Integrand size = 10, antiderivative size = 103 \[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=-\frac {a^2}{3 x}-\frac {a \coth ^{-1}(a x)}{3 x^2}+\frac {1}{3} a^3 \coth ^{-1}(a x)^2-\frac {\coth ^{-1}(a x)^2}{3 x^3}+\frac {1}{3} a^3 \text {arctanh}(a x)+\frac {2}{3} a^3 \coth ^{-1}(a x) \log \left (2-\frac {2}{1+a x}\right )-\frac {1}{3} a^3 \operatorname {PolyLog}\left (2,-1+\frac {2}{1+a x}\right ) \] Output:
-1/3*a^2/x-1/3*a*arccoth(a*x)/x^2+1/3*a^3*arccoth(a*x)^2-1/3*arccoth(a*x)^ 2/x^3+1/3*a^3*arctanh(a*x)+2/3*a^3*arccoth(a*x)*ln(2-2/(a*x+1))-1/3*a^3*po lylog(2,-1+2/(a*x+1))
Time = 0.15 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.84 \[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\frac {-a^2 x^2+\left (-1+a^3 x^3\right ) \coth ^{-1}(a x)^2+a x \coth ^{-1}(a x) \left (-1+a^2 x^2+2 a^2 x^2 \log \left (1+e^{-2 \coth ^{-1}(a x)}\right )\right )-a^3 x^3 \operatorname {PolyLog}\left (2,-e^{-2 \coth ^{-1}(a x)}\right )}{3 x^3} \] Input:
Integrate[ArcCoth[a*x]^2/x^4,x]
Output:
(-(a^2*x^2) + (-1 + a^3*x^3)*ArcCoth[a*x]^2 + a*x*ArcCoth[a*x]*(-1 + a^2*x ^2 + 2*a^2*x^2*Log[1 + E^(-2*ArcCoth[a*x])]) - a^3*x^3*PolyLog[2, -E^(-2*A rcCoth[a*x])])/(3*x^3)
Time = 0.71 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.94, number of steps used = 8, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.800, Rules used = {6453, 6545, 6453, 264, 219, 6551, 6495, 2897}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx\) |
\(\Big \downarrow \) 6453 |
\(\displaystyle \frac {2}{3} a \int \frac {\coth ^{-1}(a x)}{x^3 \left (1-a^2 x^2\right )}dx-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 6545 |
\(\displaystyle \frac {2}{3} a \left (a^2 \int \frac {\coth ^{-1}(a x)}{x \left (1-a^2 x^2\right )}dx+\int \frac {\coth ^{-1}(a x)}{x^3}dx\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 6453 |
\(\displaystyle \frac {2}{3} a \left (\frac {1}{2} a \int \frac {1}{x^2 \left (1-a^2 x^2\right )}dx+a^2 \int \frac {\coth ^{-1}(a x)}{x \left (1-a^2 x^2\right )}dx-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 264 |
\(\displaystyle \frac {2}{3} a \left (\frac {1}{2} a \left (a^2 \int \frac {1}{1-a^2 x^2}dx-\frac {1}{x}\right )+a^2 \int \frac {\coth ^{-1}(a x)}{x \left (1-a^2 x^2\right )}dx-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle \frac {2}{3} a \left (a^2 \int \frac {\coth ^{-1}(a x)}{x \left (1-a^2 x^2\right )}dx+\frac {1}{2} a \left (a \text {arctanh}(a x)-\frac {1}{x}\right )-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 6551 |
\(\displaystyle \frac {2}{3} a \left (a^2 \left (\int \frac {\coth ^{-1}(a x)}{x (a x+1)}dx+\frac {1}{2} \coth ^{-1}(a x)^2\right )+\frac {1}{2} a \left (a \text {arctanh}(a x)-\frac {1}{x}\right )-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 6495 |
\(\displaystyle \frac {2}{3} a \left (a^2 \left (-a \int \frac {\log \left (2-\frac {2}{a x+1}\right )}{1-a^2 x^2}dx+\frac {1}{2} \coth ^{-1}(a x)^2+\log \left (2-\frac {2}{a x+1}\right ) \coth ^{-1}(a x)\right )+\frac {1}{2} a \left (a \text {arctanh}(a x)-\frac {1}{x}\right )-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
\(\Big \downarrow \) 2897 |
\(\displaystyle \frac {2}{3} a \left (a^2 \left (-\frac {1}{2} \operatorname {PolyLog}\left (2,\frac {2}{a x+1}-1\right )+\frac {1}{2} \coth ^{-1}(a x)^2+\log \left (2-\frac {2}{a x+1}\right ) \coth ^{-1}(a x)\right )+\frac {1}{2} a \left (a \text {arctanh}(a x)-\frac {1}{x}\right )-\frac {\coth ^{-1}(a x)}{2 x^2}\right )-\frac {\coth ^{-1}(a x)^2}{3 x^3}\) |
Input:
Int[ArcCoth[a*x]^2/x^4,x]
Output:
-1/3*ArcCoth[a*x]^2/x^3 + (2*a*(-1/2*ArcCoth[a*x]/x^2 + (a*(-x^(-1) + a*Ar cTanh[a*x]))/2 + a^2*(ArcCoth[a*x]^2/2 + ArcCoth[a*x]*Log[2 - 2/(1 + a*x)] - PolyLog[2, -1 + 2/(1 + a*x)]/2)))/3
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(c*x)^( m + 1)*((a + b*x^2)^(p + 1)/(a*c*(m + 1))), x] - Simp[b*((m + 2*p + 3)/(a*c ^2*(m + 1))) Int[(c*x)^(m + 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b, c, p }, x] && LtQ[m, -1] && IntBinomialQ[a, b, c, 2, m, p, x]
Int[Log[u_]*(Pq_)^(m_.), x_Symbol] :> With[{C = FullSimplify[Pq^m*((1 - u)/ D[u, x])]}, Simp[C*PolyLog[2, 1 - u], x] /; FreeQ[C, x]] /; IntegerQ[m] && PolyQ[Pq, x] && RationalFunctionQ[u, x] && LeQ[RationalFunctionExponents[u, x][[2]], Expon[Pq, x]]
Int[((a_.) + ArcCoth[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*(x_)^(m_.), x_Symbol] : > Simp[x^(m + 1)*((a + b*ArcCoth[c*x^n])^p/(m + 1)), x] - Simp[b*c*n*(p/(m + 1)) Int[x^(m + n)*((a + b*ArcCoth[c*x^n])^(p - 1)/(1 - c^2*x^(2*n))), x ], x] /; FreeQ[{a, b, c, m, n}, x] && IGtQ[p, 0] && (EqQ[p, 1] || (EqQ[n, 1 ] && IntegerQ[m])) && NeQ[m, -1]
Int[((a_.) + ArcCoth[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_))), x _Symbol] :> Simp[(a + b*ArcCoth[c*x])^p*(Log[2 - 2/(1 + e*(x/d))]/d), x] - Simp[b*c*(p/d) Int[(a + b*ArcCoth[c*x])^(p - 1)*(Log[2 - 2/(1 + e*(x/d))] /(1 - c^2*x^2)), x], x] /; FreeQ[{a, b, c, d, e}, x] && IGtQ[p, 0] && EqQ[c ^2*d^2 - e^2, 0]
Int[(((a_.) + ArcCoth[(c_.)*(x_)]*(b_.))^(p_.)*((f_.)*(x_))^(m_))/((d_) + ( e_.)*(x_)^2), x_Symbol] :> Simp[1/d Int[(f*x)^m*(a + b*ArcCoth[c*x])^p, x ], x] - Simp[e/(d*f^2) Int[(f*x)^(m + 2)*((a + b*ArcCoth[c*x])^p/(d + e*x ^2)), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[p, 0] && LtQ[m, -1]
Int[((a_.) + ArcCoth[(c_.)*(x_)]*(b_.))^(p_.)/((x_)*((d_) + (e_.)*(x_)^2)), x_Symbol] :> Simp[(a + b*ArcCoth[c*x])^(p + 1)/(b*d*(p + 1)), x] + Simp[1/ d Int[(a + b*ArcCoth[c*x])^p/(x*(1 + c*x)), x], x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[c^2*d + e, 0] && GtQ[p, 0]
Leaf count of result is larger than twice the leaf count of optimal. \(183\) vs. \(2(89)=178\).
Time = 0.16 (sec) , antiderivative size = 184, normalized size of antiderivative = 1.79
method | result | size |
parts | \(-\frac {\operatorname {arccoth}\left (x a \right )^{2}}{3 x^{3}}-\frac {2 a^{3} \left (\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a +1\right )}{2}+\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a -1\right )}{2}+\frac {\operatorname {arccoth}\left (x a \right )}{2 x^{2} a^{2}}-\ln \left (x a \right ) \operatorname {arccoth}\left (x a \right )-\frac {\ln \left (x a +1\right )}{4}+\frac {\ln \left (x a -1\right )}{4}+\frac {1}{2 a x}+\frac {\ln \left (x a -1\right )^{2}}{8}-\frac {\operatorname {dilog}\left (\frac {x a}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (x a -1\right ) \ln \left (\frac {x a}{2}+\frac {1}{2}\right )}{4}-\frac {\ln \left (x a +1\right )^{2}}{8}+\frac {\left (\ln \left (x a +1\right )-\ln \left (\frac {x a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {x a}{2}+\frac {1}{2}\right )}{4}+\frac {\operatorname {dilog}\left (x a +1\right )}{2}+\frac {\ln \left (x a \right ) \ln \left (x a +1\right )}{2}+\frac {\operatorname {dilog}\left (x a \right )}{2}\right )}{3}\) | \(184\) |
derivativedivides | \(a^{3} \left (-\frac {\operatorname {arccoth}\left (x a \right )^{2}}{3 x^{3} a^{3}}-\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a +1\right )}{3}-\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a -1\right )}{3}-\frac {\operatorname {arccoth}\left (x a \right )}{3 x^{2} a^{2}}+\frac {2 \ln \left (x a \right ) \operatorname {arccoth}\left (x a \right )}{3}+\frac {\ln \left (x a +1\right )}{6}-\frac {\ln \left (x a -1\right )}{6}-\frac {1}{3 a x}-\frac {\ln \left (x a -1\right )^{2}}{12}+\frac {\operatorname {dilog}\left (\frac {x a}{2}+\frac {1}{2}\right )}{3}+\frac {\ln \left (x a -1\right ) \ln \left (\frac {x a}{2}+\frac {1}{2}\right )}{6}+\frac {\ln \left (x a +1\right )^{2}}{12}-\frac {\left (\ln \left (x a +1\right )-\ln \left (\frac {x a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {x a}{2}+\frac {1}{2}\right )}{6}-\frac {\operatorname {dilog}\left (x a +1\right )}{3}-\frac {\ln \left (x a \right ) \ln \left (x a +1\right )}{3}-\frac {\operatorname {dilog}\left (x a \right )}{3}\right )\) | \(185\) |
default | \(a^{3} \left (-\frac {\operatorname {arccoth}\left (x a \right )^{2}}{3 x^{3} a^{3}}-\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a +1\right )}{3}-\frac {\operatorname {arccoth}\left (x a \right ) \ln \left (x a -1\right )}{3}-\frac {\operatorname {arccoth}\left (x a \right )}{3 x^{2} a^{2}}+\frac {2 \ln \left (x a \right ) \operatorname {arccoth}\left (x a \right )}{3}+\frac {\ln \left (x a +1\right )}{6}-\frac {\ln \left (x a -1\right )}{6}-\frac {1}{3 a x}-\frac {\ln \left (x a -1\right )^{2}}{12}+\frac {\operatorname {dilog}\left (\frac {x a}{2}+\frac {1}{2}\right )}{3}+\frac {\ln \left (x a -1\right ) \ln \left (\frac {x a}{2}+\frac {1}{2}\right )}{6}+\frac {\ln \left (x a +1\right )^{2}}{12}-\frac {\left (\ln \left (x a +1\right )-\ln \left (\frac {x a}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {x a}{2}+\frac {1}{2}\right )}{6}-\frac {\operatorname {dilog}\left (x a +1\right )}{3}-\frac {\ln \left (x a \right ) \ln \left (x a +1\right )}{3}-\frac {\operatorname {dilog}\left (x a \right )}{3}\right )\) | \(185\) |
Input:
int(arccoth(x*a)^2/x^4,x,method=_RETURNVERBOSE)
Output:
-1/3*arccoth(x*a)^2/x^3-2/3*a^3*(1/2*arccoth(x*a)*ln(a*x+1)+1/2*arccoth(x* a)*ln(a*x-1)+1/2/x^2/a^2*arccoth(x*a)-ln(x*a)*arccoth(x*a)-1/4*ln(a*x+1)+1 /4*ln(a*x-1)+1/2/a/x+1/8*ln(a*x-1)^2-1/2*dilog(1/2*x*a+1/2)-1/4*ln(a*x-1)* ln(1/2*x*a+1/2)-1/8*ln(a*x+1)^2+1/4*(ln(a*x+1)-ln(1/2*x*a+1/2))*ln(-1/2*x* a+1/2)+1/2*dilog(a*x+1)+1/2*ln(x*a)*ln(a*x+1)+1/2*dilog(x*a))
\[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\int { \frac {\operatorname {arcoth}\left (a x\right )^{2}}{x^{4}} \,d x } \] Input:
integrate(arccoth(a*x)^2/x^4,x, algorithm="fricas")
Output:
integral(arccoth(a*x)^2/x^4, x)
\[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\int \frac {\operatorname {acoth}^{2}{\left (a x \right )}}{x^{4}}\, dx \] Input:
integrate(acoth(a*x)**2/x**4,x)
Output:
Integral(acoth(a*x)**2/x**4, x)
Time = 0.04 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.71 \[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\frac {1}{12} \, {\left (4 \, {\left (\log \left (a x - 1\right ) \log \left (\frac {1}{2} \, a x + \frac {1}{2}\right ) + {\rm Li}_2\left (-\frac {1}{2} \, a x + \frac {1}{2}\right )\right )} a - 4 \, {\left (\log \left (a x + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-a x\right )\right )} a + 4 \, {\left (\log \left (-a x + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (a x\right )\right )} a + 2 \, a \log \left (a x + 1\right ) - 2 \, a \log \left (a x - 1\right ) + \frac {a x \log \left (a x + 1\right )^{2} - 2 \, a x \log \left (a x + 1\right ) \log \left (a x - 1\right ) - a x \log \left (a x - 1\right )^{2} - 4}{x}\right )} a^{2} - \frac {1}{3} \, {\left (a^{2} \log \left (a^{2} x^{2} - 1\right ) - a^{2} \log \left (x^{2}\right ) + \frac {1}{x^{2}}\right )} a \operatorname {arcoth}\left (a x\right ) - \frac {\operatorname {arcoth}\left (a x\right )^{2}}{3 \, x^{3}} \] Input:
integrate(arccoth(a*x)^2/x^4,x, algorithm="maxima")
Output:
1/12*(4*(log(a*x - 1)*log(1/2*a*x + 1/2) + dilog(-1/2*a*x + 1/2))*a - 4*(l og(a*x + 1)*log(x) + dilog(-a*x))*a + 4*(log(-a*x + 1)*log(x) + dilog(a*x) )*a + 2*a*log(a*x + 1) - 2*a*log(a*x - 1) + (a*x*log(a*x + 1)^2 - 2*a*x*lo g(a*x + 1)*log(a*x - 1) - a*x*log(a*x - 1)^2 - 4)/x)*a^2 - 1/3*(a^2*log(a^ 2*x^2 - 1) - a^2*log(x^2) + 1/x^2)*a*arccoth(a*x) - 1/3*arccoth(a*x)^2/x^3
\[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\int { \frac {\operatorname {arcoth}\left (a x\right )^{2}}{x^{4}} \,d x } \] Input:
integrate(arccoth(a*x)^2/x^4,x, algorithm="giac")
Output:
integrate(arccoth(a*x)^2/x^4, x)
Timed out. \[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\int \frac {{\mathrm {acoth}\left (a\,x\right )}^2}{x^4} \,d x \] Input:
int(acoth(a*x)^2/x^4,x)
Output:
int(acoth(a*x)^2/x^4, x)
\[ \int \frac {\coth ^{-1}(a x)^2}{x^4} \, dx=\frac {-\mathit {acoth} \left (a x \right )^{2}-\mathit {acoth} \left (a x \right ) a^{3} x^{3}+\mathit {acoth} \left (a x \right ) a x +2 \left (\int \frac {\mathit {acoth} \left (a x \right )}{a^{2} x^{3}-x}d x \right ) a^{3} x^{3}-a^{2} x^{2}}{3 x^{3}} \] Input:
int(acoth(a*x)^2/x^4,x)
Output:
( - acoth(a*x)**2 - acoth(a*x)*a**3*x**3 + acoth(a*x)*a*x + 2*int(acoth(a* x)/(a**2*x**3 - x),x)*a**3*x**3 - a**2*x**2)/(3*x**3)