Internal problem ID [1186]
Internal file name [OUTPUT/1187_Sunday_June_05_2022_02_04_30_AM_23388380/index.tex
]
Book: Elementary differential equations with boundary value problems. William F. Trench.
Brooks/Cole 2001
Section: Chapter 5 linear second order equations. Section 5.7 Variation of Parameters. Page
262
Problem number: 32.
ODE order: 2.
ODE degree: 1.
The type(s) of ODE detected by this program : "unknown"
Maple gives the following as the ode type
[[_2nd_order, _linear, _nonhomogeneous]]
Unable to solve or complete the solution.
\[ \boxed {\left (x -1\right )^{2} y^{\prime \prime }-\left (x^{2}-1\right ) y^{\prime }+\left (x -1\right )^{3} y=\left (x -1\right )^{3} {\mathrm e}^{x}} \] With initial conditions \begin {align*} [y \left (0\right ) = 4, y^{\prime }\left (0\right ) = -6] \end {align*}
This is a linear ODE. In canonical form it is written as \begin {align*} y^{\prime \prime } + p(x)y^{\prime } + q(x) y &= F \end {align*}
Where here \begin {align*} p(x) &=\frac {-x^{2}+1}{\left (x -1\right )^{2}}\\ q(x) &=x -1\\ F &=\left (x -1\right ) {\mathrm e}^{x} \end {align*}
Hence the ode is \begin {align*} y^{\prime \prime }+\frac {\left (-x^{2}+1\right ) y^{\prime }}{\left (x -1\right )^{2}}+y \left (x -1\right ) = \left (x -1\right ) {\mathrm e}^{x} \end {align*}
The domain of \(p(x)=\frac {-x^{2}+1}{\left (x -1\right )^{2}}\) is \[
\{x <1\boldsymbol {\lor }1 Maple trace
✗ Solution by Maple
\[ \text {No solution found} \]
✗ Solution by Mathematica
Time used: 0.0 (sec). Leaf size: 0
Not solved
`Methods for second order ODEs:
--- Trying classification methods ---
trying a quadrature
trying high order exact linear fully integrable
trying differential order: 2; linear nonhomogeneous with symmetry [0,1]
trying a double symmetry of the form [xi=0, eta=F(x)]
-> Try solving first the homogeneous part of the ODE
checking if the LODE has constant coefficients
checking if the LODE is of Euler type
trying a symmetry of the form [xi=0, eta=F(x)]
checking if the LODE is missing y
-> Trying a Liouvillian solution using Kovacics algorithm
<- No Liouvillian solutions exists
-> Trying a solution in terms of special functions:
-> Bessel
-> elliptic
-> Legendre
-> Kummer
-> hyper3: Equivalence to 1F1 under a power @ Moebius
-> hypergeometric
-> heuristic approach
-> hyper3: Equivalence to 2F1, 1F1 or 0F1 under a power @ Moebius
-> Mathieu
-> Equivalence to the rational form of Mathieu ODE under a power @ Moebius
trying a solution in terms of MeijerG functions
-> Heun: Equivalence to the GHE or one of its 4 confluent cases under a power @ Moebius
-> trying a solution of the form r0(x) * Y + r1(x) * Y where Y = exp(int(r(x), dx)) * 2F1([a1, a2], [b1], f)
trying a symmetry of the form [xi=0, eta=F(x)]
trying symmetries linear in x and y(x)
trying to convert to a linear ODE with constant coefficients
trying 2nd order, integrating factor of the form mu(x,y)
-> Trying a solution in terms of special functions:
-> Bessel
-> elliptic
-> Legendre
-> Whittaker
-> hyper3: Equivalence to 1F1 under a power @ Moebius
-> hypergeometric
-> heuristic approach
-> hyper3: Equivalence to 2F1, 1F1 or 0F1 under a power @ Moebius
-> Mathieu
-> Equivalence to the rational form of Mathieu ODE under a power @ Moebius
trying 2nd order exact linear
trying symmetries linear in x and y(x)
trying to convert to a linear ODE with constant coefficients
trying to convert to an ODE of Bessel type
trying to convert to an ODE of Bessel type
-> trying reduction of order to Riccati
trying Riccati sub-methods:
-> trying a symmetry pattern of the form [F(x)*G(y), 0]
-> trying a symmetry pattern of the form [0, F(x)*G(y)]
-> trying a symmetry pattern of the form [F(x),G(x)*y+H(x)]
--- Trying Lie symmetry methods, 2nd order ---
`, `-> Computing symmetries using: way = 3
`, `-> Computing symmetries using: way = 5`
dsolve([(x-1)^2*diff(y(x),x$2)-(x^2-1)*diff(y(x),x)+(x-1)^3*y(x)=(x-1)^3*exp(x),y(0) = 4, D(y)(0) = -6],y(x), singsol=all)
DSolve[{(x-1)^2*y''[x]-(x^2-1)*y'[x]+(x-1)^3*y[x]==(x-1)^3*Exp[x],{y[0]==4,y'[0]==-6}},y[x],x,IncludeSingularSolutions -> True]