1.37 problem 44

1.37.1 Solving as quadrature ode
1.37.2 Maple step by step solution

Internal problem ID [14080]
Internal file name [OUTPUT/13761_Saturday_March_02_2024_02_49_19_PM_47175982/index.tex]

Book: INTRODUCTORY DIFFERENTIAL EQUATIONS. Martha L. Abell, James P. Braselton. Fourth edition 2014. ElScAe. 2014
Section: Chapter 1. Introduction to Differential Equations. Exercises 1.1, page 10
Problem number: 44.
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {y^{\prime }=\frac {1}{x^{2}-16}} \]

1.37.1 Solving as quadrature ode

Integrating both sides gives \begin {align*} y &= \int { \frac {1}{x^{2}-16}\,\mathop {\mathrm {d}x}}\\ &= -\frac {\operatorname {arctanh}\left (\frac {x}{4}\right )}{4}+c_{1} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= -\frac {\operatorname {arctanh}\left (\frac {x}{4}\right )}{4}+c_{1} \\ \end{align*}

Figure 52: Slope field plot

Verification of solutions

\[ y = -\frac {\operatorname {arctanh}\left (\frac {x}{4}\right )}{4}+c_{1} \] Verified OK.

1.37.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & y^{\prime }=\frac {1}{x^{2}-16} \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int \frac {1}{x^{2}-16}d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=\frac {\ln \left (x -4\right )}{8}-\frac {\ln \left (x +4\right )}{8}+c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=\frac {\ln \left (x -4\right )}{8}-\frac {\ln \left (x +4\right )}{8}+c_{1} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
<- quadrature successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 18

dsolve(diff(y(x),x)=1/(x^2-16),y(x), singsol=all)
 

\[ y \left (x \right ) = -\frac {\ln \left (x +4\right )}{8}+\frac {\ln \left (x -4\right )}{8}+c_{1} \]

Solution by Mathematica

Time used: 0.004 (sec). Leaf size: 26

DSolve[y'[x]==1/(x^2-16),y[x],x,IncludeSingularSolutions -> True]
 

\[ y(x)\to \frac {1}{8} (\log (4-x)-\log (x+4)+8 c_1) \]