\(\int x^3 \text {Shi}(b x)^2 \, dx\) [10]

Optimal result
Mathematica [A] (verified)
Rubi [A] (verified)
Maple [A] (verified)
Fricas [F]
Sympy [F]
Maxima [F]
Giac [F]
Mupad [F(-1)]
Reduce [F]

Optimal result

Integrand size = 10, antiderivative size = 149 \[ \int x^3 \text {Shi}(b x)^2 \, dx=\frac {x^2}{2 b^2}-\frac {3 \text {Chi}(2 b x)}{2 b^4}+\frac {3 \log (x)}{2 b^4}-\frac {x \cosh (b x) \sinh (b x)}{b^3}+\frac {2 \sinh ^2(b x)}{b^4}+\frac {x^2 \sinh ^2(b x)}{4 b^2}-\frac {3 x \cosh (b x) \text {Shi}(b x)}{b^3}-\frac {x^3 \cosh (b x) \text {Shi}(b x)}{2 b}+\frac {3 \sinh (b x) \text {Shi}(b x)}{b^4}+\frac {3 x^2 \sinh (b x) \text {Shi}(b x)}{2 b^2}+\frac {1}{4} x^4 \text {Shi}(b x)^2 \] Output:

1/2*x^2/b^2-3/2*Chi(2*b*x)/b^4+3/2*ln(x)/b^4-x*cosh(b*x)*sinh(b*x)/b^3+2*s 
inh(b*x)^2/b^4+1/4*x^2*sinh(b*x)^2/b^2-3*x*cosh(b*x)*Shi(b*x)/b^3-1/2*x^3* 
cosh(b*x)*Shi(b*x)/b+3*sinh(b*x)*Shi(b*x)/b^4+3/2*x^2*sinh(b*x)*Shi(b*x)/b 
^2+1/4*x^4*Shi(b*x)^2
 

Mathematica [A] (verified)

Time = 0.08 (sec) , antiderivative size = 107, normalized size of antiderivative = 0.72 \[ \int x^3 \text {Shi}(b x)^2 \, dx=\frac {3 b^2 x^2+8 \cosh (2 b x)+b^2 x^2 \cosh (2 b x)-12 \text {Chi}(2 b x)+12 \log (x)-4 b x \sinh (2 b x)-4 \left (b x \left (6+b^2 x^2\right ) \cosh (b x)-3 \left (2+b^2 x^2\right ) \sinh (b x)\right ) \text {Shi}(b x)+2 b^4 x^4 \text {Shi}(b x)^2}{8 b^4} \] Input:

Integrate[x^3*SinhIntegral[b*x]^2,x]
 

Output:

(3*b^2*x^2 + 8*Cosh[2*b*x] + b^2*x^2*Cosh[2*b*x] - 12*CoshIntegral[2*b*x] 
+ 12*Log[x] - 4*b*x*Sinh[2*b*x] - 4*(b*x*(6 + b^2*x^2)*Cosh[b*x] - 3*(2 + 
b^2*x^2)*Sinh[b*x])*SinhIntegral[b*x] + 2*b^4*x^4*SinhIntegral[b*x]^2)/(8* 
b^4)
 

Rubi [A] (verified)

Time = 1.44 (sec) , antiderivative size = 229, normalized size of antiderivative = 1.54, number of steps used = 27, number of rules used = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 2.600, Rules used = {7090, 7096, 27, 5895, 3042, 25, 3791, 15, 7102, 27, 3042, 25, 3791, 15, 7096, 27, 3042, 26, 3044, 15, 7100, 27, 3042, 25, 3793, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int x^3 \text {Shi}(b x)^2 \, dx\)

\(\Big \downarrow \) 7090

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2-\frac {1}{2} \int x^3 \sinh (b x) \text {Shi}(b x)dx\)

\(\Big \downarrow \) 7096

\(\displaystyle \frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\int \frac {x^2 \cosh (b x) \sinh (b x)}{b}dx-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {\int x^2 \cosh (b x) \sinh (b x)dx}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 5895

\(\displaystyle \frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {\frac {x^2 \sinh ^2(b x)}{2 b}-\frac {\int x \sinh ^2(b x)dx}{b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {\frac {x^2 \sinh ^2(b x)}{2 b}-\frac {\int -x \sin (i b x)^2dx}{b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {\frac {x^2 \sinh ^2(b x)}{2 b}+\frac {\int x \sin (i b x)^2dx}{b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 3791

\(\displaystyle \frac {1}{2} \left (\frac {\frac {\frac {\int xdx}{2}+\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}+\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 15

\(\displaystyle \frac {1}{2} \left (\frac {3 \int x^2 \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 7102

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}-\int \frac {x \sinh ^2(b x)}{b}dx+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}-\frac {\int x \sinh ^2(b x)dx}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}-\frac {\int -x \sin (i b x)^2dx}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}+\frac {\int x \sin (i b x)^2dx}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 3791

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (\frac {\frac {\int xdx}{2}+\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}}{b}-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 15

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \int x \sinh (b x) \text {Shi}(b x)dx}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 7096

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}-\int \frac {\cosh (b x) \sinh (b x)}{b}dx+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}-\frac {\int \cosh (b x) \sinh (b x)dx}{b}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}-\frac {\int -i \cos (i b x) \sin (i b x)dx}{b}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 26

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {i \int \cos (i b x) \sin (i b x)dx}{b}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 3044

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (\frac {\int i \sinh (b x)d(i \sinh (b x))}{b^2}-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 15

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\int \cosh (b x) \text {Shi}(b x)dx}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 7100

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\frac {\text {Shi}(b x) \sinh (b x)}{b}-\int \frac {\sinh ^2(b x)}{b x}dx}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\frac {\text {Shi}(b x) \sinh (b x)}{b}-\frac {\int \frac {\sinh ^2(b x)}{x}dx}{b}}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 3042

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\frac {\text {Shi}(b x) \sinh (b x)}{b}-\frac {\int -\frac {\sin (i b x)^2}{x}dx}{b}}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 25

\(\displaystyle \frac {1}{4} x^4 \text {Shi}(b x)^2+\frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\frac {\text {Shi}(b x) \sinh (b x)}{b}+\frac {\int \frac {\sin (i b x)^2}{x}dx}{b}}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )\)

\(\Big \downarrow \) 3793

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\frac {\int \left (\frac {1}{2 x}-\frac {\cosh (2 b x)}{2 x}\right )dx}{b}+\frac {\text {Shi}(b x) \sinh (b x)}{b}}{b}-\frac {\sinh ^2(b x)}{2 b^2}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

\(\Big \downarrow \) 2009

\(\displaystyle \frac {1}{2} \left (\frac {3 \left (-\frac {2 \left (-\frac {\sinh ^2(b x)}{2 b^2}-\frac {\frac {\frac {\log (x)}{2}-\frac {\text {Chi}(2 b x)}{2}}{b}+\frac {\text {Shi}(b x) \sinh (b x)}{b}}{b}+\frac {x \text {Shi}(b x) \cosh (b x)}{b}\right )}{b}+\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \text {Shi}(b x) \sinh (b x)}{b}\right )}{b}+\frac {\frac {\frac {\sinh ^2(b x)}{4 b^2}-\frac {x \sinh (b x) \cosh (b x)}{2 b}+\frac {x^2}{4}}{b}+\frac {x^2 \sinh ^2(b x)}{2 b}}{b}-\frac {x^3 \text {Shi}(b x) \cosh (b x)}{b}\right )+\frac {1}{4} x^4 \text {Shi}(b x)^2\)

Input:

Int[x^3*SinhIntegral[b*x]^2,x]
 

Output:

(x^4*SinhIntegral[b*x]^2)/4 + (((x^2*Sinh[b*x]^2)/(2*b) + (x^2/4 - (x*Cosh 
[b*x]*Sinh[b*x])/(2*b) + Sinh[b*x]^2/(4*b^2))/b)/b - (x^3*Cosh[b*x]*SinhIn 
tegral[b*x])/b + (3*((x^2/4 - (x*Cosh[b*x]*Sinh[b*x])/(2*b) + Sinh[b*x]^2/ 
(4*b^2))/b + (x^2*Sinh[b*x]*SinhIntegral[b*x])/b - (2*(-1/2*Sinh[b*x]^2/b^ 
2 + (x*Cosh[b*x]*SinhIntegral[b*x])/b - ((-1/2*CoshIntegral[2*b*x] + Log[x 
]/2)/b + (Sinh[b*x]*SinhIntegral[b*x])/b)/b))/b))/b)/2
 

Defintions of rubi rules used

rule 15
Int[(a_.)*(x_)^(m_.), x_Symbol] :> Simp[a*(x^(m + 1)/(m + 1)), x] /; FreeQ[ 
{a, m}, x] && NeQ[m, -1]
 

rule 25
Int[-(Fx_), x_Symbol] :> Simp[Identity[-1]   Int[Fx, x], x]
 

rule 26
Int[(Complex[0, a_])*(Fx_), x_Symbol] :> Simp[(Complex[Identity[0], a])   I 
nt[Fx, x], x] /; FreeQ[a, x] && EqQ[a^2, 1]
 

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 

rule 3042
Int[u_, x_Symbol] :> Int[DeactivateTrig[u, x], x] /; FunctionOfTrigOfLinear 
Q[u, x]
 

rule 3044
Int[cos[(e_.) + (f_.)*(x_)]^(n_.)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_.), x_ 
Symbol] :> Simp[1/(a*f)   Subst[Int[x^m*(1 - x^2/a^2)^((n - 1)/2), x], x, a 
*Sin[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2] &&  !(I 
ntegerQ[(m - 1)/2] && LtQ[0, m, n])
 

rule 3791
Int[((c_.) + (d_.)*(x_))*((b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> 
 Simp[d*((b*Sin[e + f*x])^n/(f^2*n^2)), x] + (-Simp[b*(c + d*x)*Cos[e + f*x 
]*((b*Sin[e + f*x])^(n - 1)/(f*n)), x] + Simp[b^2*((n - 1)/n)   Int[(c + d* 
x)*(b*Sin[e + f*x])^(n - 2), x], x]) /; FreeQ[{b, c, d, e, f}, x] && GtQ[n, 
 1]
 

rule 3793
Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> In 
t[ExpandTrigReduce[(c + d*x)^m, Sin[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f 
, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1]))
 

rule 5895
Int[Cosh[(a_.) + (b_.)*(x_)^(n_.)]*(x_)^(m_.)*Sinh[(a_.) + (b_.)*(x_)^(n_.) 
]^(p_.), x_Symbol] :> Simp[x^(m - n + 1)*(Sinh[a + b*x^n]^(p + 1)/(b*n*(p + 
 1))), x] - Simp[(m - n + 1)/(b*n*(p + 1))   Int[x^(m - n)*Sinh[a + b*x^n]^ 
(p + 1), x], x] /; FreeQ[{a, b, p}, x] && LtQ[0, n, m + 1] && NeQ[p, -1]
 

rule 7090
Int[(x_)^(m_.)*SinhIntegral[(b_.)*(x_)]^2, x_Symbol] :> Simp[x^(m + 1)*(Sin 
hIntegral[b*x]^2/(m + 1)), x] - Simp[2/(m + 1)   Int[x^m*Sinh[b*x]*SinhInte 
gral[b*x], x], x] /; FreeQ[b, x] && IGtQ[m, 0]
 

rule 7096
Int[((e_.) + (f_.)*(x_))^(m_.)*Sinh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) 
+ (d_.)*(x_)], x_Symbol] :> Simp[(e + f*x)^m*Cosh[a + b*x]*(SinhIntegral[c 
+ d*x]/b), x] + (-Simp[d/b   Int[(e + f*x)^m*Cosh[a + b*x]*(Sinh[c + d*x]/( 
c + d*x)), x], x] - Simp[f*(m/b)   Int[(e + f*x)^(m - 1)*Cosh[a + b*x]*Sinh 
Integral[c + d*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]
 

rule 7100
Int[Cosh[(a_.) + (b_.)*(x_)]*SinhIntegral[(c_.) + (d_.)*(x_)], x_Symbol] :> 
 Simp[Sinh[a + b*x]*(SinhIntegral[c + d*x]/b), x] - Simp[d/b   Int[Sinh[a + 
 b*x]*(Sinh[c + d*x]/(c + d*x)), x], x] /; FreeQ[{a, b, c, d}, x]
 

rule 7102
Int[Cosh[(a_.) + (b_.)*(x_)]*((e_.) + (f_.)*(x_))^(m_.)*SinhIntegral[(c_.) 
+ (d_.)*(x_)], x_Symbol] :> Simp[(e + f*x)^m*Sinh[a + b*x]*(SinhIntegral[c 
+ d*x]/b), x] + (-Simp[d/b   Int[(e + f*x)^m*Sinh[a + b*x]*(Sinh[c + d*x]/( 
c + d*x)), x], x] - Simp[f*(m/b)   Int[(e + f*x)^(m - 1)*Sinh[a + b*x]*Sinh 
Integral[c + d*x], x], x]) /; FreeQ[{a, b, c, d, e, f}, x] && IGtQ[m, 0]
 
Maple [A] (verified)

Time = 0.60 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.81

method result size
derivativedivides \(\frac {\frac {b^{4} x^{4} \operatorname {Shi}\left (b x \right )^{2}}{4}-2 \,\operatorname {Shi}\left (b x \right ) \left (\frac {b^{3} x^{3} \cosh \left (b x \right )}{4}-\frac {3 b^{2} x^{2} \sinh \left (b x \right )}{4}+\frac {3 b x \cosh \left (b x \right )}{2}-\frac {3 \sinh \left (b x \right )}{2}\right )+\frac {b^{2} x^{2} \cosh \left (b x \right )^{2}}{4}-b x \cosh \left (b x \right ) \sinh \left (b x \right )+\frac {b^{2} x^{2}}{4}+2 \cosh \left (b x \right )^{2}+\frac {3 \ln \left (b x \right )}{2}-\frac {3 \,\operatorname {Chi}\left (2 b x \right )}{2}}{b^{4}}\) \(120\)
default \(\frac {\frac {b^{4} x^{4} \operatorname {Shi}\left (b x \right )^{2}}{4}-2 \,\operatorname {Shi}\left (b x \right ) \left (\frac {b^{3} x^{3} \cosh \left (b x \right )}{4}-\frac {3 b^{2} x^{2} \sinh \left (b x \right )}{4}+\frac {3 b x \cosh \left (b x \right )}{2}-\frac {3 \sinh \left (b x \right )}{2}\right )+\frac {b^{2} x^{2} \cosh \left (b x \right )^{2}}{4}-b x \cosh \left (b x \right ) \sinh \left (b x \right )+\frac {b^{2} x^{2}}{4}+2 \cosh \left (b x \right )^{2}+\frac {3 \ln \left (b x \right )}{2}-\frac {3 \,\operatorname {Chi}\left (2 b x \right )}{2}}{b^{4}}\) \(120\)

Input:

int(x^3*Shi(b*x)^2,x,method=_RETURNVERBOSE)
 

Output:

1/b^4*(1/4*b^4*x^4*Shi(b*x)^2-2*Shi(b*x)*(1/4*b^3*x^3*cosh(b*x)-3/4*b^2*x^ 
2*sinh(b*x)+3/2*b*x*cosh(b*x)-3/2*sinh(b*x))+1/4*b^2*x^2*cosh(b*x)^2-b*x*c 
osh(b*x)*sinh(b*x)+1/4*b^2*x^2+2*cosh(b*x)^2+3/2*ln(b*x)-3/2*Chi(2*b*x))
 

Fricas [F]

\[ \int x^3 \text {Shi}(b x)^2 \, dx=\int { x^{3} {\rm Shi}\left (b x\right )^{2} \,d x } \] Input:

integrate(x^3*Shi(b*x)^2,x, algorithm="fricas")
 

Output:

integral(x^3*sinh_integral(b*x)^2, x)
 

Sympy [F]

\[ \int x^3 \text {Shi}(b x)^2 \, dx=\int x^{3} \operatorname {Shi}^{2}{\left (b x \right )}\, dx \] Input:

integrate(x**3*Shi(b*x)**2,x)
 

Output:

Integral(x**3*Shi(b*x)**2, x)
 

Maxima [F]

\[ \int x^3 \text {Shi}(b x)^2 \, dx=\int { x^{3} {\rm Shi}\left (b x\right )^{2} \,d x } \] Input:

integrate(x^3*Shi(b*x)^2,x, algorithm="maxima")
 

Output:

integrate(x^3*Shi(b*x)^2, x)
 

Giac [F]

\[ \int x^3 \text {Shi}(b x)^2 \, dx=\int { x^{3} {\rm Shi}\left (b x\right )^{2} \,d x } \] Input:

integrate(x^3*Shi(b*x)^2,x, algorithm="giac")
 

Output:

integrate(x^3*Shi(b*x)^2, x)
 

Mupad [F(-1)]

Timed out. \[ \int x^3 \text {Shi}(b x)^2 \, dx=\int x^3\,{\mathrm {sinhint}\left (b\,x\right )}^2 \,d x \] Input:

int(x^3*sinhint(b*x)^2,x)
 

Output:

int(x^3*sinhint(b*x)^2, x)
 

Reduce [F]

\[ \int x^3 \text {Shi}(b x)^2 \, dx=\int \mathit {shi} \left (b x \right )^{2} x^{3}d x \] Input:

int(x^3*Shi(b*x)^2,x)
 

Output:

int(shi(b*x)**2*x**3,x)