Internal problem ID [9483]
Internal file name [OUTPUT/8423_Monday_June_06_2022_03_02_08_AM_96394904/index.tex]
Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 2, linear second order
Problem number: 1154.
ODE order: 2.
ODE degree: 1.
The type(s) of ODE detected by this program : "second_order_bessel_ode"
Maple gives the following as the ode type
[[_2nd_order, _with_linear_symmetries]]
\[ \boxed {x^{2} y^{\prime \prime }+\left (x^{2} a +b x +c \right ) y=0} \]
Writing the ode as \begin {align*} x^{2} y^{\prime \prime }+\left (x^{2} a +b x +c \right ) y = 0\tag {1} \end {align*}
Bessel ode has the form \begin {align*} x^{2} y^{\prime \prime }+y^{\prime } x +\left (-n^{2}+x^{2}\right ) y = 0\tag {2} \end {align*}
The generalized form of Bessel ode is given by Bowman (1958) as the following \begin {align*} x^{2} y^{\prime \prime }+\left (1-2 \alpha \right ) x y^{\prime }+\left (\beta ^{2} \gamma ^{2} x^{2 \gamma }-n^{2} \gamma ^{2}+\alpha ^{2}\right ) y = 0\tag {3} \end {align*}
With the standard solution \begin {align*} y&=x^{\alpha } \left (c_{1} \operatorname {BesselJ}\left (n , \beta \,x^{\gamma }\right )+c_{2} \operatorname {BesselY}\left (n , \beta \,x^{\gamma }\right )\right )\tag {4} \end {align*}
Comparing (3) to (1) and solving for \(\alpha ,\beta ,n,\gamma \) gives \begin {align*} \alpha &= {\frac {1}{2}}\\ \beta &= 2\\ n &= \sqrt {-4 c +1}\\ \gamma &= {\frac {1}{2}} \end {align*}
Substituting all the above into (4) gives the solution as \begin {align*} y = c_{1} \sqrt {x}\, \operatorname {BesselJ}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right )+c_{2} \sqrt {x}\, \operatorname {BesselY}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right ) \end {align*}
Summary
The solution(s) found are the following \begin{align*} \tag{1} y &= c_{1} \sqrt {x}\, \operatorname {BesselJ}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right )+c_{2} \sqrt {x}\, \operatorname {BesselY}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right ) \\ \end{align*}
Verification of solutions
\[ y = c_{1} \sqrt {x}\, \operatorname {BesselJ}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right )+c_{2} \sqrt {x}\, \operatorname {BesselY}\left (\sqrt {-4 c +1}, 2 \sqrt {x}\right ) \] Verified OK.
\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & x^{2} y^{\prime \prime }+\left (x^{2} a +b x +c \right ) y=0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 2 \\ {} & {} & y^{\prime \prime } \\ \bullet & {} & \textrm {Isolate 2nd derivative}\hspace {3pt} \\ {} & {} & y^{\prime \prime }=-\frac {\left (x^{2} a +b x +c \right ) y}{x^{2}} \\ \bullet & {} & \textrm {Group terms with}\hspace {3pt} y\hspace {3pt}\textrm {on the lhs of the ODE and the rest on the rhs of the ODE; ODE is linear}\hspace {3pt} \\ {} & {} & y^{\prime \prime }+\frac {\left (x^{2} a +b x +c \right ) y}{x^{2}}=0 \\ \square & {} & \textrm {Check to see if}\hspace {3pt} x_{0}=0\hspace {3pt}\textrm {is a regular singular point}\hspace {3pt} \\ {} & \circ & \textrm {Define functions}\hspace {3pt} \\ {} & {} & \left [P_{2}\left (x \right )=0, P_{3}\left (x \right )=\frac {x^{2} a +b x +c}{x^{2}}\right ] \\ {} & \circ & x \cdot P_{2}\left (x \right )\textrm {is analytic at}\hspace {3pt} x =0 \\ {} & {} & \left (x \cdot P_{2}\left (x \right )\right )\bigg | {\mstack {}{_{x \hiderel {=}0}}}=0 \\ {} & \circ & x^{2}\cdot P_{3}\left (x \right )\textrm {is analytic at}\hspace {3pt} x =0 \\ {} & {} & \left (x^{2}\cdot P_{3}\left (x \right )\right )\bigg | {\mstack {}{_{x \hiderel {=}0}}}=c \\ {} & \circ & x =0\textrm {is a regular singular point}\hspace {3pt} \\ & {} & \textrm {Check to see if}\hspace {3pt} x_{0}=0\hspace {3pt}\textrm {is a regular singular point}\hspace {3pt} \\ {} & {} & x_{0}=0 \\ \bullet & {} & \textrm {Multiply by denominators}\hspace {3pt} \\ {} & {} & x^{2} y^{\prime \prime }+\left (x^{2} a +b x +c \right ) y=0 \\ \bullet & {} & \textrm {Assume series solution for}\hspace {3pt} y \\ {} & {} & y=\moverset {\infty }{\munderset {k =0}{\sum }}a_{k} x^{k +r} \\ \square & {} & \textrm {Rewrite ODE with series expansions}\hspace {3pt} \\ {} & \circ & \textrm {Convert}\hspace {3pt} x^{m}\cdot y\hspace {3pt}\textrm {to series expansion for}\hspace {3pt} m =0..2 \\ {} & {} & x^{m}\cdot y=\moverset {\infty }{\munderset {k =0}{\sum }}a_{k} x^{k +r +m} \\ {} & \circ & \textrm {Shift index using}\hspace {3pt} k \mathrm {->}k -m \\ {} & {} & x^{m}\cdot y=\moverset {\infty }{\munderset {k =m}{\sum }}a_{k -m} x^{k +r} \\ {} & \circ & \textrm {Convert}\hspace {3pt} x^{2}\cdot y^{\prime \prime }\hspace {3pt}\textrm {to series expansion}\hspace {3pt} \\ {} & {} & x^{2}\cdot y^{\prime \prime }=\moverset {\infty }{\munderset {k =0}{\sum }}a_{k} \left (k +r \right ) \left (k +r -1\right ) x^{k +r} \\ & {} & \textrm {Rewrite ODE with series expansions}\hspace {3pt} \\ {} & {} & a_{0} \left (r^{2}+c -r \right ) x^{r}+\left (\left (r^{2}+c +r \right ) a_{1}+a_{0} b \right ) x^{1+r}+\left (\moverset {\infty }{\munderset {k =2}{\sum }}\left (a_{k} \left (k^{2}+2 k r +r^{2}+c -k -r \right )+a_{k -1} b +a a_{k -2}\right ) x^{k +r}\right )=0 \\ \bullet & {} & a_{0}\textrm {cannot be 0 by assumption, giving the indicial equation}\hspace {3pt} \\ {} & {} & r^{2}+c -r =0 \\ \bullet & {} & \textrm {Values of r that satisfy the indicial equation}\hspace {3pt} \\ {} & {} & r \in \left \{\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}, \frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right \} \\ \bullet & {} & \textrm {Each term must be 0}\hspace {3pt} \\ {} & {} & \left (r^{2}+c +r \right ) a_{1}+a_{0} b =0 \\ \bullet & {} & \textrm {Solve for the dependent coefficient(s)}\hspace {3pt} \\ {} & {} & a_{1}=-\frac {a_{0} b}{r^{2}+c +r} \\ \bullet & {} & \textrm {Each term in the series must be 0, giving the recursion relation}\hspace {3pt} \\ {} & {} & \left (k^{2}+\left (2 r -1\right ) k +r^{2}+c -r \right ) a_{k}+a a_{k -2}+a_{k -1} b =0 \\ \bullet & {} & \textrm {Shift index using}\hspace {3pt} k \mathrm {->}k +2 \\ {} & {} & \left (\left (k +2\right )^{2}+\left (2 r -1\right ) \left (k +2\right )+r^{2}+c -r \right ) a_{k +2}+a a_{k}+a_{k +1} b =0 \\ \bullet & {} & \textrm {Recursion relation that defines series solution to ODE}\hspace {3pt} \\ {} & {} & a_{k +2}=-\frac {a a_{k}+a_{k +1} b}{k^{2}+2 k r +r^{2}+c +3 k +3 r +2} \\ \bullet & {} & \textrm {Recursion relation for}\hspace {3pt} r =\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2} \\ {} & {} & a_{k +2}=-\frac {a a_{k}+a_{k +1} b}{k^{2}+2 k \left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )+\left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )^{2}+c +3 k +\frac {7}{2}-\frac {3 \sqrt {-4 c +1}}{2}} \\ \bullet & {} & \textrm {Solution for}\hspace {3pt} r =\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2} \\ {} & {} & \left [y=\moverset {\infty }{\munderset {k =0}{\sum }}a_{k} x^{k +\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}}, a_{k +2}=-\frac {a a_{k}+a_{k +1} b}{k^{2}+2 k \left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )+\left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )^{2}+c +3 k +\frac {7}{2}-\frac {3 \sqrt {-4 c +1}}{2}}, a_{1}=-\frac {a_{0} b}{\left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )^{2}+c +\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}}\right ] \\ \bullet & {} & \textrm {Recursion relation for}\hspace {3pt} r =\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2} \\ {} & {} & a_{k +2}=-\frac {a a_{k}+a_{k +1} b}{k^{2}+2 k \left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )+\left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )^{2}+c +3 k +\frac {3 \sqrt {-4 c +1}}{2}+\frac {7}{2}} \\ \bullet & {} & \textrm {Solution for}\hspace {3pt} r =\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2} \\ {} & {} & \left [y=\moverset {\infty }{\munderset {k =0}{\sum }}a_{k} x^{k +\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}}, a_{k +2}=-\frac {a a_{k}+a_{k +1} b}{k^{2}+2 k \left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )+\left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )^{2}+c +3 k +\frac {3 \sqrt {-4 c +1}}{2}+\frac {7}{2}}, a_{1}=-\frac {a_{0} b}{\left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )^{2}+c +\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}}\right ] \\ \bullet & {} & \textrm {Combine solutions and rename parameters}\hspace {3pt} \\ {} & {} & \left [y=\left (\moverset {\infty }{\munderset {k =0}{\sum }}d_{k} x^{k +\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}}\right )+\left (\moverset {\infty }{\munderset {k =0}{\sum }}e_{k} x^{k +\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}}\right ), d_{k +2}=-\frac {a d_{k}+b d_{k +1}}{k^{2}+2 k \left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )+\left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )^{2}+c +3 k +\frac {7}{2}-\frac {3 \sqrt {-4 c +1}}{2}}, d_{1}=-\frac {d_{0} b}{\left (\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}\right )^{2}+c +\frac {1}{2}-\frac {\sqrt {-4 c +1}}{2}}, e_{k +2}=-\frac {a e_{k}+b e_{k +1}}{k^{2}+2 k \left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )+\left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )^{2}+c +3 k +\frac {3 \sqrt {-4 c +1}}{2}+\frac {7}{2}}, e_{1}=-\frac {e_{0} b}{\left (\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}\right )^{2}+c +\frac {\sqrt {-4 c +1}}{2}+\frac {1}{2}}\right ] \end {array} \]
Maple trace
`Methods for second order ODEs: --- Trying classification methods --- trying a quadrature checking if the LODE has constant coefficients checking if the LODE is of Euler type trying a symmetry of the form [xi=0, eta=F(x)] checking if the LODE is missing y -> Trying a Liouvillian solution using Kovacics algorithm <- No Liouvillian solutions exists -> Trying a solution in terms of special functions: -> Bessel -> elliptic -> Legendre -> Whittaker -> hyper3: Equivalence to 1F1 under a power @ Moebius <- hyper3 successful: received ODE is equivalent to the 1F1 ODE <- Whittaker successful <- special function solution successful`
✓ Solution by Maple
Time used: 0.094 (sec). Leaf size: 57
dsolve(x^2*diff(diff(y(x),x),x)+(a*x^2+b*x+c)*y(x)=0,y(x), singsol=all)
\[ y \left (x \right ) = c_{1} \operatorname {WhittakerM}\left (-\frac {i b}{2 \sqrt {a}}, \frac {\sqrt {1-4 c}}{2}, 2 i x \sqrt {a}\right )+c_{2} \operatorname {WhittakerW}\left (-\frac {i b}{2 \sqrt {a}}, \frac {\sqrt {1-4 c}}{2}, 2 i x \sqrt {a}\right ) \]
✓ Solution by Mathematica
Time used: 0.042 (sec). Leaf size: 88
DSolve[(c + b*x + a*x^2)*y[x] + x^2*y''[x] == 0,y[x],x,IncludeSingularSolutions -> True]
\[ y(x)\to c_1 M_{-\frac {i b}{2 \sqrt {a}},-\frac {1}{2} i \sqrt {4 c-1}}\left (2 i \sqrt {a} x\right )+c_2 W_{-\frac {i b}{2 \sqrt {a}},-\frac {1}{2} i \sqrt {4 c-1}}\left (2 i \sqrt {a} x\right ) \]