Integrand size = 10, antiderivative size = 93 \[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\frac {\sqrt {-1+\frac {1}{\sqrt {x}}} \sqrt {1+\frac {1}{\sqrt {x}}}}{2 \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}+\frac {\sqrt {1-x} \text {arctanh}\left (\sqrt {1-x}\right )}{2 \sqrt {-1+\frac {1}{\sqrt {x}}} \sqrt {1+\frac {1}{\sqrt {x}}} \sqrt {x}} \] Output:
1/2*(-1+1/x^(1/2))^(1/2)*(1/x^(1/2)+1)^(1/2)/x^(1/2)-arcsech(x^(1/2))/x+1/ 2*(1-x)^(1/2)*arctanh((1-x)^(1/2))/(-1+1/x^(1/2))^(1/2)/(1/x^(1/2)+1)^(1/2 )/x^(1/2)
Time = 0.06 (sec) , antiderivative size = 111, normalized size of antiderivative = 1.19 \[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\frac {\sqrt {\frac {1-\sqrt {x}}{1+\sqrt {x}}} \left (1+\sqrt {x}\right )-2 \text {sech}^{-1}\left (\sqrt {x}\right )+x \log \left (1+\sqrt {\frac {1-\sqrt {x}}{1+\sqrt {x}}}+\sqrt {\frac {1-\sqrt {x}}{1+\sqrt {x}}} \sqrt {x}\right )-\frac {1}{2} x \log (x)}{2 x} \] Input:
Integrate[ArcSech[Sqrt[x]]/x^2,x]
Output:
(Sqrt[(1 - Sqrt[x])/(1 + Sqrt[x])]*(1 + Sqrt[x]) - 2*ArcSech[Sqrt[x]] + x* Log[1 + Sqrt[(1 - Sqrt[x])/(1 + Sqrt[x])] + Sqrt[(1 - Sqrt[x])/(1 + Sqrt[x ])]*Sqrt[x]] - (x*Log[x])/2)/(2*x)
Time = 0.22 (sec) , antiderivative size = 79, normalized size of antiderivative = 0.85, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {6899, 27, 52, 73, 219}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx\) |
\(\Big \downarrow \) 6899 |
\(\displaystyle -\frac {\sqrt {1-x} \int \frac {1}{2 \sqrt {1-x} x^2}dx}{\sqrt {\frac {1}{\sqrt {x}}-1} \sqrt {\frac {1}{\sqrt {x}}+1} \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle -\frac {\sqrt {1-x} \int \frac {1}{\sqrt {1-x} x^2}dx}{2 \sqrt {\frac {1}{\sqrt {x}}-1} \sqrt {\frac {1}{\sqrt {x}}+1} \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}\) |
\(\Big \downarrow \) 52 |
\(\displaystyle -\frac {\sqrt {1-x} \left (\frac {1}{2} \int \frac {1}{\sqrt {1-x} x}dx-\frac {\sqrt {1-x}}{x}\right )}{2 \sqrt {\frac {1}{\sqrt {x}}-1} \sqrt {\frac {1}{\sqrt {x}}+1} \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}\) |
\(\Big \downarrow \) 73 |
\(\displaystyle -\frac {\sqrt {1-x} \left (-\int \frac {1}{x}d\sqrt {1-x}-\frac {\sqrt {1-x}}{x}\right )}{2 \sqrt {\frac {1}{\sqrt {x}}-1} \sqrt {\frac {1}{\sqrt {x}}+1} \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}\) |
\(\Big \downarrow \) 219 |
\(\displaystyle -\frac {\sqrt {1-x} \left (-\text {arctanh}\left (\sqrt {1-x}\right )-\frac {\sqrt {1-x}}{x}\right )}{2 \sqrt {\frac {1}{\sqrt {x}}-1} \sqrt {\frac {1}{\sqrt {x}}+1} \sqrt {x}}-\frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x}\) |
Input:
Int[ArcSech[Sqrt[x]]/x^2,x]
Output:
-(ArcSech[Sqrt[x]]/x) - (Sqrt[1 - x]*(-(Sqrt[1 - x]/x) - ArcTanh[Sqrt[1 - x]]))/(2*Sqrt[-1 + 1/Sqrt[x]]*Sqrt[1 + 1/Sqrt[x]]*Sqrt[x])
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[ (a + b*x)^(m + 1)*((c + d*x)^(n + 1)/((b*c - a*d)*(m + 1))), x] - Simp[d*(( m + n + 2)/((b*c - a*d)*(m + 1))) Int[(a + b*x)^(m + 1)*(c + d*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && ILtQ[m, -1] && FractionQ[n] && LtQ[n, 0]
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[ {p = Denominator[m]}, Simp[p/b Subst[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] && Lt Q[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntL inearQ[a, b, c, d, m, n, x]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1/(Rt[a, 2]*Rt[-b, 2]))* ArcTanh[Rt[-b, 2]*(x/Rt[a, 2])], x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (Gt Q[a, 0] || LtQ[b, 0])
Int[((a_.) + ArcSech[u_]*(b_.))*((c_.) + (d_.)*(x_))^(m_.), x_Symbol] :> Si mp[(c + d*x)^(m + 1)*((a + b*ArcSech[u])/(d*(m + 1))), x] + Simp[b*(Sqrt[1 - u^2]/(d*(m + 1)*u*Sqrt[-1 + 1/u]*Sqrt[1 + 1/u])) Int[SimplifyIntegrand[ (c + d*x)^(m + 1)*(D[u, x]/(u*Sqrt[1 - u^2])), x], x], x] /; FreeQ[{a, b, c , d, m}, x] && NeQ[m, -1] && InverseFunctionFreeQ[u, x] && !FunctionOfQ[(c + d*x)^(m + 1), u, x] && !FunctionOfExponentialQ[u, x]
Time = 0.19 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.69
method | result | size |
derivativedivides | \(-\frac {\operatorname {arcsech}\left (\sqrt {x}\right )}{x}+\frac {\sqrt {-\frac {\sqrt {x}-1}{\sqrt {x}}}\, \sqrt {\frac {\sqrt {x}+1}{\sqrt {x}}}\, \left (\operatorname {arctanh}\left (\frac {1}{\sqrt {1-x}}\right ) x +\sqrt {1-x}\right )}{2 \sqrt {x}\, \sqrt {1-x}}\) | \(64\) |
default | \(-\frac {\operatorname {arcsech}\left (\sqrt {x}\right )}{x}+\frac {\sqrt {-\frac {\sqrt {x}-1}{\sqrt {x}}}\, \sqrt {\frac {\sqrt {x}+1}{\sqrt {x}}}\, \left (\operatorname {arctanh}\left (\frac {1}{\sqrt {1-x}}\right ) x +\sqrt {1-x}\right )}{2 \sqrt {x}\, \sqrt {1-x}}\) | \(64\) |
parts | \(-\frac {\operatorname {arcsech}\left (\sqrt {x}\right )}{x}+\frac {\sqrt {-\frac {\sqrt {x}-1}{\sqrt {x}}}\, \sqrt {\frac {\sqrt {x}+1}{\sqrt {x}}}\, \left (\operatorname {arctanh}\left (\frac {1}{\sqrt {1-x}}\right ) x +\sqrt {1-x}\right )}{2 \sqrt {x}\, \sqrt {1-x}}\) | \(64\) |
Input:
int(arcsech(x^(1/2))/x^2,x,method=_RETURNVERBOSE)
Output:
-arcsech(x^(1/2))/x+1/2*(-(x^(1/2)-1)/x^(1/2))^(1/2)/x^(1/2)*((x^(1/2)+1)/ x^(1/2))^(1/2)*(arctanh(1/(1-x)^(1/2))*x+(1-x)^(1/2))/(1-x)^(1/2)
Time = 0.10 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.48 \[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\frac {{\left (x - 2\right )} \log \left (\frac {x \sqrt {-\frac {x - 1}{x}} + \sqrt {x}}{x}\right ) + \sqrt {x} \sqrt {-\frac {x - 1}{x}}}{2 \, x} \] Input:
integrate(arcsech(x^(1/2))/x^2,x, algorithm="fricas")
Output:
1/2*((x - 2)*log((x*sqrt(-(x - 1)/x) + sqrt(x))/x) + sqrt(x)*sqrt(-(x - 1) /x))/x
\[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\int \frac {\operatorname {asech}{\left (\sqrt {x} \right )}}{x^{2}}\, dx \] Input:
integrate(asech(x**(1/2))/x**2,x)
Output:
Integral(asech(sqrt(x))/x**2, x)
Time = 0.03 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.70 \[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=-\frac {\sqrt {x} \sqrt {\frac {1}{x} - 1}}{2 \, {\left (x {\left (\frac {1}{x} - 1\right )} - 1\right )}} - \frac {\operatorname {arsech}\left (\sqrt {x}\right )}{x} + \frac {1}{4} \, \log \left (\sqrt {x} \sqrt {\frac {1}{x} - 1} + 1\right ) - \frac {1}{4} \, \log \left (\sqrt {x} \sqrt {\frac {1}{x} - 1} - 1\right ) \] Input:
integrate(arcsech(x^(1/2))/x^2,x, algorithm="maxima")
Output:
-1/2*sqrt(x)*sqrt(1/x - 1)/(x*(1/x - 1) - 1) - arcsech(sqrt(x))/x + 1/4*lo g(sqrt(x)*sqrt(1/x - 1) + 1) - 1/4*log(sqrt(x)*sqrt(1/x - 1) - 1)
\[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\int { \frac {\operatorname {arsech}\left (\sqrt {x}\right )}{x^{2}} \,d x } \] Input:
integrate(arcsech(x^(1/2))/x^2,x, algorithm="giac")
Output:
integrate(arcsech(sqrt(x))/x^2, x)
Time = 4.24 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.43 \[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\frac {\sqrt {\frac {1}{\sqrt {x}}-1}\,\sqrt {\frac {1}{\sqrt {x}}+1}}{2\,\sqrt {x}}-\frac {2\,\mathrm {acosh}\left (\frac {1}{\sqrt {x}}\right )\,\left (\frac {1}{2\,\sqrt {x}}-\frac {\sqrt {x}}{4}\right )}{\sqrt {x}} \] Input:
int(acosh(1/x^(1/2))/x^2,x)
Output:
((1/x^(1/2) - 1)^(1/2)*(1/x^(1/2) + 1)^(1/2))/(2*x^(1/2)) - (2*acosh(1/x^( 1/2))*(1/(2*x^(1/2)) - x^(1/2)/4))/x^(1/2)
\[ \int \frac {\text {sech}^{-1}\left (\sqrt {x}\right )}{x^2} \, dx=\int \frac {\mathit {asech} \left (\sqrt {x}\right )}{x^{2}}d x \] Input:
int(asech(x^(1/2))/x^2,x)
Output:
int(asech(sqrt(x))/x**2,x)