2.362 problem 939

2.362.1 Solving as first order ode lie symmetry calculated ode
2.362.2 Maple step by step solution

Internal problem ID [9272]
Internal file name [OUTPUT/8208_Monday_June_06_2022_02_17_30_AM_3103180/index.tex]

Book: Differential Gleichungen, E. Kamke, 3rd ed. Chelsea Pub. NY, 1948
Section: Chapter 1, Additional non-linear first order
Problem number: 939.
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "first_order_ode_lie_symmetry_calculated"

Maple gives the following as the ode type

[[_1st_order, _with_linear_symmetries], _rational, [_Abel, `2nd type`, `class C`]]

Unable to solve or complete the solution.

\[ \boxed {y^{\prime }-\frac {-32 y x +16 x^{3}+16 x^{2}-32 x -64 y^{3}+48 y^{2} x^{2}+96 y^{2} x -12 x^{4} y-48 y x^{3}-48 y x^{2}+x^{6}+6 x^{5}+12 x^{4}}{-64 y+16 x^{2}+32 x -64}=0} \]

2.362.1 Solving as first order ode lie symmetry calculated ode

Writing the ode as \begin {align*} y^{\prime }&=\frac {-x^{6}-6 x^{5}+12 x^{4} y -12 x^{4}+48 y \,x^{3}-48 y^{2} x^{2}-16 x^{3}+48 x^{2} y -96 y^{2} x +64 y^{3}-16 x^{2}+32 y x +32 x}{-16 x^{2}-32 x +64 y +64}\\ y^{\prime }&= \omega \left ( x,y\right ) \end {align*}

The condition of Lie symmetry is the linearized PDE given by \begin {align*} \eta _{x}+\omega \left ( \eta _{y}-\xi _{x}\right ) -\omega ^{2}\xi _{y}-\omega _{x}\xi -\omega _{y}\eta =0\tag {A} \end {align*}

The type of this ode is not in the lookup table. To determine \(\xi ,\eta \) then (A) is solved using ansatz. Making bivariate polynomials of degree 1 to use as anstaz gives \begin{align*} \tag{1E} \xi &= x a_{2}+y a_{3}+a_{1} \\ \tag{2E} \eta &= x b_{2}+y b_{3}+b_{1} \\ \end{align*} Where the unknown coefficients are \[ \{a_{1}, a_{2}, a_{3}, b_{1}, b_{2}, b_{3}\} \] Substituting equations (1E,2E) and \(\omega \) into (A) gives \begin{equation} \tag{5E} b_{2}+\frac {\left (-x^{6}-6 x^{5}+12 x^{4} y -12 x^{4}+48 y \,x^{3}-48 y^{2} x^{2}-16 x^{3}+48 x^{2} y -96 y^{2} x +64 y^{3}-16 x^{2}+32 y x +32 x \right ) \left (b_{3}-a_{2}\right )}{-16 x^{2}-32 x +64 y +64}-\frac {\left (-x^{6}-6 x^{5}+12 x^{4} y -12 x^{4}+48 y \,x^{3}-48 y^{2} x^{2}-16 x^{3}+48 x^{2} y -96 y^{2} x +64 y^{3}-16 x^{2}+32 y x +32 x \right )^{2} a_{3}}{256 \left (-x^{2}-2 x +4 y +4\right )^{2}}-\left (\frac {-6 x^{5}-30 x^{4}+48 y \,x^{3}-48 x^{3}+144 x^{2} y -96 y^{2} x -48 x^{2}+96 y x -96 y^{2}-32 x +32 y +32}{-16 x^{2}-32 x +64 y +64}-\frac {\left (-x^{6}-6 x^{5}+12 x^{4} y -12 x^{4}+48 y \,x^{3}-48 y^{2} x^{2}-16 x^{3}+48 x^{2} y -96 y^{2} x +64 y^{3}-16 x^{2}+32 y x +32 x \right ) \left (-2 x -2\right )}{16 \left (-x^{2}-2 x +4 y +4\right )^{2}}\right ) \left (x a_{2}+y a_{3}+a_{1}\right )-\left (\frac {12 x^{4}+48 x^{3}-96 x^{2} y +48 x^{2}-192 y x +192 y^{2}+32 x}{-16 x^{2}-32 x +64 y +64}-\frac {-x^{6}-6 x^{5}+12 x^{4} y -12 x^{4}+48 y \,x^{3}-48 y^{2} x^{2}-16 x^{3}+48 x^{2} y -96 y^{2} x +64 y^{3}-16 x^{2}+32 y x +32 x}{4 \left (-x^{2}-2 x +4 y +4\right )^{2}}\right ) \left (x b_{2}+y b_{3}+b_{1}\right ) = 0 \end{equation} Putting the above in normal form gives \[ -\frac {x^{12} a_{3}+12 x^{11} a_{3}-24 x^{10} y a_{3}+60 x^{10} a_{3}-240 x^{9} y a_{3}+240 x^{8} y^{2} a_{3}+176 x^{9} a_{3}-960 x^{8} y a_{3}+1920 x^{7} y^{2} a_{3}-1280 x^{6} y^{3} a_{3}+80 x^{8} a_{2}+368 x^{8} a_{3}-16 x^{8} b_{3}-2112 x^{7} y a_{3}+5760 x^{6} y^{2} a_{3}-7680 x^{5} y^{3} a_{3}+3840 x^{4} y^{4} a_{3}+64 x^{7} a_{1}+576 x^{7} a_{2}+512 x^{7} a_{3}-128 x^{7} b_{2}-128 x^{7} b_{3}-1024 x^{6} y a_{2}-3008 x^{6} y a_{3}+128 x^{6} y b_{3}+8448 x^{5} y^{2} a_{3}-15360 x^{4} y^{3} a_{3}+15360 x^{3} y^{4} a_{3}-6144 x^{2} y^{5} a_{3}+448 x^{6} a_{1}+1088 x^{6} a_{2}+256 x^{6} a_{3}-128 x^{6} b_{1}-768 x^{6} b_{2}-320 x^{6} b_{3}-768 x^{5} y a_{1}-5376 x^{5} y a_{2}-2304 x^{5} y a_{3}+1536 x^{5} y b_{2}+768 x^{5} y b_{3}+4608 x^{4} y^{2} a_{2}+6144 x^{4} y^{2} a_{3}-11264 x^{3} y^{3} a_{3}+15360 x^{2} y^{4} a_{3}-12288 x \,y^{5} a_{3}+4096 y^{6} a_{3}+768 x^{5} a_{1}-256 x^{5} a_{2}-256 x^{5} a_{3}-768 x^{5} b_{1}-768 x^{5} b_{2}-256 x^{5} b_{3}-3840 x^{4} y a_{1}-5376 x^{4} y a_{2}+1536 x^{4} y b_{1}+6144 x^{4} y b_{2}+1536 x^{4} y b_{3}+3072 x^{3} y^{2} a_{1}+15360 x^{3} y^{2} a_{2}-6144 x^{3} y^{2} b_{2}-8192 x^{2} y^{3} a_{2}+1024 x^{2} y^{3} a_{3}-2048 x^{2} y^{3} b_{3}-512 x^{4} a_{1}-2048 x^{4} a_{2}-768 x^{4} a_{3}-768 x^{4} b_{1}+1792 x^{4} b_{2}-3072 x^{3} y a_{1}+5120 x^{3} y a_{2}+6144 x^{3} y b_{1}+2048 x^{3} y b_{3}+9216 x^{2} y^{2} a_{1}+3072 x^{2} y^{2} a_{2}-6144 x^{2} y^{2} b_{1}-12288 x^{2} y^{2} b_{2}-3072 x^{2} y^{2} b_{3}-4096 x \,y^{3} a_{1}-12288 x \,y^{3} a_{2}+4096 x \,y^{3} a_{3}+8192 x \,y^{3} b_{2}-4096 x \,y^{3} b_{3}+4096 y^{4} a_{2}-4096 y^{4} a_{3}+4096 y^{4} b_{3}-2048 x^{3} a_{1}-3072 x^{3} a_{2}-1024 x^{3} a_{3}+2048 x^{3} b_{1}+2048 x^{3} b_{2}+1024 x^{3} b_{3}+5120 x^{2} y a_{1}+5120 x^{2} y a_{2}-10240 x^{2} y b_{2}+2048 x^{2} y b_{3}-8192 x \,y^{2} a_{2}+4096 x \,y^{2} a_{3}-12288 x \,y^{2} b_{1}+12288 x \,y^{2} b_{2}-8192 x \,y^{2} b_{3}-4096 y^{3} a_{1}+4096 y^{3} a_{2}-4096 y^{3} a_{3}+8192 y^{3} b_{1}+8192 y^{3} b_{3}-2048 x^{2} a_{1}-4096 x^{2} a_{2}+1024 x^{2} a_{3}+3072 x^{2} b_{1}+1024 x^{2} b_{2}+2048 x^{2} b_{3}+4096 x y a_{1}+8192 x y a_{2}-2048 x y a_{3}-12288 x y b_{1}+4096 x y b_{2}-4096 x y b_{3}-4096 y^{2} a_{1}+4096 y^{2} a_{3}+12288 y^{2} b_{1}-4096 y^{2} b_{2}-2048 x a_{1}+4096 x a_{2}+4096 x b_{2}-2048 x b_{3}+4096 y a_{1}+2048 y a_{3}-8192 y b_{2}+2048 a_{1}-4096 b_{2}}{256 \left (x^{2}+2 x -4 y -4\right )^{2}} = 0 \] Setting the numerator to zero gives \begin{equation} \tag{6E} -x^{12} a_{3}-12 x^{11} a_{3}+24 x^{10} y a_{3}-60 x^{10} a_{3}+240 x^{9} y a_{3}-240 x^{8} y^{2} a_{3}-176 x^{9} a_{3}+960 x^{8} y a_{3}-1920 x^{7} y^{2} a_{3}+1280 x^{6} y^{3} a_{3}-80 x^{8} a_{2}-368 x^{8} a_{3}+16 x^{8} b_{3}+2112 x^{7} y a_{3}-5760 x^{6} y^{2} a_{3}+7680 x^{5} y^{3} a_{3}-3840 x^{4} y^{4} a_{3}-64 x^{7} a_{1}-576 x^{7} a_{2}-512 x^{7} a_{3}+128 x^{7} b_{2}+128 x^{7} b_{3}+1024 x^{6} y a_{2}+3008 x^{6} y a_{3}-128 x^{6} y b_{3}-8448 x^{5} y^{2} a_{3}+15360 x^{4} y^{3} a_{3}-15360 x^{3} y^{4} a_{3}+6144 x^{2} y^{5} a_{3}-448 x^{6} a_{1}-1088 x^{6} a_{2}-256 x^{6} a_{3}+128 x^{6} b_{1}+768 x^{6} b_{2}+320 x^{6} b_{3}+768 x^{5} y a_{1}+5376 x^{5} y a_{2}+2304 x^{5} y a_{3}-1536 x^{5} y b_{2}-768 x^{5} y b_{3}-4608 x^{4} y^{2} a_{2}-6144 x^{4} y^{2} a_{3}+11264 x^{3} y^{3} a_{3}-15360 x^{2} y^{4} a_{3}+12288 x \,y^{5} a_{3}-4096 y^{6} a_{3}-768 x^{5} a_{1}+256 x^{5} a_{2}+256 x^{5} a_{3}+768 x^{5} b_{1}+768 x^{5} b_{2}+256 x^{5} b_{3}+3840 x^{4} y a_{1}+5376 x^{4} y a_{2}-1536 x^{4} y b_{1}-6144 x^{4} y b_{2}-1536 x^{4} y b_{3}-3072 x^{3} y^{2} a_{1}-15360 x^{3} y^{2} a_{2}+6144 x^{3} y^{2} b_{2}+8192 x^{2} y^{3} a_{2}-1024 x^{2} y^{3} a_{3}+2048 x^{2} y^{3} b_{3}+512 x^{4} a_{1}+2048 x^{4} a_{2}+768 x^{4} a_{3}+768 x^{4} b_{1}-1792 x^{4} b_{2}+3072 x^{3} y a_{1}-5120 x^{3} y a_{2}-6144 x^{3} y b_{1}-2048 x^{3} y b_{3}-9216 x^{2} y^{2} a_{1}-3072 x^{2} y^{2} a_{2}+6144 x^{2} y^{2} b_{1}+12288 x^{2} y^{2} b_{2}+3072 x^{2} y^{2} b_{3}+4096 x \,y^{3} a_{1}+12288 x \,y^{3} a_{2}-4096 x \,y^{3} a_{3}-8192 x \,y^{3} b_{2}+4096 x \,y^{3} b_{3}-4096 y^{4} a_{2}+4096 y^{4} a_{3}-4096 y^{4} b_{3}+2048 x^{3} a_{1}+3072 x^{3} a_{2}+1024 x^{3} a_{3}-2048 x^{3} b_{1}-2048 x^{3} b_{2}-1024 x^{3} b_{3}-5120 x^{2} y a_{1}-5120 x^{2} y a_{2}+10240 x^{2} y b_{2}-2048 x^{2} y b_{3}+8192 x \,y^{2} a_{2}-4096 x \,y^{2} a_{3}+12288 x \,y^{2} b_{1}-12288 x \,y^{2} b_{2}+8192 x \,y^{2} b_{3}+4096 y^{3} a_{1}-4096 y^{3} a_{2}+4096 y^{3} a_{3}-8192 y^{3} b_{1}-8192 y^{3} b_{3}+2048 x^{2} a_{1}+4096 x^{2} a_{2}-1024 x^{2} a_{3}-3072 x^{2} b_{1}-1024 x^{2} b_{2}-2048 x^{2} b_{3}-4096 x y a_{1}-8192 x y a_{2}+2048 x y a_{3}+12288 x y b_{1}-4096 x y b_{2}+4096 x y b_{3}+4096 y^{2} a_{1}-4096 y^{2} a_{3}-12288 y^{2} b_{1}+4096 y^{2} b_{2}+2048 x a_{1}-4096 x a_{2}-4096 x b_{2}+2048 x b_{3}-4096 y a_{1}-2048 y a_{3}+8192 y b_{2}-2048 a_{1}+4096 b_{2} = 0 \end{equation} Looking at the above PDE shows the following are all the terms with \(\{x, y\}\) in them. \[ \{x, y\} \] The following substitution is now made to be able to collect on all terms with \(\{x, y\}\) in them \[ \{x = v_{1}, y = v_{2}\} \] The above PDE (6E) now becomes \begin{equation} \tag{7E} \text {Expression too large to display} \end{equation} Collecting the above on the terms \(v_i\) introduced, and these are \[ \{v_{1}, v_{2}\} \] Equation (7E) now becomes \begin{equation} \tag{8E} \left (1024 a_{2}+3008 a_{3}-128 b_{3}\right ) v_{1}^{6} v_{2}+\left (768 a_{1}+5376 a_{2}+2304 a_{3}-1536 b_{2}-768 b_{3}\right ) v_{1}^{5} v_{2}+\left (-4608 a_{2}-6144 a_{3}\right ) v_{1}^{4} v_{2}^{2}+\left (3840 a_{1}+5376 a_{2}-1536 b_{1}-6144 b_{2}-1536 b_{3}\right ) v_{1}^{4} v_{2}+\left (-3072 a_{1}-15360 a_{2}+6144 b_{2}\right ) v_{1}^{3} v_{2}^{2}+\left (3072 a_{1}-5120 a_{2}-6144 b_{1}-2048 b_{3}\right ) v_{1}^{3} v_{2}+\left (8192 a_{2}-1024 a_{3}+2048 b_{3}\right ) v_{1}^{2} v_{2}^{3}+\left (-9216 a_{1}-3072 a_{2}+6144 b_{1}+12288 b_{2}+3072 b_{3}\right ) v_{1}^{2} v_{2}^{2}+\left (-5120 a_{1}-5120 a_{2}+10240 b_{2}-2048 b_{3}\right ) v_{1}^{2} v_{2}+\left (4096 a_{1}+12288 a_{2}-4096 a_{3}-8192 b_{2}+4096 b_{3}\right ) v_{1} v_{2}^{3}+\left (8192 a_{2}-4096 a_{3}+12288 b_{1}-12288 b_{2}+8192 b_{3}\right ) v_{1} v_{2}^{2}+\left (-4096 a_{1}-8192 a_{2}+2048 a_{3}+12288 b_{1}-4096 b_{2}+4096 b_{3}\right ) v_{1} v_{2}-2048 a_{1}+4096 b_{2}+\left (-80 a_{2}-368 a_{3}+16 b_{3}\right ) v_{1}^{8}+\left (-64 a_{1}-576 a_{2}-512 a_{3}+128 b_{2}+128 b_{3}\right ) v_{1}^{7}+\left (-448 a_{1}-1088 a_{2}-256 a_{3}+128 b_{1}+768 b_{2}+320 b_{3}\right ) v_{1}^{6}-a_{3} v_{1}^{12}-12 a_{3} v_{1}^{11}-60 a_{3} v_{1}^{10}-176 a_{3} v_{1}^{9}-4096 a_{3} v_{2}^{6}+\left (2048 a_{1}+4096 a_{2}-1024 a_{3}-3072 b_{1}-1024 b_{2}-2048 b_{3}\right ) v_{1}^{2}+\left (2048 a_{1}-4096 a_{2}-4096 b_{2}+2048 b_{3}\right ) v_{1}+\left (-4096 a_{2}+4096 a_{3}-4096 b_{3}\right ) v_{2}^{4}+\left (4096 a_{1}-4096 a_{2}+4096 a_{3}-8192 b_{1}-8192 b_{3}\right ) v_{2}^{3}+\left (4096 a_{1}-4096 a_{3}-12288 b_{1}+4096 b_{2}\right ) v_{2}^{2}+\left (-4096 a_{1}-2048 a_{3}+8192 b_{2}\right ) v_{2}+24 a_{3} v_{1}^{10} v_{2}+240 a_{3} v_{1}^{9} v_{2}-240 a_{3} v_{1}^{8} v_{2}^{2}+960 a_{3} v_{1}^{8} v_{2}-1920 a_{3} v_{1}^{7} v_{2}^{2}+1280 a_{3} v_{1}^{6} v_{2}^{3}+2112 a_{3} v_{1}^{7} v_{2}-5760 a_{3} v_{1}^{6} v_{2}^{2}+7680 a_{3} v_{1}^{5} v_{2}^{3}-3840 a_{3} v_{1}^{4} v_{2}^{4}-8448 a_{3} v_{1}^{5} v_{2}^{2}+15360 a_{3} v_{1}^{4} v_{2}^{3}-15360 a_{3} v_{1}^{3} v_{2}^{4}+6144 a_{3} v_{1}^{2} v_{2}^{5}+11264 a_{3} v_{1}^{3} v_{2}^{3}-15360 a_{3} v_{1}^{2} v_{2}^{4}+12288 a_{3} v_{1} v_{2}^{5}+\left (-768 a_{1}+256 a_{2}+256 a_{3}+768 b_{1}+768 b_{2}+256 b_{3}\right ) v_{1}^{5}+\left (512 a_{1}+2048 a_{2}+768 a_{3}+768 b_{1}-1792 b_{2}\right ) v_{1}^{4}+\left (2048 a_{1}+3072 a_{2}+1024 a_{3}-2048 b_{1}-2048 b_{2}-1024 b_{3}\right ) v_{1}^{3} = 0 \end{equation} Setting each coefficients in (8E) to zero gives the following equations to solve \begin {align*} -15360 a_{3}&=0\\ -8448 a_{3}&=0\\ -5760 a_{3}&=0\\ -4096 a_{3}&=0\\ -3840 a_{3}&=0\\ -1920 a_{3}&=0\\ -240 a_{3}&=0\\ -176 a_{3}&=0\\ -60 a_{3}&=0\\ -12 a_{3}&=0\\ -a_{3}&=0\\ 24 a_{3}&=0\\ 240 a_{3}&=0\\ 960 a_{3}&=0\\ 1280 a_{3}&=0\\ 2112 a_{3}&=0\\ 6144 a_{3}&=0\\ 7680 a_{3}&=0\\ 11264 a_{3}&=0\\ 12288 a_{3}&=0\\ 15360 a_{3}&=0\\ -2048 a_{1}+4096 b_{2}&=0\\ -4608 a_{2}-6144 a_{3}&=0\\ -4096 a_{1}-2048 a_{3}+8192 b_{2}&=0\\ -3072 a_{1}-15360 a_{2}+6144 b_{2}&=0\\ -4096 a_{2}+4096 a_{3}-4096 b_{3}&=0\\ -80 a_{2}-368 a_{3}+16 b_{3}&=0\\ 1024 a_{2}+3008 a_{3}-128 b_{3}&=0\\ 8192 a_{2}-1024 a_{3}+2048 b_{3}&=0\\ -5120 a_{1}-5120 a_{2}+10240 b_{2}-2048 b_{3}&=0\\ 2048 a_{1}-4096 a_{2}-4096 b_{2}+2048 b_{3}&=0\\ 3072 a_{1}-5120 a_{2}-6144 b_{1}-2048 b_{3}&=0\\ 4096 a_{1}-4096 a_{3}-12288 b_{1}+4096 b_{2}&=0\\ -9216 a_{1}-3072 a_{2}+6144 b_{1}+12288 b_{2}+3072 b_{3}&=0\\ -64 a_{1}-576 a_{2}-512 a_{3}+128 b_{2}+128 b_{3}&=0\\ 512 a_{1}+2048 a_{2}+768 a_{3}+768 b_{1}-1792 b_{2}&=0\\ 768 a_{1}+5376 a_{2}+2304 a_{3}-1536 b_{2}-768 b_{3}&=0\\ 3840 a_{1}+5376 a_{2}-1536 b_{1}-6144 b_{2}-1536 b_{3}&=0\\ 4096 a_{1}-4096 a_{2}+4096 a_{3}-8192 b_{1}-8192 b_{3}&=0\\ 4096 a_{1}+12288 a_{2}-4096 a_{3}-8192 b_{2}+4096 b_{3}&=0\\ 8192 a_{2}-4096 a_{3}+12288 b_{1}-12288 b_{2}+8192 b_{3}&=0\\ -4096 a_{1}-8192 a_{2}+2048 a_{3}+12288 b_{1}-4096 b_{2}+4096 b_{3}&=0\\ -768 a_{1}+256 a_{2}+256 a_{3}+768 b_{1}+768 b_{2}+256 b_{3}&=0\\ -448 a_{1}-1088 a_{2}-256 a_{3}+128 b_{1}+768 b_{2}+320 b_{3}&=0\\ 2048 a_{1}+3072 a_{2}+1024 a_{3}-2048 b_{1}-2048 b_{2}-1024 b_{3}&=0\\ 2048 a_{1}+4096 a_{2}-1024 a_{3}-3072 b_{1}-1024 b_{2}-2048 b_{3}&=0 \end {align*}

Solving the above equations for the unknowns gives \begin {align*} a_{1}&=a_{1}\\ a_{2}&=0\\ a_{3}&=0\\ b_{1}&=\frac {a_{1}}{2}\\ b_{2}&=\frac {a_{1}}{2}\\ b_{3}&=0 \end {align*}

Substituting the above solution in the anstaz (1E,2E) (using \(1\) as arbitrary value for any unknown in the RHS) gives \begin{align*} \xi &= 1 \\ \eta &= \frac {x}{2}+\frac {1}{2} \\ \end{align*} The next step is to determine the canonical coordinates \(R,S\). The canonical coordinates map \(\left ( x,y\right ) \to \left ( R,S \right )\) where \(\left ( R,S \right )\) are the canonical coordinates which make the original ode become a quadrature and hence solved by integration.

The characteristic pde which is used to find the canonical coordinates is \begin {align*} \frac {d x}{\xi } &= \frac {d y}{\eta } = dS \tag {1} \end {align*}

The above comes from the requirements that \(\left ( \xi \frac {\partial }{\partial x} + \eta \frac {\partial }{\partial y}\right ) S(x,y) = 1\). Starting with the first pair of ode’s in (1) gives an ode to solve for the independent variable \(R\) in the canonical coordinates, where \(S(R)\). Unable to determine \(R\). Terminating

2.362.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & -x^{6}+12 x^{4} y-6 x^{5}-48 y^{2} x^{2}+48 y x^{3}-12 x^{4}+64 y^{3}-96 y^{2} x +48 y x^{2}+16 x^{2} y^{\prime }-16 x^{3}-64 y y^{\prime }+32 y x +32 y^{\prime } x -16 x^{2}-64 y^{\prime }+32 x =0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & y^{\prime }=\frac {-32 y x +16 x^{3}+16 x^{2}-32 x -64 y^{3}+48 y^{2} x^{2}+96 y^{2} x -12 x^{4} y-48 y x^{3}-48 y x^{2}+x^{6}+6 x^{5}+12 x^{4}}{-64 y+16 x^{2}+32 x -64} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
trying Bernoulli 
trying separable 
trying inverse linear 
trying homogeneous types: 
trying Chini 
differential order: 1; looking for linear symmetries 
differential order: 1; found: 1 linear symmetries. Trying reduction of order 
1st order, trying the canonical coordinates of the invariance group 
<- 1st order, canonical coordinates successful`
 

Solution by Maple

Time used: 0.078 (sec). Leaf size: 79

dsolve(diff(y(x),x) = (-32*x*y(x)+16*x^3+16*x^2-32*x-64*y(x)^3+48*x^2*y(x)^2+96*x*y(x)^2-12*y(x)*x^4-48*x^3*y(x)-48*x^2*y(x)+x^6+6*x^5+12*x^4)/(-64*y(x)+16*x^2+32*x-64),y(x), singsol=all)
 

\[ x +\frac {2 \ln \left (2\right )}{5}+\frac {2 \ln \left (16 y \left (x \right )^{2}+\left (-8 x^{2}-16 x +16\right ) y \left (x \right )+x^{4}+4 x^{3}-8 x +8\right )}{5}-\frac {2 \arctan \left (-2 y \left (x \right )+\frac {x^{2}}{2}+x -1\right )}{5}-\frac {4 \ln \left (4 y \left (x \right )-x^{2}-2 x -4\right )}{5}-c_{1} = 0 \]

Solution by Mathematica

Time used: 0.374 (sec). Leaf size: 136

DSolve[y'[x] == (-32*x + 16*x^2 + 16*x^3 + 12*x^4 + 6*x^5 + x^6 - 32*x*y[x] - 48*x^2*y[x] - 48*x^3*y[x] - 12*x^4*y[x] + 96*x*y[x]^2 + 48*x^2*y[x]^2 - 64*y[x]^3)/(-64 + 32*x + 16*x^2 - 64*y[x]),y[x],x,IncludeSingularSolutions -> True]
 

\[ \text {Solve}\left [\frac {2}{5} \text {RootSum}\left [\text {$\#$1}^4+4 \text {$\#$1}^3-8 \text {$\#$1}^2 y(x)-16 \text {$\#$1} y(x)-8 \text {$\#$1}+16 y(x)^2+16 y(x)+8\&,\frac {\text {$\#$1}^2 (-\log (x-\text {$\#$1}))+4 y(x) \log (x-\text {$\#$1})-2 \text {$\#$1} \log (x-\text {$\#$1})+3 \log (x-\text {$\#$1})}{-\text {$\#$1}^2-2 \text {$\#$1}+4 y(x)+2}\&\right ]-\frac {4}{5} \log \left (x^2-4 y(x)+2 x+4\right )+x=c_1,y(x)\right ] \]