\(\int \frac {1}{(1-a^2 x^2)^4 \text {arctanh}(a x)^2} \, dx\) [361]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [B] (verification not implemented)
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 19, antiderivative size = 66 \[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=-\frac {1}{a \left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}+\frac {15 \text {Shi}(2 \text {arctanh}(a x))}{16 a}+\frac {3 \text {Shi}(4 \text {arctanh}(a x))}{4 a}+\frac {3 \text {Shi}(6 \text {arctanh}(a x))}{16 a} \] Output:

-1/a/(-a^2*x^2+1)^3/arctanh(a*x)+15/16*Shi(2*arctanh(a*x))/a+3/4*Shi(4*arc 
tanh(a*x))/a+3/16*Shi(6*arctanh(a*x))/a
 

Mathematica [A] (verified)

Time = 0.25 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.85 \[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\frac {\frac {1}{\left (-1+a^2 x^2\right )^3 \text {arctanh}(a x)}+\frac {15}{16} \text {Shi}(2 \text {arctanh}(a x))+\frac {3}{4} \text {Shi}(4 \text {arctanh}(a x))+\frac {3}{16} \text {Shi}(6 \text {arctanh}(a x))}{a} \] Input:

Integrate[1/((1 - a^2*x^2)^4*ArcTanh[a*x]^2),x]
 

Output:

(1/((-1 + a^2*x^2)^3*ArcTanh[a*x]) + (15*SinhIntegral[2*ArcTanh[a*x]])/16 
+ (3*SinhIntegral[4*ArcTanh[a*x]])/4 + (3*SinhIntegral[6*ArcTanh[a*x]])/16 
)/a
 

Rubi [A] (verified)

Time = 0.44 (sec) , antiderivative size = 63, normalized size of antiderivative = 0.95, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.211, Rules used = {6528, 6596, 5971, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx\)

\(\Big \downarrow \) 6528

\(\displaystyle 6 a \int \frac {x}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)}dx-\frac {1}{a \left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}\)

\(\Big \downarrow \) 6596

\(\displaystyle \frac {6 \int \frac {a x}{\left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}d\text {arctanh}(a x)}{a}-\frac {1}{a \left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}\)

\(\Big \downarrow \) 5971

\(\displaystyle \frac {6 \int \left (\frac {5 \sinh (2 \text {arctanh}(a x))}{32 \text {arctanh}(a x)}+\frac {\sinh (4 \text {arctanh}(a x))}{8 \text {arctanh}(a x)}+\frac {\sinh (6 \text {arctanh}(a x))}{32 \text {arctanh}(a x)}\right )d\text {arctanh}(a x)}{a}-\frac {1}{a \left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {6 \left (\frac {5}{32} \text {Shi}(2 \text {arctanh}(a x))+\frac {1}{8} \text {Shi}(4 \text {arctanh}(a x))+\frac {1}{32} \text {Shi}(6 \text {arctanh}(a x))\right )}{a}-\frac {1}{a \left (1-a^2 x^2\right )^3 \text {arctanh}(a x)}\)

Input:

Int[1/((1 - a^2*x^2)^4*ArcTanh[a*x]^2),x]
 

Output:

-(1/(a*(1 - a^2*x^2)^3*ArcTanh[a*x])) + (6*((5*SinhIntegral[2*ArcTanh[a*x] 
])/32 + SinhIntegral[4*ArcTanh[a*x]]/8 + SinhIntegral[6*ArcTanh[a*x]]/32)) 
/a
 

Defintions of rubi rules used

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 5971
Int[Cosh[(a_.) + (b_.)*(x_)]^(p_.)*((c_.) + (d_.)*(x_))^(m_.)*Sinh[(a_.) + 
(b_.)*(x_)]^(n_.), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sinh[a + 
b*x]^n*Cosh[a + b*x]^p, x], x] /; FreeQ[{a, b, c, d, m}, x] && IGtQ[n, 0] & 
& IGtQ[p, 0]
 

rule 6528
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_)^2)^(q_), x_ 
Symbol] :> Simp[(d + e*x^2)^(q + 1)*((a + b*ArcTanh[c*x])^(p + 1)/(b*c*d*(p 
 + 1))), x] + Simp[2*c*((q + 1)/(b*(p + 1)))   Int[x*(d + e*x^2)^q*(a + b*A 
rcTanh[c*x])^(p + 1), x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 
 0] && LtQ[q, -1] && LtQ[p, -1]
 

rule 6596
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_.)*((d_) + (e_.)*(x_) 
^2)^(q_), x_Symbol] :> Simp[d^q/c^(m + 1)   Subst[Int[(a + b*x)^p*(Sinh[x]^ 
m/Cosh[x]^(m + 2*(q + 1))), x], x, ArcTanh[c*x]], x] /; FreeQ[{a, b, c, d, 
e, p}, x] && EqQ[c^2*d + e, 0] && IGtQ[m, 0] && ILtQ[m + 2*q + 1, 0] && (In 
tegerQ[q] || GtQ[d, 0])
 
Maple [A] (verified)

Time = 1.71 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.30

method result size
derivativedivides \(\frac {-\frac {5}{16 \,\operatorname {arctanh}\left (a x \right )}-\frac {15 \cosh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{32 \,\operatorname {arctanh}\left (a x \right )}+\frac {15 \,\operatorname {Shi}\left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{16}-\frac {3 \cosh \left (4 \,\operatorname {arctanh}\left (a x \right )\right )}{16 \,\operatorname {arctanh}\left (a x \right )}+\frac {3 \,\operatorname {Shi}\left (4 \,\operatorname {arctanh}\left (a x \right )\right )}{4}-\frac {\cosh \left (6 \,\operatorname {arctanh}\left (a x \right )\right )}{32 \,\operatorname {arctanh}\left (a x \right )}+\frac {3 \,\operatorname {Shi}\left (6 \,\operatorname {arctanh}\left (a x \right )\right )}{16}}{a}\) \(86\)
default \(\frac {-\frac {5}{16 \,\operatorname {arctanh}\left (a x \right )}-\frac {15 \cosh \left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{32 \,\operatorname {arctanh}\left (a x \right )}+\frac {15 \,\operatorname {Shi}\left (2 \,\operatorname {arctanh}\left (a x \right )\right )}{16}-\frac {3 \cosh \left (4 \,\operatorname {arctanh}\left (a x \right )\right )}{16 \,\operatorname {arctanh}\left (a x \right )}+\frac {3 \,\operatorname {Shi}\left (4 \,\operatorname {arctanh}\left (a x \right )\right )}{4}-\frac {\cosh \left (6 \,\operatorname {arctanh}\left (a x \right )\right )}{32 \,\operatorname {arctanh}\left (a x \right )}+\frac {3 \,\operatorname {Shi}\left (6 \,\operatorname {arctanh}\left (a x \right )\right )}{16}}{a}\) \(86\)

Input:

int(1/(-a^2*x^2+1)^4/arctanh(a*x)^2,x,method=_RETURNVERBOSE)
 

Output:

1/a*(-5/16/arctanh(a*x)-15/32/arctanh(a*x)*cosh(2*arctanh(a*x))+15/16*Shi( 
2*arctanh(a*x))-3/16/arctanh(a*x)*cosh(4*arctanh(a*x))+3/4*Shi(4*arctanh(a 
*x))-1/32/arctanh(a*x)*cosh(6*arctanh(a*x))+3/16*Shi(6*arctanh(a*x)))
 

Fricas [B] (verification not implemented)

Leaf count of result is larger than twice the leaf count of optimal. 413 vs. \(2 (58) = 116\).

Time = 0.09 (sec) , antiderivative size = 413, normalized size of antiderivative = 6.26 \[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\frac {3 \, {\left ({\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a^{3} x^{3} + 3 \, a^{2} x^{2} + 3 \, a x + 1}{a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1}\right ) - {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a^{3} x^{3} - 3 \, a^{2} x^{2} + 3 \, a x - 1}{a^{3} x^{3} + 3 \, a^{2} x^{2} + 3 \, a x + 1}\right ) + 4 \, {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (\frac {a^{2} x^{2} + 2 \, a x + 1}{a^{2} x^{2} - 2 \, a x + 1}\right ) - 4 \, {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (\frac {a^{2} x^{2} - 2 \, a x + 1}{a^{2} x^{2} + 2 \, a x + 1}\right ) + 5 \, {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a x + 1}{a x - 1}\right ) - 5 \, {\left (a^{6} x^{6} - 3 \, a^{4} x^{4} + 3 \, a^{2} x^{2} - 1\right )} \operatorname {log\_integral}\left (-\frac {a x - 1}{a x + 1}\right )\right )} \log \left (-\frac {a x + 1}{a x - 1}\right ) + 64}{32 \, {\left (a^{7} x^{6} - 3 \, a^{5} x^{4} + 3 \, a^{3} x^{2} - a\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )} \] Input:

integrate(1/(-a^2*x^2+1)^4/arctanh(a*x)^2,x, algorithm="fricas")
 

Output:

1/32*(3*((a^6*x^6 - 3*a^4*x^4 + 3*a^2*x^2 - 1)*log_integral(-(a^3*x^3 + 3* 
a^2*x^2 + 3*a*x + 1)/(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)) - (a^6*x^6 - 3*a^4 
*x^4 + 3*a^2*x^2 - 1)*log_integral(-(a^3*x^3 - 3*a^2*x^2 + 3*a*x - 1)/(a^3 
*x^3 + 3*a^2*x^2 + 3*a*x + 1)) + 4*(a^6*x^6 - 3*a^4*x^4 + 3*a^2*x^2 - 1)*l 
og_integral((a^2*x^2 + 2*a*x + 1)/(a^2*x^2 - 2*a*x + 1)) - 4*(a^6*x^6 - 3* 
a^4*x^4 + 3*a^2*x^2 - 1)*log_integral((a^2*x^2 - 2*a*x + 1)/(a^2*x^2 + 2*a 
*x + 1)) + 5*(a^6*x^6 - 3*a^4*x^4 + 3*a^2*x^2 - 1)*log_integral(-(a*x + 1) 
/(a*x - 1)) - 5*(a^6*x^6 - 3*a^4*x^4 + 3*a^2*x^2 - 1)*log_integral(-(a*x - 
 1)/(a*x + 1)))*log(-(a*x + 1)/(a*x - 1)) + 64)/((a^7*x^6 - 3*a^5*x^4 + 3* 
a^3*x^2 - a)*log(-(a*x + 1)/(a*x - 1)))
 

Sympy [F]

\[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\int \frac {1}{\left (a x - 1\right )^{4} \left (a x + 1\right )^{4} \operatorname {atanh}^{2}{\left (a x \right )}}\, dx \] Input:

integrate(1/(-a**2*x**2+1)**4/atanh(a*x)**2,x)
 

Output:

Integral(1/((a*x - 1)**4*(a*x + 1)**4*atanh(a*x)**2), x)
 

Maxima [F]

\[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} x^{2} - 1\right )}^{4} \operatorname {artanh}\left (a x\right )^{2}} \,d x } \] Input:

integrate(1/(-a^2*x^2+1)^4/arctanh(a*x)^2,x, algorithm="maxima")
 

Output:

-12*a*integrate(-x/((a^8*x^8 - 4*a^6*x^6 + 6*a^4*x^4 - 4*a^2*x^2 + 1)*log( 
a*x + 1) - (a^8*x^8 - 4*a^6*x^6 + 6*a^4*x^4 - 4*a^2*x^2 + 1)*log(-a*x + 1) 
), x) + 2/((a^7*x^6 - 3*a^5*x^4 + 3*a^3*x^2 - a)*log(a*x + 1) - (a^7*x^6 - 
 3*a^5*x^4 + 3*a^3*x^2 - a)*log(-a*x + 1))
 

Giac [F]

\[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\int { \frac {1}{{\left (a^{2} x^{2} - 1\right )}^{4} \operatorname {artanh}\left (a x\right )^{2}} \,d x } \] Input:

integrate(1/(-a^2*x^2+1)^4/arctanh(a*x)^2,x, algorithm="giac")
 

Output:

integrate(1/((a^2*x^2 - 1)^4*arctanh(a*x)^2), x)
 

Mupad [F(-1)]

Timed out. \[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\int \frac {1}{{\mathrm {atanh}\left (a\,x\right )}^2\,{\left (a^2\,x^2-1\right )}^4} \,d x \] Input:

int(1/(atanh(a*x)^2*(a^2*x^2 - 1)^4),x)
 

Output:

int(1/(atanh(a*x)^2*(a^2*x^2 - 1)^4), x)
 

Reduce [F]

\[ \int \frac {1}{\left (1-a^2 x^2\right )^4 \text {arctanh}(a x)^2} \, dx=\frac {6 \mathit {atanh} \left (a x \right ) \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{8} x^{8}-4 \mathit {atanh} \left (a x \right ) a^{6} x^{6}+6 \mathit {atanh} \left (a x \right ) a^{4} x^{4}-4 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a^{8} x^{6}-18 \mathit {atanh} \left (a x \right ) \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{8} x^{8}-4 \mathit {atanh} \left (a x \right ) a^{6} x^{6}+6 \mathit {atanh} \left (a x \right ) a^{4} x^{4}-4 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a^{6} x^{4}+18 \mathit {atanh} \left (a x \right ) \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{8} x^{8}-4 \mathit {atanh} \left (a x \right ) a^{6} x^{6}+6 \mathit {atanh} \left (a x \right ) a^{4} x^{4}-4 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a^{4} x^{2}-6 \mathit {atanh} \left (a x \right ) \left (\int \frac {x}{\mathit {atanh} \left (a x \right ) a^{8} x^{8}-4 \mathit {atanh} \left (a x \right ) a^{6} x^{6}+6 \mathit {atanh} \left (a x \right ) a^{4} x^{4}-4 \mathit {atanh} \left (a x \right ) a^{2} x^{2}+\mathit {atanh} \left (a x \right )}d x \right ) a^{2}+1}{\mathit {atanh} \left (a x \right ) a \left (a^{6} x^{6}-3 a^{4} x^{4}+3 a^{2} x^{2}-1\right )} \] Input:

int(1/(-a^2*x^2+1)^4/atanh(a*x)^2,x)
                                                                                    
                                                                                    
 

Output:

(6*atanh(a*x)*int(x/(atanh(a*x)*a**8*x**8 - 4*atanh(a*x)*a**6*x**6 + 6*ata 
nh(a*x)*a**4*x**4 - 4*atanh(a*x)*a**2*x**2 + atanh(a*x)),x)*a**8*x**6 - 18 
*atanh(a*x)*int(x/(atanh(a*x)*a**8*x**8 - 4*atanh(a*x)*a**6*x**6 + 6*atanh 
(a*x)*a**4*x**4 - 4*atanh(a*x)*a**2*x**2 + atanh(a*x)),x)*a**6*x**4 + 18*a 
tanh(a*x)*int(x/(atanh(a*x)*a**8*x**8 - 4*atanh(a*x)*a**6*x**6 + 6*atanh(a 
*x)*a**4*x**4 - 4*atanh(a*x)*a**2*x**2 + atanh(a*x)),x)*a**4*x**2 - 6*atan 
h(a*x)*int(x/(atanh(a*x)*a**8*x**8 - 4*atanh(a*x)*a**6*x**6 + 6*atanh(a*x) 
*a**4*x**4 - 4*atanh(a*x)*a**2*x**2 + atanh(a*x)),x)*a**2 + 1)/(atanh(a*x) 
*a*(a**6*x**6 - 3*a**4*x**4 + 3*a**2*x**2 - 1))