2.148 problem 724

Internal problem ID [8304]

Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 1, Additional non-linear first order
Problem number: 724.
ODE order: 1.
ODE degree: 1.

CAS Maple gives this as type [[_1st_order, _with_symmetry_[F(x)*G(y),0]], [_Abel, 2nd type, class C]]

Solve \begin {gather*} \boxed {y^{\prime }+\frac {y^{3}}{\left (-1+y \ln \relax (x )-y\right ) x}=0} \end {gather*}

Solution by Maple

Time used: 0.047 (sec). Leaf size: 18

dsolve(diff(y(x),x) = -y(x)^3/(-1+y(x)*ln(x)-y(x))/x,y(x), singsol=all)
 

\[ y \relax (x ) = \frac {1}{-\LambertW \left (c_{1} {\mathrm e}^{-2} x \right )+\ln \relax (x )-2} \]

Solution by Mathematica

Time used: 11.133 (sec). Leaf size: 422

DSolve[y'[x] == -(y[x]^3/(x*(-1 - y[x] + Log[x]*y[x]))),y[x],x,IncludeSingularSolutions -> True]
 

\[ \text {Solve}\left [-\frac {\sqrt [3]{-2} \left (\frac {1-y(x) (\log (x)-4)}{\sqrt [3]{2} \sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+(-2)^{2/3}\right ) \left (\frac {2^{2/3} (y(x) (\log (x)-4)-1)}{\sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+(-2)^{2/3}\right ) \left (\log \left (\frac {2^{2/3} (1-y(x) (\log (x)-4))}{\sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+2 (-2)^{2/3}\right ) \left (\frac {\sqrt [3]{-1} (1-y(x) (\log (x)-4))}{\sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+1\right )-\log \left (\frac {2^{2/3} (y(x) (\log (x)-4)-1)}{\sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+(-2)^{2/3}\right ) \left (\frac {\sqrt [3]{-1} (1-y(x) (\log (x)-4))}{\sqrt [3]{-\frac {1}{(\log (x)-1)^3}} (\log (x)-1) (y(x) (\log (x)-1)-1)}+1\right )+3\right )}{9 \left (\frac {(y(x) (\log (x)-4)-1)^3}{(y(x) (\log (x)-1)-1)^3}+\frac {3 \sqrt [3]{-1} (y(x) (\log (x)-4)-1)}{\left (-\frac {1}{(\log (x)-1)^3}\right )^{4/3} (\log (x)-1)^4 (y(x) (\log (x)-1)-1)}+2\right )}=\frac {1}{9} 2^{2/3} \left (-\frac {1}{(\log (x)-1)^3}\right )^{2/3} \log (x) (\log (x)-1)^2+c_1,y(x)\right ] \]