7.20.7 problem 36

Internal problem ID [561]
Book : Elementary Differential Equations. By C. Henry Edwards, David E. Penney and David Calvis. 6th edition. 2008
Section : Chapter 4. Laplace transform methods. Section 4.4 (Derivatives, Integrals and products of transforms). Problems at page 303
Problem number : 36
Date solved : Monday, January 27, 2025 at 02:54:49 AM
CAS classification : [[_2nd_order, _linear, _nonhomogeneous]]

\begin{align*} x^{\prime \prime }+4 x&=f \left (t \right ) \end{align*}

Using Laplace method With initial conditions

\begin{align*} x \left (0\right )&=0\\ x^{\prime }\left (0\right )&=0 \end{align*}

✓ Solution by Maple

Time used: 0.395 (sec). Leaf size: 23

dsolve([diff(x(t),t$2)+4*x(t)=f(t),x(0) = 0, D(x)(0) = 0],x(t), singsol=all)
 

\[ x \left (t \right ) = -\frac {\left (\int _{0}^{t}f \left (\textit {\_U1} \right ) \sin \left (-2 t +2 \textit {\_U1} \right )d \textit {\_U1} \right )}{2} \]

✓ Solution by Mathematica

Time used: 0.094 (sec). Leaf size: 99

DSolve[{D[x[t],{t,2}]+4*x[t]==f[t],{x[0]==0,Derivative[1][x][0] ==0}},x[t],t,IncludeSingularSolutions -> True]
 

\[ x(t)\to -\sin (2 t) \int _1^0\frac {1}{2} \cos (2 K[2]) f(K[2])dK[2]+\sin (2 t) \int _1^t\frac {1}{2} \cos (2 K[2]) f(K[2])dK[2]+\cos (2 t) \left (\int _1^t-\cos (K[1]) f(K[1]) \sin (K[1])dK[1]-\int _1^0-\cos (K[1]) f(K[1]) \sin (K[1])dK[1]\right ) \]