60.1.375 problem 376

Internal problem ID [10389]
Book : Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section : Chapter 1, linear first order
Problem number : 376
Date solved : Monday, January 27, 2025 at 07:38:52 PM
CAS classification : [_quadrature]

\begin{align*} {y^{\prime }}^{2}+a y^{\prime }+b y&=0 \end{align*}

Solution by Maple

Time used: 0.033 (sec). Leaf size: 245

dsolve(diff(y(x),x)^2+a*diff(y(x),x)+b*y(x) = 0,y(x), singsol=all)
 
\begin{align*} y &= -\frac {a^{2} \left (\operatorname {LambertW}\left (-\frac {2 \sqrt {-b}\, {\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a}\right )+2\right ) \operatorname {LambertW}\left (-\frac {2 \sqrt {-b}\, {\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a}\right )}{4 b} \\ y &= -\frac {a^{2} \left (\operatorname {LambertW}\left (\frac {2 \sqrt {-b}\, {\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a}\right )+2\right ) \operatorname {LambertW}\left (\frac {2 \sqrt {-b}\, {\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a}\right )}{4 b} \\ y &= {\mathrm e}^{\frac {-a \operatorname {LambertW}\left (\frac {2 \,{\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a \sqrt {-\frac {1}{b}}}\right )-a +\left (-x +c_{1} \right ) b}{a}} \left (a \sqrt {-\frac {1}{b}}+{\mathrm e}^{\frac {-a \operatorname {LambertW}\left (\frac {2 \,{\mathrm e}^{\frac {\left (-x +c_{1} \right ) b -a}{a}}}{a \sqrt {-\frac {1}{b}}}\right )-a +\left (-x +c_{1} \right ) b}{a}}\right ) \\ \end{align*}

Solution by Mathematica

Time used: 0.817 (sec). Leaf size: 119

DSolve[b*y[x] + a*D[y[x],x] + D[y[x],x]^2==0,y[x],x,IncludeSingularSolutions -> True]
 
\begin{align*} y(x)\to \text {InverseFunction}\left [-\frac {\sqrt {a^2-4 \text {$\#$1} b}+a \log \left (b \left (\sqrt {a^2-4 \text {$\#$1} b}-a\right )\right )}{2 b}\&\right ]\left [\frac {x}{2}+c_1\right ] \\ y(x)\to \text {InverseFunction}\left [-\frac {\sqrt {a^2-4 \text {$\#$1} b}-a \log \left (b \left (\sqrt {a^2-4 \text {$\#$1} b}+a\right )\right )}{2 b}\&\right ]\left [-\frac {x}{2}+c_1\right ] \\ y(x)\to 0 \\ \end{align*}