28.4.44 problem 7.44

Internal problem ID [4576]
Book : Differential equations for engineers by Wei-Chau XIE, Cambridge Press 2010
Section : Chapter 7. Systems of linear differential equations. Problems at page 351
Problem number : 7.44
Date solved : Monday, January 27, 2025 at 09:23:42 AM
CAS classification : system_of_ODEs

\begin{align*} x_{1}^{\prime }\left (t \right )&=-x_{1} \left (t \right )-5 x_{2} \left (t \right )\\ x_{2}^{\prime }\left (t \right )&=x_{1} \left (t \right )+x_{2} \left (t \right )+\frac {4}{\sin \left (2 t \right )} \end{align*}

Solution by Maple

Time used: 0.345 (sec). Leaf size: 160

dsolve([diff(x__1(t),t)=-x__1(t)-5*x__2(t),diff(x__2(t),t)=x__1(t)+x__2(t)+4/sin(2*t)],singsol=all)
 
\begin{align*} x_{1} \left (t \right ) &= -10 \sin \left (2 t \right ) \ln \left (\sin \left (t \right )\right )+5 \sin \left (2 t \right ) \ln \left (\tan \left (t \right )\right )+c_{2} \sin \left (2 t \right )+c_{1} \cos \left (2 t \right )+10 t \cos \left (2 t \right ) \\ x_{2} \left (t \right ) &= -\tan \left (t \right ) \sin \left (2 t \right )+2 \sin \left (2 t \right ) \ln \left (\sin \left (t \right )\right )-\sin \left (2 t \right ) \ln \left (\tan \left (t \right )\right )+\frac {2 c_{1} \sin \left (2 t \right )}{5}-\frac {c_{2} \sin \left (2 t \right )}{5}+4 t \sin \left (2 t \right )+4 \cos \left (2 t \right ) \ln \left (\sin \left (t \right )\right )-2 \cos \left (2 t \right ) \ln \left (\tan \left (t \right )\right )-\frac {c_{1} \cos \left (2 t \right )}{5}-\frac {2 c_{2} \cos \left (2 t \right )}{5}-2 t \cos \left (2 t \right )+\frac {2 \cos \left (t \right ) \sin \left (2 t \right )}{\sin \left (t \right )}-2 \cos \left (2 t \right )-\frac {\sin \left (2 t \right )}{\tan \left (t \right )} \\ \end{align*}

Solution by Mathematica

Time used: 0.014 (sec). Leaf size: 87

DSolve[{D[x1[t],t]==-x1[t]-5*x2[t],D[x2[t],t]==x1[t]+x2[t]+4/Sin[2*t]},{x1[t],x2[t]},t,IncludeSingularSolutions -> True]
 
\begin{align*} \text {x1}(t)\to (10 t+c_1) \cos (2 t)-\frac {1}{2} \sin (2 t) (10 \log (\sin (2 t))+c_1+5 c_2) \\ \text {x2}(t)\to \frac {1}{2} (\sin (2 t) (8 t+2 \log (\sin (2 t))+c_1+c_2)+\cos (2 t) (-4 t+4 \log (\sin (2 t))+2 c_2)) \\ \end{align*}