61.34.29 problem 29

Internal problem ID [12793]
Book : Handbook of exact solutions for ordinary differential equations. By Polyanin and Zaitsev. Second edition
Section : Chapter 2, Second-Order Differential Equations. section 2.1.3-1. Equations with exponential functions
Problem number : 29
Date solved : Tuesday, January 28, 2025 at 04:20:10 AM
CAS classification : [[_2nd_order, _with_linear_symmetries]]

\begin{align*} y^{\prime \prime }+\left (2 a \,{\mathrm e}^{\lambda x}+b -\lambda \right ) y^{\prime }+\left (a^{2} {\mathrm e}^{2 \lambda x}+a b \,{\mathrm e}^{\lambda x}+c \,{\mathrm e}^{2 \mu x}+d \,{\mathrm e}^{\mu x}+k \right ) y&=0 \end{align*}

✗ Solution by Maple

dsolve(diff(y(x),x$2)+(2*a*exp(lambda*x)+b-lambda)*diff(y(x),x)+( a^2*exp(2*lambda*x) + a*b*exp(lambda*x) + c*exp(2*mu*x) + d*exp(mu*x)+k )*y(x)=0,y(x), singsol=all)
 

\[ \text {No solution found} \]

✓ Solution by Mathematica

Time used: 1.299 (sec). Leaf size: 332

DSolve[D[y[x],{x,2}]+(2*a*Exp[\[Lambda]*x]+b-\[Lambda])*D[y[x],x]+( a^2*Exp[2*\[Lambda]*x] + a*b*Exp[\[Lambda]*x] + c*Exp[2*\[Mu]*x] + d*Exp[\[Mu]*x]+k )*y[x]==0,y[x],x,IncludeSingularSolutions -> True]
 

\[ y(x)\to \left (e^x\right )^{\frac {1}{2}-\frac {\mu }{2}} \left (\left (e^x\right )^{\lambda }\right )^{-\frac {b-\lambda +1}{2 \lambda }} 2^{\frac {1}{2} \left (\frac {\sqrt {\mu ^2 \left (b^2-2 b \lambda +\lambda ^2-4 k\right )}}{\mu ^2}+1\right )} e^{-\frac {a \left (e^x\right )^{\lambda }}{\lambda }+\frac {i \sqrt {c} \left (e^x\right )^{\mu }}{\mu }} \left (\left (e^x\right )^{\mu }\right )^{\frac {1}{2} \left (\frac {\sqrt {\mu ^2 \left (b^2-2 b \lambda +\lambda ^2-4 k\right )}}{\mu ^2}+1\right )} \left (c_1 \operatorname {HypergeometricU}\left (-\frac {-\mu ^2+\frac {i d \mu }{\sqrt {c}}-\sqrt {\left (b^2-2 \lambda b+\lambda ^2-4 k\right ) \mu ^2}}{2 \mu ^2},\frac {\mu ^2+\sqrt {\left (b^2-2 \lambda b+\lambda ^2-4 k\right ) \mu ^2}}{\mu ^2},-\frac {2 i \sqrt {c} \left (e^x\right )^{\mu }}{\mu }\right )+c_2 L_{-\frac {\mu ^2-\frac {i d \mu }{\sqrt {c}}+\sqrt {\left (b^2-2 \lambda b+\lambda ^2-4 k\right ) \mu ^2}}{2 \mu ^2}}^{\frac {\sqrt {\left (b^2-2 \lambda b+\lambda ^2-4 k\right ) \mu ^2}}{\mu ^2}}\left (-\frac {2 i \sqrt {c} \left (e^x\right )^{\mu }}{\mu }\right )\right ) \]