1.48 problem 48

1.48.1 Solving as abelFirstKind ode
1.48.2 Maple step by step solution

Internal problem ID [8385]
Internal file name [OUTPUT/7318_Sunday_June_05_2022_05_47_28_PM_32745466/index.tex]

Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 1, linear first order
Problem number: 48.
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "abelFirstKind"

Maple gives the following as the ode type

[_Abel]

Unable to solve or complete the solution.

\[ \boxed {y^{\prime }-\left (a \,x^{n}+b x \right ) y^{3}-c y^{2}=0} \]

1.48.1 Solving as abelFirstKind ode

This is Abel first kind ODE, it has the form \[ y^{\prime }= f_0(x)+f_1(x) y +f_2(x)y^{2}+f_3(x)y^{3} \] Comparing the above to given ODE which is \begin {align*} y^{\prime }&=\left (a \,x^{n}+b x \right ) y^{3}+c y^{2}\tag {1} \end {align*}

Therefore \begin {align*} f_0(x) &= 0\\ f_1(x) &= 0\\ f_2(x) &= c\\ f_3(x) &= a \,x^{n}+b x \end {align*}

Since \(f_2(x)=c\) is not zero, then the first step is to apply the following transformation to remove \(f_2\). Let \(y = u(x) - \frac {f_2}{3 f_3}\) or \begin {align*} y &= u(x) - \left ( \frac {c}{3 a \,x^{n}+3 b x} \right ) \\ &= u \left (x \right )-\frac {c}{3 a \,x^{n}+3 b x} \end {align*}

The above transformation applied to (1) gives a new ODE as \begin {align*} u^{\prime }\left (x \right ) = \frac {x^{3 n} u \left (x \right )^{3} a^{3}}{\left (a \,x^{n}+b x \right )^{2}}+\frac {3 x \,x^{2 n} u \left (x \right )^{3} a^{2} b}{\left (a \,x^{n}+b x \right )^{2}}+\frac {3 x^{2} x^{n} u \left (x \right )^{3} a \,b^{2}}{\left (a \,x^{n}+b x \right )^{2}}+\frac {x^{3} u \left (x \right )^{3} b^{3}}{\left (a \,x^{n}+b x \right )^{2}}-\frac {x^{n} u \left (x \right ) a \,c^{2}}{3 \left (a \,x^{n}+b x \right )^{2}}-\frac {x u \left (x \right ) b \,c^{2}}{3 \left (a \,x^{n}+b x \right )^{2}}-\frac {x^{n} a c n}{3 \left (a \,x^{n}+b x \right )^{2} x}+\frac {2 c^{3}}{27 \left (a \,x^{n}+b x \right )^{2}}-\frac {c b}{3 \left (a \,x^{n}+b x \right )^{2}}\tag {2} \end {align*}

This is Abel first kind ODE, it has the form \[ u^{\prime }\left (x \right )= f_0(x)+f_1(x) u \left (x \right ) +f_2(x)u \left (x \right )^{2}+f_3(x)u \left (x \right )^{3} \] Comparing the above to given ODE which is \begin {align*} u^{\prime }\left (x \right )&=\frac {\left (27 x \,a^{3} x^{3 n}+81 x^{2} b \,a^{2} x^{2 n}+81 x^{3} b^{2} a \,x^{n}+27 x^{4} b^{3}\right ) u \left (x \right )^{3}}{27 x \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}+\frac {\left (-9 x^{n} a \,c^{2} x -9 b \,c^{2} x^{2}\right ) u \left (x \right )}{27 x \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}+\frac {-9 x^{n} a c n +2 c^{3} x -9 c b x}{27 x \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}\tag {1} \end {align*}

Therefore \begin {align*} f_0(x) &= -\frac {x^{n} a c n}{3 x \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}+\frac {2 c^{3}}{27 \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}-\frac {c b}{3 \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}\\ f_1(x) &= -\frac {a \,x^{n} c^{2}}{3 \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}-\frac {b x \,c^{2}}{3 \left (a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}\right )}\\ f_2(x) &= 0\\ f_3(x) &= \frac {a^{3} x^{3 n}}{a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}}+\frac {3 x b \,a^{2} x^{2 n}}{a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}}+\frac {3 x^{2} b^{2} a \,x^{n}}{a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}}+\frac {b^{3} x^{3}}{a^{2} x^{2 n}+2 a \,x^{n} b x +b^{2} x^{2}} \end {align*}

Since \(f_2(x)=0\) then we check the Abel invariant to see if it depends on \(x\) or not. The Abel invariant is given by \begin {align*} -\frac {f_{1}^{3}}{f_{0}^{2} f_{3}} \end {align*}

Which when evaluating gives \begin {align*} \text {Expression too large to display} \end {align*}

Since the Abel invariant depends on \(x\) then unable to solve this ode at this time.

Unable to complete the solution now.

1.48.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }-\left (a \,x^{n}+b x \right ) y^{3}-c y^{2}=0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & y^{\prime }=\left (a \,x^{n}+b x \right ) y^{3}+c y^{2} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
trying inverse linear 
trying homogeneous types: 
trying Chini 
differential order: 1; looking for linear symmetries 
trying exact 
trying Abel 
Looking for potential symmetries 
Looking for potential symmetries 
Looking for potential symmetries 
trying inverse_Riccati 
trying an equivalence to an Abel ODE 
differential order: 1; trying a linearization to 2nd order 
--- trying a change of variables {x -> y(x), y(x) -> x} 
differential order: 1; trying a linearization to 2nd order 
trying 1st order ODE linearizable_by_differentiation 
--- Trying Lie symmetry methods, 1st order --- 
`, `-> Computing symmetries using: way = 3 
`, `-> Computing symmetries using: way = 4 
`, `-> Computing symmetries using: way = 2 
trying symmetry patterns for 1st order ODEs 
-> trying a symmetry pattern of the form [F(x)*G(y), 0] 
-> trying a symmetry pattern of the form [0, F(x)*G(y)] 
-> trying symmetry patterns of the forms [F(x),G(y)] and [G(y),F(x)] 
`, `-> Computing symmetries using: way = HINT 
   -> Calling odsolve with the ODE`, diff(y(x), x)+y(x)*(x^n*a*n+b*x)/(x*(a*x^n+b*x)), y(x)`      *** Sublevel 2 *** 
      Methods for first order ODEs: 
      --- Trying classification methods --- 
      trying a quadrature 
      trying 1st order linear 
      <- 1st order linear successful 
`, `-> Computing symmetries using: way = HINT 
   -> Calling odsolve with the ODE`, diff(y(x), x) = -y(x)*(x^n*a*n+b*x)/(x*(a*x^n+b*x)), y(x)`      *** Sublevel 2 *** 
      Methods for first order ODEs: 
      --- Trying classification methods --- 
      trying a quadrature 
      trying 1st order linear 
      <- 1st order linear successful 
   -> Calling odsolve with the ODE`, diff(y(x), x)-(b*x^2*K[1]+2*y(x)*c)/(c*x), y(x)`      *** Sublevel 2 *** 
      Methods for first order ODEs: 
      --- Trying classification methods --- 
      trying a quadrature 
      trying 1st order linear 
      <- 1st order linear successful 
-> trying a symmetry pattern of the form [F(x),G(x)] 
-> trying a symmetry pattern of the form [F(y),G(y)] 
-> trying a symmetry pattern of the form [F(x)+G(y), 0] 
-> trying a symmetry pattern of the form [0, F(x)+G(y)] 
-> trying a symmetry pattern of the form [F(x),G(x)*y+H(x)] 
-> trying a symmetry pattern of conformal type`
 

Solution by Maple

dsolve(diff(y(x),x) - (a*x^n + b*x)*y(x)^3 - c*y(x)^2=0,y(x), singsol=all)
 

\[ \text {No solution found} \]

Solution by Mathematica

Time used: 0.0 (sec). Leaf size: 0

DSolve[y'[x] - (a*x^n + b*x)*y[x]^3 - c*y[x]^2==0,y[x],x,IncludeSingularSolutions -> True]
 

Not solved