[[_1st_order, _with_linear_symmetries]]
Book solution method
Change of variable
Mathematica ✓
cpu = 0.0145078 (sec), leaf count = 47
Maple ✓
cpu = 0.076 (sec), leaf count = 50
DSolve[y[x]*y'[x]^2 == E^(2*x),y[x],x]
Mathematica raw output
{{y[x] -> (3/2)^(2/3)*(-E^x + C[1])^(2/3)}, {y[x] -> (3/2)^(2/3)*(E^x + C[1])^(2
/3)}}
Maple raw input
dsolve(y(x)*diff(y(x),x)^2 = exp(2*x), y(x),'implicit')
Maple raw output
-1/y(x)^(1/2)*(y(x)*exp(x)^2)^(1/2)+2/3*y(x)^(3/2)+_C1 = 0, 1/y(x)^(1/2)*(y(x)*e
xp(x)^2)^(1/2)+2/3*y(x)^(3/2)+_C1 = 0