Integrand size = 24, antiderivative size = 220 \[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=-\frac {6 x}{a^3 \sqrt {1-a^2 x^2}}+\frac {6 \text {arctanh}(a x)}{a^4 \sqrt {1-a^2 x^2}}-\frac {3 x \text {arctanh}(a x)^2}{a^3 \sqrt {1-a^2 x^2}}-\frac {6 \arctan \left (e^{\text {arctanh}(a x)}\right ) \text {arctanh}(a x)^2}{a^4}+\frac {\text {arctanh}(a x)^3}{a^4 \sqrt {1-a^2 x^2}}+\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^4}+\frac {6 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )}{a^4}-\frac {6 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )}{a^4}-\frac {6 i \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )}{a^4}+\frac {6 i \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )}{a^4} \] Output:
-6*x/a^3/(-a^2*x^2+1)^(1/2)+6*arctanh(a*x)/a^4/(-a^2*x^2+1)^(1/2)-3*x*arct anh(a*x)^2/a^3/(-a^2*x^2+1)^(1/2)-6*arctan((a*x+1)/(-a^2*x^2+1)^(1/2))*arc tanh(a*x)^2/a^4+arctanh(a*x)^3/a^4/(-a^2*x^2+1)^(1/2)+(-a^2*x^2+1)^(1/2)*a rctanh(a*x)^3/a^4+6*I*arctanh(a*x)*polylog(2,-I*(a*x+1)/(-a^2*x^2+1)^(1/2) )/a^4-6*I*arctanh(a*x)*polylog(2,I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a^4-6*I*pol ylog(3,-I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a^4+6*I*polylog(3,I*(a*x+1)/(-a^2*x^ 2+1)^(1/2))/a^4
Time = 0.35 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.13 \[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\frac {6 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{-\text {arctanh}(a x)}\right )-6 i \text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{-\text {arctanh}(a x)}\right )+\frac {-6 a x+6 \text {arctanh}(a x)-3 a x \text {arctanh}(a x)^2+2 \text {arctanh}(a x)^3-a^2 x^2 \text {arctanh}(a x)^3+3 i \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2 \log \left (1-i e^{-\text {arctanh}(a x)}\right )-3 i \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2 \log \left (1+i e^{-\text {arctanh}(a x)}\right )+6 i \sqrt {1-a^2 x^2} \operatorname {PolyLog}\left (3,-i e^{-\text {arctanh}(a x)}\right )-6 i \sqrt {1-a^2 x^2} \operatorname {PolyLog}\left (3,i e^{-\text {arctanh}(a x)}\right )}{\sqrt {1-a^2 x^2}}}{a^4} \] Input:
Integrate[(x^3*ArcTanh[a*x]^3)/(1 - a^2*x^2)^(3/2),x]
Output:
((6*I)*ArcTanh[a*x]*PolyLog[2, (-I)/E^ArcTanh[a*x]] - (6*I)*ArcTanh[a*x]*P olyLog[2, I/E^ArcTanh[a*x]] + (-6*a*x + 6*ArcTanh[a*x] - 3*a*x*ArcTanh[a*x ]^2 + 2*ArcTanh[a*x]^3 - a^2*x^2*ArcTanh[a*x]^3 + (3*I)*Sqrt[1 - a^2*x^2]* ArcTanh[a*x]^2*Log[1 - I/E^ArcTanh[a*x]] - (3*I)*Sqrt[1 - a^2*x^2]*ArcTanh [a*x]^2*Log[1 + I/E^ArcTanh[a*x]] + (6*I)*Sqrt[1 - a^2*x^2]*PolyLog[3, (-I )/E^ArcTanh[a*x]] - (6*I)*Sqrt[1 - a^2*x^2]*PolyLog[3, I/E^ArcTanh[a*x]])/ Sqrt[1 - a^2*x^2])/a^4
Time = 1.39 (sec) , antiderivative size = 220, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {6590, 6556, 6514, 3042, 4668, 3011, 2720, 6524, 208, 7143}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx\) |
\(\Big \downarrow \) 6590 |
\(\displaystyle \frac {\int \frac {x \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}}dx}{a^2}-\frac {\int \frac {x \text {arctanh}(a x)^3}{\sqrt {1-a^2 x^2}}dx}{a^2}\) |
\(\Big \downarrow \) 6556 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {\frac {3 \int \frac {\text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}}dx}{a}-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}}{a^2}\) |
\(\Big \downarrow \) 6514 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {\frac {3 \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2d\text {arctanh}(a x)}{a^2}-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}}{a^2}\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \int \text {arctanh}(a x)^2 \csc \left (i \text {arctanh}(a x)+\frac {\pi }{2}\right )d\text {arctanh}(a x)}{a^2}}{a^2}\) |
\(\Big \downarrow \) 4668 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (-2 i \int \text {arctanh}(a x) \log \left (1-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+2 i \int \text {arctanh}(a x) \log \left (1+i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )\right )}{a^2}}{a^2}\) |
\(\Big \downarrow \) 3011 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (2 i \left (\int \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )\right )}{a^2}}{a^2}\) |
\(\Big \downarrow \) 2720 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \int \frac {\text {arctanh}(a x)^2}{\left (1-a^2 x^2\right )^{3/2}}dx}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )\right )}{a^2}}{a^2}\) |
\(\Big \downarrow \) 6524 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \left (2 \int \frac {1}{\left (1-a^2 x^2\right )^{3/2}}dx+\frac {x \text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}}-\frac {2 \text {arctanh}(a x)}{a \sqrt {1-a^2 x^2}}\right )}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )\right )}{a^2}}{a^2}\) |
\(\Big \downarrow \) 208 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \left (\frac {x \text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}}-\frac {2 \text {arctanh}(a x)}{a \sqrt {1-a^2 x^2}}+\frac {2 x}{\sqrt {1-a^2 x^2}}\right )}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )\right )}{a^2}}{a^2}\) |
\(\Big \downarrow \) 7143 |
\(\displaystyle \frac {\frac {\text {arctanh}(a x)^3}{a^2 \sqrt {1-a^2 x^2}}-\frac {3 \left (\frac {x \text {arctanh}(a x)^2}{\sqrt {1-a^2 x^2}}-\frac {2 \text {arctanh}(a x)}{a \sqrt {1-a^2 x^2}}+\frac {2 x}{\sqrt {1-a^2 x^2}}\right )}{a}}{a^2}-\frac {-\frac {\sqrt {1-a^2 x^2} \text {arctanh}(a x)^3}{a^2}+\frac {3 \left (2 \text {arctanh}(a x)^2 \arctan \left (e^{\text {arctanh}(a x)}\right )+2 i \left (\operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-2 i \left (\operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )\right )}{a^2}}{a^2}\) |
Input:
Int[(x^3*ArcTanh[a*x]^3)/(1 - a^2*x^2)^(3/2),x]
Output:
(ArcTanh[a*x]^3/(a^2*Sqrt[1 - a^2*x^2]) - (3*((2*x)/Sqrt[1 - a^2*x^2] - (2 *ArcTanh[a*x])/(a*Sqrt[1 - a^2*x^2]) + (x*ArcTanh[a*x]^2)/Sqrt[1 - a^2*x^2 ]))/a)/a^2 - (-((Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^3)/a^2) + (3*(2*ArcTan[E^A rcTanh[a*x]]*ArcTanh[a*x]^2 + (2*I)*(-(ArcTanh[a*x]*PolyLog[2, (-I)*E^ArcT anh[a*x]]) + PolyLog[3, (-I)*E^ArcTanh[a*x]]) - (2*I)*(-(ArcTanh[a*x]*Poly Log[2, I*E^ArcTanh[a*x]]) + PolyLog[3, I*E^ArcTanh[a*x]])))/a^2)/a^2
Int[((a_) + (b_.)*(x_)^2)^(-3/2), x_Symbol] :> Simp[x/(a*Sqrt[a + b*x^2]), x] /; FreeQ[{a, b}, x]
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct ionOfExponentialQ[u, x] && !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ [{a, m, n}, x] && IntegerQ[m*n]] && !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) *(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) *(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F])) Int[(f + g*x)^( m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e , f, g, n}, x] && GtQ[m, 0]
Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_ ))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^( I*k*Pi)]/(f*fz*I)), x] + (-Simp[d*(m/(f*fz*I)) Int[(c + d*x)^(m - 1)*Log[ 1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Simp[d*(m/(f*fz*I)) Int[(c + d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c , d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_ Symbol] :> Simp[1/(c*Sqrt[d]) Subst[Int[(a + b*x)^p*Sech[x], x], x, ArcTa nh[c*x]], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0 ] && GtQ[d, 0]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_)/((d_) + (e_.)*(x_)^2)^(3/2), x _Symbol] :> Simp[(-b)*p*((a + b*ArcTanh[c*x])^(p - 1)/(c*d*Sqrt[d + e*x^2]) ), x] + (Simp[x*((a + b*ArcTanh[c*x])^p/(d*Sqrt[d + e*x^2])), x] + Simp[b^2 *p*(p - 1) Int[(a + b*ArcTanh[c*x])^(p - 2)/(d + e*x^2)^(3/2), x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && GtQ[p, 1]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_)*((d_) + (e_.)*(x_)^2)^(q _.), x_Symbol] :> Simp[(d + e*x^2)^(q + 1)*((a + b*ArcTanh[c*x])^p/(2*e*(q + 1))), x] + Simp[b*(p/(2*c*(q + 1))) Int[(d + e*x^2)^q*(a + b*ArcTanh[c* x])^(p - 1), x], x] /; FreeQ[{a, b, c, d, e, q}, x] && EqQ[c^2*d + e, 0] && GtQ[p, 0] && NeQ[q, -1]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)*(x_)^(m_)*((d_) + (e_.)*(x_)^ 2)^(q_), x_Symbol] :> Simp[1/e Int[x^(m - 2)*(d + e*x^2)^(q + 1)*(a + b*A rcTanh[c*x])^p, x], x] - Simp[d/e Int[x^(m - 2)*(d + e*x^2)^q*(a + b*ArcT anh[c*x])^p, x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && In tegersQ[p, 2*q] && LtQ[q, -1] && IGtQ[m, 1] && NeQ[p, -1]
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d , e, n, p}, x] && EqQ[b*d, a*e]
\[\int \frac {x^{3} \operatorname {arctanh}\left (a x \right )^{3}}{\left (-a^{2} x^{2}+1\right )^{\frac {3}{2}}}d x\]
Input:
int(x^3*arctanh(a*x)^3/(-a^2*x^2+1)^(3/2),x)
Output:
int(x^3*arctanh(a*x)^3/(-a^2*x^2+1)^(3/2),x)
\[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\int { \frac {x^{3} \operatorname {artanh}\left (a x\right )^{3}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(x^3*arctanh(a*x)^3/(-a^2*x^2+1)^(3/2),x, algorithm="fricas")
Output:
integral(sqrt(-a^2*x^2 + 1)*x^3*arctanh(a*x)^3/(a^4*x^4 - 2*a^2*x^2 + 1), x)
\[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\int \frac {x^{3} \operatorname {atanh}^{3}{\left (a x \right )}}{\left (- \left (a x - 1\right ) \left (a x + 1\right )\right )^{\frac {3}{2}}}\, dx \] Input:
integrate(x**3*atanh(a*x)**3/(-a**2*x**2+1)**(3/2),x)
Output:
Integral(x**3*atanh(a*x)**3/(-(a*x - 1)*(a*x + 1))**(3/2), x)
\[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\int { \frac {x^{3} \operatorname {artanh}\left (a x\right )^{3}}{{\left (-a^{2} x^{2} + 1\right )}^{\frac {3}{2}}} \,d x } \] Input:
integrate(x^3*arctanh(a*x)^3/(-a^2*x^2+1)^(3/2),x, algorithm="maxima")
Output:
integrate(x^3*arctanh(a*x)^3/(-a^2*x^2 + 1)^(3/2), x)
Exception generated. \[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\text {Exception raised: TypeError} \] Input:
integrate(x^3*arctanh(a*x)^3/(-a^2*x^2+1)^(3/2),x, algorithm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=\int \frac {x^3\,{\mathrm {atanh}\left (a\,x\right )}^3}{{\left (1-a^2\,x^2\right )}^{3/2}} \,d x \] Input:
int((x^3*atanh(a*x)^3)/(1 - a^2*x^2)^(3/2),x)
Output:
int((x^3*atanh(a*x)^3)/(1 - a^2*x^2)^(3/2), x)
\[ \int \frac {x^3 \text {arctanh}(a x)^3}{\left (1-a^2 x^2\right )^{3/2}} \, dx=-\left (\int \frac {\mathit {atanh} \left (a x \right )^{3} x^{3}}{\sqrt {-a^{2} x^{2}+1}\, a^{2} x^{2}-\sqrt {-a^{2} x^{2}+1}}d x \right ) \] Input:
int(x^3*atanh(a*x)^3/(-a^2*x^2+1)^(3/2),x)
Output:
- int((atanh(a*x)**3*x**3)/(sqrt( - a**2*x**2 + 1)*a**2*x**2 - sqrt( - a* *2*x**2 + 1)),x)