Integrand size = 47, antiderivative size = 148 \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=-\frac {F^{c (a+b x)} (2+n) \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^{1+n} \left (f \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )+g \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )}{b c \left (f^2-g^2\right ) (1+n) \log (F)} \] Output:
-F^(c*(b*x+a))*(2+n)*(g*cosh(-d+b*c*x*ln(F)/(2+n))-f*sinh(-d+b*c*x*ln(F)/( 2+n)))^(1+n)*(f*cosh(-d+b*c*x*ln(F)/(2+n))+g*cosh(-d+b*c*x*ln(F)/(2+n))-f* sinh(-d+b*c*x*ln(F)/(2+n))-g*sinh(-d+b*c*x*ln(F)/(2+n)))/b/c/(f^2-g^2)/(1+ n)/ln(F)
Time = 4.19 (sec) , antiderivative size = 122, normalized size of antiderivative = 0.82 \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=-\frac {F^{c \left (a+\frac {b n x}{2+n}\right )} \left (F^{\frac {2 b c x}{2+n}} (-f+g)+e^{2 d} (f+g)\right ) \left (\frac {1}{2} e^{-d} F^{\frac {b c x}{2+n}} (-f+g)+\frac {1}{2} e^d F^{-\frac {b c x}{2+n}} (f+g)\right )^n (2+n)}{2 b c (f-g) (1+n) \log (F)} \] Input:
Integrate[F^(c*(a + b*x))*(g*Cosh[d - (b*c*x*Log[F])/(2 + n)] + f*Sinh[d - (b*c*x*Log[F])/(2 + n)])^n,x]
Output:
-1/2*(F^(c*(a + (b*n*x)/(2 + n)))*(F^((2*b*c*x)/(2 + n))*(-f + g) + E^(2*d )*(f + g))*((F^((b*c*x)/(2 + n))*(-f + g))/(2*E^d) + (E^d*(f + g))/(2*F^(( b*c*x)/(2 + n))))^n*(2 + n))/(b*c*(f - g)*(1 + n)*Log[F])
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int F^{c (a+b x)} \left (f \sinh \left (d-\frac {b c x \log (F)}{n+2}\right )+g \cosh \left (d-\frac {b c x \log (F)}{n+2}\right )\right )^n \, dx\) |
\(\Big \downarrow \) 7292 |
\(\displaystyle \int F^{a c+b c x} \left (f \sinh \left (d-\frac {b c x \log (F)}{n+2}\right )+g \cosh \left (d-\frac {b c x \log (F)}{n+2}\right )\right )^ndx\) |
\(\Big \downarrow \) 7299 |
\(\displaystyle \int F^{a c+b c x} \left (f \sinh \left (d-\frac {b c x \log (F)}{n+2}\right )+g \cosh \left (d-\frac {b c x \log (F)}{n+2}\right )\right )^ndx\) |
Input:
Int[F^(c*(a + b*x))*(g*Cosh[d - (b*c*x*Log[F])/(2 + n)] + f*Sinh[d - (b*c* x*Log[F])/(2 + n)])^n,x]
Output:
$Aborted
\[\int F^{c \left (b x +a \right )} \left (g \cosh \left (-d +\frac {b c x \ln \left (F \right )}{2+n}\right )-f \sinh \left (-d +\frac {b c x \ln \left (F \right )}{2+n}\right )\right )^{n}d x\]
Input:
int(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*ln(F)/(2+n))-f*sinh(-d+b*c*x*ln(F)/(2+n )))^n,x)
Output:
int(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*ln(F)/(2+n))-f*sinh(-d+b*c*x*ln(F)/(2+n )))^n,x)
Leaf count of result is larger than twice the leaf count of optimal. 518 vs. \(2 (157) = 314\).
Time = 0.10 (sec) , antiderivative size = 518, normalized size of antiderivative = 3.50 \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=-\frac {{\left ({\left (g n + 2 \, g\right )} \cosh \left ({\left (b c x + a c\right )} \log \left (F\right )\right ) \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - {\left (f n + 2 \, f\right )} \cosh \left ({\left (b c x + a c\right )} \log \left (F\right )\right ) \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) + {\left ({\left (g n + 2 \, g\right )} \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - {\left (f n + 2 \, f\right )} \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right )\right )} \sinh \left ({\left (b c x + a c\right )} \log \left (F\right )\right )\right )} \cosh \left (n \log \left (g \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - f \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right )\right )\right ) + {\left ({\left (g n + 2 \, g\right )} \cosh \left ({\left (b c x + a c\right )} \log \left (F\right )\right ) \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - {\left (f n + 2 \, f\right )} \cosh \left ({\left (b c x + a c\right )} \log \left (F\right )\right ) \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) + {\left ({\left (g n + 2 \, g\right )} \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - {\left (f n + 2 \, f\right )} \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right )\right )} \sinh \left ({\left (b c x + a c\right )} \log \left (F\right )\right )\right )} \sinh \left (n \log \left (g \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) - f \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right )\right )\right )}{{\left (b c f - b c g + {\left (b c f - b c g\right )} n\right )} \cosh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right ) \log \left (F\right ) + {\left (b c f - b c g + {\left (b c f - b c g\right )} n\right )} \log \left (F\right ) \sinh \left (\frac {b c x \log \left (F\right ) - d n - 2 \, d}{n + 2}\right )} \] Input:
integrate(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*log(F)/(2+n))-f*sinh(-d+b*c*x*log (F)/(2+n)))^n,x, algorithm="fricas")
Output:
-(((g*n + 2*g)*cosh((b*c*x + a*c)*log(F))*cosh((b*c*x*log(F) - d*n - 2*d)/ (n + 2)) - (f*n + 2*f)*cosh((b*c*x + a*c)*log(F))*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)) + ((g*n + 2*g)*cosh((b*c*x*log(F) - d*n - 2*d)/(n + 2)) - (f*n + 2*f)*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)))*sinh((b*c*x + a*c)* log(F)))*cosh(n*log(g*cosh((b*c*x*log(F) - d*n - 2*d)/(n + 2)) - f*sinh((b *c*x*log(F) - d*n - 2*d)/(n + 2)))) + ((g*n + 2*g)*cosh((b*c*x + a*c)*log( F))*cosh((b*c*x*log(F) - d*n - 2*d)/(n + 2)) - (f*n + 2*f)*cosh((b*c*x + a *c)*log(F))*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)) + ((g*n + 2*g)*cosh(( b*c*x*log(F) - d*n - 2*d)/(n + 2)) - (f*n + 2*f)*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)))*sinh((b*c*x + a*c)*log(F)))*sinh(n*log(g*cosh((b*c*x*log( F) - d*n - 2*d)/(n + 2)) - f*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)))))/( (b*c*f - b*c*g + (b*c*f - b*c*g)*n)*cosh((b*c*x*log(F) - d*n - 2*d)/(n + 2 ))*log(F) + (b*c*f - b*c*g + (b*c*f - b*c*g)*n)*log(F)*sinh((b*c*x*log(F) - d*n - 2*d)/(n + 2)))
\[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=\int F^{c \left (a + b x\right )} \left (- f \sinh {\left (\frac {b c x \log {\left (F \right )}}{n + 2} - d \right )} + g \cosh {\left (\frac {b c x \log {\left (F \right )}}{n + 2} - d \right )}\right )^{n}\, dx \] Input:
integrate(F**(c*(b*x+a))*(g*cosh(-d+b*c*x*ln(F)/(2+n))-f*sinh(-d+b*c*x*ln( F)/(2+n)))**n,x)
Output:
Integral(F**(c*(a + b*x))*(-f*sinh(b*c*x*log(F)/(n + 2) - d) + g*cosh(b*c* x*log(F)/(n + 2) - d))**n, x)
\[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=\int { {\left (g \cosh \left (\frac {b c x \log \left (F\right )}{n + 2} - d\right ) - f \sinh \left (\frac {b c x \log \left (F\right )}{n + 2} - d\right )\right )}^{n} F^{{\left (b x + a\right )} c} \,d x } \] Input:
integrate(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*log(F)/(2+n))-f*sinh(-d+b*c*x*log (F)/(2+n)))^n,x, algorithm="maxima")
Output:
integrate((g*cosh(b*c*x*log(F)/(n + 2) - d) - f*sinh(b*c*x*log(F)/(n + 2) - d))^n*F^((b*x + a)*c), x)
Leaf count of result is larger than twice the leaf count of optimal. 1469 vs. \(2 (157) = 314\).
Time = 1.19 (sec) , antiderivative size = 1469, normalized size of antiderivative = 9.93 \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=\text {Too large to display} \] Input:
integrate(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*log(F)/(2+n))-f*sinh(-d+b*c*x*log (F)/(2+n)))^n,x, algorithm="giac")
Output:
1/2*(F^(a*c)*f*n*e^((2*b*c*x*log(F) + d*n^2 - n^2*log(2) + n^2*log(-f*e^(2 *(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/( n + 2)) + f + g) + 2*d*n - 2*n*log(2) + 2*n*log(-f*e^(2*(b*c*x*log(F) - d* n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + f + g))/( n + 2) + 2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) - F^(a*c)*g*n*e^((2*b*c*x*l og(F) + d*n^2 - n^2*log(2) + n^2*log(-f*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + f + g) + 2*d*n - 2*n *log(2) + 2*n*log(-f*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b* c*x*log(F) - d*n - 2*d)/(n + 2)) + f + g))/(n + 2) + 2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) - F^(a*c)*f*n*e^((2*b*c*x*log(F) + d*n^2 - n^2*log(2) + n ^2*log(-f*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + f + g) + 2*d*n - 2*n*log(2) + 2*n*log(-f*e^(2*(b*c *x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2 )) + f + g))/(n + 2)) - F^(a*c)*g*n*e^((2*b*c*x*log(F) + d*n^2 - n^2*log(2 ) + n^2*log(-f*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*lo g(F) - d*n - 2*d)/(n + 2)) + f + g) + 2*d*n - 2*n*log(2) + 2*n*log(-f*e^(2 *(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c*x*log(F) - d*n - 2*d)/( n + 2)) + f + g))/(n + 2)) + 2*F^(a*c)*f*e^((2*b*c*x*log(F) + d*n^2 - n^2* log(2) + n^2*log(-f*e^(2*(b*c*x*log(F) - d*n - 2*d)/(n + 2)) + g*e^(2*(b*c *x*log(F) - d*n - 2*d)/(n + 2)) + f + g) + 2*d*n - 2*n*log(2) + 2*n*log...
Timed out. \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx=\int F^{c\,\left (a+b\,x\right )}\,{\left (g\,\mathrm {cosh}\left (d-\frac {b\,c\,x\,\ln \left (F\right )}{n+2}\right )+f\,\mathrm {sinh}\left (d-\frac {b\,c\,x\,\ln \left (F\right )}{n+2}\right )\right )}^n \,d x \] Input:
int(F^(c*(a + b*x))*(g*cosh(d - (b*c*x*log(F))/(n + 2)) + f*sinh(d - (b*c* x*log(F))/(n + 2)))^n,x)
Output:
int(F^(c*(a + b*x))*(g*cosh(d - (b*c*x*log(F))/(n + 2)) + f*sinh(d - (b*c* x*log(F))/(n + 2)))^n, x)
Time = 0.29 (sec) , antiderivative size = 1207, normalized size of antiderivative = 8.16 \[ \int F^{c (a+b x)} \left (g \cosh \left (d-\frac {b c x \log (F)}{2+n}\right )+f \sinh \left (d-\frac {b c x \log (F)}{2+n}\right )\right )^n \, dx =\text {Too large to display} \] Input:
int(F^(c*(b*x+a))*(g*cosh(-d+b*c*x*log(F)/(2+n))-f*sinh(-d+b*c*x*log(F)/(2 +n)))^n,x)
Output:
(f**(a*c)*(e**((2*log(f)*b*c*x)/(n + 2))*( - e**((2*log(f)*b*c*x)/(n + 2)) *f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*f**2*n* *2 + 2*e**((2*log(f)*b*c*x)/(n + 2))*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*f**2*n - e* *((2*log(f)*b*c*x)/(n + 2))*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*l og(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*g**2*n**2 - 2*e**((2 *log(f)*b*c*x)/(n + 2))*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*log(f )*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*g**2*n - e**(2*d)*( - e* *((2*log(f)*b*c*x)/(n + 2))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d) *f + e**(2*d)*g)**n*f**2*n**2 - 2*e**(2*d)*( - e**((2*log(f)*b*c*x)/(n + 2 ))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*f**2* n + 2*e**(2*d)*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*log(f)*b*c*x)/ (n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*f*g*n + 4*e**(2*d)*( - e**((2*log (f)*b*c*x)/(n + 2))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e** (2*d)*g)**n*f*g + e**(2*d)*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*lo g(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*g**2*n**2 + 4*e**(2*d )*( - e**((2*log(f)*b*c*x)/(n + 2))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n*g**2*n + 4*e**(2*d)*( - e**((2*log(f)*b*c*x)/( n + 2))*f + e**((2*log(f)*b*c*x)/(n + 2))*g + e**(2*d)*f + e**(2*d)*g)**n* g**2 - 2*f**(b*c*x)*e**(d*n)*(cosh((log(f)*b*c*x - d*n - 2*d)/(n + 2))*...