Integrand size = 10, antiderivative size = 149 \[ \int x^3 \text {Si}(b x)^2 \, dx=\frac {x^2}{2 b^2}+\frac {3 \operatorname {CosIntegral}(2 b x)}{2 b^4}-\frac {3 \log (x)}{2 b^4}-\frac {x \cos (b x) \sin (b x)}{b^3}+\frac {2 \sin ^2(b x)}{b^4}-\frac {x^2 \sin ^2(b x)}{4 b^2}-\frac {3 x \cos (b x) \text {Si}(b x)}{b^3}+\frac {x^3 \cos (b x) \text {Si}(b x)}{2 b}+\frac {3 \sin (b x) \text {Si}(b x)}{b^4}-\frac {3 x^2 \sin (b x) \text {Si}(b x)}{2 b^2}+\frac {1}{4} x^4 \text {Si}(b x)^2 \] Output:
1/2*x^2/b^2+3/2*Ci(2*b*x)/b^4-3/2*ln(x)/b^4-x*cos(b*x)*sin(b*x)/b^3+2*sin( b*x)^2/b^4-1/4*x^2*sin(b*x)^2/b^2-3*x*cos(b*x)*Si(b*x)/b^3+1/2*x^3*cos(b*x )*Si(b*x)/b+3*sin(b*x)*Si(b*x)/b^4-3/2*x^2*sin(b*x)*Si(b*x)/b^2+1/4*x^4*Si (b*x)^2
Time = 0.09 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.72 \[ \int x^3 \text {Si}(b x)^2 \, dx=\frac {3 b^2 x^2-8 \cos (2 b x)+b^2 x^2 \cos (2 b x)+12 \operatorname {CosIntegral}(2 b x)-12 \log (x)-4 b x \sin (2 b x)+4 \left (b x \left (-6+b^2 x^2\right ) \cos (b x)-3 \left (-2+b^2 x^2\right ) \sin (b x)\right ) \text {Si}(b x)+2 b^4 x^4 \text {Si}(b x)^2}{8 b^4} \] Input:
Integrate[x^3*SinIntegral[b*x]^2,x]
Output:
(3*b^2*x^2 - 8*Cos[2*b*x] + b^2*x^2*Cos[2*b*x] + 12*CosIntegral[2*b*x] - 1 2*Log[x] - 4*b*x*Sin[2*b*x] + 4*(b*x*(-6 + b^2*x^2)*Cos[b*x] - 3*(-2 + b^2 *x^2)*Sin[b*x])*SinIntegral[b*x] + 2*b^4*x^4*SinIntegral[b*x]^2)/(8*b^4)
Time = 1.43 (sec) , antiderivative size = 232, normalized size of antiderivative = 1.56, number of steps used = 23, number of rules used = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 2.200, Rules used = {7061, 7067, 27, 3924, 3042, 3791, 15, 7073, 27, 3042, 3791, 15, 7067, 27, 3042, 3044, 15, 7071, 27, 3042, 3793, 2009}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int x^3 \text {Si}(b x)^2 \, dx\) |
\(\Big \downarrow \) 7061 |
\(\displaystyle \frac {1}{4} x^4 \text {Si}(b x)^2-\frac {1}{2} \int x^3 \sin (b x) \text {Si}(b x)dx\) |
\(\Big \downarrow \) 7067 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}-\int \frac {x^2 \cos (b x) \sin (b x)}{b}dx+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}-\frac {\int x^2 \cos (b x) \sin (b x)dx}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3924 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\int x \sin ^2(b x)dx}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\int x \sin (b x)^2dx}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3791 |
\(\displaystyle \frac {1}{2} \left (-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\int xdx}{2}+\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}}{b}}{b}-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 15 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \int x^2 \cos (b x) \text {Si}(b x)dx}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 7073 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \int x \sin (b x) \text {Si}(b x)dx}{b}-\int \frac {x \sin ^2(b x)}{b}dx+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \int x \sin (b x) \text {Si}(b x)dx}{b}-\frac {\int x \sin ^2(b x)dx}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \int x \sin (b x) \text {Si}(b x)dx}{b}-\frac {\int x \sin (b x)^2dx}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3791 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {\frac {\int xdx}{2}+\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}}{b}-\frac {2 \int x \sin (b x) \text {Si}(b x)dx}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 15 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \int x \sin (b x) \text {Si}(b x)dx}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 7067 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\int \cos (b x) \text {Si}(b x)dx}{b}+\int \frac {\cos (b x) \sin (b x)}{b}dx-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\int \cos (b x) \text {Si}(b x)dx}{b}+\frac {\int \cos (b x) \sin (b x)dx}{b}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\int \cos (b x) \text {Si}(b x)dx}{b}+\frac {\int \cos (b x) \sin (b x)dx}{b}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3044 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\int \sin (b x)d\sin (b x)}{b^2}+\frac {\int \cos (b x) \text {Si}(b x)dx}{b}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 15 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\int \cos (b x) \text {Si}(b x)dx}{b}+\frac {\sin ^2(b x)}{2 b^2}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 7071 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\frac {\text {Si}(b x) \sin (b x)}{b}-\int \frac {\sin ^2(b x)}{b x}dx}{b}+\frac {\sin ^2(b x)}{2 b^2}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\frac {\text {Si}(b x) \sin (b x)}{b}-\frac {\int \frac {\sin ^2(b x)}{x}dx}{b}}{b}+\frac {\sin ^2(b x)}{2 b^2}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3042 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\frac {\text {Si}(b x) \sin (b x)}{b}-\frac {\int \frac {\sin (b x)^2}{x}dx}{b}}{b}+\frac {\sin ^2(b x)}{2 b^2}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 3793 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\frac {\text {Si}(b x) \sin (b x)}{b}-\frac {\int \left (\frac {1}{2 x}-\frac {\cos (2 b x)}{2 x}\right )dx}{b}}{b}+\frac {\sin ^2(b x)}{2 b^2}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
\(\Big \downarrow \) 2009 |
\(\displaystyle \frac {1}{2} \left (-\frac {3 \left (-\frac {2 \left (\frac {\sin ^2(b x)}{2 b^2}+\frac {\frac {\text {Si}(b x) \sin (b x)}{b}-\frac {\frac {\log (x)}{2}-\frac {\operatorname {CosIntegral}(2 b x)}{2}}{b}}{b}-\frac {x \text {Si}(b x) \cos (b x)}{b}\right )}{b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Si}(b x) \sin (b x)}{b}\right )}{b}-\frac {\frac {x^2 \sin ^2(b x)}{2 b}-\frac {\frac {\sin ^2(b x)}{4 b^2}-\frac {x \sin (b x) \cos (b x)}{2 b}+\frac {x^2}{4}}{b}}{b}+\frac {x^3 \text {Si}(b x) \cos (b x)}{b}\right )+\frac {1}{4} x^4 \text {Si}(b x)^2\) |
Input:
Int[x^3*SinIntegral[b*x]^2,x]
Output:
(x^4*SinIntegral[b*x]^2)/4 + (-(((x^2*Sin[b*x]^2)/(2*b) - (x^2/4 - (x*Cos[ b*x]*Sin[b*x])/(2*b) + Sin[b*x]^2/(4*b^2))/b)/b) + (x^3*Cos[b*x]*SinIntegr al[b*x])/b - (3*(-((x^2/4 - (x*Cos[b*x]*Sin[b*x])/(2*b) + Sin[b*x]^2/(4*b^ 2))/b) + (x^2*Sin[b*x]*SinIntegral[b*x])/b - (2*(Sin[b*x]^2/(2*b^2) - (x*C os[b*x]*SinIntegral[b*x])/b + (-((-1/2*CosIntegral[2*b*x] + Log[x]/2)/b) + (Sin[b*x]*SinIntegral[b*x])/b)/b))/b))/b)/2
Int[(a_.)*(x_)^(m_.), x_Symbol] :> Simp[a*(x^(m + 1)/(m + 1)), x] /; FreeQ[ {a, m}, x] && NeQ[m, -1]
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[cos[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_ Symbol] :> Simp[1/(a*f) Subst[Int[x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a *Sin[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] && !(I ntegerQ[(m - 1)/2] && LtQ[0, m, n])
Int[((c_.) + (d_.)*(x_))*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Simp[d*((b*Sin[e + f*x])^n/(f^2*n^2)), x] + (-Simp[b*(c + d*x)*Cos[e + f*x ]*((b*Sin[e + f*x])^(n - 1)/(f*n)), x] + Simp[b^2*((n - 1)/n) Int[(c + d* x)*(b*Sin[e + f*x])^(n - 2), x], x]) /; FreeQ[{b, c, d, e, f}, x] && GtQ[n, 1]
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f , m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
Int[Cos[(a_.) + (b_.)*(x_)^(n_.)]*(x_)^(m_.)*Sin[(a_.) + (b_.)*(x_)^(n_.)]^ (p_.), x_Symbol] :> Simp[x^(m - n + 1)*(Sin[a + b*x^n]^(p + 1)/(b*n*(p + 1) )), x] - Simp[(m - n + 1)/(b*n*(p + 1)) Int[x^(m - n)*Sin[a + b*x^n]^(p + 1), x], x] /; FreeQ[{a, b, p}, x] && LtQ[0, n, m + 1] && NeQ[p, -1]
Int[(x_)^(m_.)*SinIntegral[(b_.)*(x_)]^2, x_Symbol] :> Simp[x^(m + 1)*(SinI ntegral[b*x]^2/(m + 1)), x] - Simp[2/(m + 1) Int[x^m*Sin[b*x]*SinIntegral [b*x], x], x] /; FreeQ[b, x] && IGtQ[m, 0]
Int[((e_.) + (f_.)*(x_))^(m_.)*Sin[(a_.) + (b_.)*(x_)]*SinIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[(-(e + f*x)^m)*Cos[a + b*x]*(SinIntegral[c + d*x]/b), x] + (Simp[d/b Int[(e + f*x)^m*Cos[a + b*x]*(Sin[c + d*x]/(c + d*x)), x], x] + Simp[f*(m/b) Int[(e + f*x)^(m - 1)*Cos[a + b*x]*SinIntegr al[c + d*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]
Int[Cos[(a_.) + (b_.)*(x_)]*SinIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> S imp[Sin[a + b*x]*(SinIntegral[c + d*x]/b), x] - Simp[d/b Int[Sin[a + b*x] *(Sin[c + d*x]/(c + d*x)), x], x] /; FreeQ[{a, b, c, d}, x]
Int[Cos[(a_.) + (b_.)*(x_)]*((e_.) + (f_.)*(x_))^(m_.)*SinIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[(e + f*x)^m*Sin[a + b*x]*(SinIntegral[c + d* x]/b), x] + (-Simp[d/b Int[(e + f*x)^m*Sin[a + b*x]*(Sin[c + d*x]/(c + d* x)), x], x] - Simp[f*(m/b) Int[(e + f*x)^(m - 1)*Sin[a + b*x]*SinIntegral [c + d*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]
Time = 7.20 (sec) , antiderivative size = 154, normalized size of antiderivative = 1.03
method | result | size |
derivativedivides | \(\frac {\frac {b^{4} x^{4} \operatorname {Si}\left (b x \right )^{2}}{4}-2 \,\operatorname {Si}\left (b x \right ) \left (-\frac {b^{3} x^{3} \cos \left (b x \right )}{4}+\frac {3 b^{2} x^{2} \sin \left (b x \right )}{4}-\frac {3 \sin \left (b x \right )}{2}+\frac {3 b x \cos \left (b x \right )}{2}\right )+\frac {\cos \left (b x \right )^{2} b^{2} x^{2}}{4}-\frac {b x \left (\frac {\sin \left (b x \right ) \cos \left (b x \right )}{2}+\frac {b x}{2}\right )}{2}-\frac {b^{2} x^{2}}{4}+\frac {\sin \left (b x \right )^{2}}{2}+\frac {3 b x \left (-\frac {\sin \left (b x \right ) \cos \left (b x \right )}{2}+\frac {b x}{2}\right )}{2}-\frac {3 \cos \left (b x \right )^{2}}{2}-\frac {3 \ln \left (b x \right )}{2}+\frac {3 \,\operatorname {Ci}\left (2 b x \right )}{2}}{b^{4}}\) | \(154\) |
default | \(\frac {\frac {b^{4} x^{4} \operatorname {Si}\left (b x \right )^{2}}{4}-2 \,\operatorname {Si}\left (b x \right ) \left (-\frac {b^{3} x^{3} \cos \left (b x \right )}{4}+\frac {3 b^{2} x^{2} \sin \left (b x \right )}{4}-\frac {3 \sin \left (b x \right )}{2}+\frac {3 b x \cos \left (b x \right )}{2}\right )+\frac {\cos \left (b x \right )^{2} b^{2} x^{2}}{4}-\frac {b x \left (\frac {\sin \left (b x \right ) \cos \left (b x \right )}{2}+\frac {b x}{2}\right )}{2}-\frac {b^{2} x^{2}}{4}+\frac {\sin \left (b x \right )^{2}}{2}+\frac {3 b x \left (-\frac {\sin \left (b x \right ) \cos \left (b x \right )}{2}+\frac {b x}{2}\right )}{2}-\frac {3 \cos \left (b x \right )^{2}}{2}-\frac {3 \ln \left (b x \right )}{2}+\frac {3 \,\operatorname {Ci}\left (2 b x \right )}{2}}{b^{4}}\) | \(154\) |
Input:
int(x^3*Si(b*x)^2,x,method=_RETURNVERBOSE)
Output:
1/b^4*(1/4*b^4*x^4*Si(b*x)^2-2*Si(b*x)*(-1/4*b^3*x^3*cos(b*x)+3/4*b^2*x^2* sin(b*x)-3/2*sin(b*x)+3/2*b*x*cos(b*x))+1/4*cos(b*x)^2*b^2*x^2-1/2*b*x*(1/ 2*sin(b*x)*cos(b*x)+1/2*b*x)-1/4*b^2*x^2+1/2*sin(b*x)^2+3/2*b*x*(-1/2*sin( b*x)*cos(b*x)+1/2*b*x)-3/2*cos(b*x)^2-3/2*ln(b*x)+3/2*Ci(2*b*x))
Time = 0.09 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.70 \[ \int x^3 \text {Si}(b x)^2 \, dx=\frac {b^{4} x^{4} \operatorname {Si}\left (b x\right )^{2} + b^{2} x^{2} + {\left (b^{2} x^{2} - 8\right )} \cos \left (b x\right )^{2} + 2 \, {\left (b^{3} x^{3} - 6 \, b x\right )} \cos \left (b x\right ) \operatorname {Si}\left (b x\right ) - 2 \, {\left (2 \, b x \cos \left (b x\right ) + 3 \, {\left (b^{2} x^{2} - 2\right )} \operatorname {Si}\left (b x\right )\right )} \sin \left (b x\right ) + 6 \, \operatorname {Ci}\left (2 \, b x\right ) - 6 \, \log \left (x\right )}{4 \, b^{4}} \] Input:
integrate(x^3*sin_integral(b*x)^2,x, algorithm="fricas")
Output:
1/4*(b^4*x^4*sin_integral(b*x)^2 + b^2*x^2 + (b^2*x^2 - 8)*cos(b*x)^2 + 2* (b^3*x^3 - 6*b*x)*cos(b*x)*sin_integral(b*x) - 2*(2*b*x*cos(b*x) + 3*(b^2* x^2 - 2)*sin_integral(b*x))*sin(b*x) + 6*cos_integral(2*b*x) - 6*log(x))/b ^4
\[ \int x^3 \text {Si}(b x)^2 \, dx=\int x^{3} \operatorname {Si}^{2}{\left (b x \right )}\, dx \] Input:
integrate(x**3*Si(b*x)**2,x)
Output:
Integral(x**3*Si(b*x)**2, x)
\[ \int x^3 \text {Si}(b x)^2 \, dx=\int { x^{3} \operatorname {Si}\left (b x\right )^{2} \,d x } \] Input:
integrate(x^3*sin_integral(b*x)^2,x, algorithm="maxima")
Output:
integrate(x^3*sin_integral(b*x)^2, x)
Time = 0.13 (sec) , antiderivative size = 117, normalized size of antiderivative = 0.79 \[ \int x^3 \text {Si}(b x)^2 \, dx=\frac {1}{4} \, x^{4} \operatorname {Si}\left (b x\right )^{2} + \frac {1}{2} \, {\left (\frac {{\left (b^{3} x^{3} - 6 \, b x\right )} \cos \left (b x\right )}{b^{4}} - \frac {3 \, {\left (b^{2} x^{2} - 2\right )} \sin \left (b x\right )}{b^{4}}\right )} \operatorname {Si}\left (b x\right ) + \frac {b^{2} x^{2} \cos \left (2 \, b x\right ) + 3 \, b^{2} x^{2} - 4 \, b x \sin \left (2 \, b x\right ) - 8 \, \cos \left (2 \, b x\right ) + 6 \, \operatorname {Ci}\left (2 \, b x\right ) + 6 \, \operatorname {Ci}\left (-2 \, b x\right ) - 12 \, \log \left (x\right )}{8 \, b^{4}} \] Input:
integrate(x^3*sin_integral(b*x)^2,x, algorithm="giac")
Output:
1/4*x^4*sin_integral(b*x)^2 + 1/2*((b^3*x^3 - 6*b*x)*cos(b*x)/b^4 - 3*(b^2 *x^2 - 2)*sin(b*x)/b^4)*sin_integral(b*x) + 1/8*(b^2*x^2*cos(2*b*x) + 3*b^ 2*x^2 - 4*b*x*sin(2*b*x) - 8*cos(2*b*x) + 6*cos_integral(2*b*x) + 6*cos_in tegral(-2*b*x) - 12*log(x))/b^4
Timed out. \[ \int x^3 \text {Si}(b x)^2 \, dx=\int x^3\,{\mathrm {sinint}\left (b\,x\right )}^2 \,d x \] Input:
int(x^3*sinint(b*x)^2,x)
Output:
int(x^3*sinint(b*x)^2, x)
\[ \int x^3 \text {Si}(b x)^2 \, dx=\int \mathit {si} \left (b x \right )^{2} x^{3}d x \] Input:
int(x^3*Si(b*x)^2,x)
Output:
int(si(b*x)**2*x**3,x)