Given linear second order ode
With initial conditions at \(x_{0}\)
If \(p\left ( x\right ) ,q\left ( x\right ) ,f\left ( x\right ) \) are all continuous at \(x_{0}\) then theorem guarantees that a solution exist and is unique on some interval than includes \(x_{0}\). If this was not the case, (i.e. if any of \(p,q,f\) are not continuous at \(x_{0}\)) then the theorem does not apply. This means a solution could still exists and even be unique, but theory does not say anything about this.