\(\int \frac {a+b \text {arcsinh}(c x)}{x^4 (\pi +c^2 \pi x^2)^{3/2}} \, dx\) [109]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [B] (verified)
Fricas [F]
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 26, antiderivative size = 149 \[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=-\frac {b c}{6 \pi ^{3/2} x^2}+\frac {a+b \text {arcsinh}(c x)}{\pi x^3 \sqrt {\pi +c^2 \pi x^2}}-\frac {4 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 \pi ^2 x^3}+\frac {8 c^2 \sqrt {\pi +c^2 \pi x^2} (a+b \text {arcsinh}(c x))}{3 \pi ^2 x}-\frac {5 b c^3 \log (x)}{3 \pi ^{3/2}}-\frac {b c^3 \log \left (1+c^2 x^2\right )}{2 \pi ^{3/2}} \] Output:

-1/6*b*c/Pi^(3/2)/x^2+(a+b*arcsinh(c*x))/Pi/x^3/(Pi*c^2*x^2+Pi)^(1/2)-4/3* 
(Pi*c^2*x^2+Pi)^(1/2)*(a+b*arcsinh(c*x))/Pi^2/x^3+8/3*c^2*(Pi*c^2*x^2+Pi)^ 
(1/2)*(a+b*arcsinh(c*x))/Pi^2/x-5/3*b*c^3*ln(x)/Pi^(3/2)-1/2*b*c^3*ln(c^2* 
x^2+1)/Pi^(3/2)
 

Mathematica [A] (verified)

Time = 0.28 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.13 \[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\frac {-2 a+8 a c^2 x^2+16 a c^4 x^4-b c x \sqrt {1+c^2 x^2}-16 b c^3 x^3 \sqrt {1+c^2 x^2}+2 b \left (-1+4 c^2 x^2+8 c^4 x^4\right ) \text {arcsinh}(c x)-10 b c^3 x^3 \sqrt {1+c^2 x^2} \log (x)-3 b c^3 x^3 \sqrt {1+c^2 x^2} \log \left (1+c^2 x^2\right )}{6 \pi ^{3/2} x^3 \sqrt {1+c^2 x^2}} \] Input:

Integrate[(a + b*ArcSinh[c*x])/(x^4*(Pi + c^2*Pi*x^2)^(3/2)),x]
 

Output:

(-2*a + 8*a*c^2*x^2 + 16*a*c^4*x^4 - b*c*x*Sqrt[1 + c^2*x^2] - 16*b*c^3*x^ 
3*Sqrt[1 + c^2*x^2] + 2*b*(-1 + 4*c^2*x^2 + 8*c^4*x^4)*ArcSinh[c*x] - 10*b 
*c^3*x^3*Sqrt[1 + c^2*x^2]*Log[x] - 3*b*c^3*x^3*Sqrt[1 + c^2*x^2]*Log[1 + 
c^2*x^2])/(6*Pi^(3/2)*x^3*Sqrt[1 + c^2*x^2])
 

Rubi [A] (verified)

Time = 0.48 (sec) , antiderivative size = 142, normalized size of antiderivative = 0.95, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {6219, 27, 1578, 1195, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi c^2 x^2+\pi \right )^{3/2}} \, dx\)

\(\Big \downarrow \) 6219

\(\displaystyle -\sqrt {\pi } b c \int -\frac {-8 c^4 x^4-4 c^2 x^2+1}{3 \pi ^2 x^3 \left (c^2 x^2+1\right )}dx+\frac {4 c^2 (a+b \text {arcsinh}(c x))}{3 \pi x \sqrt {\pi c^2 x^2+\pi }}-\frac {a+b \text {arcsinh}(c x)}{3 \pi x^3 \sqrt {\pi c^2 x^2+\pi }}+\frac {8 c^4 x (a+b \text {arcsinh}(c x))}{3 \pi \sqrt {\pi c^2 x^2+\pi }}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {b c \int \frac {-8 c^4 x^4-4 c^2 x^2+1}{x^3 \left (c^2 x^2+1\right )}dx}{3 \pi ^{3/2}}+\frac {4 c^2 (a+b \text {arcsinh}(c x))}{3 \pi x \sqrt {\pi c^2 x^2+\pi }}-\frac {a+b \text {arcsinh}(c x)}{3 \pi x^3 \sqrt {\pi c^2 x^2+\pi }}+\frac {8 c^4 x (a+b \text {arcsinh}(c x))}{3 \pi \sqrt {\pi c^2 x^2+\pi }}\)

\(\Big \downarrow \) 1578

\(\displaystyle \frac {b c \int \frac {-8 c^4 x^4-4 c^2 x^2+1}{x^4 \left (c^2 x^2+1\right )}dx^2}{6 \pi ^{3/2}}+\frac {4 c^2 (a+b \text {arcsinh}(c x))}{3 \pi x \sqrt {\pi c^2 x^2+\pi }}-\frac {a+b \text {arcsinh}(c x)}{3 \pi x^3 \sqrt {\pi c^2 x^2+\pi }}+\frac {8 c^4 x (a+b \text {arcsinh}(c x))}{3 \pi \sqrt {\pi c^2 x^2+\pi }}\)

\(\Big \downarrow \) 1195

\(\displaystyle \frac {b c \int \left (-\frac {3 c^4}{c^2 x^2+1}-\frac {5 c^2}{x^2}+\frac {1}{x^4}\right )dx^2}{6 \pi ^{3/2}}+\frac {4 c^2 (a+b \text {arcsinh}(c x))}{3 \pi x \sqrt {\pi c^2 x^2+\pi }}-\frac {a+b \text {arcsinh}(c x)}{3 \pi x^3 \sqrt {\pi c^2 x^2+\pi }}+\frac {8 c^4 x (a+b \text {arcsinh}(c x))}{3 \pi \sqrt {\pi c^2 x^2+\pi }}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {4 c^2 (a+b \text {arcsinh}(c x))}{3 \pi x \sqrt {\pi c^2 x^2+\pi }}-\frac {a+b \text {arcsinh}(c x)}{3 \pi x^3 \sqrt {\pi c^2 x^2+\pi }}+\frac {8 c^4 x (a+b \text {arcsinh}(c x))}{3 \pi \sqrt {\pi c^2 x^2+\pi }}+\frac {b c \left (-5 c^2 \log \left (x^2\right )-3 c^2 \log \left (c^2 x^2+1\right )-\frac {1}{x^2}\right )}{6 \pi ^{3/2}}\)

Input:

Int[(a + b*ArcSinh[c*x])/(x^4*(Pi + c^2*Pi*x^2)^(3/2)),x]
 

Output:

-1/3*(a + b*ArcSinh[c*x])/(Pi*x^3*Sqrt[Pi + c^2*Pi*x^2]) + (4*c^2*(a + b*A 
rcSinh[c*x]))/(3*Pi*x*Sqrt[Pi + c^2*Pi*x^2]) + (8*c^4*x*(a + b*ArcSinh[c*x 
]))/(3*Pi*Sqrt[Pi + c^2*Pi*x^2]) + (b*c*(-x^(-2) - 5*c^2*Log[x^2] - 3*c^2* 
Log[1 + c^2*x^2]))/(6*Pi^(3/2))
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 1195
Int[((d_.) + (e_.)*(x_))^(m_.)*((f_.) + (g_.)*(x_))^(n_.)*((a_.) + (b_.)*(x 
_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*(f + 
 g*x)^n*(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, f, g, m, n}, x 
] && IGtQ[p, 0]
 

rule 1578
Int[(x_)^(m_.)*((d_) + (e_.)*(x_)^2)^(q_.)*((a_) + (b_.)*(x_)^2 + (c_.)*(x_ 
)^4)^(p_.), x_Symbol] :> Simp[1/2   Subst[Int[x^((m - 1)/2)*(d + e*x)^q*(a 
+ b*x + c*x^2)^p, x], x, x^2], x] /; FreeQ[{a, b, c, d, e, p, q}, x] && Int 
egerQ[(m - 1)/2]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 6219
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))*(x_)^(m_)*((d_) + (e_.)*(x_)^2)^(p_ 
), x_Symbol] :> With[{u = IntHide[x^m*(d + e*x^2)^p, x]}, Simp[(a + b*ArcSi 
nh[c*x])   u, x] - Simp[b*c*Simp[Sqrt[d + e*x^2]/Sqrt[1 + c^2*x^2]]   Int[S 
implifyIntegrand[u/Sqrt[d + e*x^2], x], x], x]] /; FreeQ[{a, b, c, d, e}, x 
] && EqQ[e, c^2*d] && IntegerQ[p - 1/2] && NeQ[p, -2^(-1)] && (IGtQ[(m + 1) 
/2, 0] || ILtQ[(m + 2*p + 3)/2, 0])
 
Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(603\) vs. \(2(127)=254\).

Time = 1.22 (sec) , antiderivative size = 604, normalized size of antiderivative = 4.05

method result size
default \(a \left (-\frac {1}{3 \pi \,x^{3} \sqrt {\pi \,c^{2} x^{2}+\pi }}-\frac {4 c^{2} \left (-\frac {1}{\pi x \sqrt {\pi \,c^{2} x^{2}+\pi }}-\frac {2 c^{2} x}{\pi \sqrt {\pi \,c^{2} x^{2}+\pi }}\right )}{3}\right )+\frac {16 b \,c^{3} \operatorname {arcsinh}\left (x c \right )}{3 \pi ^{\frac {3}{2}}}-\frac {32 b \,x^{8} c^{11}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {32 b \,x^{6} c^{9}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}-\frac {64 b \,x^{6} c^{9}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {32 b \,x^{4} c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}-\frac {64 b \,x^{4} \operatorname {arcsinh}\left (x c \right ) c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {64 b \,x^{3} \operatorname {arcsinh}\left (x c \right ) c^{6}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \sqrt {c^{2} x^{2}+1}}-\frac {32 b \,x^{4} c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}-\frac {56 b \,x^{2} \operatorname {arcsinh}\left (x c \right ) c^{5}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {8 b x \,\operatorname {arcsinh}\left (x c \right ) c^{4}}{\pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \sqrt {c^{2} x^{2}+1}}-\frac {4 b \,c^{3}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}+\frac {8 b \,\operatorname {arcsinh}\left (x c \right ) c^{3}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}-\frac {4 b \,\operatorname {arcsinh}\left (x c \right ) c^{2}}{\pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x \sqrt {c^{2} x^{2}+1}}+\frac {b c}{6 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x^{2}}+\frac {b \,\operatorname {arcsinh}\left (x c \right )}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x^{3} \sqrt {c^{2} x^{2}+1}}-\frac {5 b \,c^{3} \ln \left (\left (x c +\sqrt {c^{2} x^{2}+1}\right )^{2}-1\right )}{3 \pi ^{\frac {3}{2}}}-\frac {b \,c^{3} \ln \left (1+\left (x c +\sqrt {c^{2} x^{2}+1}\right )^{2}\right )}{\pi ^{\frac {3}{2}}}\) \(604\)
parts \(a \left (-\frac {1}{3 \pi \,x^{3} \sqrt {\pi \,c^{2} x^{2}+\pi }}-\frac {4 c^{2} \left (-\frac {1}{\pi x \sqrt {\pi \,c^{2} x^{2}+\pi }}-\frac {2 c^{2} x}{\pi \sqrt {\pi \,c^{2} x^{2}+\pi }}\right )}{3}\right )+\frac {16 b \,c^{3} \operatorname {arcsinh}\left (x c \right )}{3 \pi ^{\frac {3}{2}}}-\frac {32 b \,x^{8} c^{11}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {32 b \,x^{6} c^{9}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}-\frac {64 b \,x^{6} c^{9}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {32 b \,x^{4} c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}-\frac {64 b \,x^{4} \operatorname {arcsinh}\left (x c \right ) c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {64 b \,x^{3} \operatorname {arcsinh}\left (x c \right ) c^{6}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \sqrt {c^{2} x^{2}+1}}-\frac {32 b \,x^{4} c^{7}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}-\frac {56 b \,x^{2} \operatorname {arcsinh}\left (x c \right ) c^{5}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}+\frac {8 b x \,\operatorname {arcsinh}\left (x c \right ) c^{4}}{\pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \sqrt {c^{2} x^{2}+1}}-\frac {4 b \,c^{3}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right )}+\frac {8 b \,\operatorname {arcsinh}\left (x c \right ) c^{3}}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) \left (c^{2} x^{2}+1\right )}-\frac {4 b \,\operatorname {arcsinh}\left (x c \right ) c^{2}}{\pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x \sqrt {c^{2} x^{2}+1}}+\frac {b c}{6 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x^{2}}+\frac {b \,\operatorname {arcsinh}\left (x c \right )}{3 \pi ^{\frac {3}{2}} \left (8 c^{2} x^{2}-1\right ) x^{3} \sqrt {c^{2} x^{2}+1}}-\frac {5 b \,c^{3} \ln \left (\left (x c +\sqrt {c^{2} x^{2}+1}\right )^{2}-1\right )}{3 \pi ^{\frac {3}{2}}}-\frac {b \,c^{3} \ln \left (1+\left (x c +\sqrt {c^{2} x^{2}+1}\right )^{2}\right )}{\pi ^{\frac {3}{2}}}\) \(604\)

Input:

int((a+b*arcsinh(x*c))/x^4/(Pi*c^2*x^2+Pi)^(3/2),x,method=_RETURNVERBOSE)
 

Output:

a*(-1/3/Pi/x^3/(Pi*c^2*x^2+Pi)^(1/2)-4/3*c^2*(-1/Pi/x/(Pi*c^2*x^2+Pi)^(1/2 
)-2/Pi*c^2*x/(Pi*c^2*x^2+Pi)^(1/2)))+16/3*b/Pi^(3/2)*c^3*arcsinh(x*c)-32/3 
*b/Pi^(3/2)/(8*c^2*x^2-1)*x^8/(c^2*x^2+1)*c^11+32/3*b/Pi^(3/2)/(8*c^2*x^2- 
1)*x^6*c^9-64/3*b/Pi^(3/2)/(8*c^2*x^2-1)*x^6/(c^2*x^2+1)*c^9+32/3*b/Pi^(3/ 
2)/(8*c^2*x^2-1)*x^4*c^7-64/3*b/Pi^(3/2)/(8*c^2*x^2-1)*x^4/(c^2*x^2+1)*arc 
sinh(x*c)*c^7+64/3*b/Pi^(3/2)/(8*c^2*x^2-1)*x^3/(c^2*x^2+1)^(1/2)*arcsinh( 
x*c)*c^6-32/3*b/Pi^(3/2)/(8*c^2*x^2-1)*x^4/(c^2*x^2+1)*c^7-56/3*b/Pi^(3/2) 
/(8*c^2*x^2-1)*x^2/(c^2*x^2+1)*arcsinh(x*c)*c^5+8*b/Pi^(3/2)/(8*c^2*x^2-1) 
*x/(c^2*x^2+1)^(1/2)*arcsinh(x*c)*c^4-4/3*b/Pi^(3/2)/(8*c^2*x^2-1)*c^3+8/3 
*b/Pi^(3/2)/(8*c^2*x^2-1)/(c^2*x^2+1)*arcsinh(x*c)*c^3-4*b/Pi^(3/2)/(8*c^2 
*x^2-1)/x/(c^2*x^2+1)^(1/2)*arcsinh(x*c)*c^2+1/6*b/Pi^(3/2)/(8*c^2*x^2-1)/ 
x^2*c+1/3*b/Pi^(3/2)/(8*c^2*x^2-1)/x^3/(c^2*x^2+1)^(1/2)*arcsinh(x*c)-5/3* 
b/Pi^(3/2)*c^3*ln((x*c+(c^2*x^2+1)^(1/2))^2-1)-b/Pi^(3/2)*c^3*ln(1+(x*c+(c 
^2*x^2+1)^(1/2))^2)
 

Fricas [F]

\[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac {3}{2}} x^{4}} \,d x } \] Input:

integrate((a+b*arcsinh(c*x))/x^4/(pi*c^2*x^2+pi)^(3/2),x, algorithm="frica 
s")
 

Output:

integral(sqrt(pi + pi*c^2*x^2)*(b*arcsinh(c*x) + a)/(pi^2*c^4*x^8 + 2*pi^2 
*c^2*x^6 + pi^2*x^4), x)
                                                                                    
                                                                                    
 

Sympy [F]

\[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\frac {\int \frac {a}{c^{2} x^{6} \sqrt {c^{2} x^{2} + 1} + x^{4} \sqrt {c^{2} x^{2} + 1}}\, dx + \int \frac {b \operatorname {asinh}{\left (c x \right )}}{c^{2} x^{6} \sqrt {c^{2} x^{2} + 1} + x^{4} \sqrt {c^{2} x^{2} + 1}}\, dx}{\pi ^{\frac {3}{2}}} \] Input:

integrate((a+b*asinh(c*x))/x**4/(pi*c**2*x**2+pi)**(3/2),x)
 

Output:

(Integral(a/(c**2*x**6*sqrt(c**2*x**2 + 1) + x**4*sqrt(c**2*x**2 + 1)), x) 
 + Integral(b*asinh(c*x)/(c**2*x**6*sqrt(c**2*x**2 + 1) + x**4*sqrt(c**2*x 
**2 + 1)), x))/pi**(3/2)
 

Maxima [F]

\[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac {3}{2}} x^{4}} \,d x } \] Input:

integrate((a+b*arcsinh(c*x))/x^4/(pi*c^2*x^2+pi)^(3/2),x, algorithm="maxim 
a")
 

Output:

1/3*(8*c^4*x/(pi*sqrt(pi + pi*c^2*x^2)) + 4*c^2/(pi*sqrt(pi + pi*c^2*x^2)* 
x) - 1/(pi*sqrt(pi + pi*c^2*x^2)*x^3))*a + b*integrate(log(c*x + sqrt(c^2* 
x^2 + 1))/((pi + pi*c^2*x^2)^(3/2)*x^4), x)
 

Giac [F]

\[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\int { \frac {b \operatorname {arsinh}\left (c x\right ) + a}{{\left (\pi + \pi c^{2} x^{2}\right )}^{\frac {3}{2}} x^{4}} \,d x } \] Input:

integrate((a+b*arcsinh(c*x))/x^4/(pi*c^2*x^2+pi)^(3/2),x, algorithm="giac" 
)
 

Output:

integrate((b*arcsinh(c*x) + a)/((pi + pi*c^2*x^2)^(3/2)*x^4), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\int \frac {a+b\,\mathrm {asinh}\left (c\,x\right )}{x^4\,{\left (\Pi \,c^2\,x^2+\Pi \right )}^{3/2}} \,d x \] Input:

int((a + b*asinh(c*x))/(x^4*(Pi + Pi*c^2*x^2)^(3/2)),x)
 

Output:

int((a + b*asinh(c*x))/(x^4*(Pi + Pi*c^2*x^2)^(3/2)), x)
 

Reduce [F]

\[ \int \frac {a+b \text {arcsinh}(c x)}{x^4 \left (\pi +c^2 \pi x^2\right )^{3/2}} \, dx=\frac {8 \sqrt {c^{2} x^{2}+1}\, a \,c^{4} x^{4}+4 \sqrt {c^{2} x^{2}+1}\, a \,c^{2} x^{2}-\sqrt {c^{2} x^{2}+1}\, a +3 \left (\int \frac {\mathit {asinh} \left (c x \right )}{\sqrt {c^{2} x^{2}+1}\, c^{2} x^{6}+\sqrt {c^{2} x^{2}+1}\, x^{4}}d x \right ) b \,c^{2} x^{5}+3 \left (\int \frac {\mathit {asinh} \left (c x \right )}{\sqrt {c^{2} x^{2}+1}\, c^{2} x^{6}+\sqrt {c^{2} x^{2}+1}\, x^{4}}d x \right ) b \,x^{3}-8 a \,c^{5} x^{5}-8 a \,c^{3} x^{3}}{3 \sqrt {\pi }\, \pi \,x^{3} \left (c^{2} x^{2}+1\right )} \] Input:

int((a+b*asinh(c*x))/x^4/(Pi*c^2*x^2+Pi)^(3/2),x)
 

Output:

(8*sqrt(c**2*x**2 + 1)*a*c**4*x**4 + 4*sqrt(c**2*x**2 + 1)*a*c**2*x**2 - s 
qrt(c**2*x**2 + 1)*a + 3*int(asinh(c*x)/(sqrt(c**2*x**2 + 1)*c**2*x**6 + s 
qrt(c**2*x**2 + 1)*x**4),x)*b*c**2*x**5 + 3*int(asinh(c*x)/(sqrt(c**2*x**2 
 + 1)*c**2*x**6 + sqrt(c**2*x**2 + 1)*x**4),x)*b*x**3 - 8*a*c**5*x**5 - 8* 
a*c**3*x**3)/(3*sqrt(pi)*pi*x**3*(c**2*x**2 + 1))