\(\int \frac {a+b \text {arctanh}(c x^2)}{(d x)^{5/2}} \, dx\) [87]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [C] (verification not implemented)
Sympy [F]
Maxima [A] (verification not implemented)
Giac [B] (verification not implemented)
Mupad [F(-1)]
Reduce [B] (verification not implemented)

Optimal result

Integrand size = 18, antiderivative size = 241 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\frac {2 b c^{3/4} \arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{3 d^{5/2}}-\frac {\sqrt {2} b c^{3/4} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{3 d^{5/2}}+\frac {\sqrt {2} b c^{3/4} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{3 d^{5/2}}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}+\frac {2 b c^{3/4} \text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{3 d^{5/2}}+\frac {\sqrt {2} b c^{3/4} \text {arctanh}\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d} \left (1+\sqrt {c} x\right )}\right )}{3 d^{5/2}} \] Output:

2/3*b*c^(3/4)*arctan(c^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(5/2)+1/3*2^(1/2)*b*c^ 
(3/4)*arctan(-1+2^(1/2)*c^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(5/2)+1/3*2^(1/2)*b 
*c^(3/4)*arctan(1+2^(1/2)*c^(1/4)*(d*x)^(1/2)/d^(1/2))/d^(5/2)-2/3*(a+b*ar 
ctanh(c*x^2))/d/(d*x)^(3/2)+2/3*b*c^(3/4)*arctanh(c^(1/4)*(d*x)^(1/2)/d^(1 
/2))/d^(5/2)+1/3*2^(1/2)*b*c^(3/4)*arctanh(2^(1/2)*c^(1/4)*(d*x)^(1/2)/d^( 
1/2)/(1+c^(1/2)*x))/d^(5/2)
 

Mathematica [A] (verified)

Time = 0.10 (sec) , antiderivative size = 268, normalized size of antiderivative = 1.11 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=-\frac {x \left (4 a+2 \sqrt {2} b c^{3/4} x^{3/2} \arctan \left (1-\sqrt {2} \sqrt [4]{c} \sqrt {x}\right )-2 \sqrt {2} b c^{3/4} x^{3/2} \arctan \left (1+\sqrt {2} \sqrt [4]{c} \sqrt {x}\right )-4 b c^{3/4} x^{3/2} \arctan \left (\sqrt [4]{c} \sqrt {x}\right )+4 b \text {arctanh}\left (c x^2\right )+2 b c^{3/4} x^{3/2} \log \left (1-\sqrt [4]{c} \sqrt {x}\right )-2 b c^{3/4} x^{3/2} \log \left (1+\sqrt [4]{c} \sqrt {x}\right )+\sqrt {2} b c^{3/4} x^{3/2} \log \left (1-\sqrt {2} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )-\sqrt {2} b c^{3/4} x^{3/2} \log \left (1+\sqrt {2} \sqrt [4]{c} \sqrt {x}+\sqrt {c} x\right )\right )}{6 (d x)^{5/2}} \] Input:

Integrate[(a + b*ArcTanh[c*x^2])/(d*x)^(5/2),x]
 

Output:

-1/6*(x*(4*a + 2*Sqrt[2]*b*c^(3/4)*x^(3/2)*ArcTan[1 - Sqrt[2]*c^(1/4)*Sqrt 
[x]] - 2*Sqrt[2]*b*c^(3/4)*x^(3/2)*ArcTan[1 + Sqrt[2]*c^(1/4)*Sqrt[x]] - 4 
*b*c^(3/4)*x^(3/2)*ArcTan[c^(1/4)*Sqrt[x]] + 4*b*ArcTanh[c*x^2] + 2*b*c^(3 
/4)*x^(3/2)*Log[1 - c^(1/4)*Sqrt[x]] - 2*b*c^(3/4)*x^(3/2)*Log[1 + c^(1/4) 
*Sqrt[x]] + Sqrt[2]*b*c^(3/4)*x^(3/2)*Log[1 - Sqrt[2]*c^(1/4)*Sqrt[x] + Sq 
rt[c]*x] - Sqrt[2]*b*c^(3/4)*x^(3/2)*Log[1 + Sqrt[2]*c^(1/4)*Sqrt[x] + Sqr 
t[c]*x]))/(d*x)^(5/2)
 

Rubi [A] (verified)

Time = 0.57 (sec) , antiderivative size = 326, normalized size of antiderivative = 1.35, number of steps used = 15, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.778, Rules used = {6464, 851, 758, 755, 756, 218, 221, 1476, 1082, 217, 1479, 25, 27, 1103}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx\)

\(\Big \downarrow \) 6464

\(\displaystyle \frac {4 b c \int \frac {1}{\sqrt {d x} \left (1-c^2 x^4\right )}dx}{3 d^2}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 851

\(\displaystyle \frac {8 b c \int \frac {1}{1-c^2 x^4}d\sqrt {d x}}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 758

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \int \frac {1}{d^2-c d^2 x^2}d\sqrt {d x}+\frac {1}{2} d^2 \int \frac {1}{c x^2 d^2+d^2}d\sqrt {d x}\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 755

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \int \frac {1}{d^2-c d^2 x^2}d\sqrt {d x}+\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\int \frac {\sqrt {c} x d+d}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 756

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\int \frac {\sqrt {c} x d+d}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\int \frac {1}{d-\sqrt {c} d x}d\sqrt {d x}}{2 d}+\frac {\int \frac {1}{\sqrt {c} x d+d}d\sqrt {d x}}{2 d}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 218

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {1}{d-\sqrt {c} d x}d\sqrt {d x}}{2 d}+\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )+\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\int \frac {\sqrt {c} x d+d}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 221

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\int \frac {\sqrt {c} x d+d}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 1476

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\frac {\int \frac {1}{x d+\frac {d}{\sqrt {c}}-\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}}d\sqrt {d x}}{2 \sqrt {c}}+\frac {\int \frac {1}{x d+\frac {d}{\sqrt {c}}+\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}}d\sqrt {d x}}{2 \sqrt {c}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 1082

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\frac {\int \frac {1}{-d x-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\int \frac {1}{-d x-1}d\left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 217

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\int \frac {d-\sqrt {c} d x}{c x^2 d^2+d^2}d\sqrt {d x}}{2 d}+\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 1479

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {-\frac {\int -\frac {\sqrt {2} \sqrt {d}-2 \sqrt [4]{c} \sqrt {d x}}{\sqrt [4]{c} \left (x d+\frac {d}{\sqrt {c}}-\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {d}+\sqrt {2} \sqrt [4]{c} \sqrt {d x}\right )}{\sqrt [4]{c} \left (x d+\frac {d}{\sqrt {c}}+\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}+\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\frac {\int \frac {\sqrt {2} \sqrt {d}-2 \sqrt [4]{c} \sqrt {d x}}{\sqrt [4]{c} \left (x d+\frac {d}{\sqrt {c}}-\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {d}+\sqrt {2} \sqrt [4]{c} \sqrt {d x}\right )}{\sqrt [4]{c} \left (x d+\frac {d}{\sqrt {c}}+\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}\right )}d\sqrt {d x}}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}+\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\frac {\int \frac {\sqrt {2} \sqrt {d}-2 \sqrt [4]{c} \sqrt {d x}}{x d+\frac {d}{\sqrt {c}}-\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}}d\sqrt {d x}}{2 \sqrt {2} \sqrt {c} \sqrt {d}}+\frac {\int \frac {\sqrt {d}+\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{x d+\frac {d}{\sqrt {c}}+\frac {\sqrt {2} \sqrt {d x} \sqrt {d}}{\sqrt [4]{c}}}d\sqrt {d x}}{2 \sqrt {c} \sqrt {d}}}{2 d}+\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )+\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

\(\Big \downarrow \) 1103

\(\displaystyle \frac {8 b c \left (\frac {1}{2} d^2 \left (\frac {\arctan \left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{2 \sqrt [4]{c} d^{3/2}}\right )+\frac {1}{2} d^2 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}+1\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{c} \sqrt {d x}}{\sqrt {d}}\right )}{\sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}+\frac {\frac {\log \left (\sqrt {c} d x+\sqrt {2} \sqrt [4]{c} \sqrt {d} \sqrt {d x}+d\right )}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}-\frac {\log \left (\sqrt {c} d x-\sqrt {2} \sqrt [4]{c} \sqrt {d} \sqrt {d x}+d\right )}{2 \sqrt {2} \sqrt [4]{c} \sqrt {d}}}{2 d}\right )\right )}{3 d^3}-\frac {2 \left (a+b \text {arctanh}\left (c x^2\right )\right )}{3 d (d x)^{3/2}}\)

Input:

Int[(a + b*ArcTanh[c*x^2])/(d*x)^(5/2),x]
 

Output:

(-2*(a + b*ArcTanh[c*x^2]))/(3*d*(d*x)^(3/2)) + (8*b*c*((d^2*(ArcTan[(c^(1 
/4)*Sqrt[d*x])/Sqrt[d]]/(2*c^(1/4)*d^(3/2)) + ArcTanh[(c^(1/4)*Sqrt[d*x])/ 
Sqrt[d]]/(2*c^(1/4)*d^(3/2))))/2 + (d^2*((-(ArcTan[1 - (Sqrt[2]*c^(1/4)*Sq 
rt[d*x])/Sqrt[d]]/(Sqrt[2]*c^(1/4)*Sqrt[d])) + ArcTan[1 + (Sqrt[2]*c^(1/4) 
*Sqrt[d*x])/Sqrt[d]]/(Sqrt[2]*c^(1/4)*Sqrt[d]))/(2*d) + (-1/2*Log[d + Sqrt 
[c]*d*x - Sqrt[2]*c^(1/4)*Sqrt[d]*Sqrt[d*x]]/(Sqrt[2]*c^(1/4)*Sqrt[d]) + L 
og[d + Sqrt[c]*d*x + Sqrt[2]*c^(1/4)*Sqrt[d]*Sqrt[d*x]]/(2*Sqrt[2]*c^(1/4) 
*Sqrt[d]))/(2*d)))/2))/(3*d^3)
 

Defintions of rubi rules used

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 217
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( 
-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & 
& (LtQ[a, 0] || LtQ[b, 0])
 

rule 218
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]/a)*ArcTan[x/R 
t[a/b, 2]], x] /; FreeQ[{a, b}, x] && PosQ[a/b]
 

rule 221
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[-a/b, 2]/a)*ArcTanh[x 
/Rt[-a/b, 2]], x] /; FreeQ[{a, b}, x] && NegQ[a/b]
 

rule 755
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2] 
], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*r)   Int[(r - s*x^2)/(a + b*x^4) 
, x], x] + Simp[1/(2*r)   Int[(r + s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{a, 
 b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] & 
& AtomQ[SplitProduct[SumBaseQ, b]]))
 

rule 756
Int[((a_) + (b_.)*(x_)^4)^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b, 2 
]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a)   Int[1/(r - s*x^2), x], x] 
 + Simp[r/(2*a)   Int[1/(r + s*x^2), x], x]] /; FreeQ[{a, b}, x] &&  !GtQ[a 
/b, 0]
 

rule 758
Int[((a_) + (b_.)*(x_)^(n_))^(-1), x_Symbol] :> With[{r = Numerator[Rt[-a/b 
, 2]], s = Denominator[Rt[-a/b, 2]]}, Simp[r/(2*a)   Int[1/(r - s*x^(n/2)), 
 x], x] + Simp[r/(2*a)   Int[1/(r + s*x^(n/2)), x], x]] /; FreeQ[{a, b}, x] 
 && IGtQ[n/4, 1] &&  !GtQ[a/b, 0]
 

rule 851
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = 
 Denominator[m]}, Simp[k/c   Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^ 
n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && 
FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]
 

rule 1082
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S 
implify[a*(c/b^2)]}, Simp[-2/b   Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b 
)], x] /; RationalQ[q] && (EqQ[q^2, 1] ||  !RationalQ[b^2 - 4*a*c])] /; Fre 
eQ[{a, b, c}, x]
 

rule 1103
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S 
imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, 
e}, x] && EqQ[2*c*d - b*e, 0]
 

rule 1476
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
2*(d/e), 2]}, Simp[e/(2*c)   Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ 
e/(2*c)   Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] 
 && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
 

rule 1479
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 
-2*(d/e), 2]}, Simp[e/(2*c*q)   Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], 
 x] + Simp[e/(2*c*q)   Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F 
reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
 

rule 6464
Int[((a_.) + ArcTanh[(c_.)*(x_)^(n_.)]*(b_.))*((d_)*(x_))^(m_), x_Symbol] : 
> Simp[(d*x)^(m + 1)*((a + b*ArcTanh[c*x^n])/(d*(m + 1))), x] - Simp[b*c*(n 
/(d^n*(m + 1)))   Int[(d*x)^(m + n)/(1 - c^2*x^(2*n)), x], x] /; FreeQ[{a, 
b, c, d, m, n}, x] && IntegerQ[n] && NeQ[m, -1]
 
Maple [A] (verified)

Time = 0.39 (sec) , antiderivative size = 238, normalized size of antiderivative = 0.99

method result size
derivativedivides \(\frac {-\frac {2 a}{3 \left (d x \right )^{\frac {3}{2}}}+2 b \left (-\frac {\operatorname {arctanh}\left (c \,x^{2}\right )}{3 \left (d x \right )^{\frac {3}{2}}}+\frac {4 c \,d^{2} \left (\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \left (\ln \left (\frac {\sqrt {d x}+\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}{\sqrt {d x}-\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )+2 \arctan \left (\frac {\sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )\right )}{8 d^{4}}+\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}{d x -\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{16 d^{4}}\right )}{3}\right )}{d}\) \(238\)
default \(\frac {-\frac {2 a}{3 \left (d x \right )^{\frac {3}{2}}}+2 b \left (-\frac {\operatorname {arctanh}\left (c \,x^{2}\right )}{3 \left (d x \right )^{\frac {3}{2}}}+\frac {4 c \,d^{2} \left (\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \left (\ln \left (\frac {\sqrt {d x}+\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}{\sqrt {d x}-\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )+2 \arctan \left (\frac {\sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )\right )}{8 d^{4}}+\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}{d x -\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{16 d^{4}}\right )}{3}\right )}{d}\) \(238\)
parts \(-\frac {2 a}{3 \left (d x \right )^{\frac {3}{2}} d}+\frac {2 b \left (-\frac {\operatorname {arctanh}\left (c \,x^{2}\right )}{3 \left (d x \right )^{\frac {3}{2}}}+\frac {4 c \,d^{2} \left (\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \left (\ln \left (\frac {\sqrt {d x}+\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}{\sqrt {d x}-\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )+2 \arctan \left (\frac {\sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )\right )}{8 d^{4}}+\frac {\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {2}\, \left (\ln \left (\frac {d x +\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}{d x -\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} \sqrt {d x}\, \sqrt {2}+\sqrt {\frac {d^{2}}{c}}}\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}+1\right )+2 \arctan \left (\frac {\sqrt {2}\, \sqrt {d x}}{\left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}-1\right )\right )}{16 d^{4}}\right )}{3}\right )}{d}\) \(240\)

Input:

int((a+b*arctanh(c*x^2))/(d*x)^(5/2),x,method=_RETURNVERBOSE)
 

Output:

2/d*(-1/3*a/(d*x)^(3/2)+b*(-1/3/(d*x)^(3/2)*arctanh(c*x^2)+4/3*c*d^2*(1/8/ 
d^4*(d^2/c)^(1/4)*(ln(((d*x)^(1/2)+(d^2/c)^(1/4))/((d*x)^(1/2)-(d^2/c)^(1/ 
4)))+2*arctan((d*x)^(1/2)/(d^2/c)^(1/4)))+1/16/d^4*(d^2/c)^(1/4)*2^(1/2)*( 
ln((d*x+(d^2/c)^(1/4)*(d*x)^(1/2)*2^(1/2)+(d^2/c)^(1/2))/(d*x-(d^2/c)^(1/4 
)*(d*x)^(1/2)*2^(1/2)+(d^2/c)^(1/2)))+2*arctan(2^(1/2)/(d^2/c)^(1/4)*(d*x) 
^(1/2)+1)+2*arctan(2^(1/2)/(d^2/c)^(1/4)*(d*x)^(1/2)-1)))))
 

Fricas [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 0.10 (sec) , antiderivative size = 421, normalized size of antiderivative = 1.75 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\frac {d^{3} x^{2} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (d^{3} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) + i \, d^{3} x^{2} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (i \, d^{3} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) - i \, d^{3} x^{2} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-i \, d^{3} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) - d^{3} x^{2} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-d^{3} \left (\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) + d^{3} x^{2} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (d^{3} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) + i \, d^{3} x^{2} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (i \, d^{3} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) - i \, d^{3} x^{2} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-i \, d^{3} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) - d^{3} x^{2} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} \log \left (-d^{3} \left (-\frac {b^{4} c^{3}}{d^{10}}\right )^{\frac {1}{4}} + \sqrt {d x} b c\right ) - \sqrt {d x} {\left (b \log \left (-\frac {c x^{2} + 1}{c x^{2} - 1}\right ) + 2 \, a\right )}}{3 \, d^{3} x^{2}} \] Input:

integrate((a+b*arctanh(c*x^2))/(d*x)^(5/2),x, algorithm="fricas")
 

Output:

1/3*(d^3*x^2*(b^4*c^3/d^10)^(1/4)*log(d^3*(b^4*c^3/d^10)^(1/4) + sqrt(d*x) 
*b*c) + I*d^3*x^2*(b^4*c^3/d^10)^(1/4)*log(I*d^3*(b^4*c^3/d^10)^(1/4) + sq 
rt(d*x)*b*c) - I*d^3*x^2*(b^4*c^3/d^10)^(1/4)*log(-I*d^3*(b^4*c^3/d^10)^(1 
/4) + sqrt(d*x)*b*c) - d^3*x^2*(b^4*c^3/d^10)^(1/4)*log(-d^3*(b^4*c^3/d^10 
)^(1/4) + sqrt(d*x)*b*c) + d^3*x^2*(-b^4*c^3/d^10)^(1/4)*log(d^3*(-b^4*c^3 
/d^10)^(1/4) + sqrt(d*x)*b*c) + I*d^3*x^2*(-b^4*c^3/d^10)^(1/4)*log(I*d^3* 
(-b^4*c^3/d^10)^(1/4) + sqrt(d*x)*b*c) - I*d^3*x^2*(-b^4*c^3/d^10)^(1/4)*l 
og(-I*d^3*(-b^4*c^3/d^10)^(1/4) + sqrt(d*x)*b*c) - d^3*x^2*(-b^4*c^3/d^10) 
^(1/4)*log(-d^3*(-b^4*c^3/d^10)^(1/4) + sqrt(d*x)*b*c) - sqrt(d*x)*(b*log( 
-(c*x^2 + 1)/(c*x^2 - 1)) + 2*a))/(d^3*x^2)
 

Sympy [F]

\[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\int \frac {a + b \operatorname {atanh}{\left (c x^{2} \right )}}{\left (d x\right )^{\frac {5}{2}}}\, dx \] Input:

integrate((a+b*atanh(c*x**2))/(d*x)**(5/2),x)
 

Output:

Integral((a + b*atanh(c*x**2))/(d*x)**(5/2), x)
 

Maxima [A] (verification not implemented)

Time = 0.11 (sec) , antiderivative size = 277, normalized size of antiderivative = 1.15 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\frac {b {\left (\frac {{\left (\frac {2 \, \sqrt {2} d \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} c^{\frac {1}{4}} \sqrt {d} + 2 \, \sqrt {d x} \sqrt {c}\right )}}{2 \, \sqrt {\sqrt {c} d}}\right )}{\sqrt {\sqrt {c} d}} + \frac {2 \, \sqrt {2} d \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} c^{\frac {1}{4}} \sqrt {d} - 2 \, \sqrt {d x} \sqrt {c}\right )}}{2 \, \sqrt {\sqrt {c} d}}\right )}{\sqrt {\sqrt {c} d}} + \frac {\sqrt {2} \sqrt {d} \log \left (\sqrt {c} d x + \sqrt {2} \sqrt {d x} c^{\frac {1}{4}} \sqrt {d} + d\right )}{c^{\frac {1}{4}}} - \frac {\sqrt {2} \sqrt {d} \log \left (\sqrt {c} d x - \sqrt {2} \sqrt {d x} c^{\frac {1}{4}} \sqrt {d} + d\right )}{c^{\frac {1}{4}}} + \frac {4 \, d \arctan \left (\frac {\sqrt {d x} \sqrt {c}}{\sqrt {\sqrt {c} d}}\right )}{\sqrt {\sqrt {c} d}} - \frac {2 \, d \log \left (\frac {\sqrt {d x} \sqrt {c} - \sqrt {\sqrt {c} d}}{\sqrt {d x} \sqrt {c} + \sqrt {\sqrt {c} d}}\right )}{\sqrt {\sqrt {c} d}}\right )} c}{d^{2}} - \frac {4 \, \operatorname {artanh}\left (c x^{2}\right )}{\left (d x\right )^{\frac {3}{2}}}\right )} - \frac {4 \, a}{\left (d x\right )^{\frac {3}{2}}}}{6 \, d} \] Input:

integrate((a+b*arctanh(c*x^2))/(d*x)^(5/2),x, algorithm="maxima")
 

Output:

1/6*(b*((2*sqrt(2)*d*arctan(1/2*sqrt(2)*(sqrt(2)*c^(1/4)*sqrt(d) + 2*sqrt( 
d*x)*sqrt(c))/sqrt(sqrt(c)*d))/sqrt(sqrt(c)*d) + 2*sqrt(2)*d*arctan(-1/2*s 
qrt(2)*(sqrt(2)*c^(1/4)*sqrt(d) - 2*sqrt(d*x)*sqrt(c))/sqrt(sqrt(c)*d))/sq 
rt(sqrt(c)*d) + sqrt(2)*sqrt(d)*log(sqrt(c)*d*x + sqrt(2)*sqrt(d*x)*c^(1/4 
)*sqrt(d) + d)/c^(1/4) - sqrt(2)*sqrt(d)*log(sqrt(c)*d*x - sqrt(2)*sqrt(d* 
x)*c^(1/4)*sqrt(d) + d)/c^(1/4) + 4*d*arctan(sqrt(d*x)*sqrt(c)/sqrt(sqrt(c 
)*d))/sqrt(sqrt(c)*d) - 2*d*log((sqrt(d*x)*sqrt(c) - sqrt(sqrt(c)*d))/(sqr 
t(d*x)*sqrt(c) + sqrt(sqrt(c)*d)))/sqrt(sqrt(c)*d))*c/d^2 - 4*arctanh(c*x^ 
2)/(d*x)^(3/2)) - 4*a/(d*x)^(3/2))/d
 

Giac [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 516 vs. \(2 (162) = 324\).

Time = 0.47 (sec) , antiderivative size = 516, normalized size of antiderivative = 2.14 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\frac {b c d^{2} {\left (\frac {2 \, \sqrt {2} \left (c^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )}{c d^{4}} + \frac {2 \, \sqrt {2} \left (c^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )}{c d^{4}} + \frac {2 \, \sqrt {2} \left (-c^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}} + 2 \, \sqrt {d x}\right )}}{2 \, \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )}{c d^{4}} + \frac {2 \, \sqrt {2} \left (-c^{3} d^{2}\right )^{\frac {1}{4}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}} - 2 \, \sqrt {d x}\right )}}{2 \, \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}}}\right )}{c d^{4}} + \frac {\sqrt {2} \left (c^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x + \sqrt {2} \sqrt {d x} \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {d^{2}}{c}}\right )}{c d^{4}} - \frac {\sqrt {2} \left (c^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x - \sqrt {2} \sqrt {d x} \left (\frac {d^{2}}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {d^{2}}{c}}\right )}{c d^{4}} + \frac {\sqrt {2} \left (-c^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x + \sqrt {2} \sqrt {d x} \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}} + \sqrt {-\frac {d^{2}}{c}}\right )}{c d^{4}} - \frac {\sqrt {2} \left (-c^{3} d^{2}\right )^{\frac {1}{4}} \log \left (d x - \sqrt {2} \sqrt {d x} \left (-\frac {d^{2}}{c}\right )^{\frac {1}{4}} + \sqrt {-\frac {d^{2}}{c}}\right )}{c d^{4}}\right )} - \frac {2 \, b \log \left (-\frac {c d^{2} x^{2} + d^{2}}{c d^{2} x^{2} - d^{2}}\right )}{\sqrt {d x} d x} - \frac {4 \, a}{\sqrt {d x} d x}}{6 \, d} \] Input:

integrate((a+b*arctanh(c*x^2))/(d*x)^(5/2),x, algorithm="giac")
 

Output:

1/6*(b*c*d^2*(2*sqrt(2)*(c^3*d^2)^(1/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(d^2/c 
)^(1/4) + 2*sqrt(d*x))/(d^2/c)^(1/4))/(c*d^4) + 2*sqrt(2)*(c^3*d^2)^(1/4)* 
arctan(-1/2*sqrt(2)*(sqrt(2)*(d^2/c)^(1/4) - 2*sqrt(d*x))/(d^2/c)^(1/4))/( 
c*d^4) + 2*sqrt(2)*(-c^3*d^2)^(1/4)*arctan(1/2*sqrt(2)*(sqrt(2)*(-d^2/c)^( 
1/4) + 2*sqrt(d*x))/(-d^2/c)^(1/4))/(c*d^4) + 2*sqrt(2)*(-c^3*d^2)^(1/4)*a 
rctan(-1/2*sqrt(2)*(sqrt(2)*(-d^2/c)^(1/4) - 2*sqrt(d*x))/(-d^2/c)^(1/4))/ 
(c*d^4) + sqrt(2)*(c^3*d^2)^(1/4)*log(d*x + sqrt(2)*sqrt(d*x)*(d^2/c)^(1/4 
) + sqrt(d^2/c))/(c*d^4) - sqrt(2)*(c^3*d^2)^(1/4)*log(d*x - sqrt(2)*sqrt( 
d*x)*(d^2/c)^(1/4) + sqrt(d^2/c))/(c*d^4) + sqrt(2)*(-c^3*d^2)^(1/4)*log(d 
*x + sqrt(2)*sqrt(d*x)*(-d^2/c)^(1/4) + sqrt(-d^2/c))/(c*d^4) - sqrt(2)*(- 
c^3*d^2)^(1/4)*log(d*x - sqrt(2)*sqrt(d*x)*(-d^2/c)^(1/4) + sqrt(-d^2/c))/ 
(c*d^4)) - 2*b*log(-(c*d^2*x^2 + d^2)/(c*d^2*x^2 - d^2))/(sqrt(d*x)*d*x) - 
 4*a/(sqrt(d*x)*d*x))/d
 

Mupad [F(-1)]

Timed out. \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\int \frac {a+b\,\mathrm {atanh}\left (c\,x^2\right )}{{\left (d\,x\right )}^{5/2}} \,d x \] Input:

int((a + b*atanh(c*x^2))/(d*x)^(5/2),x)
 

Output:

int((a + b*atanh(c*x^2))/(d*x)^(5/2), x)
 

Reduce [B] (verification not implemented)

Time = 0.18 (sec) , antiderivative size = 254, normalized size of antiderivative = 1.05 \[ \int \frac {a+b \text {arctanh}\left (c x^2\right )}{(d x)^{5/2}} \, dx=\frac {\sqrt {d}\, \left (-2 \sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathit {atan} \left (\frac {c^{\frac {1}{4}} \sqrt {2}-2 \sqrt {x}\, \sqrt {c}}{c^{\frac {1}{4}} \sqrt {2}}\right ) b x +2 \sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathit {atan} \left (\frac {c^{\frac {1}{4}} \sqrt {2}+2 \sqrt {x}\, \sqrt {c}}{c^{\frac {1}{4}} \sqrt {2}}\right ) b x +4 \sqrt {x}\, c^{\frac {3}{4}} \mathit {atan} \left (\frac {\sqrt {x}\, \sqrt {c}}{c^{\frac {1}{4}}}\right ) b x +2 \sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathit {atanh} \left (c \,x^{2}\right ) b x -4 \mathit {atanh} \left (c \,x^{2}\right ) b +\sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathrm {log}\left (c^{\frac {1}{4}}+\sqrt {x}\, \sqrt {c}\right ) b x +\sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathrm {log}\left (-c^{\frac {1}{4}}+\sqrt {x}\, \sqrt {c}\right ) b x -2 \sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathrm {log}\left (-\sqrt {x}\, c^{\frac {1}{4}} \sqrt {2}+\sqrt {c}\, x +1\right ) b x +\sqrt {x}\, c^{\frac {3}{4}} \sqrt {2}\, \mathrm {log}\left (\sqrt {c}\, x +1\right ) b x +2 \sqrt {x}\, c^{\frac {3}{4}} \mathrm {log}\left (c^{\frac {1}{4}}+\sqrt {x}\, \sqrt {c}\right ) b x -2 \sqrt {x}\, c^{\frac {3}{4}} \mathrm {log}\left (-c^{\frac {1}{4}}+\sqrt {x}\, \sqrt {c}\right ) b x -4 a \right )}{6 \sqrt {x}\, d^{3} x} \] Input:

int((a+b*atanh(c*x^2))/(d*x)^(5/2),x)
 

Output:

(sqrt(d)*( - 2*sqrt(x)*c**(3/4)*sqrt(2)*atan((c**(1/4)*sqrt(2) - 2*sqrt(x) 
*sqrt(c))/(c**(1/4)*sqrt(2)))*b*x + 2*sqrt(x)*c**(3/4)*sqrt(2)*atan((c**(1 
/4)*sqrt(2) + 2*sqrt(x)*sqrt(c))/(c**(1/4)*sqrt(2)))*b*x + 4*sqrt(x)*c**(3 
/4)*atan((sqrt(x)*sqrt(c))/c**(1/4))*b*x + 2*sqrt(x)*c**(3/4)*sqrt(2)*atan 
h(c*x**2)*b*x - 4*atanh(c*x**2)*b + sqrt(x)*c**(3/4)*sqrt(2)*log(c**(1/4) 
+ sqrt(x)*sqrt(c))*b*x + sqrt(x)*c**(3/4)*sqrt(2)*log( - c**(1/4) + sqrt(x 
)*sqrt(c))*b*x - 2*sqrt(x)*c**(3/4)*sqrt(2)*log( - sqrt(x)*c**(1/4)*sqrt(2 
) + sqrt(c)*x + 1)*b*x + sqrt(x)*c**(3/4)*sqrt(2)*log(sqrt(c)*x + 1)*b*x + 
 2*sqrt(x)*c**(3/4)*log(c**(1/4) + sqrt(x)*sqrt(c))*b*x - 2*sqrt(x)*c**(3/ 
4)*log( - c**(1/4) + sqrt(x)*sqrt(c))*b*x - 4*a))/(6*sqrt(x)*d**3*x)