Internal
problem
ID
[10850]
Book
:
Differential
Gleichungen,
E.
Kamke,
3rd
ed.
Chelsea
Pub.
NY,
1948
Section
:
Chapter
1,
Additional
non-linear
first
order
Problem
number
:
839
Date
solved
:
Monday, January 27, 2025 at 10:15:16 PM
CAS
classification
:
[[_1st_order, _with_linear_symmetries]]
\begin{align*} y^{\prime }&=\frac {\left ({\mathrm e}^{-\frac {y}{x}} y+{\mathrm e}^{-\frac {y}{x}} x +x^{2}\right ) {\mathrm e}^{\frac {y}{x}}}{x} \end{align*}
Time used: 0.020 (sec). Leaf size: 21
\[
y = \left (\ln \left (2\right )+\ln \left (\frac {x}{-x^{2}+c_{1}}\right )\right ) x
\]
Time used: 0.335 (sec). Leaf size: 533
\[
\text {Solve}\left [\int _1^{y(x)}-\frac {e^{\frac {K[2]}{x}} \int _1^x\left (\frac {e^{\frac {K[2]}{K[1]}} \left (e^{\frac {K[2]}{K[1]}} K[2]+2\right )}{4 K[1] \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )}-\frac {e^{\frac {2 K[2]}{K[1]}} \left (e^{\frac {K[2]}{K[1]}} K[2]+2\right )}{4 \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )^2}+\frac {-\frac {e^{\frac {K[2]}{K[1]}} K[2]}{K[1]}-e^{\frac {K[2]}{K[1]}}}{4 K[1]}+\frac {e^{\frac {K[2]}{K[1]}} \left (\frac {e^{\frac {K[2]}{K[1]}} K[2]}{K[1]}+e^{\frac {K[2]}{K[1]}}\right )}{4 \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )}+\frac {1}{2 K[1]^2}\right )dK[1] x^2+2 \int _1^x\left (\frac {e^{\frac {K[2]}{K[1]}} \left (e^{\frac {K[2]}{K[1]}} K[2]+2\right )}{4 K[1] \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )}-\frac {e^{\frac {2 K[2]}{K[1]}} \left (e^{\frac {K[2]}{K[1]}} K[2]+2\right )}{4 \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )^2}+\frac {-\frac {e^{\frac {K[2]}{K[1]}} K[2]}{K[1]}-e^{\frac {K[2]}{K[1]}}}{4 K[1]}+\frac {e^{\frac {K[2]}{K[1]}} \left (\frac {e^{\frac {K[2]}{K[1]}} K[2]}{K[1]}+e^{\frac {K[2]}{K[1]}}\right )}{4 \left (e^{\frac {K[2]}{K[1]}} K[1]+2\right )}+\frac {1}{2 K[1]^2}\right )dK[1] x+1}{x \left (e^{\frac {K[2]}{x}} x+2\right )}dK[2]+\int _1^x\left (\frac {y(x)}{2 K[1]^2}+\frac {2-e^{\frac {y(x)}{K[1]}} y(x)}{4 K[1]}+\frac {e^{\frac {y(x)}{K[1]}} \left (e^{\frac {y(x)}{K[1]}} y(x)+2\right )}{4 \left (e^{\frac {y(x)}{K[1]}} K[1]+2\right )}\right )dK[1]=c_1,y(x)\right ]
\]