1.156 problem 157

Internal problem ID [8493]

Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 1, linear first order
Problem number: 157.
ODE order: 1.
ODE degree: 1.

CAS Maple gives this as type [_rational, _Riccati]

\[ \boxed {\left (x^{2}-1\right ) y^{\prime }+a \left (y^{2}-2 y x +1\right )=0} \]

Solution by Maple

Time used: 0.016 (sec). Leaf size: 280

dsolve((x^2-1)*diff(y(x),x) + a*(y(x)^2-2*x*y(x)+1)=0,y(x), singsol=all)
 

\[ y \left (x \right ) = \frac {2 \left (-\frac {x}{2}-\frac {1}{2}\right )^{2 a} \left (-\frac {\left (-\frac {x}{2}-\frac {1}{2}\right )^{-2 a} \left (x +1\right ) \left (x -1\right )^{2} \operatorname {HeunCPrime}\left (0, 2 a -1, 0, 0, a^{2}-a +\frac {1}{2}, \frac {2}{x +1}\right )}{8}-\left (x -1\right )^{2} \operatorname {HeunCPrime}\left (0, -2 a +1, 0, 0, a^{2}-a +\frac {1}{2}, \frac {2}{x +1}\right ) c_{1} +\left (c_{1} \left (\frac {x +1}{x -1}\right )^{-a} \left (\left (a -\frac {1}{2}\right ) x -\frac {a}{2}+\frac {1}{2}\right ) \operatorname {hypergeom}\left (\left [-a +1, -a +1\right ], \left [-2 a +2\right ], -\frac {2}{x -1}\right )+\frac {\operatorname {hypergeom}\left (\left [a , a\right ], \left [2 a \right ], -\frac {2}{x -1}\right ) \left (\frac {x +1}{x -1}\right )^{a} a \left (-\frac {x}{2}-\frac {1}{2}\right )^{-2 a} \left (x -1\right )}{16}\right ) \left (x +1\right )^{2}\right ) \left (\frac {x +1}{x -1}\right )^{a}}{a \left (x +1\right )^{2} \left (c_{1} \operatorname {hypergeom}\left (\left [-a +1, -a +1\right ], \left [-2 a +2\right ], -\frac {2}{x -1}\right ) \left (-\frac {x}{2}-\frac {1}{2}\right )^{2 a}+\frac {\operatorname {hypergeom}\left (\left [a , a\right ], \left [2 a \right ], -\frac {2}{x -1}\right ) \left (\frac {x +1}{x -1}\right )^{2 a} \left (x -1\right )}{8}\right )} \]

Solution by Mathematica

Time used: 0.355 (sec). Leaf size: 47

DSolve[(x^2-1)*y'[x] + a*(y[x]^2-2*x*y[x]+1)==0,y[x],x,IncludeSingularSolutions -> True]
                                                                                    
                                                                                    
 

\begin{align*} y(x)\to \frac {\operatorname {LegendreQ}(a,x)+c_1 \operatorname {LegendreP}(a,x)}{\operatorname {LegendreQ}(a-1,x)+c_1 \operatorname {LegendreP}(a-1,x)} \\ y(x)\to \frac {\operatorname {LegendreP}(a,x)}{\operatorname {LegendreP}(a-1,x)} \\ \end{align*}