1.14 problem 2.3 (d)

1.14.1 Solving as quadrature ode
1.14.2 Maple step by step solution

Internal problem ID [13255]
Internal file name [OUTPUT/12427_Wednesday_February_14_2024_02_06_11_AM_9493631/index.tex]

Book: Ordinary Differential Equations. An introduction to the fundamentals. Kenneth B. Howell. second edition. CRC Press. FL, USA. 2020
Section: Chapter 2. Integration and differential equations. Additional exercises. page 32
Problem number: 2.3 (d).
ODE order: 1.
ODE degree: 1.

The type(s) of ODE detected by this program : "quadrature"

Maple gives the following as the ode type

[_quadrature]

\[ \boxed {\sqrt {x +4}\, y^{\prime }=1} \]

1.14.1 Solving as quadrature ode

Integrating both sides gives \begin {align*} y &= \int { \frac {1}{\sqrt {x +4}}\,\mathop {\mathrm {d}x}}\\ &= 2 \sqrt {x +4}+c_{1} \end {align*}

Summary

The solution(s) found are the following \begin{align*} \tag{1} y &= 2 \sqrt {x +4}+c_{1} \\ \end{align*}

Figure 29: Slope field plot

Verification of solutions

\[ y = 2 \sqrt {x +4}+c_{1} \] Verified OK.

1.14.2 Maple step by step solution

\[ \begin {array}{lll} & {} & \textrm {Let's solve}\hspace {3pt} \\ {} & {} & \sqrt {x +4}\, y^{\prime }=1 \\ \bullet & {} & \textrm {Highest derivative means the order of the ODE is}\hspace {3pt} 1 \\ {} & {} & y^{\prime } \\ \bullet & {} & \textrm {Solve for the highest derivative}\hspace {3pt} \\ {} & {} & y^{\prime }=\frac {1}{\sqrt {x +4}} \\ \bullet & {} & \textrm {Integrate both sides with respect to}\hspace {3pt} x \\ {} & {} & \int y^{\prime }d x =\int \frac {1}{\sqrt {x +4}}d x +c_{1} \\ \bullet & {} & \textrm {Evaluate integral}\hspace {3pt} \\ {} & {} & y=2 \sqrt {x +4}+c_{1} \\ \bullet & {} & \textrm {Solve for}\hspace {3pt} y \\ {} & {} & y=2 \sqrt {x +4}+c_{1} \end {array} \]

Maple trace

`Methods for first order ODEs: 
--- Trying classification methods --- 
trying a quadrature 
<- quadrature successful`
 

Solution by Maple

Time used: 0.0 (sec). Leaf size: 13

dsolve(sqrt(x+4)*diff(y(x),x)=1,y(x), singsol=all)
 

\[ y \left (x \right ) = 2 \sqrt {x +4}+c_{1} \]

Solution by Mathematica

Time used: 0.003 (sec). Leaf size: 17

DSolve[Sqrt[x+4]*y'[x]==1,y[x],x,IncludeSingularSolutions -> True]
 

\[ y(x)\to 2 \sqrt {x+4}+c_1 \]