Integrand size = 15, antiderivative size = 91 \[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=2 \arctan \left (\frac {\sqrt {\text {arctanh}(\tanh (a+b x))}}{\sqrt {b x-\text {arctanh}(\tanh (a+b x))}}\right ) (b x-\text {arctanh}(\tanh (a+b x)))^{3/2}-2 (b x-\text {arctanh}(\tanh (a+b x))) \sqrt {\text {arctanh}(\tanh (a+b x))}+\frac {2}{3} \text {arctanh}(\tanh (a+b x))^{3/2} \] Output:
2*arctan(arctanh(tanh(b*x+a))^(1/2)/(b*x-arctanh(tanh(b*x+a)))^(1/2))*(b*x -arctanh(tanh(b*x+a)))^(3/2)-2*(b*x-arctanh(tanh(b*x+a)))*arctanh(tanh(b*x +a))^(1/2)+2/3*arctanh(tanh(b*x+a))^(3/2)
Time = 0.10 (sec) , antiderivative size = 80, normalized size of antiderivative = 0.88 \[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=-\frac {2}{3} \left (3 b x \sqrt {\text {arctanh}(\tanh (a+b x))}-4 \text {arctanh}(\tanh (a+b x))^{3/2}+3 \text {arctanh}\left (\frac {\sqrt {\text {arctanh}(\tanh (a+b x))}}{\sqrt {-b x+\text {arctanh}(\tanh (a+b x))}}\right ) (-b x+\text {arctanh}(\tanh (a+b x)))^{3/2}\right ) \] Input:
Integrate[ArcTanh[Tanh[a + b*x]]^(3/2)/x,x]
Output:
(-2*(3*b*x*Sqrt[ArcTanh[Tanh[a + b*x]]] - 4*ArcTanh[Tanh[a + b*x]]^(3/2) + 3*ArcTanh[Sqrt[ArcTanh[Tanh[a + b*x]]]/Sqrt[-(b*x) + ArcTanh[Tanh[a + b*x ]]]]*(-(b*x) + ArcTanh[Tanh[a + b*x]])^(3/2)))/3
Time = 0.38 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.03, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2590, 2590, 2592}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx\) |
\(\Big \downarrow \) 2590 |
\(\displaystyle \frac {2}{3} \text {arctanh}(\tanh (a+b x))^{3/2}-(b x-\text {arctanh}(\tanh (a+b x))) \int \frac {\sqrt {\text {arctanh}(\tanh (a+b x))}}{x}dx\) |
\(\Big \downarrow \) 2590 |
\(\displaystyle \frac {2}{3} \text {arctanh}(\tanh (a+b x))^{3/2}-(b x-\text {arctanh}(\tanh (a+b x))) \left (2 \sqrt {\text {arctanh}(\tanh (a+b x))}-(b x-\text {arctanh}(\tanh (a+b x))) \int \frac {1}{x \sqrt {\text {arctanh}(\tanh (a+b x))}}dx\right )\) |
\(\Big \downarrow \) 2592 |
\(\displaystyle \frac {2}{3} \text {arctanh}(\tanh (a+b x))^{3/2}-(b x-\text {arctanh}(\tanh (a+b x))) \left (2 \sqrt {\text {arctanh}(\tanh (a+b x))}-2 \sqrt {b x-\text {arctanh}(\tanh (a+b x))} \arctan \left (\frac {\sqrt {\text {arctanh}(\tanh (a+b x))}}{\sqrt {b x-\text {arctanh}(\tanh (a+b x))}}\right )\right )\) |
Input:
Int[ArcTanh[Tanh[a + b*x]]^(3/2)/x,x]
Output:
-((-2*ArcTan[Sqrt[ArcTanh[Tanh[a + b*x]]]/Sqrt[b*x - ArcTanh[Tanh[a + b*x] ]]]*Sqrt[b*x - ArcTanh[Tanh[a + b*x]]] + 2*Sqrt[ArcTanh[Tanh[a + b*x]]])*( b*x - ArcTanh[Tanh[a + b*x]])) + (2*ArcTanh[Tanh[a + b*x]]^(3/2))/3
Int[(v_)^(n_)/(u_), x_Symbol] :> With[{a = Simplify[D[u, x]], b = Simplify[ D[v, x]]}, Simp[v^n/(a*n), x] - Simp[(b*u - a*v)/a Int[v^(n - 1)/u, x], x ] /; NeQ[b*u - a*v, 0]] /; PiecewiseLinearQ[u, v, x] && GtQ[n, 0] && NeQ[n, 1]
Int[1/((u_)*Sqrt[v_]), x_Symbol] :> With[{a = Simplify[D[u, x]], b = Simpli fy[D[v, x]]}, Simp[2*(ArcTan[Sqrt[v]/Rt[(b*u - a*v)/a, 2]]/(a*Rt[(b*u - a*v )/a, 2])), x] /; NeQ[b*u - a*v, 0] && PosQ[(b*u - a*v)/a]] /; PiecewiseLine arQ[u, v, x]
Time = 0.19 (sec) , antiderivative size = 131, normalized size of antiderivative = 1.44
method | result | size |
default | \(\frac {2 \operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )^{\frac {3}{2}}}{3}+2 \sqrt {\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )}\, a +2 \left (\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )-b x -a \right ) \sqrt {\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )}-\frac {2 \left (a^{2}+2 a \left (\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )-b x -a \right )+\left (\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )-b x -a \right )^{2}\right ) \operatorname {arctanh}\left (\frac {\sqrt {\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )}}{\sqrt {\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )-b x}}\right )}{\sqrt {\operatorname {arctanh}\left (\tanh \left (b x +a \right )\right )-b x}}\) | \(131\) |
Input:
int(arctanh(tanh(b*x+a))^(3/2)/x,x,method=_RETURNVERBOSE)
Output:
2/3*arctanh(tanh(b*x+a))^(3/2)+2*arctanh(tanh(b*x+a))^(1/2)*a+2*(arctanh(t anh(b*x+a))-b*x-a)*arctanh(tanh(b*x+a))^(1/2)-2*(a^2+2*a*(arctanh(tanh(b*x +a))-b*x-a)+(arctanh(tanh(b*x+a))-b*x-a)^2)/(arctanh(tanh(b*x+a))-b*x)^(1/ 2)*arctanh(arctanh(tanh(b*x+a))^(1/2)/(arctanh(tanh(b*x+a))-b*x)^(1/2))
Time = 0.08 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.93 \[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=\left [a^{\frac {3}{2}} \log \left (\frac {b x - 2 \, \sqrt {b x + a} \sqrt {a} + 2 \, a}{x}\right ) + \frac {2}{3} \, {\left (b x + 4 \, a\right )} \sqrt {b x + a}, 2 \, \sqrt {-a} a \arctan \left (\frac {\sqrt {-a}}{\sqrt {b x + a}}\right ) + \frac {2}{3} \, {\left (b x + 4 \, a\right )} \sqrt {b x + a}\right ] \] Input:
integrate(arctanh(tanh(b*x+a))^(3/2)/x,x, algorithm="fricas")
Output:
[a^(3/2)*log((b*x - 2*sqrt(b*x + a)*sqrt(a) + 2*a)/x) + 2/3*(b*x + 4*a)*sq rt(b*x + a), 2*sqrt(-a)*a*arctan(sqrt(-a)/sqrt(b*x + a)) + 2/3*(b*x + 4*a) *sqrt(b*x + a)]
\[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=\int \frac {\operatorname {atanh}^{\frac {3}{2}}{\left (\tanh {\left (a + b x \right )} \right )}}{x}\, dx \] Input:
integrate(atanh(tanh(b*x+a))**(3/2)/x,x)
Output:
Integral(atanh(tanh(a + b*x))**(3/2)/x, x)
\[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=\int { \frac {\operatorname {artanh}\left (\tanh \left (b x + a\right )\right )^{\frac {3}{2}}}{x} \,d x } \] Input:
integrate(arctanh(tanh(b*x+a))^(3/2)/x,x, algorithm="maxima")
Output:
integrate(arctanh(tanh(b*x + a))^(3/2)/x, x)
Time = 0.11 (sec) , antiderivative size = 57, normalized size of antiderivative = 0.63 \[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=\frac {1}{3} \, \sqrt {2} {\left (\frac {3 \, \sqrt {2} a^{2} \arctan \left (\frac {\sqrt {b x + a}}{\sqrt {-a}}\right )}{\sqrt {-a}} + \sqrt {2} {\left (b x + a\right )}^{\frac {3}{2}} + 3 \, \sqrt {2} \sqrt {b x + a} a\right )} \] Input:
integrate(arctanh(tanh(b*x+a))^(3/2)/x,x, algorithm="giac")
Output:
1/3*sqrt(2)*(3*sqrt(2)*a^2*arctan(sqrt(b*x + a)/sqrt(-a))/sqrt(-a) + sqrt( 2)*(b*x + a)^(3/2) + 3*sqrt(2)*sqrt(b*x + a)*a)
Time = 7.58 (sec) , antiderivative size = 501, normalized size of antiderivative = 5.51 \[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx =\text {Too large to display} \] Input:
int(atanh(tanh(a + b*x))^(3/2)/x,x)
Output:
((log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*exp(2*b*x) + 1))/2 - log(2/(exp(2* a)*exp(2*b*x) + 1))/2)^(1/2)*((4*b*(log(2/(exp(2*a)*exp(2*b*x) + 1))/2 - l og((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*exp(2*b*x) + 1))/2 + b*x))/3 - 2*b*(l og(2/(exp(2*a)*exp(2*b*x) + 1)) - log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*ex p(2*b*x) + 1)) + 2*b*x)))/b + (2^(1/2)*log((((log((2*exp(2*a)*exp(2*b*x))/ (exp(2*a)*exp(2*b*x) + 1))/2 - log(2/(exp(2*a)*exp(2*b*x) + 1))/2)^(1/2)*( log(2/(exp(2*a)*exp(2*b*x) + 1)) - log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*e xp(2*b*x) + 1)) + 2*b*x)^(1/2)*2i - 2^(1/2)*(log(2/(exp(2*a)*exp(2*b*x) + 1)) - log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*exp(2*b*x) + 1)) + 2*b*x) + 2^ (1/2)*b*x)*4i)/(x*(log(2/(exp(2*a)*exp(2*b*x) + 1)) - log((2*exp(2*a)*exp( 2*b*x))/(exp(2*a)*exp(2*b*x) + 1)) + 2*b*x)^(1/2)))*(log(2/(exp(2*a)*exp(2 *b*x) + 1)) - log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*exp(2*b*x) + 1)) + 2*b *x)^(3/2)*1i)/4 + (2*b*x*(log((2*exp(2*a)*exp(2*b*x))/(exp(2*a)*exp(2*b*x) + 1))/2 - log(2/(exp(2*a)*exp(2*b*x) + 1))/2)^(1/2))/3
\[ \int \frac {\text {arctanh}(\tanh (a+b x))^{3/2}}{x} \, dx=\int \frac {\sqrt {\mathit {atanh} \left (\tanh \left (b x +a \right )\right )}\, \mathit {atanh} \left (\tanh \left (b x +a \right )\right )}{x}d x \] Input:
int(atanh(tanh(b*x+a))^(3/2)/x,x)
Output:
int((sqrt(atanh(tanh(a + b*x)))*atanh(tanh(a + b*x)))/x,x)