Internal problem ID [6150]
Internal file name [OUTPUT/5398_Sunday_June_05_2022_03_36_15_PM_15070873/index.tex
]
Book: Differential Equations: Theory, Technique, and Practice by George Simmons, Steven
Krantz. McGraw-Hill NY. 2007. 1st Edition.
Section: Chapter 1. What is a differential equation. Section 1.3 SEPARABLE EQUATIONS. Page
12
Problem number: 2(b).
ODE order: 1.
ODE degree: 1.
The type(s) of ODE detected by this program : "exact", "linear", "separable", "homogeneousTypeD2", "first_order_ode_lie_symmetry_lookup"
Maple gives the following as the ode type
[_separable]
\[ \boxed {x^{2} y^{\prime }-y=0} \] With initial conditions \begin {align*} [y \left (1\right ) = 0] \end {align*}
This is a linear ODE. In canonical form it is written as \begin {align*} y^{\prime } + p(x)y &= q(x) \end {align*}
Where here \begin {align*} p(x) &=-\frac {1}{x^{2}}\\ q(x) &=0 \end {align*}
Hence the ode is \begin {align*} y^{\prime }-\frac {y}{x^{2}} = 0 \end {align*}
The domain of \(p(x)=-\frac {1}{x^{2}}\) is \[
\{x <0\boldsymbol {\lor }0
In canonical form the ODE is \begin {align*} y' &= F(x,y)\\ &= f( x) g(y)\\ &= \frac {y}{x^{2}} \end {align*}
Where \(f(x)=\frac {1}{x^{2}}\) and \(g(y)=y\). Since unique solution exists and \(g(y)\) evaluated at \(y_0 = 0\) is zero, then the solution is
\begin {align*} y &= y_0 \\ &= 0 \end {align*}
Summary
The solution(s) found are the following \begin{align*}
\tag{1} y &= 0 \\
\end{align*} Verification of solutions
\[
y = 0
\] Verified OK. \[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \left [x^{2} y^{\prime }-y=0, y \left (1\right )=0\right ] \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & y^{\prime }=\frac {y}{x^{2}} \\ \bullet & {} & \textrm {Separate variables}\hspace {3pt} \\ {} & {} & \frac {y^{\prime }}{y}=\frac {1}{x^{2}} \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int \frac {y^{\prime }}{y}d x =\int \frac {1}{x^{2}}d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & \ln \left (y\right )=c_{1} -\frac {1}{x} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y={\mathrm e}^{\frac {c_{1} x -1}{x}} \\ \bullet & {} & \textrm {Use initial condition}\hspace {3pt} y \left (1\right )=0 \\ {} & {} & 0={\mathrm e}^{-1+c_{1}} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} c_{1} \\ {} & {} & c_{1} =\left (\right ) \\ \bullet & {} & \textrm {Solution does not satisfy initial condition}\hspace {3pt} \end {array} \]
Maple trace
✓ Solution by Maple
Time used: 0.0 (sec). Leaf size: 5
\[
y \left (x \right ) = 0
\]
✓ Solution by Mathematica
Time used: 0.001 (sec). Leaf size: 6
\[
y(x)\to 0
\]
2.12.2 Solving as separable ode
2.12.3 Maple step by step solution
`Methods for first order ODEs:
--- Trying classification methods ---
trying a quadrature
trying 1st order linear
<- 1st order linear successful`
dsolve([diff(y(x),x)*x^2=y(x),y(1) = 0],y(x), singsol=all)
DSolve[{y'[x]*x^2==y[x],{y[1]==0}},y[x],x,IncludeSingularSolutions -> True]