Integrand size = 12, antiderivative size = 205 \[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=-\frac {1}{3} \text {arcsinh}(a+b x)^3+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )+2 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )+2 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right )-2 \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-2 \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right ) \] Output:
-1/3*arcsinh(b*x+a)^3+arcsinh(b*x+a)^2*ln(1-(b*x+a+(1+(b*x+a)^2)^(1/2))/(a -(a^2+1)^(1/2)))+arcsinh(b*x+a)^2*ln(1-(b*x+a+(1+(b*x+a)^2)^(1/2))/(a+(a^2 +1)^(1/2)))+2*arcsinh(b*x+a)*polylog(2,(b*x+a+(1+(b*x+a)^2)^(1/2))/(a-(a^2 +1)^(1/2)))+2*arcsinh(b*x+a)*polylog(2,(b*x+a+(1+(b*x+a)^2)^(1/2))/(a+(a^2 +1)^(1/2)))-2*polylog(3,(b*x+a+(1+(b*x+a)^2)^(1/2))/(a-(a^2+1)^(1/2)))-2*p olylog(3,(b*x+a+(1+(b*x+a)^2)^(1/2))/(a+(a^2+1)^(1/2)))
Time = 0.03 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.22 \[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=-\frac {1}{3} \text {arcsinh}(a+b x)^3+\text {arcsinh}(a+b x)^2 \log \left (1+\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+\text {arcsinh}(a+b x)^2 \log \left (1+\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+2 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}-\frac {\sqrt {1+a^2}}{b}\right ) b}\right )+2 \text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,-\frac {e^{\text {arcsinh}(a+b x)}}{\left (-\frac {a}{b}+\frac {\sqrt {1+a^2}}{b}\right ) b}\right )-2 \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {1+a^2}}\right )-2 \operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {1+a^2}}\right ) \] Input:
Integrate[ArcSinh[a + b*x]^2/x,x]
Output:
-1/3*ArcSinh[a + b*x]^3 + ArcSinh[a + b*x]^2*Log[1 + E^ArcSinh[a + b*x]/(( -(a/b) - Sqrt[1 + a^2]/b)*b)] + ArcSinh[a + b*x]^2*Log[1 + E^ArcSinh[a + b *x]/((-(a/b) + Sqrt[1 + a^2]/b)*b)] + 2*ArcSinh[a + b*x]*PolyLog[2, -(E^Ar cSinh[a + b*x]/((-(a/b) - Sqrt[1 + a^2]/b)*b))] + 2*ArcSinh[a + b*x]*PolyL og[2, -(E^ArcSinh[a + b*x]/((-(a/b) + Sqrt[1 + a^2]/b)*b))] - 2*PolyLog[3, E^ArcSinh[a + b*x]/(a - Sqrt[1 + a^2])] - 2*PolyLog[3, E^ArcSinh[a + b*x] /(a + Sqrt[1 + a^2])]
Time = 0.80 (sec) , antiderivative size = 207, normalized size of antiderivative = 1.01, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.750, Rules used = {6274, 25, 27, 6242, 6095, 2620, 3011, 2720, 7143}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx\) |
\(\Big \downarrow \) 6274 |
\(\displaystyle \frac {\int \frac {\text {arcsinh}(a+b x)^2}{x}d(a+b x)}{b}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle -\frac {\int -\frac {\text {arcsinh}(a+b x)^2}{x}d(a+b x)}{b}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\int -\frac {\text {arcsinh}(a+b x)^2}{b x}d(a+b x)\) |
\(\Big \downarrow \) 6242 |
\(\displaystyle -\int -\frac {\sqrt {(a+b x)^2+1} \text {arcsinh}(a+b x)^2}{b x}d\text {arcsinh}(a+b x)\) |
\(\Big \downarrow \) 6095 |
\(\displaystyle -\int \frac {e^{\text {arcsinh}(a+b x)} \text {arcsinh}(a+b x)^2}{a-e^{\text {arcsinh}(a+b x)}-\sqrt {a^2+1}}d\text {arcsinh}(a+b x)-\int \frac {e^{\text {arcsinh}(a+b x)} \text {arcsinh}(a+b x)^2}{a-e^{\text {arcsinh}(a+b x)}+\sqrt {a^2+1}}d\text {arcsinh}(a+b x)-\frac {1}{3} \text {arcsinh}(a+b x)^3\) |
\(\Big \downarrow \) 2620 |
\(\displaystyle -2 \int \text {arcsinh}(a+b x) \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )d\text {arcsinh}(a+b x)-2 \int \text {arcsinh}(a+b x) \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )d\text {arcsinh}(a+b x)+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{\sqrt {a^2+1}+a}\right )-\frac {1}{3} \text {arcsinh}(a+b x)^3\) |
\(\Big \downarrow \) 3011 |
\(\displaystyle -2 \left (\int \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )d\text {arcsinh}(a+b x)-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )\right )-2 \left (\int \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )d\text {arcsinh}(a+b x)-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{\sqrt {a^2+1}+a}\right )-\frac {1}{3} \text {arcsinh}(a+b x)^3\) |
\(\Big \downarrow \) 2720 |
\(\displaystyle -2 \left (\int e^{-\text {arcsinh}(a+b x)} \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )de^{\text {arcsinh}(a+b x)}-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )\right )-2 \left (\int e^{-\text {arcsinh}(a+b x)} \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )de^{\text {arcsinh}(a+b x)}-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{\sqrt {a^2+1}+a}\right )-\frac {1}{3} \text {arcsinh}(a+b x)^3\) |
\(\Big \downarrow \) 7143 |
\(\displaystyle -2 \left (\operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )\right )-2 \left (\operatorname {PolyLog}\left (3,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )-\text {arcsinh}(a+b x) \operatorname {PolyLog}\left (2,\frac {e^{\text {arcsinh}(a+b x)}}{a+\sqrt {a^2+1}}\right )\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{a-\sqrt {a^2+1}}\right )+\text {arcsinh}(a+b x)^2 \log \left (1-\frac {e^{\text {arcsinh}(a+b x)}}{\sqrt {a^2+1}+a}\right )-\frac {1}{3} \text {arcsinh}(a+b x)^3\) |
Input:
Int[ArcSinh[a + b*x]^2/x,x]
Output:
-1/3*ArcSinh[a + b*x]^3 + ArcSinh[a + b*x]^2*Log[1 - E^ArcSinh[a + b*x]/(a - Sqrt[1 + a^2])] + ArcSinh[a + b*x]^2*Log[1 - E^ArcSinh[a + b*x]/(a + Sq rt[1 + a^2])] - 2*(-(ArcSinh[a + b*x]*PolyLog[2, E^ArcSinh[a + b*x]/(a - S qrt[1 + a^2])]) + PolyLog[3, E^ArcSinh[a + b*x]/(a - Sqrt[1 + a^2])]) - 2* (-(ArcSinh[a + b*x]*PolyLog[2, E^ArcSinh[a + b*x]/(a + Sqrt[1 + a^2])]) + PolyLog[3, E^ArcSinh[a + b*x]/(a + Sqrt[1 + a^2])])
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[(((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)*((c_.) + (d_.)*(x_))^(m_.))/ ((a_) + (b_.)*((F_)^((g_.)*((e_.) + (f_.)*(x_))))^(n_.)), x_Symbol] :> Simp [((c + d*x)^m/(b*f*g*n*Log[F]))*Log[1 + b*((F^(g*(e + f*x)))^n/a)], x] - Si mp[d*(m/(b*f*g*n*Log[F])) Int[(c + d*x)^(m - 1)*Log[1 + b*((F^(g*(e + f*x )))^n/a)], x], x] /; FreeQ[{F, a, b, c, d, e, f, g, n}, x] && IGtQ[m, 0]
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct ionOfExponentialQ[u, x] && !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ [{a, m, n}, x] && IntegerQ[m*n]] && !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) *(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) *(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F])) Int[(f + g*x)^( m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e , f, g, n}, x] && GtQ[m, 0]
Int[(Cosh[(c_.) + (d_.)*(x_)]*((e_.) + (f_.)*(x_))^(m_.))/((a_) + (b_.)*Sin h[(c_.) + (d_.)*(x_)]), x_Symbol] :> Simp[-(e + f*x)^(m + 1)/(b*f*(m + 1)), x] + (Int[(e + f*x)^m*(E^(c + d*x)/(a - Rt[a^2 + b^2, 2] + b*E^(c + d*x))) , x] + Int[(e + f*x)^m*(E^(c + d*x)/(a + Rt[a^2 + b^2, 2] + b*E^(c + d*x))) , x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0] && NeQ[a^2 + b^2, 0]
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)/((d_.) + (e_.)*(x_)), x_Symbo l] :> Subst[Int[(a + b*x)^n*(Cosh[x]/(c*d + e*Sinh[x])), x], x, ArcSinh[c*x ]] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[n, 0]
Int[((a_.) + ArcSinh[(c_) + (d_.)*(x_)]*(b_.))^(n_.)*((e_.) + (f_.)*(x_))^( m_.), x_Symbol] :> Simp[1/d Subst[Int[((d*e - c*f)/d + f*(x/d))^m*(a + b* ArcSinh[x])^n, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m, n}, x]
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d , e, n, p}, x] && EqQ[b*d, a*e]
\[\int \frac {\operatorname {arcsinh}\left (b x +a \right )^{2}}{x}d x\]
Input:
int(arcsinh(b*x+a)^2/x,x)
Output:
int(arcsinh(b*x+a)^2/x,x)
\[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{2}}{x} \,d x } \] Input:
integrate(arcsinh(b*x+a)^2/x,x, algorithm="fricas")
Output:
integral(arcsinh(b*x + a)^2/x, x)
\[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int \frac {\operatorname {asinh}^{2}{\left (a + b x \right )}}{x}\, dx \] Input:
integrate(asinh(b*x+a)**2/x,x)
Output:
Integral(asinh(a + b*x)**2/x, x)
\[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{2}}{x} \,d x } \] Input:
integrate(arcsinh(b*x+a)^2/x,x, algorithm="maxima")
Output:
integrate(arcsinh(b*x + a)^2/x, x)
\[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int { \frac {\operatorname {arsinh}\left (b x + a\right )^{2}}{x} \,d x } \] Input:
integrate(arcsinh(b*x+a)^2/x,x, algorithm="giac")
Output:
integrate(arcsinh(b*x + a)^2/x, x)
Timed out. \[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int \frac {{\mathrm {asinh}\left (a+b\,x\right )}^2}{x} \,d x \] Input:
int(asinh(a + b*x)^2/x,x)
Output:
int(asinh(a + b*x)^2/x, x)
\[ \int \frac {\text {arcsinh}(a+b x)^2}{x} \, dx=\int \frac {\mathit {asinh} \left (b x +a \right )^{2}}{x}d x \] Input:
int(asinh(b*x+a)^2/x,x)
Output:
int(asinh(a + b*x)**2/x,x)