Internal problem ID [13029]
Internal file name [OUTPUT/11682_Wednesday_November_08_2023_03_28_43_AM_26569994/index.tex]
Book: DIFFERENTIAL EQUATIONS by Paul Blanchard, Robert L. Devaney, Glen R. Hall. 4th
edition. Brooks/Cole. Boston, USA. 2012
Section: Chapter 1. First-Order Differential Equations. Review Exercises for chapter 1. page
136
Problem number: 3.
ODE order: 1.
ODE degree: 1.
The type(s) of ODE detected by this program : "quadrature"
Maple gives the following as the ode type
[_quadrature]
\[ \boxed {y^{\prime }=t^{2} \left (t^{2}+1\right )} \]
Integrating both sides gives \begin {align*} y &= \int { t^{2} \left (t^{2}+1\right )\,\mathop {\mathrm {d}t}}\\ &= \frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \end {align*}
Summary
The solution(s) found are the following \begin{align*} \tag{1} y &= \frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \\ \end{align*}
Verification of solutions
\[ y = \frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \] Verified OK.
\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }=t^{2} \left (t^{2}+1\right ) \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} t \\ {} & {} & \int y^{\prime }d t =\int t^{2} \left (t^{2}+1\right )d t +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=\frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=\frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \end {array} \]
Maple trace
`Methods for first order ODEs: --- Trying classification methods --- trying a quadrature <- quadrature successful`
✓ Solution by Maple
Time used: 0.015 (sec). Leaf size: 16
dsolve(diff(y(t),t)=t^2*(t^2+1),y(t), singsol=all)
\[ y \left (t \right ) = \frac {1}{5} t^{5}+\frac {1}{3} t^{3}+c_{1} \]
✓ Solution by Mathematica
Time used: 0.004 (sec). Leaf size: 22
DSolve[y'[t]==t^2*(t^2+1),y[t],t,IncludeSingularSolutions -> True]
\[ y(t)\to \frac {t^5}{5}+\frac {t^3}{3}+c_1 \]