Internal
problem
ID
[6337]
Book
:
Fundamentals
of
Differential
Equations.
By
Nagle,
Saff
and
Snider.
9th
edition.
Boston.
Pearson
2018.
Section
:
Chapter
2,
First
order
differential
equations.
Section
2.4,
Exact
equations.
Exercises.
page
64
Problem
number
:
17
Date
solved
:
Monday, January 27, 2025 at 01:56:53 PM
CAS
classification
:
[[_homogeneous, `class G`], _rational]
\begin{align*} \frac {1}{y}-\left (3 y-\frac {x}{y^{2}}\right ) y^{\prime }&=0 \end{align*}
Time used: 0.007 (sec). Leaf size: 18
Time used: 36.497 (sec). Leaf size: 870
\begin{align*}
y(x)\to -\frac {\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt {-\frac {2 \sqrt {6} x}{\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}-\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}-\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}}{\sqrt {6}} \\
y(x)\to \frac {\sqrt {-\frac {2 \sqrt {6} x}{\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}-\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}-\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}-\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}{\sqrt {6}} \\
y(x)\to \frac {\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}-\sqrt {\frac {2 \sqrt {6} x}{\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}-\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}-\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}}{\sqrt {6}} \\
y(x)\to \frac {\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt {\frac {2 \sqrt {6} x}{\sqrt {\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}+\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}-\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}-\frac {4 c_1}{\sqrt [3]{3 x^2-\sqrt {9 x^4-64 c_1{}^3}}}}}{\sqrt {6}} \\
\end{align*}