1.1 problem 1.1-2 (a)

1.1.1 Solving as quadrature ode
1.1.2 Maple step by step solution

Internal problem ID [2447]
Internal file name [OUTPUT/1939_Sunday_June_05_2022_02_40_08_AM_92199210/index.tex]

Book: Ordinary Differential Equations, Robert H. Martin, 1983
Section: Problem 1.1-2, page 6
Problem number: 1.1-2 (a).
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {y^{\prime }=t^{2}+3} \]

1.1.1 Solving as quadrature ode

Integrating both sides gives \begin {align*} y &= \int { t^{2}+3\,\mathop {\mathrm {d}t}}\\ &= \frac {t \left (t^{2}+9\right )}{3}+c_{1} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= \frac {t \left (t^{2}+9\right )}{3}+c_{1} \\ \end{align*}

Figure 1: Slope field plot

Verification of solutions

\[ y = \frac {t \left (t^{2}+9\right )}{3}+c_{1} \] Verified OK.

1.1.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }=t^{2}+3 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} t \\ {} & {} & \int y^{\prime }d t =\int \left (t^{2}+3\right )d t +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=\frac {1}{3} t^{3}+3 t +c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=\frac {1}{3} t^{3}+3 t +c_{1} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
<- quadrature successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 14

dsolve(diff(y(t),t)=t^2+3,y(t), singsol=all)
 

\[ y \left (t \right ) = \frac {1}{3} t^{3}+3 t +c_{1} \]

Solution by Mathematica

Time used: 0.003 (sec). Leaf size: 18

DSolve[y'[t]==t^2+3,y[t],t,IncludeSingularSolutions -> True]
 

\[ y(t)\to \frac {t^3}{3}+3 t+c_1 \]