28.5 problem 802

28.5.1 Maple step by step solution

Internal problem ID [4042]
Internal file name [OUTPUT/3535_Sunday_June_05_2022_09_35_58_AM_32424933/index.tex]

Book: Ordinary differential equations and their solutions. By George Moseley Murphy. 1960
Section: Various 28
Problem number: 802.
ODE order: 1.
ODE degree: 2.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {{y^{\prime }}^{2}-2 x^{2} y^{\prime }+2 x y^{\prime }=0} \] The ode \begin {align*} {y^{\prime }}^{2}-2 x^{2} y^{\prime }+2 x y^{\prime } = 0 \end {align*}

is factored to \begin {align*} y^{\prime } \left (-2 x^{2}+y^{\prime }+2 x \right ) = 0 \end {align*}

Which gives the following equations \begin {align*} y^{\prime } = 0\tag {1} \\ -2 x^{2}+y^{\prime }+2 x = 0\tag {2} \\ \end {align*}

Each of the above equations is now solved.

Solving ODE (1) Integrating both sides gives \begin {align*} y &= \int { 0\,\mathop {\mathrm {d}x}}\\ &= c_{1} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= c_{1} \\ \end{align*}

Verification of solutions

\[ y = c_{1} \] Verified OK.

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= c_{1} \\ \end{align*}

Verification of solutions

\[ y = c_{1} \] Verified OK.

Solving ODE (2) Integrating both sides gives \begin {align*} y &= \int { 2 x^{2}-2 x\,\mathop {\mathrm {d}x}}\\ &= \frac {x^{2} \left (2 x -3\right )}{3}+c_{2} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= \frac {x^{2} \left (2 x -3\right )}{3}+c_{2} \\ \end{align*}

Verification of solutions

\[ y = \frac {x^{2} \left (2 x -3\right )}{3}+c_{2} \] Verified OK.

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= \frac {x^{2} \left (2 x -3\right )}{3}+c_{2} \\ \end{align*}

Verification of solutions

\[ y = \frac {x^{2} \left (2 x -3\right )}{3}+c_{2} \] Verified OK.

28.5.1 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & {y^{\prime }}^{2}-2 x^{2} y^{\prime }+2 x y^{\prime }=0 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & \left [y^{\prime }=0, y^{\prime }=2 x^{2}-2 x \right ] \\ \square & {} & \textrm {Solve the equation}\hspace {3pt} y^{\prime }=0 \\ {} & \circ & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int 0d x +c_{1} \\ {} & \circ & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=c_{1} \\ {} & \circ & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=c_{1} \\ \square & {} & \textrm {Solve the equation}\hspace {3pt} y^{\prime }=2 x^{2}-2 x \\ {} & \circ & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int \left (2 x^{2}-2 x \right )d x +c_{1} \\ {} & \circ & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=\frac {2}{3} x^{3}-x^{2}+c_{1} \\ {} & \circ & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=\frac {2}{3} x^{3}-x^{2}+c_{1} \\ \bullet & {} & \textrm {Set of solutions}\hspace {3pt} \\ {} & {} & \left \{y=c_{1} , y=\frac {2}{3} x^{3}-x^{2}+c_{1} \right \} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
<- quadrature successful 
Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
trying 1st order linear 
<- 1st order linear successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 20

dsolve(diff(y(x),x)^2-2*x^2*diff(y(x),x)+2*x*diff(y(x),x) = 0,y(x), singsol=all)
 

\begin{align*} y \left (x \right ) &= \frac {2}{3} x^{3}-x^{2}+c_{1} \\ y \left (x \right ) &= c_{1} \\ \end{align*}

Solution by Mathematica

Time used: 0.006 (sec). Leaf size: 26

DSolve[(y'[x])^2-2 x^2 y'[x]+2 x y'[x]==0,y[x],x,IncludeSingularSolutions -> True]
 

\begin{align*} y(x)\to c_1 \\ y(x)\to \frac {2 x^3}{3}-x^2+c_1 \\ \end{align*}