Integrand size = 21, antiderivative size = 302 \[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\frac {6 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {1+a x}}\right ) \text {arctanh}(a x)}{a}+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {\arctan \left (e^{\text {arctanh}(a x)}\right ) \text {arctanh}(a x)^3}{a}-\frac {3 i \text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {3 i \text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {3 i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {1+a x}}\right )}{a}-\frac {3 i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {1+a x}}\right )}{a}+\frac {3 i \text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )}{a}-\frac {3 i \text {arctanh}(a x) \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )}{a}-\frac {3 i \operatorname {PolyLog}\left (4,-i e^{\text {arctanh}(a x)}\right )}{a}+\frac {3 i \operatorname {PolyLog}\left (4,i e^{\text {arctanh}(a x)}\right )}{a} \] Output:
6*arctan((-a*x+1)^(1/2)/(a*x+1)^(1/2))*arctanh(a*x)/a+3/2*(-a^2*x^2+1)^(1/ 2)*arctanh(a*x)^2/a+1/2*x*(-a^2*x^2+1)^(1/2)*arctanh(a*x)^3+arctan((a*x+1) /(-a^2*x^2+1)^(1/2))*arctanh(a*x)^3/a-3/2*I*arctanh(a*x)^2*polylog(2,-I*(a *x+1)/(-a^2*x^2+1)^(1/2))/a+3/2*I*arctanh(a*x)^2*polylog(2,I*(a*x+1)/(-a^2 *x^2+1)^(1/2))/a+3*I*polylog(2,-I*(-a*x+1)^(1/2)/(a*x+1)^(1/2))/a-3*I*poly log(2,I*(-a*x+1)^(1/2)/(a*x+1)^(1/2))/a+3*I*arctanh(a*x)*polylog(3,-I*(a*x +1)/(-a^2*x^2+1)^(1/2))/a-3*I*arctanh(a*x)*polylog(3,I*(a*x+1)/(-a^2*x^2+1 )^(1/2))/a-3*I*polylog(4,-I*(a*x+1)/(-a^2*x^2+1)^(1/2))/a+3*I*polylog(4,I* (a*x+1)/(-a^2*x^2+1)^(1/2))/a
Time = 2.23 (sec) , antiderivative size = 569, normalized size of antiderivative = 1.88 \[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=-\frac {i \left (7 \pi ^4+8 i \pi ^3 \text {arctanh}(a x)+24 \pi ^2 \text {arctanh}(a x)^2+192 i \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2-32 i \pi \text {arctanh}(a x)^3+64 i a x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3-16 \text {arctanh}(a x)^4-384 \text {arctanh}(a x) \log \left (1-i e^{-\text {arctanh}(a x)}\right )+8 i \pi ^3 \log \left (1+i e^{-\text {arctanh}(a x)}\right )+384 \text {arctanh}(a x) \log \left (1+i e^{-\text {arctanh}(a x)}\right )+48 \pi ^2 \text {arctanh}(a x) \log \left (1+i e^{-\text {arctanh}(a x)}\right )-96 i \pi \text {arctanh}(a x)^2 \log \left (1+i e^{-\text {arctanh}(a x)}\right )-64 \text {arctanh}(a x)^3 \log \left (1+i e^{-\text {arctanh}(a x)}\right )-48 \pi ^2 \text {arctanh}(a x) \log \left (1-i e^{\text {arctanh}(a x)}\right )+96 i \pi \text {arctanh}(a x)^2 \log \left (1-i e^{\text {arctanh}(a x)}\right )-8 i \pi ^3 \log \left (1+i e^{\text {arctanh}(a x)}\right )+64 \text {arctanh}(a x)^3 \log \left (1+i e^{\text {arctanh}(a x)}\right )+8 i \pi ^3 \log \left (\tan \left (\frac {1}{4} (\pi +2 i \text {arctanh}(a x))\right )\right )-48 \left (8+\pi ^2-4 i \pi \text {arctanh}(a x)-4 \text {arctanh}(a x)^2\right ) \operatorname {PolyLog}\left (2,-i e^{-\text {arctanh}(a x)}\right )+384 \operatorname {PolyLog}\left (2,i e^{-\text {arctanh}(a x)}\right )+192 \text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )-48 \pi ^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )+192 i \pi \text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )+192 i \pi \operatorname {PolyLog}\left (3,-i e^{-\text {arctanh}(a x)}\right )+384 \text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{-\text {arctanh}(a x)}\right )-384 \text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-192 i \pi \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )+384 \operatorname {PolyLog}\left (4,-i e^{-\text {arctanh}(a x)}\right )+384 \operatorname {PolyLog}\left (4,-i e^{\text {arctanh}(a x)}\right )\right )}{128 a} \] Input:
Integrate[Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^3,x]
Output:
((-1/128*I)*(7*Pi^4 + (8*I)*Pi^3*ArcTanh[a*x] + 24*Pi^2*ArcTanh[a*x]^2 + ( 192*I)*Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^2 - (32*I)*Pi*ArcTanh[a*x]^3 + (64*I )*a*x*Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^3 - 16*ArcTanh[a*x]^4 - 384*ArcTanh[a *x]*Log[1 - I/E^ArcTanh[a*x]] + (8*I)*Pi^3*Log[1 + I/E^ArcTanh[a*x]] + 384 *ArcTanh[a*x]*Log[1 + I/E^ArcTanh[a*x]] + 48*Pi^2*ArcTanh[a*x]*Log[1 + I/E ^ArcTanh[a*x]] - (96*I)*Pi*ArcTanh[a*x]^2*Log[1 + I/E^ArcTanh[a*x]] - 64*A rcTanh[a*x]^3*Log[1 + I/E^ArcTanh[a*x]] - 48*Pi^2*ArcTanh[a*x]*Log[1 - I*E ^ArcTanh[a*x]] + (96*I)*Pi*ArcTanh[a*x]^2*Log[1 - I*E^ArcTanh[a*x]] - (8*I )*Pi^3*Log[1 + I*E^ArcTanh[a*x]] + 64*ArcTanh[a*x]^3*Log[1 + I*E^ArcTanh[a *x]] + (8*I)*Pi^3*Log[Tan[(Pi + (2*I)*ArcTanh[a*x])/4]] - 48*(8 + Pi^2 - ( 4*I)*Pi*ArcTanh[a*x] - 4*ArcTanh[a*x]^2)*PolyLog[2, (-I)/E^ArcTanh[a*x]] + 384*PolyLog[2, I/E^ArcTanh[a*x]] + 192*ArcTanh[a*x]^2*PolyLog[2, (-I)*E^A rcTanh[a*x]] - 48*Pi^2*PolyLog[2, I*E^ArcTanh[a*x]] + (192*I)*Pi*ArcTanh[a *x]*PolyLog[2, I*E^ArcTanh[a*x]] + (192*I)*Pi*PolyLog[3, (-I)/E^ArcTanh[a* x]] + 384*ArcTanh[a*x]*PolyLog[3, (-I)/E^ArcTanh[a*x]] - 384*ArcTanh[a*x]* PolyLog[3, (-I)*E^ArcTanh[a*x]] - (192*I)*Pi*PolyLog[3, I*E^ArcTanh[a*x]] + 384*PolyLog[4, (-I)/E^ArcTanh[a*x]] + 384*PolyLog[4, (-I)*E^ArcTanh[a*x] ]))/a
Time = 1.20 (sec) , antiderivative size = 291, normalized size of antiderivative = 0.96, number of steps used = 10, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.429, Rules used = {6506, 6512, 6514, 3042, 4668, 3011, 7163, 2720, 7143}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx\) |
\(\Big \downarrow \) 6506 |
\(\displaystyle -3 \int \frac {\text {arctanh}(a x)}{\sqrt {1-a^2 x^2}}dx+\frac {1}{2} \int \frac {\text {arctanh}(a x)^3}{\sqrt {1-a^2 x^2}}dx+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}\) |
\(\Big \downarrow \) 6512 |
\(\displaystyle \frac {1}{2} \int \frac {\text {arctanh}(a x)^3}{\sqrt {1-a^2 x^2}}dx+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 6514 |
\(\displaystyle \frac {\int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3d\text {arctanh}(a x)}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {\int \text {arctanh}(a x)^3 \csc \left (i \text {arctanh}(a x)+\frac {\pi }{2}\right )d\text {arctanh}(a x)}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 4668 |
\(\displaystyle \frac {-3 i \int \text {arctanh}(a x)^2 \log \left (1-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+3 i \int \text {arctanh}(a x)^2 \log \left (1+i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)+2 \text {arctanh}(a x)^3 \arctan \left (e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 3011 |
\(\displaystyle \frac {3 i \left (2 \int \text {arctanh}(a x) \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-3 i \left (2 \int \text {arctanh}(a x) \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^3 \arctan \left (e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 7163 |
\(\displaystyle \frac {3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-\int \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )-\int \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )d\text {arctanh}(a x)\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^3 \arctan \left (e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 2720 |
\(\displaystyle \frac {3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )-\int e^{-\text {arctanh}(a x)} \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )de^{\text {arctanh}(a x)}\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )+2 \text {arctanh}(a x)^3 \arctan \left (e^{\text {arctanh}(a x)}\right )}{2 a}+\frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )\) |
\(\Big \downarrow \) 7143 |
\(\displaystyle \frac {1}{2} x \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3+\frac {3 \sqrt {1-a^2 x^2} \text {arctanh}(a x)^2}{2 a}-3 \left (-\frac {2 \arctan \left (\frac {\sqrt {1-a x}}{\sqrt {a x+1}}\right ) \text {arctanh}(a x)}{a}-\frac {i \operatorname {PolyLog}\left (2,-\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}+\frac {i \operatorname {PolyLog}\left (2,\frac {i \sqrt {1-a x}}{\sqrt {a x+1}}\right )}{a}\right )+\frac {2 \text {arctanh}(a x)^3 \arctan \left (e^{\text {arctanh}(a x)}\right )+3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,-i e^{\text {arctanh}(a x)}\right )-\operatorname {PolyLog}\left (4,-i e^{\text {arctanh}(a x)}\right )\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,-i e^{\text {arctanh}(a x)}\right )\right )-3 i \left (2 \left (\text {arctanh}(a x) \operatorname {PolyLog}\left (3,i e^{\text {arctanh}(a x)}\right )-\operatorname {PolyLog}\left (4,i e^{\text {arctanh}(a x)}\right )\right )-\text {arctanh}(a x)^2 \operatorname {PolyLog}\left (2,i e^{\text {arctanh}(a x)}\right )\right )}{2 a}\) |
Input:
Int[Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^3,x]
Output:
(3*Sqrt[1 - a^2*x^2]*ArcTanh[a*x]^2)/(2*a) + (x*Sqrt[1 - a^2*x^2]*ArcTanh[ a*x]^3)/2 - 3*((-2*ArcTan[Sqrt[1 - a*x]/Sqrt[1 + a*x]]*ArcTanh[a*x])/a - ( I*PolyLog[2, ((-I)*Sqrt[1 - a*x])/Sqrt[1 + a*x]])/a + (I*PolyLog[2, (I*Sqr t[1 - a*x])/Sqrt[1 + a*x]])/a) + (2*ArcTan[E^ArcTanh[a*x]]*ArcTanh[a*x]^3 + (3*I)*(-(ArcTanh[a*x]^2*PolyLog[2, (-I)*E^ArcTanh[a*x]]) + 2*(ArcTanh[a* x]*PolyLog[3, (-I)*E^ArcTanh[a*x]] - PolyLog[4, (-I)*E^ArcTanh[a*x]])) - ( 3*I)*(-(ArcTanh[a*x]^2*PolyLog[2, I*E^ArcTanh[a*x]]) + 2*(ArcTanh[a*x]*Pol yLog[3, I*E^ArcTanh[a*x]] - PolyLog[4, I*E^ArcTanh[a*x]])))/(2*a)
Int[u_, x_Symbol] :> With[{v = FunctionOfExponential[u, x]}, Simp[v/D[v, x] Subst[Int[FunctionOfExponentialFunction[u, x]/x, x], x, v], x]] /; Funct ionOfExponentialQ[u, x] && !MatchQ[u, (w_)*((a_.)*(v_)^(n_))^(m_) /; FreeQ [{a, m, n}, x] && IntegerQ[m*n]] && !MatchQ[u, E^((c_.)*((a_.) + (b_.)*x)) *(F_)[v_] /; FreeQ[{a, b, c}, x] && InverseFunctionQ[F[x]]]
Int[Log[1 + (e_.)*((F_)^((c_.)*((a_.) + (b_.)*(x_))))^(n_.)]*((f_.) + (g_.) *(x_))^(m_.), x_Symbol] :> Simp[(-(f + g*x)^m)*(PolyLog[2, (-e)*(F^(c*(a + b*x)))^n]/(b*c*n*Log[F])), x] + Simp[g*(m/(b*c*n*Log[F])) Int[(f + g*x)^( m - 1)*PolyLog[2, (-e)*(F^(c*(a + b*x)))^n], x], x] /; FreeQ[{F, a, b, c, e , f, g, n}, x] && GtQ[m, 0]
Int[csc[(e_.) + Pi*(k_.) + (Complex[0, fz_])*(f_.)*(x_)]*((c_.) + (d_.)*(x_ ))^(m_.), x_Symbol] :> Simp[-2*(c + d*x)^m*(ArcTanh[E^((-I)*e + f*fz*x)/E^( I*k*Pi)]/(f*fz*I)), x] + (-Simp[d*(m/(f*fz*I)) Int[(c + d*x)^(m - 1)*Log[ 1 - E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x] + Simp[d*(m/(f*fz*I)) Int[(c + d*x)^(m - 1)*Log[1 + E^((-I)*e + f*fz*x)/E^(I*k*Pi)], x], x]) /; FreeQ[{c , d, e, f, fz}, x] && IntegerQ[2*k] && IGtQ[m, 0]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_)^2)^(q_.), x _Symbol] :> Simp[b*p*(d + e*x^2)^q*((a + b*ArcTanh[c*x])^(p - 1)/(2*c*q*(2* q + 1))), x] + (Simp[x*(d + e*x^2)^q*((a + b*ArcTanh[c*x])^p/(2*q + 1)), x] + Simp[2*d*(q/(2*q + 1)) Int[(d + e*x^2)^(q - 1)*(a + b*ArcTanh[c*x])^p, x], x] - Simp[b^2*d*p*((p - 1)/(2*q*(2*q + 1))) Int[(d + e*x^2)^(q - 1)* (a + b*ArcTanh[c*x])^(p - 2), x], x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[c ^2*d + e, 0] && GtQ[q, 0] && GtQ[p, 1]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))/Sqrt[(d_) + (e_.)*(x_)^2], x_Symbol ] :> Simp[-2*(a + b*ArcTanh[c*x])*(ArcTan[Sqrt[1 - c*x]/Sqrt[1 + c*x]]/(c*S qrt[d])), x] + (-Simp[I*b*(PolyLog[2, (-I)*(Sqrt[1 - c*x]/Sqrt[1 + c*x])]/( c*Sqrt[d])), x] + Simp[I*b*(PolyLog[2, I*(Sqrt[1 - c*x]/Sqrt[1 + c*x])]/(c* Sqrt[d])), x]) /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && GtQ[d, 0]
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_.)/Sqrt[(d_) + (e_.)*(x_)^2], x_ Symbol] :> Simp[1/(c*Sqrt[d]) Subst[Int[(a + b*x)^p*Sech[x], x], x, ArcTa nh[c*x]], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && IGtQ[p, 0 ] && GtQ[d, 0]
Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_S ymbol] :> Simp[PolyLog[n + 1, c*(a + b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d , e, n, p}, x] && EqQ[b*d, a*e]
Int[((e_.) + (f_.)*(x_))^(m_.)*PolyLog[n_, (d_.)*((F_)^((c_.)*((a_.) + (b_. )*(x_))))^(p_.)], x_Symbol] :> Simp[(e + f*x)^m*(PolyLog[n + 1, d*(F^(c*(a + b*x)))^p]/(b*c*p*Log[F])), x] - Simp[f*(m/(b*c*p*Log[F])) Int[(e + f*x) ^(m - 1)*PolyLog[n + 1, d*(F^(c*(a + b*x)))^p], x], x] /; FreeQ[{F, a, b, c , d, e, f, n, p}, x] && GtQ[m, 0]
\[\int \sqrt {-a^{2} x^{2}+1}\, \operatorname {arctanh}\left (a x \right )^{3}d x\]
Input:
int((-a^2*x^2+1)^(1/2)*arctanh(a*x)^3,x)
Output:
int((-a^2*x^2+1)^(1/2)*arctanh(a*x)^3,x)
\[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\int { \sqrt {-a^{2} x^{2} + 1} \operatorname {artanh}\left (a x\right )^{3} \,d x } \] Input:
integrate((-a^2*x^2+1)^(1/2)*arctanh(a*x)^3,x, algorithm="fricas")
Output:
integral(sqrt(-a^2*x^2 + 1)*arctanh(a*x)^3, x)
\[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\int \sqrt {- \left (a x - 1\right ) \left (a x + 1\right )} \operatorname {atanh}^{3}{\left (a x \right )}\, dx \] Input:
integrate((-a**2*x**2+1)**(1/2)*atanh(a*x)**3,x)
Output:
Integral(sqrt(-(a*x - 1)*(a*x + 1))*atanh(a*x)**3, x)
\[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\int { \sqrt {-a^{2} x^{2} + 1} \operatorname {artanh}\left (a x\right )^{3} \,d x } \] Input:
integrate((-a^2*x^2+1)^(1/2)*arctanh(a*x)^3,x, algorithm="maxima")
Output:
integrate(sqrt(-a^2*x^2 + 1)*arctanh(a*x)^3, x)
Exception generated. \[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\text {Exception raised: TypeError} \] Input:
integrate((-a^2*x^2+1)^(1/2)*arctanh(a*x)^3,x, algorithm="giac")
Output:
Exception raised: TypeError >> an error occurred running a Giac command:IN PUT:sage2:=int(sage0,sageVARx):;OUTPUT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value
Timed out. \[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\int {\mathrm {atanh}\left (a\,x\right )}^3\,\sqrt {1-a^2\,x^2} \,d x \] Input:
int(atanh(a*x)^3*(1 - a^2*x^2)^(1/2),x)
Output:
int(atanh(a*x)^3*(1 - a^2*x^2)^(1/2), x)
\[ \int \sqrt {1-a^2 x^2} \text {arctanh}(a x)^3 \, dx=\int \sqrt {-a^{2} x^{2}+1}\, \mathit {atanh} \left (a x \right )^{3}d x \] Input:
int((-a^2*x^2+1)^(1/2)*atanh(a*x)^3,x)
Output:
int(sqrt( - a**2*x**2 + 1)*atanh(a*x)**3,x)