\(\int x^2 \text {arctanh}(a+b x)^2 \, dx\) [2]

Optimal result
Mathematica [B] (warning: unable to verify)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [F]
Sympy [F]
Maxima [A] (verification not implemented)
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 12, antiderivative size = 204 \[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\frac {x}{3 b^2}-\frac {\text {arctanh}(a+b x)}{3 b^3}-\frac {2 a (a+b x) \text {arctanh}(a+b x)}{b^3}+\frac {(a+b x)^2 \text {arctanh}(a+b x)}{3 b^3}+\frac {a \left (3+a^2\right ) \text {arctanh}(a+b x)^2}{3 b^3}+\frac {\left (1+3 a^2\right ) \text {arctanh}(a+b x)^2}{3 b^3}+\frac {1}{3} x^3 \text {arctanh}(a+b x)^2-\frac {2 \left (1+3 a^2\right ) \text {arctanh}(a+b x) \log \left (\frac {2}{1-a-b x}\right )}{3 b^3}-\frac {a \log \left (1-(a+b x)^2\right )}{b^3}-\frac {\left (1+3 a^2\right ) \operatorname {PolyLog}\left (2,-\frac {1+a+b x}{1-a-b x}\right )}{3 b^3} \] Output:

1/3*x/b^2-1/3*arctanh(b*x+a)/b^3-2*a*(b*x+a)*arctanh(b*x+a)/b^3+1/3*(b*x+a 
)^2*arctanh(b*x+a)/b^3+1/3*a*(a^2+3)*arctanh(b*x+a)^2/b^3+1/3*(3*a^2+1)*ar 
ctanh(b*x+a)^2/b^3+1/3*x^3*arctanh(b*x+a)^2-2/3*(3*a^2+1)*arctanh(b*x+a)*l 
n(2/(-b*x-a+1))/b^3-a*ln(1-(b*x+a)^2)/b^3-1/3*(3*a^2+1)*polylog(2,-(b*x+a+ 
1)/(-b*x-a+1))/b^3
 

Mathematica [B] (warning: unable to verify)

Leaf count is larger than twice the leaf count of optimal. \(463\) vs. \(2(204)=408\).

Time = 1.46 (sec) , antiderivative size = 463, normalized size of antiderivative = 2.27 \[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=-\frac {\left (1-(a+b x)^2\right )^{3/2} \left (-\frac {a+b x}{\sqrt {1-(a+b x)^2}}+\frac {6 a (a+b x) \text {arctanh}(a+b x)}{\sqrt {1-(a+b x)^2}}+\frac {3 (a+b x) \text {arctanh}(a+b x)^2}{\sqrt {1-(a+b x)^2}}-\frac {3 a^2 (a+b x) \text {arctanh}(a+b x)^2}{\sqrt {1-(a+b x)^2}}+\text {arctanh}(a+b x)^2 \cosh (3 \text {arctanh}(a+b x))+3 a^2 \text {arctanh}(a+b x)^2 \cosh (3 \text {arctanh}(a+b x))+2 \text {arctanh}(a+b x) \cosh (3 \text {arctanh}(a+b x)) \log \left (1+e^{-2 \text {arctanh}(a+b x)}\right )+6 a^2 \text {arctanh}(a+b x) \cosh (3 \text {arctanh}(a+b x)) \log \left (1+e^{-2 \text {arctanh}(a+b x)}\right )-6 a \cosh (3 \text {arctanh}(a+b x)) \log \left (\frac {1}{\sqrt {1-(a+b x)^2}}\right )+\frac {3 \left (1-4 a+3 a^2\right ) \text {arctanh}(a+b x)^2+2 \text {arctanh}(a+b x) \left (2+\left (3+9 a^2\right ) \log \left (1+e^{-2 \text {arctanh}(a+b x)}\right )\right )-18 a \log \left (\frac {1}{\sqrt {1-(a+b x)^2}}\right )}{\sqrt {1-(a+b x)^2}}-\frac {4 \left (1+3 a^2\right ) \operatorname {PolyLog}\left (2,-e^{-2 \text {arctanh}(a+b x)}\right )}{\left (1-(a+b x)^2\right )^{3/2}}-\sinh (3 \text {arctanh}(a+b x))+6 a \text {arctanh}(a+b x) \sinh (3 \text {arctanh}(a+b x))-\text {arctanh}(a+b x)^2 \sinh (3 \text {arctanh}(a+b x))-3 a^2 \text {arctanh}(a+b x)^2 \sinh (3 \text {arctanh}(a+b x))\right )}{12 b^3} \] Input:

Integrate[x^2*ArcTanh[a + b*x]^2,x]
 

Output:

-1/12*((1 - (a + b*x)^2)^(3/2)*(-((a + b*x)/Sqrt[1 - (a + b*x)^2]) + (6*a* 
(a + b*x)*ArcTanh[a + b*x])/Sqrt[1 - (a + b*x)^2] + (3*(a + b*x)*ArcTanh[a 
 + b*x]^2)/Sqrt[1 - (a + b*x)^2] - (3*a^2*(a + b*x)*ArcTanh[a + b*x]^2)/Sq 
rt[1 - (a + b*x)^2] + ArcTanh[a + b*x]^2*Cosh[3*ArcTanh[a + b*x]] + 3*a^2* 
ArcTanh[a + b*x]^2*Cosh[3*ArcTanh[a + b*x]] + 2*ArcTanh[a + b*x]*Cosh[3*Ar 
cTanh[a + b*x]]*Log[1 + E^(-2*ArcTanh[a + b*x])] + 6*a^2*ArcTanh[a + b*x]* 
Cosh[3*ArcTanh[a + b*x]]*Log[1 + E^(-2*ArcTanh[a + b*x])] - 6*a*Cosh[3*Arc 
Tanh[a + b*x]]*Log[1/Sqrt[1 - (a + b*x)^2]] + (3*(1 - 4*a + 3*a^2)*ArcTanh 
[a + b*x]^2 + 2*ArcTanh[a + b*x]*(2 + (3 + 9*a^2)*Log[1 + E^(-2*ArcTanh[a 
+ b*x])]) - 18*a*Log[1/Sqrt[1 - (a + b*x)^2]])/Sqrt[1 - (a + b*x)^2] - (4* 
(1 + 3*a^2)*PolyLog[2, -E^(-2*ArcTanh[a + b*x])])/(1 - (a + b*x)^2)^(3/2) 
- Sinh[3*ArcTanh[a + b*x]] + 6*a*ArcTanh[a + b*x]*Sinh[3*ArcTanh[a + b*x]] 
 - ArcTanh[a + b*x]^2*Sinh[3*ArcTanh[a + b*x]] - 3*a^2*ArcTanh[a + b*x]^2* 
Sinh[3*ArcTanh[a + b*x]]))/b^3
 

Rubi [A] (verified)

Time = 0.50 (sec) , antiderivative size = 193, normalized size of antiderivative = 0.95, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {6661, 27, 6480, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x^2 \text {arctanh}(a+b x)^2 \, dx\)

\(\Big \downarrow \) 6661

\(\displaystyle \frac {\int x^2 \text {arctanh}(a+b x)^2d(a+b x)}{b}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {\int b^2 x^2 \text {arctanh}(a+b x)^2d(a+b x)}{b^3}\)

\(\Big \downarrow \) 6480

\(\displaystyle \frac {\frac {2}{3} \int \left (-3 a \text {arctanh}(a+b x)+(a+b x) \text {arctanh}(a+b x)+\frac {\left (a \left (a^2+3\right )-\left (3 a^2+1\right ) (a+b x)\right ) \text {arctanh}(a+b x)}{1-(a+b x)^2}\right )d(a+b x)+\frac {1}{3} b^3 x^3 \text {arctanh}(a+b x)^2}{b^3}\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {\frac {2}{3} \left (\frac {1}{2} a \left (a^2+3\right ) \text {arctanh}(a+b x)^2+\frac {1}{2} \left (3 a^2+1\right ) \text {arctanh}(a+b x)^2-\left (3 a^2+1\right ) \text {arctanh}(a+b x) \log \left (\frac {2}{-a-b x+1}\right )-\frac {1}{2} \left (3 a^2+1\right ) \operatorname {PolyLog}\left (2,-\frac {a+b x+1}{-a-b x+1}\right )+\frac {1}{2} (a+b x)^2 \text {arctanh}(a+b x)-3 a (a+b x) \text {arctanh}(a+b x)-\frac {1}{2} \text {arctanh}(a+b x)+\frac {1}{2} (a+b x)-\frac {3}{2} a \log \left (1-(a+b x)^2\right )\right )+\frac {1}{3} b^3 x^3 \text {arctanh}(a+b x)^2}{b^3}\)

Input:

Int[x^2*ArcTanh[a + b*x]^2,x]
 

Output:

((b^3*x^3*ArcTanh[a + b*x]^2)/3 + (2*((a + b*x)/2 - ArcTanh[a + b*x]/2 - 3 
*a*(a + b*x)*ArcTanh[a + b*x] + ((a + b*x)^2*ArcTanh[a + b*x])/2 + (a*(3 + 
 a^2)*ArcTanh[a + b*x]^2)/2 + ((1 + 3*a^2)*ArcTanh[a + b*x]^2)/2 - (1 + 3* 
a^2)*ArcTanh[a + b*x]*Log[2/(1 - a - b*x)] - (3*a*Log[1 - (a + b*x)^2])/2 
- ((1 + 3*a^2)*PolyLog[2, -((1 + a + b*x)/(1 - a - b*x))])/2))/3)/b^3
 

Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 6480
Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))^(p_)*((d_) + (e_.)*(x_))^(q_.), x_S 
ymbol] :> Simp[(d + e*x)^(q + 1)*((a + b*ArcTanh[c*x])^p/(e*(q + 1))), x] - 
 Simp[b*c*(p/(e*(q + 1)))   Int[ExpandIntegrand[(a + b*ArcTanh[c*x])^(p - 1 
), (d + e*x)^(q + 1)/(1 - c^2*x^2), x], x], x] /; FreeQ[{a, b, c, d, e}, x] 
 && IGtQ[p, 1] && IntegerQ[q] && NeQ[q, -1]
 

rule 6661
Int[((a_.) + ArcTanh[(c_) + (d_.)*(x_)]*(b_.))^(p_.)*((e_.) + (f_.)*(x_))^( 
m_.), x_Symbol] :> Simp[1/d   Subst[Int[((d*e - c*f)/d + f*(x/d))^m*(a + b* 
ArcTanh[x])^p, x], x, c + d*x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && IG 
tQ[p, 0]
 
Maple [A] (verified)

Time = 0.26 (sec) , antiderivative size = 350, normalized size of antiderivative = 1.72

method result size
parts \(\frac {x^{3} \operatorname {arctanh}\left (b x +a \right )^{2}}{3}-\frac {2 \left (3 \,\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right ) a -\frac {\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right )^{2}}{2}+\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{3}}{2}-\frac {3 \,\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{2}}{2}+\frac {3 \,\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a}{2}-\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right )}{2}-\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{3}}{2}-\frac {3 \,\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{2}}{2}-\frac {3 \,\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a}{2}-\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right )}{2}-\frac {\left (a^{3}+3 a^{2}+3 a +1\right ) \left (-\frac {\ln \left (b x +a +1\right )^{2}}{4}+\frac {\left (\ln \left (b x +a +1\right )-\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{2}-\frac {b x}{2}-\frac {a}{2}+\frac {\left (6 a -1\right ) \ln \left (b x +a -1\right )}{4}-\frac {\left (-6 a -1\right ) \ln \left (b x +a +1\right )}{4}-\frac {\left (-a^{3}+3 a^{2}-3 a +1\right ) \left (\frac {\ln \left (b x +a -1\right )^{2}}{4}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (b x +a -1\right ) \ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{2}\right )}{3 b^{3}}\) \(350\)
derivativedivides \(\frac {-\frac {\operatorname {arctanh}\left (b x +a \right )^{2} a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right )^{2} a^{2} \left (b x +a \right )-\operatorname {arctanh}\left (b x +a \right )^{2} a \left (b x +a \right )^{2}+\frac {\operatorname {arctanh}\left (b x +a \right )^{2} \left (b x +a \right )^{3}}{3}-2 \,\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right )^{2}}{3}-\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{2}-\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right )}{3}+\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{2}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right )}{3}+\frac {b x}{3}+\frac {a}{3}-\frac {\left (6 a -1\right ) \ln \left (b x +a -1\right )}{6}+\frac {\left (-6 a -1\right ) \ln \left (b x +a +1\right )}{6}-\frac {\left (a^{3}-3 a^{2}+3 a -1\right ) \left (\frac {\ln \left (b x +a -1\right )^{2}}{4}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (b x +a -1\right ) \ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{3}-\frac {\left (-a^{3}-3 a^{2}-3 a -1\right ) \left (-\frac {\ln \left (b x +a +1\right )^{2}}{4}+\frac {\left (\ln \left (b x +a +1\right )-\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{3}}{b^{3}}\) \(397\)
default \(\frac {-\frac {\operatorname {arctanh}\left (b x +a \right )^{2} a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right )^{2} a^{2} \left (b x +a \right )-\operatorname {arctanh}\left (b x +a \right )^{2} a \left (b x +a \right )^{2}+\frac {\operatorname {arctanh}\left (b x +a \right )^{2} \left (b x +a \right )^{3}}{3}-2 \,\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \left (b x +a \right )^{2}}{3}-\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a^{2}-\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a -1\right )}{3}+\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{3}}{3}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a^{2}+\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right ) a +\frac {\operatorname {arctanh}\left (b x +a \right ) \ln \left (b x +a +1\right )}{3}+\frac {b x}{3}+\frac {a}{3}-\frac {\left (6 a -1\right ) \ln \left (b x +a -1\right )}{6}+\frac {\left (-6 a -1\right ) \ln \left (b x +a +1\right )}{6}-\frac {\left (a^{3}-3 a^{2}+3 a -1\right ) \left (\frac {\ln \left (b x +a -1\right )^{2}}{4}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (b x +a -1\right ) \ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{3}-\frac {\left (-a^{3}-3 a^{2}-3 a -1\right ) \left (-\frac {\ln \left (b x +a +1\right )^{2}}{4}+\frac {\left (\ln \left (b x +a +1\right )-\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right )}{2}-\frac {\operatorname {dilog}\left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right )}{2}\right )}{3}}{b^{3}}\) \(397\)
risch \(-\frac {1}{3 b^{3}}+\frac {x}{3 b^{2}}+\frac {a}{3 b^{3}}+\frac {x^{3} \ln \left (-b x -a +1\right )^{2}}{12}-\frac {\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right ) \ln \left (-b x -a +1\right )}{3 b^{3}}+\frac {\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right ) \ln \left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right )}{3 b^{3}}+\frac {\operatorname {dilog}\left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right ) a^{2}}{b^{3}}-\frac {5 \ln \left (-b x -a -1\right ) a^{2}}{6 b^{3}}-\frac {\ln \left (-b x -a -1\right ) a}{b^{3}}+\frac {\left (b^{3} x^{3}+a^{3}+3 a^{2}+3 a +1\right ) \ln \left (b x +a +1\right )^{2}}{12 b^{3}}+\frac {\operatorname {dilog}\left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right )}{3 b^{3}}-\frac {\ln \left (-b x -a -1\right )}{6 b^{3}}+\left (-\frac {\ln \left (-b x -a +1\right ) x^{3}}{6}+\frac {-\ln \left (-b x -a +1\right ) a^{3}+b^{2} x^{2}+3 \ln \left (-b x -a +1\right ) a^{2}-4 b a x -3 \ln \left (-b x -a +1\right ) a +\ln \left (-b x -a +1\right )}{6 b^{3}}\right ) \ln \left (b x +a +1\right )+\frac {\ln \left (-b x -a +1\right )}{6 b^{3}}-\frac {\ln \left (-b x -a +1\right )^{2}}{12 b^{3}}+\frac {\ln \left (-b x -a +1\right )^{2} a^{3}}{12 b^{3}}-\frac {\ln \left (-b x -a +1\right )^{2} a^{2}}{4 b^{3}}+\frac {\ln \left (-b x -a +1\right )^{2} a}{4 b^{3}}+\frac {5 \ln \left (-b x -a +1\right ) a^{2}}{6 b^{3}}-\frac {\ln \left (-b x -a +1\right ) a}{b^{3}}-\frac {\ln \left (-b x -a +1\right ) x^{2}}{6 b}+\frac {\ln \left (-\frac {b x}{2}-\frac {a}{2}+\frac {1}{2}\right ) \ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right ) a^{2}}{b^{3}}-\frac {\ln \left (\frac {b x}{2}+\frac {a}{2}+\frac {1}{2}\right ) \ln \left (-b x -a +1\right ) a^{2}}{b^{3}}+\frac {2 \ln \left (-b x -a +1\right ) x a}{3 b^{2}}\) \(510\)

Input:

int(x^2*arctanh(b*x+a)^2,x,method=_RETURNVERBOSE)
 

Output:

1/3*x^3*arctanh(b*x+a)^2-2/3/b^3*(3*arctanh(b*x+a)*(b*x+a)*a-1/2*arctanh(b 
*x+a)*(b*x+a)^2+1/2*arctanh(b*x+a)*ln(b*x+a-1)*a^3-3/2*arctanh(b*x+a)*ln(b 
*x+a-1)*a^2+3/2*arctanh(b*x+a)*ln(b*x+a-1)*a-1/2*arctanh(b*x+a)*ln(b*x+a-1 
)-1/2*arctanh(b*x+a)*ln(b*x+a+1)*a^3-3/2*arctanh(b*x+a)*ln(b*x+a+1)*a^2-3/ 
2*arctanh(b*x+a)*ln(b*x+a+1)*a-1/2*arctanh(b*x+a)*ln(b*x+a+1)-1/2*(a^3+3*a 
^2+3*a+1)*(-1/4*ln(b*x+a+1)^2+1/2*(ln(b*x+a+1)-ln(1/2*b*x+1/2*a+1/2))*ln(- 
1/2*b*x-1/2*a+1/2)-1/2*dilog(1/2*b*x+1/2*a+1/2))-1/2*b*x-1/2*a+1/4*(6*a-1) 
*ln(b*x+a-1)-1/4*(-6*a-1)*ln(b*x+a+1)-1/2*(-a^3+3*a^2-3*a+1)*(1/4*ln(b*x+a 
-1)^2-1/2*dilog(1/2*b*x+1/2*a+1/2)-1/2*ln(b*x+a-1)*ln(1/2*b*x+1/2*a+1/2)))
 

Fricas [F]

\[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\int { x^{2} \operatorname {artanh}\left (b x + a\right )^{2} \,d x } \] Input:

integrate(x^2*arctanh(b*x+a)^2,x, algorithm="fricas")
 

Output:

integral(x^2*arctanh(b*x + a)^2, x)
 

Sympy [F]

\[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\int x^{2} \operatorname {atanh}^{2}{\left (a + b x \right )}\, dx \] Input:

integrate(x**2*atanh(b*x+a)**2,x)
 

Output:

Integral(x**2*atanh(a + b*x)**2, x)
 

Maxima [A] (verification not implemented)

Time = 0.03 (sec) , antiderivative size = 259, normalized size of antiderivative = 1.27 \[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\frac {1}{3} \, x^{3} \operatorname {artanh}\left (b x + a\right )^{2} - \frac {1}{12} \, b^{2} {\left (\frac {4 \, {\left (3 \, a^{2} + 1\right )} {\left (\log \left (b x + a - 1\right ) \log \left (\frac {1}{2} \, b x + \frac {1}{2} \, a + \frac {1}{2}\right ) + {\rm Li}_2\left (-\frac {1}{2} \, b x - \frac {1}{2} \, a + \frac {1}{2}\right )\right )}}{b^{5}} + \frac {2 \, {\left (5 \, a^{2} + 6 \, a + 1\right )} \log \left (b x + a + 1\right )}{b^{5}} + \frac {{\left (a^{3} + 3 \, a^{2} + 3 \, a + 1\right )} \log \left (b x + a + 1\right )^{2} - 2 \, {\left (a^{3} + 3 \, a^{2} + 3 \, a + 1\right )} \log \left (b x + a + 1\right ) \log \left (b x + a - 1\right ) + {\left (a^{3} - 3 \, a^{2} + 3 \, a - 1\right )} \log \left (b x + a - 1\right )^{2} - 4 \, b x - 2 \, {\left (5 \, a^{2} - 6 \, a + 1\right )} \log \left (b x + a - 1\right )}{b^{5}}\right )} + \frac {1}{3} \, b {\left (\frac {b x^{2} - 4 \, a x}{b^{3}} + \frac {{\left (a^{3} + 3 \, a^{2} + 3 \, a + 1\right )} \log \left (b x + a + 1\right )}{b^{4}} - \frac {{\left (a^{3} - 3 \, a^{2} + 3 \, a - 1\right )} \log \left (b x + a - 1\right )}{b^{4}}\right )} \operatorname {artanh}\left (b x + a\right ) \] Input:

integrate(x^2*arctanh(b*x+a)^2,x, algorithm="maxima")
 

Output:

1/3*x^3*arctanh(b*x + a)^2 - 1/12*b^2*(4*(3*a^2 + 1)*(log(b*x + a - 1)*log 
(1/2*b*x + 1/2*a + 1/2) + dilog(-1/2*b*x - 1/2*a + 1/2))/b^5 + 2*(5*a^2 + 
6*a + 1)*log(b*x + a + 1)/b^5 + ((a^3 + 3*a^2 + 3*a + 1)*log(b*x + a + 1)^ 
2 - 2*(a^3 + 3*a^2 + 3*a + 1)*log(b*x + a + 1)*log(b*x + a - 1) + (a^3 - 3 
*a^2 + 3*a - 1)*log(b*x + a - 1)^2 - 4*b*x - 2*(5*a^2 - 6*a + 1)*log(b*x + 
 a - 1))/b^5) + 1/3*b*((b*x^2 - 4*a*x)/b^3 + (a^3 + 3*a^2 + 3*a + 1)*log(b 
*x + a + 1)/b^4 - (a^3 - 3*a^2 + 3*a - 1)*log(b*x + a - 1)/b^4)*arctanh(b* 
x + a)
 

Giac [F]

\[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\int { x^{2} \operatorname {artanh}\left (b x + a\right )^{2} \,d x } \] Input:

integrate(x^2*arctanh(b*x+a)^2,x, algorithm="giac")
 

Output:

integrate(x^2*arctanh(b*x + a)^2, x)
 

Mupad [F(-1)]

Timed out. \[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\int x^2\,{\mathrm {atanh}\left (a+b\,x\right )}^2 \,d x \] Input:

int(x^2*atanh(a + b*x)^2,x)
 

Output:

int(x^2*atanh(a + b*x)^2, x)
 

Reduce [F]

\[ \int x^2 \text {arctanh}(a+b x)^2 \, dx=\frac {-\mathit {atanh} \left (b x +a \right )^{2} a^{4}+2 \mathit {atanh} \left (b x +a \right )^{2} a^{2}+2 \mathit {atanh} \left (b x +a \right )^{2} a \,b^{3} x^{3}-\mathit {atanh} \left (b x +a \right )^{2}-4 \mathit {atanh} \left (b x +a \right ) a^{3}-2 \mathit {atanh} \left (b x +a \right ) a^{2} b x -6 \mathit {atanh} \left (b x +a \right ) a^{2}+2 \mathit {atanh} \left (b x +a \right ) a \,b^{2} x^{2}+2 \mathit {atanh} \left (b x +a \right ) b x +2 \mathit {atanh} \left (b x +a \right )-6 \left (\int \frac {\mathit {atanh} \left (b x +a \right ) x^{2}}{b^{2} x^{2}+2 a b x +a^{2}-1}d x \right ) a^{2} b^{3}-2 \left (\int \frac {\mathit {atanh} \left (b x +a \right ) x^{2}}{b^{2} x^{2}+2 a b x +a^{2}-1}d x \right ) b^{3}-6 \,\mathrm {log}\left (b x +a -1\right ) a^{2}+2 \,\mathrm {log}\left (b x +a -1\right )+2 a b x}{6 a \,b^{3}} \] Input:

int(x^2*atanh(b*x+a)^2,x)
                                                                                    
                                                                                    
 

Output:

( - atanh(a + b*x)**2*a**4 + 2*atanh(a + b*x)**2*a**2 + 2*atanh(a + b*x)** 
2*a*b**3*x**3 - atanh(a + b*x)**2 - 4*atanh(a + b*x)*a**3 - 2*atanh(a + b* 
x)*a**2*b*x - 6*atanh(a + b*x)*a**2 + 2*atanh(a + b*x)*a*b**2*x**2 + 2*ata 
nh(a + b*x)*b*x + 2*atanh(a + b*x) - 6*int((atanh(a + b*x)*x**2)/(a**2 + 2 
*a*b*x + b**2*x**2 - 1),x)*a**2*b**3 - 2*int((atanh(a + b*x)*x**2)/(a**2 + 
 2*a*b*x + b**2*x**2 - 1),x)*b**3 - 6*log(a + b*x - 1)*a**2 + 2*log(a + b* 
x - 1) + 2*a*b*x)/(6*a*b**3)