63.11.9 problem 2

Internal problem ID [13162]
Book : A First Course in Differential Equations by J. David Logan. Third Edition. Springer-Verlag, NY. 2015.
Section : Chapter 2, Second order linear equations. Section 2.4.1 Cauchy-Euler equations. Exercises page 120
Problem number : 2
Date solved : Tuesday, January 28, 2025 at 05:11:33 AM
CAS classification : [[_2nd_order, _missing_y]]

\begin{align*} x^{\prime \prime }+t^{2} x^{\prime }&=0 \end{align*}

With initial conditions

\begin{align*} x \left (0\right )&=0\\ x^{\prime }\left (0\right )&=1 \end{align*}

✓ Solution by Maple

Time used: 2.875 (sec). Leaf size: 62

dsolve([diff(x(t),t$2)+t^2*diff(x(t),t)=0,x(0) = 0, D(x)(0) = 1],x(t), singsol=all)
 

\[ x \left (t \right ) = \frac {{\mathrm e}^{-\frac {t^{3}}{3}} \sqrt {t}\, \left (4 \,3^{{5}/{6}} \left (t^{3}\right )^{{1}/{6}}+9 \operatorname {WhittakerM}\left (\frac {1}{6}, \frac {2}{3}, \frac {t^{3}}{3}\right ) {\mathrm e}^{\frac {t^{3}}{6}}\right ) 3^{{1}/{6}} \left (\left \{\begin {array}{cc} \frac {1}{1-i \sqrt {3}} & t <0 \\ \frac {1}{2} & 0\le t \end {array}\right .\right )}{6} \]

✓ Solution by Mathematica

Time used: 0.095 (sec). Leaf size: 43

DSolve[{D[x[t],{t,2}]+t^2*D[x[t],t]==0,{x[0]==0,Derivative[1][x][0 ]==1}},x[t],t,IncludeSingularSolutions -> True]
 

\[ x(t)\to \frac {t^2 \operatorname {Gamma}\left (\frac {1}{3}\right )-\left (t^3\right )^{2/3} \Gamma \left (\frac {1}{3},\frac {t^3}{3}\right )}{3^{2/3} t^2} \]