7.101 problem 1692 (book 6.101)

Internal problem ID [9266]

Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 6, non-linear second order
Problem number: 1692 (book 6.101).
ODE order: 2.
ODE degree: 1.

CAS Maple gives this as type [NONE]

\[ \boxed {\left (a \,x^{2}+b x +c \right )^{\frac {3}{2}} y^{\prime \prime }-F \left (\frac {y}{\sqrt {a \,x^{2}+b x +c}}\right )=0} \]

Solution by Maple

Time used: 0.078 (sec). Leaf size: 254

dsolve((a*x^2+b*x+c)^(3/2)*diff(diff(y(x),x),x)-F(y(x)/(a*x^2+b*x+c)^(1/2))=0,y(x), singsol=all)
 

\begin{align*} y \left (x \right ) = \operatorname {RootOf}\left (4 \textit {\_Z} a c -\textit {\_Z} \,b^{2}-4 F \left (\frac {\textit {\_Z}}{\sqrt {a \,x^{2}+x b +c}}\right ) \sqrt {a \,x^{2}+x b +c}\right ) \\ y \left (x \right ) = \operatorname {RootOf}\left (-2 \left (\int _{}^{\textit {\_Z}}\frac {a}{\sqrt {4 c_{1} a^{2}-4 c \,\textit {\_g}^{2} a +\textit {\_g}^{2} b^{2}+8 \left (\int F \left (\textit {\_g} \right )d \textit {\_g} \right )}}d \textit {\_g} \right ) \sqrt {4 a c -b^{2}}-2 a \arctan \left (\frac {2 a x +b}{\sqrt {4 a c -b^{2}}}\right )+c_{2} \sqrt {4 a c -b^{2}}\right ) \sqrt {a \,x^{2}+x b +c} \\ y \left (x \right ) = \operatorname {RootOf}\left (2 \left (\int _{}^{\textit {\_Z}}\frac {a}{\sqrt {4 c_{1} a^{2}-4 c \,\textit {\_g}^{2} a +\textit {\_g}^{2} b^{2}+8 \left (\int F \left (\textit {\_g} \right )d \textit {\_g} \right )}}d \textit {\_g} \right ) \sqrt {4 a c -b^{2}}-2 a \arctan \left (\frac {2 a x +b}{\sqrt {4 a c -b^{2}}}\right )+c_{2} \sqrt {4 a c -b^{2}}\right ) \sqrt {a \,x^{2}+x b +c} \\ \end{align*}

Solution by Mathematica

Time used: 16.802 (sec). Leaf size: 251

DSolve[-f[y[x]/Sqrt[c + b*x + a*x^2]] + (c + b*x + a*x^2)^(3/2)*y''[x] == 0,y[x],x,IncludeSingularSolutions -> True]
 

\begin{align*} \text {Solve}\left [2 a \arctan \left (\frac {2 a x+b}{\sqrt {4 a c-b^2}}\right )+2 \sqrt {4 a c-b^2} \int _1^{\frac {y(x)}{\sqrt {c+x (b+a x)}}}\frac {a}{\sqrt {4 c_1 a^2+\left (b^2-4 a c\right ) K[3]^2+8 \int _1^{K[3]}f(K[2])dK[2]}}dK[3]=c_2 \sqrt {4 a c-b^2},y(x)\right ] \\ \text {Solve}\left [2 a \arctan \left (\frac {2 a x+b}{\sqrt {4 a c-b^2}}\right )-2 \sqrt {4 a c-b^2} \int _1^{\frac {y(x)}{\sqrt {c+x (b+a x)}}}\frac {a}{\sqrt {4 c_1 a^2+\left (b^2-4 a c\right ) K[5]^2+8 \int _1^{K[5]}f(K[4])dK[4]}}dK[5]=c_2 \sqrt {4 a c-b^2},y(x)\right ] \\ \end{align*}