5.14 problem Problem 5.15 part 3

Internal problem ID [5158]

Book: THEORY OF DIFFERENTIAL EQUATIONS IN ENGINEERING AND MECHANICS. K.T. CHAU, CRC Press. Boca Raton, FL. 2018
Section: Chapter 5. Systems of First Order Differential Equations. Section 5.11 Problems. Page 360
Problem number: Problem 5.15 part 3.
ODE order: 1.
ODE degree: 1.

Solve \begin {align*} x_{1}^{\prime }\relax (t )&=x_{1}\relax (t )+x_{2}\relax (t )-8\\ x_{2}^{\prime }\relax (t )&=x_{1}\relax (t )+x_{2}\relax (t )+3 \end {align*}

With initial conditions \[ [x_{1}\relax (0) = 1, x_{2}\relax (0) = 2] \]

Solution by Maple

Time used: 0.008 (sec). Leaf size: 30

dsolve([diff(x__1(t),t) = x__1(t)+x__2(t)-8, diff(x__2(t),t) = x__1(t)+x__2(t)+3, x__1(0) = 1, x__2(0) = 2],[x__1(t), x__2(t)], singsol=all)
 

\[ x_{1}\relax (t ) = \frac {{\mathrm e}^{2 t}}{4}+\frac {3}{4}-\frac {11 t}{2} \] \[ x_{2}\relax (t ) = \frac {{\mathrm e}^{2 t}}{4}+\frac {11 t}{2}+\frac {7}{4} \]

Solution by Mathematica

Time used: 0.008 (sec). Leaf size: 36

DSolve[{x1'[t]==x1[t]+x2[t]-8,x2'[t]==x1[t]+x2[t]+3},{x1[0]==1,x2[0]==2},{x1[t],x2[t]},t,IncludeSingularSolutions -> True]
 

\begin{align*} \text {x1}(t)\to \frac {1}{4} \left (-22 t+e^{2 t}+3\right ) \\ \text {x2}(t)\to \frac {1}{4} \left (22 t+e^{2 t}+7\right ) \\ \end{align*}