\Big \downarrow \) 4373 |
\(\displaystyle -\frac {\int \frac {\cosh (c+d x) \sqrt {a+b \text {sech}(c+d x)}}{b}d(b \text {sech}(c+d x))}{d}\) |
\(\Big \downarrow \) 60 |
\(\displaystyle -\frac {a \int \frac {\cosh (c+d x)}{b \sqrt {a+b \text {sech}(c+d x)}}d(b \text {sech}(c+d x))+2 \sqrt {a+b \text {sech}(c+d x)}}{d}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle -\frac {2 a \int \frac {1}{b^2 \text {sech}^2(c+d x)-a}d\sqrt {a+b \text {sech}(c+d x)}+2 \sqrt {a+b \text {sech}(c+d x)}}{d}\) |
\(\Big \downarrow \) 220 |
\(\displaystyle -\frac {2 \sqrt {a+b \text {sech}(c+d x)}-2 \sqrt {a} \text {arctanh}\left (\frac {\sqrt {a+b \text {sech}(c+d x)}}{\sqrt {a}}\right )}{d}\) |
Input:
Int[Sqrt[a + b*Sech[c + d*x]]*Tanh[c + d*x],x]
Output:
-((-2*Sqrt[a]*ArcTanh[Sqrt[a + b*Sech[c + d*x]]/Sqrt[a]] + 2*Sqrt[a + b*Se ch[c + d*x]])/d)
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^n/(b*(m + n + 1))), x] + Simp[n*((b*c - a*d)/( b*(m + n + 1))) Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d}, x] && GtQ[n, 0] && NeQ[m + n + 1, 0] && !(IGtQ[m, 0] && ( !Integer Q[n] || (GtQ[m, 0] && LtQ[m - n, 0]))) && !ILtQ[m + n + 2, 0] && IntLinear Q[a, b, c, d, m, n, x]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[b, 2])^(- 1))*ArcTanh[Rt[b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])
Int[cot[(c_.) + (d_.)*(x_)]^(m_.)*(csc[(c_.) + (d_.)*(x_)]*(b_.) + (a_))^(n _), x_Symbol] :> Simp[-(-1)^((m - 1)/2)/(d*b^(m - 1)) Subst[Int[(b^2 - x^ 2)^((m - 1)/2)*((a + x)^n/x), x], x, b*Csc[c + d*x]], x] /; FreeQ[{a, b, c, d, n}, x] && IntegerQ[(m - 1)/2] && NeQ[a^2 - b^2, 0]
Time = 0.14 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.84
method | result | size |
derivativedivides | \(-\frac {2 \sqrt {a +b \,\operatorname {sech}\left (d x +c \right )}-2 \sqrt {a}\, \operatorname {arctanh}\left (\frac {\sqrt {a +b \,\operatorname {sech}\left (d x +c \right )}}{\sqrt {a}}\right )}{d}\) | \(43\) |
default | \(-\frac {2 \sqrt {a +b \,\operatorname {sech}\left (d x +c \right )}-2 \sqrt {a}\, \operatorname {arctanh}\left (\frac {\sqrt {a +b \,\operatorname {sech}\left (d x +c \right )}}{\sqrt {a}}\right )}{d}\) | \(43\) |
Input:
int((a+b*sech(d*x+c))^(1/2)*tanh(d*x+c),x,method=_RETURNVERBOSE)
Output:
-1/d*(2*(a+b*sech(d*x+c))^(1/2)-2*a^(1/2)*arctanh((a+b*sech(d*x+c))^(1/2)/ a^(1/2)))
Leaf count of result is larger than twice the leaf count of optimal. 173 vs. \(2 (43) = 86\).
Time = 0.49 (sec) , antiderivative size = 605, normalized size of antiderivative = 11.86 \[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx =\text {Too large to display} \] Input:
integrate((a+b*sech(d*x+c))^(1/2)*tanh(d*x+c),x, algorithm="fricas")
Output:
[1/2*(sqrt(a)*log(-(2*a^2*cosh(d*x + c)^4 + 2*a^2*sinh(d*x + c)^4 + 4*a*b* cosh(d*x + c)^3 + 4*(2*a^2*cosh(d*x + c) + a*b)*sinh(d*x + c)^3 + 4*a*b*co sh(d*x + c) + (4*a^2 + b^2)*cosh(d*x + c)^2 + (12*a^2*cosh(d*x + c)^2 + 12 *a*b*cosh(d*x + c) + 4*a^2 + b^2)*sinh(d*x + c)^2 + 2*a^2 + 2*(a*cosh(d*x + c)^4 + a*sinh(d*x + c)^4 + b*cosh(d*x + c)^3 + (4*a*cosh(d*x + c) + b)*s inh(d*x + c)^3 + 2*a*cosh(d*x + c)^2 + (6*a*cosh(d*x + c)^2 + 3*b*cosh(d*x + c) + 2*a)*sinh(d*x + c)^2 + b*cosh(d*x + c) + (4*a*cosh(d*x + c)^3 + 3* b*cosh(d*x + c)^2 + 4*a*cosh(d*x + c) + b)*sinh(d*x + c) + a)*sqrt(a)*sqrt ((a*cosh(d*x + c) + b)/cosh(d*x + c)) + 2*(4*a^2*cosh(d*x + c)^3 + 6*a*b*c osh(d*x + c)^2 + 2*a*b + (4*a^2 + b^2)*cosh(d*x + c))*sinh(d*x + c))/(cosh (d*x + c)^2 + 2*cosh(d*x + c)*sinh(d*x + c) + sinh(d*x + c)^2)) - 4*sqrt(( a*cosh(d*x + c) + b)/cosh(d*x + c)))/d, -(sqrt(-a)*arctan((a*cosh(d*x + c) ^2 + a*sinh(d*x + c)^2 + b*cosh(d*x + c) + (2*a*cosh(d*x + c) + b)*sinh(d* x + c) + a)*sqrt(-a)*sqrt((a*cosh(d*x + c) + b)/cosh(d*x + c))/(a^2*cosh(d *x + c)^2 + a^2*sinh(d*x + c)^2 + 2*a*b*cosh(d*x + c) + a^2 + 2*(a^2*cosh( d*x + c) + a*b)*sinh(d*x + c))) + 2*sqrt((a*cosh(d*x + c) + b)/cosh(d*x + c)))/d]
\[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\int \sqrt {a + b \operatorname {sech}{\left (c + d x \right )}} \tanh {\left (c + d x \right )}\, dx \] Input:
integrate((a+b*sech(d*x+c))**(1/2)*tanh(d*x+c),x)
Output:
Integral(sqrt(a + b*sech(c + d*x))*tanh(c + d*x), x)
\[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\int { \sqrt {b \operatorname {sech}\left (d x + c\right ) + a} \tanh \left (d x + c\right ) \,d x } \] Input:
integrate((a+b*sech(d*x+c))^(1/2)*tanh(d*x+c),x, algorithm="maxima")
Output:
integrate(sqrt(b*sech(d*x + c) + a)*tanh(d*x + c), x)
\[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\int { \sqrt {b \operatorname {sech}\left (d x + c\right ) + a} \tanh \left (d x + c\right ) \,d x } \] Input:
integrate((a+b*sech(d*x+c))^(1/2)*tanh(d*x+c),x, algorithm="giac")
Output:
integrate(sqrt(b*sech(d*x + c) + a)*tanh(d*x + c), x)
Time = 2.72 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.92 \[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\frac {2\,\sqrt {a}\,\mathrm {atanh}\left (\frac {\sqrt {a+\frac {b}{\mathrm {cosh}\left (c+d\,x\right )}}}{\sqrt {a}}\right )}{d}-\frac {2\,\sqrt {a+\frac {b}{\mathrm {cosh}\left (c+d\,x\right )}}}{d} \] Input:
int(tanh(c + d*x)*(a + b/cosh(c + d*x))^(1/2),x)
Output:
(2*a^(1/2)*atanh((a + b/cosh(c + d*x))^(1/2)/a^(1/2)))/d - (2*(a + b/cosh( c + d*x))^(1/2))/d
\[ \int \sqrt {a+b \text {sech}(c+d x)} \tanh (c+d x) \, dx=\frac {-2 \sqrt {\mathrm {sech}\left (d x +c \right ) b +a}+\left (\int \frac {\sqrt {\mathrm {sech}\left (d x +c \right ) b +a}\, \tanh \left (d x +c \right )}{\mathrm {sech}\left (d x +c \right ) b +a}d x \right ) a d}{d} \] Input:
int((a+b*sech(d*x+c))^(1/2)*tanh(d*x+c),x)
Output:
( - 2*sqrt(sech(c + d*x)*b + a) + int((sqrt(sech(c + d*x)*b + a)*tanh(c + d*x))/(sech(c + d*x)*b + a),x)*a*d)/d