Integrand size = 18, antiderivative size = 394 \[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\frac {d^3 \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}-\frac {3 d e^2 \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{4 b c^3}+\frac {3 d e^2 \cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (\frac {3 a}{b}+3 \text {arcsinh}(c x)\right )}{4 b c^3}-\frac {3 d^2 e \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right ) \sinh \left (\frac {2 a}{b}\right )}{2 b c^2}+\frac {e^3 \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right ) \sinh \left (\frac {2 a}{b}\right )}{4 b c^4}-\frac {e^3 \text {Chi}\left (\frac {4 a}{b}+4 \text {arcsinh}(c x)\right ) \sinh \left (\frac {4 a}{b}\right )}{8 b c^4}-\frac {d^3 \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b c}+\frac {3 d e^2 \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{4 b c^3}+\frac {3 d^2 e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b c^2}-\frac {e^3 \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{4 b c^4}-\frac {3 d e^2 \sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 a}{b}+3 \text {arcsinh}(c x)\right )}{4 b c^3}+\frac {e^3 \cosh \left (\frac {4 a}{b}\right ) \text {Shi}\left (\frac {4 a}{b}+4 \text {arcsinh}(c x)\right )}{8 b c^4} \] Output:
d^3*cosh(a/b)*Chi(a/b+arcsinh(c*x))/b/c-3/4*d*e^2*cosh(a/b)*Chi(a/b+arcsin h(c*x))/b/c^3+3/4*d*e^2*cosh(3*a/b)*Chi(3*a/b+3*arcsinh(c*x))/b/c^3-3/2*d^ 2*e*Chi(2*a/b+2*arcsinh(c*x))*sinh(2*a/b)/b/c^2+1/4*e^3*Chi(2*a/b+2*arcsin h(c*x))*sinh(2*a/b)/b/c^4-1/8*e^3*Chi(4*a/b+4*arcsinh(c*x))*sinh(4*a/b)/b/ c^4-d^3*sinh(a/b)*Shi(a/b+arcsinh(c*x))/b/c+3/4*d*e^2*sinh(a/b)*Shi(a/b+ar csinh(c*x))/b/c^3+3/2*d^2*e*cosh(2*a/b)*Shi(2*a/b+2*arcsinh(c*x))/b/c^2-1/ 4*e^3*cosh(2*a/b)*Shi(2*a/b+2*arcsinh(c*x))/b/c^4-3/4*d*e^2*sinh(3*a/b)*Sh i(3*a/b+3*arcsinh(c*x))/b/c^3+1/8*e^3*cosh(4*a/b)*Shi(4*a/b+4*arcsinh(c*x) )/b/c^4
Time = 0.46 (sec) , antiderivative size = 305, normalized size of antiderivative = 0.77 \[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\frac {d^3 \left (\cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )-\sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )}{b c}+\frac {3 d e^2 \left (-\cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )+\cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )+\sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )-\sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (3 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )\right )}{4 b c^3}+\frac {e^3 \left (2 \text {Chi}\left (2 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right ) \sinh \left (\frac {2 a}{b}\right )-\text {Chi}\left (4 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right ) \sinh \left (\frac {4 a}{b}\right )-2 \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (2 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )+\cosh \left (\frac {4 a}{b}\right ) \text {Shi}\left (4 \left (\frac {a}{b}+\text {arcsinh}(c x)\right )\right )\right )}{8 b c^4}-\frac {3 d^2 e \left (\text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right ) \sinh \left (\frac {2 a}{b}\right )-\cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )\right )}{2 b c^2} \] Input:
Integrate[(d + e*x)^3/(a + b*ArcSinh[c*x]),x]
Output:
(d^3*(Cosh[a/b]*CoshIntegral[a/b + ArcSinh[c*x]] - Sinh[a/b]*SinhIntegral[ a/b + ArcSinh[c*x]]))/(b*c) + (3*d*e^2*(-(Cosh[a/b]*CoshIntegral[a/b + Arc Sinh[c*x]]) + Cosh[(3*a)/b]*CoshIntegral[3*(a/b + ArcSinh[c*x])] + Sinh[a/ b]*SinhIntegral[a/b + ArcSinh[c*x]] - Sinh[(3*a)/b]*SinhIntegral[3*(a/b + ArcSinh[c*x])]))/(4*b*c^3) + (e^3*(2*CoshIntegral[2*(a/b + ArcSinh[c*x])]* Sinh[(2*a)/b] - CoshIntegral[4*(a/b + ArcSinh[c*x])]*Sinh[(4*a)/b] - 2*Cos h[(2*a)/b]*SinhIntegral[2*(a/b + ArcSinh[c*x])] + Cosh[(4*a)/b]*SinhIntegr al[4*(a/b + ArcSinh[c*x])]))/(8*b*c^4) - (3*d^2*e*(CoshIntegral[(2*a)/b + 2*ArcSinh[c*x]]*Sinh[(2*a)/b] - Cosh[(2*a)/b]*SinhIntegral[(2*a)/b + 2*Arc Sinh[c*x]]))/(2*b*c^2)
Time = 1.41 (sec) , antiderivative size = 378, normalized size of antiderivative = 0.96, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {6245, 7293, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx\) |
\(\Big \downarrow \) 6245 |
\(\displaystyle \frac {\int \frac {(c d+c e x)^3 \sqrt {c^2 x^2+1}}{a+b \text {arcsinh}(c x)}d\text {arcsinh}(c x)}{c^4}\) |
\(\Big \downarrow \) 7293 |
\(\displaystyle \frac {\int \left (\frac {d^3 \sqrt {c^2 x^2+1} c^3}{a+b \text {arcsinh}(c x)}+\frac {e^3 x^3 \sqrt {c^2 x^2+1} c^3}{a+b \text {arcsinh}(c x)}+\frac {3 d e^2 x^2 \sqrt {c^2 x^2+1} c^3}{a+b \text {arcsinh}(c x)}+\frac {3 d^2 e x \sqrt {c^2 x^2+1} c^3}{a+b \text {arcsinh}(c x)}\right )d\text {arcsinh}(c x)}{c^4}\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {\frac {c^3 d^3 \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b}-\frac {c^3 d^3 \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{b}-\frac {3 c^2 d^2 e \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b}+\frac {3 c^2 d^2 e \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{2 b}-\frac {3 c d e^2 \cosh \left (\frac {a}{b}\right ) \text {Chi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{4 b}+\frac {3 c d e^2 \cosh \left (\frac {3 a}{b}\right ) \text {Chi}\left (\frac {3 a}{b}+3 \text {arcsinh}(c x)\right )}{4 b}+\frac {e^3 \sinh \left (\frac {2 a}{b}\right ) \text {Chi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{4 b}-\frac {e^3 \sinh \left (\frac {4 a}{b}\right ) \text {Chi}\left (\frac {4 a}{b}+4 \text {arcsinh}(c x)\right )}{8 b}+\frac {3 c d e^2 \sinh \left (\frac {a}{b}\right ) \text {Shi}\left (\frac {a}{b}+\text {arcsinh}(c x)\right )}{4 b}-\frac {3 c d e^2 \sinh \left (\frac {3 a}{b}\right ) \text {Shi}\left (\frac {3 a}{b}+3 \text {arcsinh}(c x)\right )}{4 b}-\frac {e^3 \cosh \left (\frac {2 a}{b}\right ) \text {Shi}\left (\frac {2 a}{b}+2 \text {arcsinh}(c x)\right )}{4 b}+\frac {e^3 \cosh \left (\frac {4 a}{b}\right ) \text {Shi}\left (\frac {4 a}{b}+4 \text {arcsinh}(c x)\right )}{8 b}}{c^4}\) |
Input:
Int[(d + e*x)^3/(a + b*ArcSinh[c*x]),x]
Output:
((c^3*d^3*Cosh[a/b]*CoshIntegral[a/b + ArcSinh[c*x]])/b - (3*c*d*e^2*Cosh[ a/b]*CoshIntegral[a/b + ArcSinh[c*x]])/(4*b) + (3*c*d*e^2*Cosh[(3*a)/b]*Co shIntegral[(3*a)/b + 3*ArcSinh[c*x]])/(4*b) - (3*c^2*d^2*e*CoshIntegral[(2 *a)/b + 2*ArcSinh[c*x]]*Sinh[(2*a)/b])/(2*b) + (e^3*CoshIntegral[(2*a)/b + 2*ArcSinh[c*x]]*Sinh[(2*a)/b])/(4*b) - (e^3*CoshIntegral[(4*a)/b + 4*ArcS inh[c*x]]*Sinh[(4*a)/b])/(8*b) - (c^3*d^3*Sinh[a/b]*SinhIntegral[a/b + Arc Sinh[c*x]])/b + (3*c*d*e^2*Sinh[a/b]*SinhIntegral[a/b + ArcSinh[c*x]])/(4* b) + (3*c^2*d^2*e*Cosh[(2*a)/b]*SinhIntegral[(2*a)/b + 2*ArcSinh[c*x]])/(2 *b) - (e^3*Cosh[(2*a)/b]*SinhIntegral[(2*a)/b + 2*ArcSinh[c*x]])/(4*b) - ( 3*c*d*e^2*Sinh[(3*a)/b]*SinhIntegral[(3*a)/b + 3*ArcSinh[c*x]])/(4*b) + (e ^3*Cosh[(4*a)/b]*SinhIntegral[(4*a)/b + 4*ArcSinh[c*x]])/(8*b))/c^4
Int[((a_.) + ArcSinh[(c_.)*(x_)]*(b_.))^(n_.)*((d_.) + (e_.)*(x_))^(m_.), x _Symbol] :> Simp[1/c^(m + 1) Subst[Int[(a + b*x)^n*Cosh[x]*(c*d + e*Sinh[ x])^m, x], x, ArcSinh[c*x]], x] /; FreeQ[{a, b, c, d, e, n}, x] && IGtQ[m, 0]
Time = 4.47 (sec) , antiderivative size = 394, normalized size of antiderivative = 1.00
method | result | size |
derivativedivides | \(\frac {\frac {e^{3} {\mathrm e}^{\frac {4 a}{b}} \operatorname {expIntegral}_{1}\left (4 \,\operatorname {arcsinh}\left (x c \right )+\frac {4 a}{b}\right )}{16 c^{3} b}-\frac {e^{3} {\mathrm e}^{-\frac {4 a}{b}} \operatorname {expIntegral}_{1}\left (-4 \,\operatorname {arcsinh}\left (x c \right )-\frac {4 a}{b}\right )}{16 c^{3} b}+\frac {3 e \,{\mathrm e}^{\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (2 \,\operatorname {arcsinh}\left (x c \right )+\frac {2 a}{b}\right ) d^{2}}{4 c b}-\frac {e^{3} {\mathrm e}^{\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (2 \,\operatorname {arcsinh}\left (x c \right )+\frac {2 a}{b}\right )}{8 c^{3} b}-\frac {3 e \,{\mathrm e}^{-\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (-2 \,\operatorname {arcsinh}\left (x c \right )-\frac {2 a}{b}\right ) d^{2}}{4 c b}+\frac {e^{3} {\mathrm e}^{-\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (-2 \,\operatorname {arcsinh}\left (x c \right )-\frac {2 a}{b}\right )}{8 c^{3} b}-\frac {3 d \,e^{2} {\mathrm e}^{-\frac {3 a}{b}} \operatorname {expIntegral}_{1}\left (-3 \,\operatorname {arcsinh}\left (x c \right )-\frac {3 a}{b}\right )}{8 c^{2} b}-\frac {3 d \,e^{2} {\mathrm e}^{\frac {3 a}{b}} \operatorname {expIntegral}_{1}\left (3 \,\operatorname {arcsinh}\left (x c \right )+\frac {3 a}{b}\right )}{8 c^{2} b}-\frac {d^{3} {\mathrm e}^{\frac {a}{b}} \operatorname {expIntegral}_{1}\left (\operatorname {arcsinh}\left (x c \right )+\frac {a}{b}\right )}{2 b}+\frac {3 d \,{\mathrm e}^{\frac {a}{b}} \operatorname {expIntegral}_{1}\left (\operatorname {arcsinh}\left (x c \right )+\frac {a}{b}\right ) e^{2}}{8 c^{2} b}-\frac {d^{3} {\mathrm e}^{-\frac {a}{b}} \operatorname {expIntegral}_{1}\left (-\operatorname {arcsinh}\left (x c \right )-\frac {a}{b}\right )}{2 b}+\frac {3 d \,{\mathrm e}^{-\frac {a}{b}} \operatorname {expIntegral}_{1}\left (-\operatorname {arcsinh}\left (x c \right )-\frac {a}{b}\right ) e^{2}}{8 c^{2} b}}{c}\) | \(394\) |
default | \(\frac {\frac {e^{3} {\mathrm e}^{\frac {4 a}{b}} \operatorname {expIntegral}_{1}\left (4 \,\operatorname {arcsinh}\left (x c \right )+\frac {4 a}{b}\right )}{16 c^{3} b}-\frac {e^{3} {\mathrm e}^{-\frac {4 a}{b}} \operatorname {expIntegral}_{1}\left (-4 \,\operatorname {arcsinh}\left (x c \right )-\frac {4 a}{b}\right )}{16 c^{3} b}+\frac {3 e \,{\mathrm e}^{\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (2 \,\operatorname {arcsinh}\left (x c \right )+\frac {2 a}{b}\right ) d^{2}}{4 c b}-\frac {e^{3} {\mathrm e}^{\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (2 \,\operatorname {arcsinh}\left (x c \right )+\frac {2 a}{b}\right )}{8 c^{3} b}-\frac {3 e \,{\mathrm e}^{-\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (-2 \,\operatorname {arcsinh}\left (x c \right )-\frac {2 a}{b}\right ) d^{2}}{4 c b}+\frac {e^{3} {\mathrm e}^{-\frac {2 a}{b}} \operatorname {expIntegral}_{1}\left (-2 \,\operatorname {arcsinh}\left (x c \right )-\frac {2 a}{b}\right )}{8 c^{3} b}-\frac {3 d \,e^{2} {\mathrm e}^{-\frac {3 a}{b}} \operatorname {expIntegral}_{1}\left (-3 \,\operatorname {arcsinh}\left (x c \right )-\frac {3 a}{b}\right )}{8 c^{2} b}-\frac {3 d \,e^{2} {\mathrm e}^{\frac {3 a}{b}} \operatorname {expIntegral}_{1}\left (3 \,\operatorname {arcsinh}\left (x c \right )+\frac {3 a}{b}\right )}{8 c^{2} b}-\frac {d^{3} {\mathrm e}^{\frac {a}{b}} \operatorname {expIntegral}_{1}\left (\operatorname {arcsinh}\left (x c \right )+\frac {a}{b}\right )}{2 b}+\frac {3 d \,{\mathrm e}^{\frac {a}{b}} \operatorname {expIntegral}_{1}\left (\operatorname {arcsinh}\left (x c \right )+\frac {a}{b}\right ) e^{2}}{8 c^{2} b}-\frac {d^{3} {\mathrm e}^{-\frac {a}{b}} \operatorname {expIntegral}_{1}\left (-\operatorname {arcsinh}\left (x c \right )-\frac {a}{b}\right )}{2 b}+\frac {3 d \,{\mathrm e}^{-\frac {a}{b}} \operatorname {expIntegral}_{1}\left (-\operatorname {arcsinh}\left (x c \right )-\frac {a}{b}\right ) e^{2}}{8 c^{2} b}}{c}\) | \(394\) |
Input:
int((e*x+d)^3/(a+b*arcsinh(x*c)),x,method=_RETURNVERBOSE)
Output:
1/c*(1/16/c^3*e^3/b*exp(4*a/b)*Ei(1,4*arcsinh(x*c)+4*a/b)-1/16/c^3*e^3/b*e xp(-4*a/b)*Ei(1,-4*arcsinh(x*c)-4*a/b)+3/4/c*e/b*exp(2*a/b)*Ei(1,2*arcsinh (x*c)+2*a/b)*d^2-1/8/c^3*e^3/b*exp(2*a/b)*Ei(1,2*arcsinh(x*c)+2*a/b)-3/4/c *e/b*exp(-2*a/b)*Ei(1,-2*arcsinh(x*c)-2*a/b)*d^2+1/8/c^3*e^3/b*exp(-2*a/b) *Ei(1,-2*arcsinh(x*c)-2*a/b)-3/8/c^2*d*e^2/b*exp(-3*a/b)*Ei(1,-3*arcsinh(x *c)-3*a/b)-3/8/c^2*d*e^2/b*exp(3*a/b)*Ei(1,3*arcsinh(x*c)+3*a/b)-1/2*d^3/b *exp(a/b)*Ei(1,arcsinh(x*c)+a/b)+3/8/c^2*d/b*exp(a/b)*Ei(1,arcsinh(x*c)+a/ b)*e^2-1/2*d^3/b*exp(-a/b)*Ei(1,-arcsinh(x*c)-a/b)+3/8/c^2*d/b*exp(-a/b)*E i(1,-arcsinh(x*c)-a/b)*e^2)
\[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \] Input:
integrate((e*x+d)^3/(a+b*arcsinh(c*x)),x, algorithm="fricas")
Output:
integral((e^3*x^3 + 3*d*e^2*x^2 + 3*d^2*e*x + d^3)/(b*arcsinh(c*x) + a), x )
\[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\int \frac {\left (d + e x\right )^{3}}{a + b \operatorname {asinh}{\left (c x \right )}}\, dx \] Input:
integrate((e*x+d)**3/(a+b*asinh(c*x)),x)
Output:
Integral((d + e*x)**3/(a + b*asinh(c*x)), x)
\[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \] Input:
integrate((e*x+d)^3/(a+b*arcsinh(c*x)),x, algorithm="maxima")
Output:
integrate((e*x + d)^3/(b*arcsinh(c*x) + a), x)
\[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\int { \frac {{\left (e x + d\right )}^{3}}{b \operatorname {arsinh}\left (c x\right ) + a} \,d x } \] Input:
integrate((e*x+d)^3/(a+b*arcsinh(c*x)),x, algorithm="giac")
Output:
integrate((e*x + d)^3/(b*arcsinh(c*x) + a), x)
Timed out. \[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\int \frac {{\left (d+e\,x\right )}^3}{a+b\,\mathrm {asinh}\left (c\,x\right )} \,d x \] Input:
int((d + e*x)^3/(a + b*asinh(c*x)),x)
Output:
int((d + e*x)^3/(a + b*asinh(c*x)), x)
\[ \int \frac {(d+e x)^3}{a+b \text {arcsinh}(c x)} \, dx=\left (\int \frac {x^{3}}{\mathit {asinh} \left (c x \right ) b +a}d x \right ) e^{3}+3 \left (\int \frac {x^{2}}{\mathit {asinh} \left (c x \right ) b +a}d x \right ) d \,e^{2}+3 \left (\int \frac {x}{\mathit {asinh} \left (c x \right ) b +a}d x \right ) d^{2} e +\left (\int \frac {1}{\mathit {asinh} \left (c x \right ) b +a}d x \right ) d^{3} \] Input:
int((e*x+d)^3/(a+b*asinh(c*x)),x)
Output:
int(x**3/(asinh(c*x)*b + a),x)*e**3 + 3*int(x**2/(asinh(c*x)*b + a),x)*d*e **2 + 3*int(x/(asinh(c*x)*b + a),x)*d**2*e + int(1/(asinh(c*x)*b + a),x)*d **3