2.9 problem Problem 1(i)

2.9.1 Solving as quadrature ode
2.9.2 Maple step by step solution

Internal problem ID [12229]
Internal file name [OUTPUT/10882_Thursday_September_28_2023_01_07_02_AM_25852880/index.tex]

Book: APPLIED DIFFERENTIAL EQUATIONS The Primary Course by Vladimir A. Dobrushkin. CRC Press 2015
Section: Chapter 4, Second and Higher Order Linear Differential Equations. Problems page 221
Problem number: Problem 1(i).
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {y y^{\prime }=1} \]

2.9.1 Solving as quadrature ode

Integrating both sides gives \begin {align*} \int y d y &= x +c_{1}\\ \frac {y^{2}}{2}&=x +c_{1} \end {align*}

Solving for \(y\) gives these solutions \begin {align*} y_1&=\sqrt {2 x +2 c_{1}}\\ y_2&=-\sqrt {2 x +2 c_{1}} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= \sqrt {2 x +2 c_{1}} \\ \tag{2} y &= -\sqrt {2 x +2 c_{1}} \\ \end{align*}

Figure 24: Slope field plot

Verification of solutions

\[ y = \sqrt {2 x +2 c_{1}} \] Verified OK.

\[ y = -\sqrt {2 x +2 c_{1}} \] Verified OK.

2.9.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y y^{\prime }=1 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y y^{\prime }d x =\int 1d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & \frac {y^{2}}{2}=x +c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & \left \{y=\sqrt {2 x +2 c_{1}}, y=-\sqrt {2 x +2 c_{1}}\right \} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
<- Bernoulli successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 23

dsolve(y(x)*diff(y(x),x)=1,y(x), singsol=all)
 

\begin{align*} y \left (x \right ) &= \sqrt {c_{1} +2 x} \\ y \left (x \right ) &= -\sqrt {c_{1} +2 x} \\ \end{align*}

Solution by Mathematica

Time used: 0.018 (sec). Leaf size: 38

DSolve[y[x]*y'[x]==1,y[x],x,IncludeSingularSolutions -> True]
 

\begin{align*} y(x)\to -\sqrt {2} \sqrt {x+c_1} \\ y(x)\to \sqrt {2} \sqrt {x+c_1} \\ \end{align*}