20.5 problem 640

Internal problem ID [15408]
Internal file name [OUTPUT/15409_Wednesday_May_08_2024_03_58_15_PM_32792851/index.tex]

Book: A book of problems in ordinary differential equations. M.L. KRASNOV, A.L. KISELYOV, G.I. MARKARENKO. MIR, MOSCOW. 1983
Section: Chapter 2 (Higher order ODE’s). Section 15.5 Linear equations with variable coefficients. The Lagrange method. Exercises page 148
Problem number: 640.
ODE order: 2.
ODE degree: 1.

The type(s) of ODE detected by this program : "reduction_of_order", "second_order_change_of_variable_on_x_method_2"

Maple gives the following as the ode type

[[_2nd_order, _with_linear_symmetries]]

\[ \boxed {y^{\prime \prime }+\left (\tan \left (x \right )-2 \cot \left (x \right )\right ) y^{\prime }+2 \cot \left (x \right )^{2} y=0} \] Given that one solution of the ode is \begin {align*} y_1 &= \sin \left (x \right ) \end {align*}

Given one basis solution \(y_{1}\left (x \right )\), then the second basis solution is given by \[ y_{2}\left (x \right ) = y_{1} \left (\int \frac {{\mathrm e}^{-\left (\int p d x \right )}}{y_{1}^{2}}d x \right ) \] Where \(p(x)\) is the coefficient of \(y^{\prime }\) when the ode is written in the normal form \[ y^{\prime \prime }+p \left (x \right ) y^{\prime }+q \left (x \right ) y = f \left (x \right ) \] Looking at the ode to solve shows that \[ p \left (x \right ) = \tan \left (x \right )-2 \cot \left (x \right ) \] Therefore \begin{align*} y_{2}\left (x \right ) &= \sin \left (x \right ) \left (\int \frac {{\mathrm e}^{-\left (\int \left (\tan \left (x \right )-2 \cot \left (x \right )\right )d x \right )}}{\sin \left (x \right )^{2}}d x \right ) \\ y_{2}\left (x \right ) &= \sin \left (x \right ) \int \frac {{\mathrm e}^{2 \ln \left (\sin \left (x \right )\right )+\ln \left (\cos \left (x \right )\right )}}{\sin \left (x \right )^{2}} , dx \\ y_{2}\left (x \right ) &= \sin \left (x \right ) \left (\int \cos \left (x \right ) \sin \left (x \right )^{2} \csc \left (x \right )^{2}d x \right ) \\ y_{2}\left (x \right ) &= \sin \left (x \right )^{2} \\ \end{align*} Hence the solution is \begin{align*} y &= c_{1} y_{1}\left (x \right )+c_{2} y_{2}\left (x \right ) \\ &= c_{1} \sin \left (x \right )+c_{2} \sin \left (x \right )^{2} \\ \end{align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= c_{1} \sin \left (x \right )+c_{2} \sin \left (x \right )^{2} \\ \end{align*}

Verification of solutions

\[ y = c_{1} \sin \left (x \right )+c_{2} \sin \left (x \right )^{2} \] Verified OK.

Maple trace

`Methods for second order ODEs: 
--- Trying classification methods --- 
trying a symmetry of the form [xi=0, eta=F(x)] 
checking if the LODE is missing y 
-> Heun: Equivalence to the GHE or one of its 4 confluent cases under a power @ Moebius 
-> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int(r(x), dx)) * 2F1([a1, a2], [b1], f) 
-> Trying changes of variables to rationalize or make the ODE simpler 
   trying a quadrature 
   checking if the LODE has constant coefficients 
   checking if the LODE is of Euler type 
   <- LODE of Euler type successful 
   Change of variables used: 
      [x = arcsin(t)] 
   Linear ODE actually solved: 
      -2*u(t)+2*t*diff(u(t),t)-t^2*diff(diff(u(t),t),t) = 0 
<- change of variables successful`
 

Solution by Maple

Time used: 0.032 (sec). Leaf size: 13

dsolve([diff(y(x),x$2)+(tan(x)-2*cot(x))*diff(y(x),x)+2*cot(x)^2*y(x)=0,sin(x)],singsol=all)
 

\[ y \left (x \right ) = \sin \left (x \right ) \left (\sin \left (x \right ) c_{2} +c_{1} \right ) \]

Solution by Mathematica

Time used: 2.22 (sec). Leaf size: 27

DSolve[y''[x]+(Tan[x]-2*Cot[x])*y'[x]+2*Cot[x]^2*y[x]==0,y[x],x,IncludeSingularSolutions -> True]
 

\[ y(x)\to c_1 \sqrt {-\sin ^2(x)}-c_2 \sin ^2(x) \]