Internal problem ID [10050]
Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 6, non-linear second order
Problem number: 1719 (book 6.128).
ODE order: 2.
ODE degree: 1.
CAS Maple gives this as type [[_2nd_order, _missing_x], [_2nd_order, _reducible, _mu_xy]]
\[ \boxed {y^{\prime \prime } y+a {y^{\prime }}^{2}+b y y^{\prime }+c y^{2}+d y^{1-a}=0} \]
✓ Solution by Maple
Time used: 0.188 (sec). Leaf size: 150
dsolve(diff(diff(y(x),x),x)*y(x)+a*diff(y(x),x)^2+b*y(x)*diff(y(x),x)+c*y(x)^2+d*y(x)^(1-a)=0,y(x), singsol=all)
\[ y \left (x \right ) = {\mathrm e}^{\frac {x \sqrt {-4 a c +b^{2}-4 c}}{2 a +2}} {\mathrm e}^{-\frac {x b}{2 \left (a +1\right )}} \left (\frac {c^{2} \left (-4 a c +b^{2}-4 c \right )}{\left (a c c_{2} {\mathrm e}^{-x \sqrt {-4 a c +b^{2}-4 c}}+c c_{2} {\mathrm e}^{-x \sqrt {-4 a c +b^{2}-4 c}}-d \,{\mathrm e}^{-\frac {\left (-b +\sqrt {-4 a c +b^{2}-4 c}\right ) x}{2}} \sqrt {-4 a c +b^{2}-4 c}-c_{1} c a -c_{1} c \right )^{2}}\right )^{-\frac {1}{2 \left (a +1\right )}} \]
✓ Solution by Mathematica
Time used: 61.36 (sec). Leaf size: 396
DSolve[c*y[x]^2 + d*y[x]^(1 - a) + b*y[x]*y'[x] + a*y'[x]^2 + y[x]*y''[x] == 0,y[x],x,IncludeSingularSolutions -> True]
\[ y(x)\to \left (-\frac {\exp \left (-\frac {x \left (b \sqrt {b^2-4 (a+1) c}-2 (a+1) c+b^2\right )}{\sqrt {b^2-4 (a+1) c}+b}\right ) \left (b^2 \left (d e^{\frac {1}{2} x \left (\sqrt {b^2-4 (a+1) c}+b\right )}-c c_2 \exp \left (\frac {x \left (b \sqrt {b^2-4 (a+1) c}-4 (a+1) c+b^2\right )}{\sqrt {b^2-4 (a+1) c}+b}\right )\right )+(a+1) c \left (-4 d e^{\frac {1}{2} x \left (\sqrt {b^2-4 (a+1) c}+b\right )}+4 c c_2 \exp \left (\frac {x \left (b \sqrt {b^2-4 (a+1) c}-4 (a+1) c+b^2\right )}{\sqrt {b^2-4 (a+1) c}+b}\right )-c_1 \sqrt {b^2-4 (a+1) c}\right )+b d \sqrt {b^2-4 (a+1) c} e^{\frac {1}{2} x \left (\sqrt {b^2-4 (a+1) c}+b\right )}-b c \left (c_2 \sqrt {b^2-4 (a+1) c} \exp \left (\frac {x \left (b \sqrt {b^2-4 (a+1) c}-4 (a+1) c+b^2\right )}{\sqrt {b^2-4 (a+1) c}+b}\right )+(a+1) c_1\right )\right )}{c \left (b \sqrt {b^2-4 (a+1) c}-4 (a+1) c+b^2\right )}\right ){}^{\frac {1}{a+1}} \]