3.1.2 Example 2

y=y13y(0)=0

First we find the region where solution exists and is unique. f(x,y)=y13. The domain of y13 is y0 since we do not want complex values. Hence solution exists. The domain of fy=131y23 is y>0. Hence the region is all x and y>0. i.e. the top half of the plane not including x-axis. Since the point given is (0,0) on the x-axis, then the theory do not apply. There is no guarantee solution is unique. Only way to find out is to try to solve the ode and find out. Solving the ode gives

dyy13=dx32y23=x+C

Applying IC gives C=0. Hence solution is

32y23=x

Solving for y

y2=(23x)3

Taking the square root of both sides gives

y=±(23x)3=±(23x)32

So there are two solutions. There is also a trivial solution y=0. We see that the solution exists but not unique.