Integrand size = 20, antiderivative size = 72 \[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {1+a^2 x^2}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}+\frac {\text {Shi}(2 \text {arctanh}(a x))}{a^2} \] Output:
-1/2*x/a/(-a^2*x^2+1)/arctanh(a*x)^2-1/2*(a^2*x^2+1)/a^2/(-a^2*x^2+1)/arct anh(a*x)+Shi(2*arctanh(a*x))/a^2
Time = 0.06 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.92 \[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\frac {a x+\left (1+a^2 x^2\right ) \text {arctanh}(a x)+2 \left (-1+a^2 x^2\right ) \text {arctanh}(a x)^2 \text {Shi}(2 \text {arctanh}(a x))}{2 a^2 \left (-1+a^2 x^2\right ) \text {arctanh}(a x)^2} \] Input:
Integrate[x/((1 - a^2*x^2)^2*ArcTanh[a*x]^3),x]
Output:
(a*x + (1 + a^2*x^2)*ArcTanh[a*x] + 2*(-1 + a^2*x^2)*ArcTanh[a*x]^2*SinhIn tegral[2*ArcTanh[a*x]])/(2*a^2*(-1 + a^2*x^2)*ArcTanh[a*x]^2)
Time = 0.52 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.350, Rules used = {6558, 6596, 5971, 27, 3042, 26, 3779}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx\) |
\(\Big \downarrow \) 6558 |
\(\displaystyle 2 \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)}dx-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 6596 |
\(\displaystyle \frac {2 \int \frac {a x}{\left (1-a^2 x^2\right ) \text {arctanh}(a x)}d\text {arctanh}(a x)}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 5971 |
\(\displaystyle \frac {2 \int \frac {\sinh (2 \text {arctanh}(a x))}{2 \text {arctanh}(a x)}d\text {arctanh}(a x)}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {\int \frac {\sinh (2 \text {arctanh}(a x))}{\text {arctanh}(a x)}d\text {arctanh}(a x)}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\int -\frac {i \sin (2 i \text {arctanh}(a x))}{\text {arctanh}(a x)}d\text {arctanh}(a x)}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 26 |
\(\displaystyle -\frac {i \int \frac {\sin (2 i \text {arctanh}(a x))}{\text {arctanh}(a x)}d\text {arctanh}(a x)}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
\(\Big \downarrow \) 3779 |
\(\displaystyle \frac {\text {Shi}(2 \text {arctanh}(a x))}{a^2}-\frac {x}{2 a \left (1-a^2 x^2\right ) \text {arctanh}(a x)^2}-\frac {a^2 x^2+1}{2 a^2 \left (1-a^2 x^2\right ) \text {arctanh}(a x)}\) |
Input:
Int[x/((1 - a^2*x^2)^2*ArcTanh[a*x]^3),x]
Output:
-1/2*x/(a*(1 - a^2*x^2)*ArcTanh[a*x]^2) - (1 + a^2*x^2)/(2*a^2*(1 - a^2*x^ 2)*ArcTanh[a*x]) + SinhIntegral[2*ArcTanh[a*x]]/a^2
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a]) I nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[sin[(e_.) + (Complex[0, fz_])*(f_.)*(x_)]/((c_.) + (d_.)*(x_)), x_Symbo l] :> Simp[I*(SinhIntegral[c*f*(fz/d) + f*fz*x]/d), x] /; FreeQ[{c, d, e, f , fz}, x] && EqQ[d*e - c*f*fz*I, 0]
Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sinh[a + b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] & & IGtQ[p, 0]
Int[(((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_)*(x_))/((d_) + (e_.)*(x_)^2)^2 , x_Symbol] :> Simp[x*((a + b*ArcTanh[c*x])^(p + 1)/(b*c*d*(p + 1)*(d + e*x ^2))), x] + (Simp[(1 + c^2*x^2)*((a + b*ArcTanh[c*x])^(p + 2)/(b^2*e*(p + 1 )*(p + 2)*(d + e*x^2))), x] + Simp[4/(b^2*(p + 1)*(p + 2)) Int[x*((a + b* ArcTanh[c*x])^(p + 2)/(d + e*x^2)^2), x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && LtQ[p, -1] && NeQ[p, -2]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_) ^2)^(q_), x_Symbol] :> Simp[d^q/c^(m + 1) Subst[Int[(a + b*x)^p*(Sinh[x]^ m/Cosh[x]^(m + 2*(q + 1))), x], x, ArcTanh[c*x]], x] /; FreeQ[{a, b, c, d, e, p}, x] && EqQ[c^2*d + e, 0] && IGtQ[m, 0] && ILtQ[m + 2*q + 1, 0] && (In tegerQ[q] || GtQ[d, 0])
Time = 1.50 (sec) , antiderivative size = 43, normalized size of antiderivative = 0.60
method | result | size |
derivativedivides | \(\frac {-\frac {\sinh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{4 \operatorname {arctanh}\left (a x \right )^{2}}-\frac {\cosh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{2 \,\operatorname {arctanh}\left (a x \right )}+\operatorname {Shi}\left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{a^{2}}\) | \(43\) |
default | \(\frac {-\frac {\sinh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{4 \operatorname {arctanh}\left (a x \right )^{2}}-\frac {\cosh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{2 \,\operatorname {arctanh}\left (a x \right )}+\operatorname {Shi}\left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{a^{2}}\) | \(43\) |
Input:
int(x/(-a^2*x^2+1)^2/arctanh(a*x)^3,x,method=_RETURNVERBOSE)
Output:
1/a^2*(-1/4/arctanh(a*x)^2*sinh(2*arctanh(a*x))-1/2/arctanh(a*x)*cosh(2*ar ctanh(a*x))+Shi(2*arctanh(a*x)))
Leaf count of result is larger than twice the leaf count of optimal. 135 vs. \(2 (66) = 132\).
Time = 0.08 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.88 \[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\frac {{\left ({\left (a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a x + 1}{a x - 1}\right ) - {\left (a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a x - 1}{a x + 1}\right )\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2} + 4 \, a x + 2 \, {\left (a^{2} x^{2} + 1\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )}{2 \, {\left (a^{4} x^{2} - a^{2}\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2}} \] Input:
integrate(x/(-a^2*x^2+1)^2/arctanh(a*x)^3,x, algorithm="fricas")
Output:
1/2*(((a^2*x^2 - 1)*log_integral(-(a*x + 1)/(a*x - 1)) - (a^2*x^2 - 1)*log _integral(-(a*x - 1)/(a*x + 1)))*log(-(a*x + 1)/(a*x - 1))^2 + 4*a*x + 2*( a^2*x^2 + 1)*log(-(a*x + 1)/(a*x - 1)))/((a^4*x^2 - a^2)*log(-(a*x + 1)/(a *x - 1))^2)
\[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\int \frac {x}{\left (a x - 1\right )^{2} \left (a x + 1\right )^{2} \operatorname {atanh}^{3}{\left (a x \right )}}\, dx \] Input:
integrate(x/(-a**2*x**2+1)**2/atanh(a*x)**3,x)
Output:
Integral(x/((a*x - 1)**2*(a*x + 1)**2*atanh(a*x)**3), x)
\[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\int { \frac {x}{{\left (a^{2} x^{2} - 1\right )}^{2} \operatorname {artanh}\left (a x\right )^{3}} \,d x } \] Input:
integrate(x/(-a^2*x^2+1)^2/arctanh(a*x)^3,x, algorithm="maxima")
Output:
(2*a*x + (a^2*x^2 + 1)*log(a*x + 1) - (a^2*x^2 + 1)*log(-a*x + 1))/((a^4*x ^2 - a^2)*log(a*x + 1)^2 - 2*(a^4*x^2 - a^2)*log(a*x + 1)*log(-a*x + 1) + (a^4*x^2 - a^2)*log(-a*x + 1)^2) - 4*integrate(-x/((a^4*x^4 - 2*a^2*x^2 + 1)*log(a*x + 1) - (a^4*x^4 - 2*a^2*x^2 + 1)*log(-a*x + 1)), x)
\[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\int { \frac {x}{{\left (a^{2} x^{2} - 1\right )}^{2} \operatorname {artanh}\left (a x\right )^{3}} \,d x } \] Input:
integrate(x/(-a^2*x^2+1)^2/arctanh(a*x)^3,x, algorithm="giac")
Output:
integrate(x/((a^2*x^2 - 1)^2*arctanh(a*x)^3), x)
Timed out. \[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\int \frac {x}{{\mathrm {atanh}\left (a\,x\right )}^3\,{\left (a^2\,x^2-1\right )}^2} \,d x \] Input:
int(x/(atanh(a*x)^3*(a^2*x^2 - 1)^2),x)
Output:
int(x/(atanh(a*x)^3*(a^2*x^2 - 1)^2), x)
\[ \int \frac {x}{\left (1-a^2 x^2\right )^2 \text {arctanh}(a x)^3} \, dx=\frac {2 \mathit {atanh} \left (a x \right )^{2} \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{4} x^{4}-2 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a^{3} x^{2}-2 \mathit {atanh} \left (a x \right )^{2} \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{4} x^{4}-2 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a +\mathit {atanh} \left (a x \right )^{2} \left (\int \frac {1}{\mathit {atanh} \left (a x \right )^{2} a^{4} x^{4}-2 \mathit {atanh} \left (a x \right )^{2} a^{2} x^{2}+\mathit {atanh} \left (a x \right )^{2}}d x \right ) a^{2} x^{2}-\mathit {atanh} \left (a x \right )^{2} \left (\int \frac {1}{\mathit {atanh} \left (a x \right )^{2} a^{4} x^{4}-2 \mathit {atanh} \left (a x \right )^{2} a^{2} x^{2}+\mathit {atanh} \left (a x \right )^{2}}d x \right )+\mathit {atanh} \left (a x \right ) a \,x^{2}+x}{2 \mathit {atanh} \left (a x \right )^{2} a \left (a^{2} x^{2}-1\right )} \] Input:
int(x/(-a^2*x^2+1)^2/atanh(a*x)^3,x)
Output:
(2*atanh(a*x)**2*int(x/(atanh(a*x)*a**4*x**4 - 2*atanh(a*x)*a**2*x**2 + at anh(a*x)),x)*a**3*x**2 - 2*atanh(a*x)**2*int(x/(atanh(a*x)*a**4*x**4 - 2*a tanh(a*x)*a**2*x**2 + atanh(a*x)),x)*a + atanh(a*x)**2*int(1/(atanh(a*x)** 2*a**4*x**4 - 2*atanh(a*x)**2*a**2*x**2 + atanh(a*x)**2),x)*a**2*x**2 - at anh(a*x)**2*int(1/(atanh(a*x)**2*a**4*x**4 - 2*atanh(a*x)**2*a**2*x**2 + a tanh(a*x)**2),x) + atanh(a*x)*a*x**2 + x)/(2*atanh(a*x)**2*a*(a**2*x**2 - 1))