63.1.15 problem 15

Internal problem ID [15455]
Book : DIFFERENTIAL and INTEGRAL CALCULUS. VOL I. by N. PISKUNOV. MIR PUBLISHERS, Moscow 1969.
Section : Chapter 8. Differential equations. Exercises page 595
Problem number : 15
Date solved : Thursday, October 02, 2025 at 10:15:03 AM
CAS classification : [_separable]

\begin{align*} y^{\prime }&=\frac {1+y^{2}}{x^{2}+1} \end{align*}
Maple. Time used: 0.003 (sec). Leaf size: 9
ode:=diff(y(x),x) = (1+y(x)^2)/(x^2+1); 
dsolve(ode,y(x), singsol=all);
 
\[ y = \tan \left (\arctan \left (x \right )+c_1 \right ) \]
Mathematica. Time used: 0.176 (sec). Leaf size: 55
ode=D[y[x],x]==(1+y[x]^2)/(1+x^2); 
ic={}; 
DSolve[{ode,ic},y[x],x,IncludeSingularSolutions->True]
 
\begin{align*} y(x)&\to \text {InverseFunction}\left [\int _1^{\text {$\#$1}}\frac {1}{K[1]^2+1}dK[1]\&\right ]\left [\int _1^x\frac {1}{K[2]^2+1}dK[2]+c_1\right ]\\ y(x)&\to -i\\ y(x)&\to i \end{align*}
Sympy. Time used: 0.159 (sec). Leaf size: 8
from sympy import * 
x = symbols("x") 
y = Function("y") 
ode = Eq(Derivative(y(x), x) - (y(x)**2 + 1)/(x**2 + 1),0) 
ics = {} 
dsolve(ode,func=y(x),ics=ics)
 
\[ y{\left (x \right )} = \tan {\left (C_{1} + \operatorname {atan}{\left (x \right )} \right )} \]