3.17.99 $\int \frac{1}{x\log (\frac{1}{5x})}dx$

Optimal. Leaf size=19 $$\frac{1}{25e^4}-\log (\log \left(\frac{1}{5x}\right))$$

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Rubi [A]  time = 0.01, antiderivative size = 11, normalized size of antiderivative = 0.58, number of steps used = 2, number of rules used = 2, integrand size = 14, $\frac{\text{number of rules}}{\text{integrand size}}$ = 0.143, Rules used = {2302, 29} $$\begin{array}{c}-\log (\log \left(\frac{1}{5x}\right))\end{array}$$

Antiderivative was successfully verified.

[In]

Int[1/(x*Log[1/(5*x)]),x]

[Out]

-Log[Log[1/(5*x)]]

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 2302

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)/(x_), x_Symbol] :> Dist[1/(b*n), Subst[Int[x^p, x], x, a + b*L
og[c*x^n]], x] /; FreeQ[{a, b, c, n, p}, x]

Rubi steps

$$\begin{array}{c}\begin{array}{rl}\text{integral}& =-\mathrm{Subst}(\int \frac{1}{x}dx,x,\log \left(\frac{1}{5x}\right))\\ & =-\log (\log \left(\frac{1}{5x}\right))\end{array}\end{array}$$

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Mathematica [A]  time = 0.01, size = 11, normalized size = 0.58 $$\begin{array}{c}-\log (\log \left(\frac{1}{5x}\right))\end{array}$$

Antiderivative was successfully verified.

[In]

Integrate[1/(x*Log[1/(5*x)]),x]

[Out]

-Log[Log[1/(5*x)]]

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fricas [A]  time = 0.70, size = 9, normalized size = 0.47 $$\begin{array}{c}-\log (\log \left(\frac{1}{5x}\right))\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/log(1/5/x),x, algorithm="fricas")

[Out]

-log(log(1/5/x))

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giac [A]  time = 0.51, size = 8, normalized size = 0.42 $$\begin{array}{c}-\log \left(|\log \left(5x\right)|\right)\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/log(1/5/x),x, algorithm="giac")

[Out]

-log(abs(log(5*x)))

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maple [A]  time = 0.02, size = 10, normalized size = 0.53

method	result	size
derivativedivides	$-\ln (\ln \left(\frac{1}{5x}\right))$	$10$
default	$-\ln (\ln \left(\frac{1}{5x}\right))$	$10$
norman	$-\ln (\ln \left(\frac{1}{5x}\right))$	$10$
risch	$-\ln (\ln \left(\frac{1}{5x}\right))$	$10$

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x/ln(1/5/x),x,method=_RETURNVERBOSE)

[Out]

-ln(ln(1/5/x))

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maxima [A]  time = 0.41, size = 9, normalized size = 0.47 $$\begin{array}{c}-\log (\log \left(\frac{1}{5x}\right))\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/log(1/5/x),x, algorithm="maxima")

[Out]

-log(log(1/5/x))

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mupad [B]  time = 1.14, size = 9, normalized size = 0.47 $$\begin{array}{c}-\ln (\ln \left(\frac{1}{5x}\right))\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x*log(1/(5*x))),x)

[Out]

-log(log(1/(5*x)))

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sympy [A]  time = 0.12, size = 8, normalized size = 0.42 $$\begin{array}{c}-\log (\log \left(\frac{1}{5x}\right))\end{array}$$

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x/ln(1/5/x),x)

[Out]

-log(log(1/(5*x)))

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